How to divide the Recordset by groups in SQL itself.

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• How to rename the temporary tablespace group name

  How to rename the temporary tablespace group name?  I have to remove all the temporary tablespace under the Group and then re-create the temporary tablespace again.

  EBS r12.1.1

  Database 11.0.1.7

  Please see any id doc.

  concerning

  pritesh Rodriguez

  Thanks for your update. I have solved my problem by creating a new group and add temporary tablespace to new goup.

  concerning

  pritesh Rodriguez

• How to divide the Dates

  Hi all...

  Here, I use the following scripts...

  create table a10 (eno number, date f, date t, number of sal)

  INSERT IN A10 (ENO, F, T, SAL) VALUES)

  1, TO_Date (1 July 2013 12:00:00 AM ',' DD/MM/YYYY HH: mi: SS AM'), TO_Date (June 30, 2014 12:00 ',' DD/MM/YYYY HH: mi: SS AM')

  (100);

  INSERT IN A10 (ENO, F, T, SAL) VALUES)

  1, TO_Date (May 1, 2013 12:00:00 AM ',' DD/MM/YYYY HH: mi: SS AM'), TO_Date (April 30, 2014 12:00 ',' DD/MM/YYYY HH: mi: SS AM')

  (200);

  COMMIT;

  entry:

  ENO      F             T                SAL

  07/01/2013 2014/06/30 100 1

  1 05/01/2013 30/04/2014 200

  Expected results:

  ENO F

  T

  SAL

  1 05/01/2013 2013/06/30 200

  1 30/04/2014 300 07/01/2013

  1 05/01/2014 2014/06/30 100

  I'm little bit confused how to divide the dates here... Any help is appreciated.

  Thank you all

  Stéphane

  Hello

  Always tell what version of Oracle you are using, especially if it's so old.

  In Oracle 10 (or 9, by the way) you can do this way:

  WITH cntr AS

  (

  SELECT LEVEL AS n

  OF the double

  CONNECT BY LEVEL<=>

  )

  got_change_date AS

  (

  SELECT d.eno

  C.n

  WHEN 1 THEN f

  ANOTHER t + 1

  END AS change_date

  C.n

  WHEN 1 THEN 1

  OF ANOTHER-1

  END as mul

  sal

  BY a10 d

  CROSS JOIN cntr c

  -WHERE... - If you need any filtering, put it here

  )

  got_total_sal AS

  (

  SELECT eno

  change_date f

  Advance (change_date) OVER (PARTITION BY eno

  ORDER BY change_date

  ) - 1 AS t

  SUM (sal * mul) over (PARTITION BY eno

  ORDER BY change_date

  ) AS total_sal

  OF got_change_date

  )

  SELECT *.

  OF got_total_sal

  WHERE t IS NOT NULL

  ORDER BY eno, f

  ;

• How to divide the column Date OBIEE

  Hello
  We have the name of the date column: To_Date and the format is DD/MM/YY hh.
  How to divide the date in YEARS, MONTHS, DAY as new columns.
  kindly help on that.
  
  
  Kind regards.
  CHR
  
  Published by: 867932 on November 23, 2011 22:18

  Hi user,

  All 3 functions can be written in RPD too. MDB layer, duplicate the date column-> the mapping tab to column of Goto-> expression-> functions Builder Select-> calendar Date functions / hour-> select DayofMOnth function. The column of your logic formula will look like,

  DayofMonth (YourDateColumn)

  Rgds,
  DpKa

• How to solve the error ORA-00001 in SQL Insert?

  Hi all, I need your help appreciated.
  
  I do a plsql procedure that inserts a line according to the value of the slider, I have error oracle ORA-00001: unique constraint (constraint_name) violated.
  
  This message may appear if a duplicate entry exists at a different level: in the RDBMS MySQL, I have the syntax IGNORES to solve this error of duplication... and in Oracle?
  
