How to convert a string to uppercase initial capital letters?

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• How to convert a string and use a rope as a property?

  I have an array in the following format:

  {ownsCar: 'true', ownsBike: 'true', ownsHouse: 'true'}

  {ownsCar: ownsBike 'false',: 'true', ownsHouse: 'true'}

  {ownsCar: 'true', ownsBike: ownsHouse 'false',: 'true'}

  etc ............

  And I need to test against each element, for example

  If...

  myDataGrid ["myItem"] .ownsCar is object (myCheckbox) .label

  ... then

  If...

  myDataGrid ["myItem"] .ownsBike is object (myCheckbox) .label

  ... then

  If...

  myDataGrid ["myItem"] .ownsHouse is object (myCheckbox) .label

  ... then

  But I have to build my application where the property (for example 'ownsCar', 'ownsBike', 'ownsHouse') is a variable such as:

  If...

  myDataGrid ["myItem"] .myProperty is object (myCheckbox) .label

  ... then

  I would like to browse my table, by counting the number of items and then use each element as a property.

  How to convert the string (for example, "ownsCar") in a property "myProperty"?

  Thanks in advance

  Chris

  OK, if I got this right what you need to do is introspection.

  The easiest way to do this would be:

  for ( var propertyName:String in myObject ) {
       // Do what you need with this here:
       myObject[ propertyName ];
  }
  

• [Oracle 8i] How to convert a string (timestamp) in a date?

  I find it difficult to know how to convert a string to a date time stamp (or possibly several).
  
  The timestamp is 20 positions, character (NOT NULL, CHAR (20))
  in the format: YYYYMMDDHHMMSSUUUUUU
  where Y = year, M = month, D = day, M = Minutes, S = seconds and U = microseconds
  
  The reason why I want to convert it is so that I can compare a timestamp to each other (that is, I want to be able to find the MIN (timestamp), MAX (timestamp) and make comparisons of inequality).
  
  Is this possible?
  
  Thanks in advance for the help on this!

  Hello

  As Damorgan said, if all you want to do is find which is the earlier or later, then you can just compare the strings: they are in a format where it works.

  If you need to do other things, such as compare to today date or see the difference between two of your lines of days, you will need to convert it to date. (He has no reason to convert them to numbers).

  A new TIMESTAMP data type, which manages the fractions of a second, was introduced in Oracle 9.
  Since you use Oracle 8 (depending on your subject line), or it must be
  (1) ignores the microseconds, or
  (2) use a separate column for microseconds.

  Whatever it is, use TO_DATE to convert the first 14 characters in DATE:

  TO_DATE ( SUBSTR (txt, 1, 14)
          , 'YYYYMMDDHH24MISS'
          )
  

  where txt is your column of type CHAR.
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• How to convert a string to a number?

  How to convert a numeric string to a number of TestStand?

  Use Val().

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• How to convert the string with numbers in U8 with ascii

  Hello

  I have a string with only numbers 0. 9 paper.

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  He works here, but now the problem: How can I change each character to its ascii value?

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  Thanks for the help

  It's very easy

  String to Byte Array Function
  Have the Palette: string/array/path Conversion functions

  Converts a string to an array of unsigned bytes. Each byte in the array has the ASCII value of the character corresponding to the string.

• How to convert the string in milliseconds

  Hello

  Please suggest how I can convert a string (October 9, 1989) in milliseconds...

  If it has a certain format, you can use HttpDateParser, otherwise create a calendar object, set the relevant values and get the time to it.

• How to convert the string to a full decimal point and left shift

  Hey guys I tried to convert gps string to an integer, like this

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  Hi Awais07,

  Once you have created an indicator that signals the output of parsing the string, right-click on this indicator > display... Format > increase the value of the digit 9

  Kind regards

  Lennard.C

• How to convert a string to byte array

  Hello

  I want to convert a string with a hexadecimal number in the array of bytes, this string includes a cutting-edge information, but I don't want to add this tip to arry bytes.

  detailed information please see the photo. I hope someone can give me some instructions, thank you very much.

  

  The accepted solution of Giedrius.S is not correct, based on the image shown in the first post. That the solution will not eliminate the spaces before the tip, and the string to byte array to convert individual characters '0', '8', 'space', '9', etc. for them to byte values. The right solution, based on the image below:

  

• How to convert a string literal function function valid

  Hello
  
  I have a situation where I need to get the built-in (sysdate/sysdate-1/sysdate-2) as variables. As the variable is taken as a string, it is considered as a string, not a function. Is it possible to convert the string literal in valid function.
  
  Here is an example for better understanding. I used v_var to store the 'sysdate-1 "in the form of string literal. Try to change the value.
  
  
  */*-------------------------------------------------------------------------------------*/*
  declare
  
  v_var varchar2 (20): = ' sysdate-1';
  date of v_var2;
  
  Start
  
  Select v_var in the double v_var2;
  
  dbms_output.put_line ('v_var2: ' | v_var2);
  
  end;
  
  */*-------------------------------------------------------------------------------------*/*
  
  
  Thanks in advance

  Or

  SQL>  var str varchar2(20)
  SQL>  exec :str := 'sysdate - 1'
  PL/SQL procedure successfully completed.
  
  SQL>  select trim(dbms_xmlgen.getxmltype('select ' || :str || ' s from dual').extract('//text()')) str from dual
  /
  STR
  ------------------------
  15.07.09
  1 row selected.
  

• How can I identify all the words in capital letters and change to initcaps?

