Similar Questions

• Find the archive logs generated per day (for 7.3.4 database)?

  I use a query like the one below to determine the average amount archives logs generated per day for a database for a month:
  
  Select sum (GB_USED_PER_DAY) count (GB_USED_PER_DAY) in (SELECT
  To_char(completion_time,'YYYY-mm-DD') completion_date,
  round (SUM (block_size *(blocks+1)) / 1024 / 1024 / 1024, 2) GB_USED_PER_DAY
  V $ archived_log
  WHEN TRUNC (completion_time) BETWEEN
  TRUNC(SYSDATE-30) AND TRUNC (SYSDATE)
  GROUP OF TO_CHAR(completion_time,'YYYY-MM-DD')
  order by 1 desc);
  
  This query does not work on Oracle 7.3.4 database. Anyone know how I can calculate average archive generation of newspapers per day for Oracle 7.3.4?
  
  Thanks in advance!

  Select substr(first_time,1,8), round (sum (bytes) /(1024*1024)) MB of v$ log group by substr (first_time, 1, 8);

• How to disable the log on the windows sound?

  How to disable the log on the windows sound?

  Hello

  To disable startup sound in Windows XP, follow these steps:

  a. click Start, click run, type mmsys.cpl and then click OK.

  b. click the sounds tab.

  c. under program events, click Windows logon.

  d. in the sounds box, click (none)and then click OK.

  See also: change Windows XP sounds

• How to view the log with the identifier of Eloqua UI/API?

  I am trying to import customer contact Eloqua system using a restful api in Java.

  He got 500 Internal Server Error when call POST Api/rest/1.0/data/contact.

  In fiddler, we know that answer pleased as below:

  Internal server error

  There was an internal server error.

  The error was logged with log identifier 551654381.

  Please provide this identifier to log technical support.

  I want to know how to view the log of 551654381 ?

  Anyone who has the experience to import contacts using the Restful API or API bulk?

  Screenshot of Fiddler:

  

  Hi Tim,.

  The API error log is not available through the UI Eloqua, is accessible by Eloqua support only.  If you supply the ID error when you connect to a service request with the support of Eloqua, it will make it easier for them to diagnose your problem.

• How to count the page that is provided on page element

  How to count the page that is provided on page element

  Hi durgeshj41842015,

  the kDocBoss has an IPageList interface with GetPageCount() function.

  Markus

• How to count the number of pages on the spread

  How to count the number of pages on the spread

  #include "ILayoutControlData.h".

  #include "ILayoutUIUtils.h".

  #include "ISpread.h".

  InterfacePtr layoutData (Utils()-> QueryFrontLayoutData());

  If (layoutData)

  {

  UIDRef spreadRef is layoutData-> GetSpreadRef();.

  InterfacePtr activeSpread (spreadRef, UseDefaultIID ());

  Int32 count is activeSpread-> GetNumPages();.   Number of pages of active propagation.

  }

• How to count the number or lines in the file

  Hi Experts,
  
  I'm file as source and Oracle as target. My folder that contains some data that will load the target.
  My requirement is that I want to count the number of lines that contains my folder. Please help me how to count the total number of lines in the file.
  
  
  THX,
  Sara.

  Hi Sahaveda,

  Now, I tried and it works.

  Sorry my mistake again.

  I created HR. ETL_FILE_LOG as below:

  CREATE THE TABLE HR. ETL_FILE_LOG (numero_fichier varchar2 (10))

  Below the code will run without error:

  import java.lang as lang

  import java.sql SQL

  import of java.lang.String

  Import os

  disadvantages is sql. DriverManager.getConnection ("<%=snpRef.getInfo("DEST_JAVA_URL")%>", "<%=snpRef.getInfo("DEST_USER_NAME")%>", "<%=snpRef.getInfo("DEST_PASS")%>")

  dblinks = cons.createStatement)

  File1 = Open ('c:\EMP.txt','r')

  Count = 0

  Line = file1. ReadLine()

  all online! ='' :

  Count += 1

  Line = file1. ReadLine()

  File1. Close()

  sqlQuery = "insert into HR. "The values of ETL_FILE_LOG (numero_fichier) (" + str (count) + ' ") '.

  rqQuery = dblinks.execute (sqlQuery)

  jerks. Close()

  Concerning

• How to count the number of hit on the page, click

  Hello..
  can someone tell me...
  How to count the number of hit on the page, click
  
  Thanks in anticipation...