  Thanks for your time and your advice.
  Miguelito

  user6317803 wrote:
  How to solve the error ORA-00001 in SQL Insert?

  ORA-00001 means table a unique/primary key / index and you attempt to insert a row with the key value already exists in the table. I'll assume table has a primary key on COUNTRY_ID. Then modify SQL for:

  SQL = "INSERT INTO COUNTRIES (COUNTRY_ID, COUNTRY_NAME, REGION_ID) SELECT"BZ","BLZ", 3 DOUBLE WHERE DOES NOT EXIST (SELECT 1 FROM COUNTRIES WHERE COUNTRY_ID ="BZ").

  There is a good chance COUNTRY table also has unique key/index on COUNTRY_NAME. If so use:

  SQL = "INSERT INTO COUNTRIES (COUNTRY_ID, COUNTRY_NAME, REGION_ID) SELECT"BZ","BLZ", 3 DOUBLE WHERE DOES NOT EXIST (SELECT 1 FROM COUNTRIES WHERE COUNTRY_ID = 'BZ' OR 'BLZ' = COUNTRY_NAME).

  SY.

• How to divide the three PARTITION HD

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  {Information}

  Going to be hard to do since you already have 4 primary partitions. See the link below

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• How to filter the Recordsets using the session variable?  Please help this makes me crazy...!

  I'm having the same problem as user "Gabe the facilitator" in a message sent in 2007.

  «My recordset that animates a PivotTable will not filter the results based on a session variable.» I know that the session variables are working because I have the echo of session variable in the page (dragged-n-dropped my session variable since the panels on my page links), and that works fine. So why can't filter my recordset with the same session variable? »

  Here is the code:

  <? php require_once('Connections/mockconn.php');? >

  <? PHP

  session_start();

  ? >

  <? PHP

  If (! function_exists ("GetSQLValueString")) {}

  function GetSQLValueString ($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "")

  {

  If (via PHP_VERSION < 6) {}

  $theValue = get_magic_quotes_gpc()? stripslashes ($TheValue): $theValue;

  }

  $theValue = function_exists ("mysql_real_escape_string")? mysql_real_escape_string ($TheValue): mysql_escape_string ($theValue);

  Switch ($theType) {}

  case 'text ':

  $theValue = ($theValue! = "")? « " ». $theValue. "" "": "NULL";

  break;

  case "long":

  case "int":

  $theValue = ($theValue! = "")? intval ($TheValue): 'NULL ';

  break;

  case "double":

  $theValue = ($theValue! = "")? doubleVal ($TheValue): 'NULL ';

  break;

  case "date":

  $theValue = ($theValue! = "")? « " ». $theValue. "" "": "NULL";

  break;

  case "set":

  $theValue = ($theValue! = "")? $theDefinedValue: $theNotDefinedValue;

  break;

  }

  Return $theValue;

  }

  }

  {if (! session_id ())}

  session_start();

  }

  $colname_info = "-1";

  If (isset($_SESSION['email'])) {}

  $colname_info = $_SESSION ['email'];

  }

  @mysql_select_db ($database_mockconn, $mockconn);

  $query_info = sprintf ("SELECT name, last_name, email, password registration E-mail WHERE = %s", GetSQLValueString ($colname_info, "text") ");

  $info = mysql_query ($query_info, $mockconn) or die (mysql_error ());

  $row_info = mysql_fetch_assoc ($info);

  $totalRows_info = mysql_num_rows ($info);

  ? >

  < ! DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional / / IN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd" > ""

  " < html xmlns =" http://www.w3.org/1999/xhtml ">

  < head >

  < meta http-equiv = "Content-Type" content = text/html"; charset = utf-8 "/ >"

  Home < title > < /title >

  < / head >

  < body >

  < div id = "info" > Hello <? PHP echo $row_info [""];? > < / div >

  <? PHP

  If (isset($_SESSION['email'])) {}

  echo ' your email: '.' '. $_SESSION ['email'].' '.' good work ";}

  ? >

  < / body >

  < / html >

  PLEASE PLEASE HELP... I've been to this day of...