  Hello

  I'm using Oracle 11.g

  I have a table with multiple textual data varchar2 columns.  There are several words that are all uppercase.  In all cases, these capital words should be replaced by different cases (for example, HELLO Hello).  How find the capitalized words in all the lines and change them to mixed-case?

  Thanks for your help.

  The rownum in your update statement is probably taken as the virtual rownum http://docs.oracle.com/cd/E11882_01/server.112/e41084/pseudocolumns009.htm#SQLRF00255

  This is probably the reason why the script compiles, but the update does not work as there is no column named rownum in your table (even if it exists, rename it as is among the reserved words http://docs.oracle.com/cd/E11882_01/server.112/e41084/ap_keywd001.htm#SQLRF55621)

  trying to avoid loops to the extent possible, that I see it more as

  CREATE TABLE 'LITURGY_READING_COPY' ("ROW_ID" NUMBER NOT NULL ACTIVATE, VARCHAR2 (4000) 'TEXT')

  Table created.

  insert into liturgy_reading_copy

  Select 1, ' a reading from the letter of Saint PAUL to the Romans: BROTHERS and SŒURS: everything that has been written above... ". »

  of all the double union

  Select 2, "another text, less HOLY inspiration, containing all the WORDS in capital LETTERS

  of the double

  2 inserted rows.

  ROW_ID	TEXT
  1	A reading from the letter of Saint PAUL to the Romans: BROTHERS and SŒURS: everything that has been written above...
  2	Another text, at least the HOLY inspiration, containing all the WORDS in capital LETTERS

  merge into liturgy_reading_copy lrc

  using (with

  init_capitalizer (RID, CBC, res) as

  (select row_id,

  substr (text, instr (text,' ') + 1) | '  ',

  -case when substr (text, 1, instr (text,' ')) = upper (substr (text, 1, instr (text,' ')))

  then initcap (substr (text, 1, instr (text,' ')))

  of another substr (text, 1, instr (text,' '))

  end

  of liturgy_reading_copy

  Union of all the

  Select RID.

  substr (src, instr (CBC,' ') + 1) | ' ',

  RES | -case when substr (src, 1, instr (CBC,' ')) = upper (substr (src, 1, instr (CBC,' ')))

  then initcap (substr (src, 1, instr (CBC,' ')))

  of another substr (src, 1, instr (CBC,' '))

  end

  of init_capitalizer

  where rtrim (src) is not null

  )

  Select RID, res

  of init_capitalizer

  where rtrim (src) is null

  ) ic

  on (lrc.row_id = ic.rid)

  when matched

  then update

  text = ic.res

  Statement processed.

  ROW_ID	TEXT
  1	A reading from the letter of Saint Paul to the Romans: siblings: everything that has been written above...
  2	Another text, less Holy inspiration containing all the words in capital letters

  Concerning

  Etbin

• How to convert the string 'True' to Boolean

  Hi all

  I have strings as 'True' and 'False. ' I want to convert to a Boolean value so that I can change the value of the check box control.

  Thank you best regards &,.

  Shrinivas

  Ford Hi,

  Just compare with a string constant 'TRUE' for equality (maybe do a uppercase or lowercase conversion front to channel more easy to handle...)!

• How to convert a string of data to a table 1 d

  Dear all,

  I wonder if someone can help me.

  In the attached Elf, I have my program (in labview 8.6) who read the updates and the data of temperature for the time.

  I want to use temperature update in a calculation.  How can I get the new temperature I think it's in a format string and convert it into table 1 d?

  I tried, but the number I got the temperature wasn't the same temperature, which is shonw in the section of the program data.

  Could someone help me please?

  Kind regards

  You do not read the temperature, you read a binary file. You seem to be assuming that the string format, but do you really know? Nobody here can say since you do not have the file, if it is you need to use one of the functions of conversion of the string. And please, get rid of the local data variable. You're already usin shift registers. Do the same with the data from the file.

• How to convert the string with numbers in the table of Boolean 2D

  Hello

  I have input a string with comma separated numbers 1,192 (starting at 1).

  This string must be converted to a table 2D-boolean. Each number that appears should be true, not true rest.

  The 2D table consists of 4 times of 0.47 Boolean values.

  1.48--> [0.47] numbers [0]
  49.96--> [0.47] numbers [1]
  Numbers 97.144--> [0.47] [2]
  145.192--> [0.47] numbers [3]

  If a '1, 49, 97 145' input string put all [0] [0.3] true.

  How can it be easy/fast resolved?

  Thanks for help

  Break the string of numbers in a table of numbers.  (Spreasheet String to Array).

  In a loop For, index with each issue of this table.  Use in the range and Coerce to see if it is in the range of numbers.  (You can put this in a loop For as auto good indexing through the ranges).  If it's in the range, then use subset replace table to activate the corresponding item in a real.  If this is not the case, do nothing.  Maintain the table of Boolean in a shift register.

  Repeat this step for each number in your table.

  (What is a class assignment?)

• How to convert a string to a data type double

  I'm eager to take a string representation of a number and convert it to an INT64 data type to perform a function.  What can I use for this?

  Do a right click on the blockdiagram... go to programming--> string--> sting / numberconversion--> fract/expstringtonumber

• How to convert the string Primitive in PMString.

  Hello

  I'm working on string manipulation tasks. I have a primitive type string (std::string), I want to turn it into PMString. Does anyone know how to do this?

  Cann't we use directly instead of WideString PMString?

  Like: -.

  std::string tempString ("TempString");

  PMString tempPMString (tempString.c_str ());

  tempPMString.Append (tempWideString);

  ????