How to display the records from a query in the non-base data field

Hello

I have a problem:
I have a query with a lot of tables and column 6 (select a, b, c, d, e, f x, y, z, t, s, g where the conditions) and I use 3 parameters.
I create 3 settings: datai,: dataf and: partner and a button with a trigger when the button is pressed.
Then a create a block manually with six field non-database a1, b1, c1, d1, e1, f1.
Now, I want to display all the records in my query in a1, b1, c1, d1, e1, f1 where a1 = a, b1 = b, etc. and all the records (if I have 20 record, it will display 20 records in the non-base data field) when I press the button.

How I did it:
I create a cursor with the query, and then
start the open cursor
loop
Fetch cursor in: a1,: b1,: c1: d1: e1,: f1;
end loop;
close the cursor;
end;

It displays a single record in a1, b1, c1 only, and it must display 100 records and date for all fields.

Can someone help me with this problem?
Thank you.

Published by: 928437 on October 1, 2012 02:55

Creating a view and the query in a database block are a great solution.

To use the block non-base of data:
You are missing the most important Next_Record; command.

 Begin

Go_block('X'); -- block X is the non-database block

Clear_Block(No_Validate);

open cursor X1;

loop

If :System.Record_status != 'NEW' then

Next_Record;

End if;

fetch X1 into :a1,:b1,:c1,:d1,:e1,:f1;

Exit when X1%NOTFOUND;

end loop;

close X1;

end;

Tags: Oracle Development

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