  Somethig like that?
  http://www.baigzeeshan.com/2011/12/Oracle-ADF-storing-temporary-values-in.html

• How to count the number of nodes under each parent in any given xml

  How to count the number of nodes under each parent in any given xml. for example the xml below was
  books has 3 childern, library [1] has 4, [2] library has 6 and bookshop [3] has 2. is it possible to get the number of tags in a childnode duplicate IE library [1]
  Book1 Tagus repeated twice... vice versa. do we need to make plsql lie we can achieve through sql
  
  < book >
  < library >
  ABC < book1 > < / book1 >
  BCA < book2 > < / book2 >
  ACR < book1 > < / book1 >
  Lac < Book4 > < / Book4 >
  < / book >
  < library >
  ABC < book1 > < / book1 >
  BCA < book2 > < / book2 >
  ACR < book3 > < / book3 >
  ACR < book3 > < / book3 >
  tray of < bookn_1 > < / bookn_1 >
  adjusted cost base < bookn > < / bookn >
  < / book >
  < library >
  ABC < book1 > < / book1 >
  BCA < book2 > < / book2 >
  < / book >
  < / books >
  
  
  I tried this... query.
  
  Select
  XMLQUERY ('count($doc/Books/Bookstore[1]/descendant::*)' in the way of xmltype ("< books >
  < library >
  ABC < book1 > < / book1 >
  ACR < book1 > < / book1 >
  Lac < Book4 > < / Book4 >
  < / book >
  < library >
  ABC < book1 > < / book1 >
  BCA < book2 > < / book2 >
  < / book >
  (< / books > ')
  as 'doc' of happy return) .getNumberVal () as node_count
  of the double
  
  Select
  XMLQUERY ('count($doc/Books/descendant::*)' in the way of xmltype ("< books >
  < library >
  ABC < book1 > < / book1 >
  ACR < book1 > < / book1 >
  Lac < Book4 > < / Book4 >
  < / book >
  < library >
  ABC < book1 > < / book1 >
  BCA < book2 > < / book2 >
  < / book >
  (< / books > ')
  as 'doc' of happy return) .getNumberVal () as node_count
  of the double
  
  How can I get the counts for each parent in a single query
  
  Published by: user7955917 on August 24, 2012 07:26

  Generic function how you want the query to be.

  If the structure is known in advance, as in your example a 'books' and then a 'library' root element, it's as simple as:

  SQL> select x1.parent_id, x2.child_name, count(*)
    2  from tmp_xml t
    3     , xmltable(
    4         '/books/bookstore'
    5         passing t.object_value
    6         columns parent_id   for ordinality
    7               , child_list  xmltype path '*'
    8       ) x1
    9     , xmltable(
   10         '/*'
   11         passing x1.child_list
   12         columns child_name varchar2(30) path 'name()'
   13       ) x2
   14  group by x1.parent_id, x2.child_name
   15  order by x1.parent_id, x2.child_name
   16  ;
  
   PARENT_ID CHILD_NAME                       COUNT(*)
  ---------- ------------------------------ ----------
           1 book1                                   2
           1 book2                                   1
           1 book4                                   1
           2 bookn                                   1
           2 bookn_1                                 1
           2 book1                                   1
           2 book2                                   1
           2 book3                                   2
           3 book1                                   1
           3 book2                                   1
  
  10 rows selected
   
  

  If you want a generic solution that works without knowledge of the structure, you will need a recursive approach, and most importantly, you should know which nodes in distinct, I suppose that the leafs?

  Also, please help if you can provide the link of reference on the function name() years what are the other expression, that I can use after the path

  You can start reading the documentation: http://docs.oracle.com/cd/E11882_01/appdev.112/e23094/xdb_xquery.htm#CBAGCBGJ

  The clause PATH expects a XQuery expression however before 11.2, we can put only simple XPath expressions.

• How to count the number of elements in a data block

  Hi all
  How to count the number of elements in a particular data block oracle Forms 10g.
  If it's a text_item or the display_item or the list_item etc is there any method to do this.
  
  Please answer...

  get the first element with GET_BLCOK_PROPERTY(..., FIRST_ITEM);
  loop until GET_ITEM_PROPERTY(..., NEXTITEM) is null
  count on in the loop.

• How to count the number of columns in an oracle table using sql

  How to count the number of columns in an oracle table using sql

  You must put the name of the table in capital letters

  As

  SELECT COUNT(1)
    FROM user_tab_columns
  WHERE table_name = 'EMP';
  
  or
  
  SELECT COUNT(1)
    FROM user_tab_columns
  WHERE table_name = UPPER('Emp');
  

  Concerning
  Arun

• How to count the number of data records?

  Hey guys, how to count the number of records, I had on a data object variable?

  Im having a result of sql query in a variable like this:

  oDB.resolveNode("#command").query.select.value = "SELECT * FROM Customers WHERE CliNombre LIKE ' % ' + input1 +" %' ";

  oDB.open ();

  oDB.first ();

  So I need to count the number of records retrieved by this SQL query at the moment. Help please

  Then move the cursor back to the first record after you have your account.

  There is a keyword count in SQL that will allow you to get the account of your request. You can run that first - get your account, and then run the actual query to get the Recordset. This would require a separate data connection. Some examples of code.

  var xfa.event.newText = inName;
  If (inName == "") {}
  App.Alert ("you must enter a name--try again!")
  }
  var nIndex = 0;
  While (xfa.sourceSet.nodes.item (nIndex) .name! = "DataConnection2")
  {
  nIndex ++;
  }

  oDB = xfa.sourceSet.nodes.item (nIndex) .racing var (1); pertaining to the specified data connection node
  App.Alert (ODB.saveXML ("Pretty"));

  var nIndex = 0;
  While (xfa.sourceSet.nodes.item (nIndex) .name! = "DataConnection3")
  {
  nIndex ++;
  }
  var oDBCount = xfa.sourceSet.nodes.item (nIndex) .racing (1); pertaining to the specified data connection node
  Configure sql call DB to get the number of records that match the criteria

  oDBCount.nodes.item (1).query.setAttribute ("text", "commandType");
  oDBCount.nodes.item (1).query.select.nodes.item (0) .value = "Select count (*) from table1 where AcctNumber = '" + inName + "'";
  oDBCount.open)
  oDBCount.close)

  Configure sql call DB to get the specified employee number

  oDB.nodes.item (1).query.setAttribute ("text", "commandType");
  oDB.nodes.item (1).query.select.nodes.item (0) .value = "Select * from table1 where AcctNumber = '" + inName + "'";
  App.Alert (ODB. Nodes.Item (1) .saveXML ("Pretty"));

  now connect to the DB and get a recording
  oDB.open)
  oDB.close ();

  Note the SQL command use the keyword count (take a look at the oDBCount section). This will return a number of return to the cllaer. When I set up the data connection, a node count (*) that appeared there. I dragged to the form and it has created a field called count that the onus at this node. When the query is executed, the number of resulting records returns to this field. You can have hidden it so that your users can not see it and also to change the binding votes to zero, so it is not included in the data file that is submitted when the form is complete.

  Paul

• How to count the time exactly?

  I tried to count the time using a VI like the one attached.

  It's that's not couting correctly. There is a possible reason, I have observed.

  The computer isn't able to handle the VI as soon as necessary.

  I thought about this because, when in edit mode the time count was very bad, and, when I created an application and installed, it ran okay, how 'light '. But today, when I tried to use this application with an old computer it did not work. The clock is slow.

  Is it possible to count the time correctly?

  I use a DAQ6009 to make my works, my VI is big enough and I need one iteration to each 1 ms (milliseconds) as I am with digital inputs from 5 events of coders (I know that's not the right way to count the encoders, but it's the only way I can do it, and it works).

  Thank you in advace! I hope you can help me!

  Hugs!

  Ok.  I will try to help you understand certain things.

  The number of cycles and wait (and wait until the next ms Multiple) functions all use a 1 kHz derived from the clock of the processor clock. The accuracy of these clocks is not large, although they are probably similar to the precision of the stopwatch.  Any time generated by these functions will show some differences in the time of the clock as it is derived from a different oscillator.

  Updates from the front panel are time by LabVIEW and the operating system. Most of the screens are updated with 60 to 80 times per second, maximum. What made the operating system, an update of the screen might be delayed by 10s of milliseconds or more.  It is certain that not all of the values at the end of the Add function will be displayed.

  Wait for him until the next ms many will wait more than 1 ms if the other code in the loop takes longer than 1 ms.  I don't know, but I think that the indicator is buffered so that any delay by the operating system to update the display should not slow down the loop. I tried to remove the flag, and it doesn't seem to make a big difference.

  I modified your VI to provide several indications of the performance. First of all, I added to the sequence of three-frame structure to allow synchronization of the loop. Second, I changed to a loop which runs a specified number of iterations. Thirdly, I hooked up the output of the timer until the next ms Multiple to a tunnel of autoindexing allowing a record of the time of each iteration appears in the table of ticks. I calculated the differences between successive instants and poster on a chart, so that you can see the performance.

  I didn't want to sound criticism of your use of English.  You write in English, much better than I could in your language!  What I was trying to make is that such general descriptions that ' Besides correctly ' without quantitative results or evidence in support of the application do not have enough information to help us help you.

  Lynn

• How to count the peaks?

  Hi all

  I am a new user of LabVIEW and I'm going to ask you about a problem that certainly many of you will find quite annoying.

  I develop software for a test machine management that uses an another bend, a tachometer that generates a signal of rectangular analog output in volts, 0V to 8V. Like many I thi signal in a waveform graph.

  My goal is to be able to count the number of cycles of the machine and power count the tension peaks and subsequently be able to work on the machine with respect to the number of rounds to make. the ultimate goal is to be able to tell the machine how many rounds/cycles to do and the voltage applied to the load cell.

  Would you be able to give me some advice on this subject? Especially about count and store the number of revolutions.

  If necessary, I could send a screenshot of the program.

  I tried to use a crest of the threshold detector but I'm still inexperienced, it's why I ask for your help.

  can someone help me?

  Thanks in advance.

  Greetings

  LV

  Look at the detection of peaks VI and examples (help-> find examples).

  It should be fairly easy to understand and implement

• How to get the fixed lines per page? really Urgent!

  I am facing problem with the fixed lines per page. The footer (Subtotal) block moves upward, leaving space at the bottom when the number of items is lower.
  
  I have a two groups: one for the KIT and the KIT COMPONENTS. When I'm generation report for KIT only ITEMS I'm attaches footer using the
  
  < name of xsl: variable = "no_of_lines_per_page" select = "number (30)" / >
  <? for-each@section:Q1? >
  < xsl: variable xdofo:ctx = 'incontext' name = "inner_group" select=".//Q2"/ >
  <?-foreach: $inner_group? > <? If: (position () - 1) mod $no_of_lines_per_page = 0? >
  < name of xsl: variable = "first_rec" xdofo:ctx = 'incontext' select = 'position ()' / >
  
  but when I try to generate the report in combination with KIT COMPONENTS together, I am not able to set the number of lines per page. The footer is allocated to the next page. Now I Q2 and Q3 where Q2 makes Parent Kit and Q3 is child components Kit.
  
  How can I get it fixed lines per page for Q3 in regards to the Q2?
  
  I would appreciate if someone can answer me quickly.

  You have sent the updated RTF.