  How do I filter the recordset based on the value of the session variable

  Then it works fine.

  Each test returned correct results.  We checked one) your session variable is set correctly, b) the SQL statement is properly filtered by email, and c) the returned results are as expected.

• How to divide the resultset SQL based on the data in the form of scenarios?

  Hello
  
  I need to develop a query that should be divided into scenarios
  
  Ex:
  
  Scenario 1: If a product is sold to the United States and charged in the United Kingdom
  Scenario 2: If a product is sold to the United Kingdom and charged in the United States
  Scenario 3: If a product is sold and invoiced to the United States
  Scenario 4: If a product is sold and invoiced to the United Kingdom
  
  Based on 1 how to divide and provide SQL result to users based on the scenarios?
  
  Ex: Result should show all the data, saying that the result set is in scenario 1, etc..,.
  
  Please advice
  
  Thank you
  user12048986

  Hello

  You can use an expression BOX to classify each line:

  CASE  sold_country || ' ' || billed_country
       WHEN  'US UK'     THEN  1
       WHEN  'UK US'     THEN  2
       WHEN  'US US'     THEN  3
       WHEN  'UK UK'     THEN  4
  END     AS scenario_num
  

  If sold_country or billed_country is anything except 'UK' or 'US', then the above expression returns null.

  I hope that answers your question.
  If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements), and the results you want from this data.

• How to divide the DB results in addition to a column

  I have some code (see below) which separates the results from a query db in two columns. However, the results print left to right, row by row. Which displays almost correctly, however, I need to display the results of the first half in a column, and the second half of the results in a second column. I can't understand how to change the code to display the first column with 1/2 of the results.
  
  
  < CFSET maxcol = 2 >
  < TABLE BORDER = "0" cellpadding = "3" cellspacing = "0" >
  < CFSET outcol = 0 >
  < CFOUTPUT QUERY = "Candidate" >
  < CFIF outcol EQ 0 > < TR > < / CFIF >
  < TD width = "30%" > < span class = "BodyContent" > #Candidate # </span > < table >
  < CFSET outcol = outcol + 1 >
  < CFIF outcol EQ maxcol >
  < /TR >
  < CFSET outcol = 0 >
  < / CFIF >
  < / CFOUTPUT >
  < CFIF outcol NEQ 0 > < /TR > < / CFIF >

  This could be a little Kludgy, but hey, it works...
  First of all, a quick count of the db
  SELECT COUNT (*) AS CandidateCount
  Candidates

  Then divide the total by 2 and 1 for good luck.
  

  Then write on the table.

  #Candidate #.

• How to divide the characters in table 1 d

  I am looking for a way to divide the 'print' to a string 1-d subarray. For example instead of:

  1 / AAAABBBB

  2 / CCCCDDDD

  3 / EEEEFFFF

  ...

  etc.

  then there would be two tables 1 d separated where before there was a:

  1 / AAAA and BBBB

  2 / CCCC and Delalande

  3 / EEEE and FFFF

  ...

  etc.

  Something like that?

  

  You need better on where the split to take place?  I doubt somehow you want just a simple divided into a constant place.

• How to divide the C: drive into two partitions without a third-party program?

  Hello

  Is there a way to divide the C: drive into two partitions C: and D: on Windows XP without a third pary program?

  If anyone has an idea, please give some steps.

  Thank you.

  Assem

  Hey Assem,

  Once you have created a primary partition, it is not possible (for Windows XP) to divide the partition without using third-party software. You can see:http://support.microsoft.com/kb/309000 to create a new partition.

  I hope this helps...

• How to divide the string in bb-cascades

  1. I have a table of data as json

     {"RegistrationResult":"Registered Success:Empid:157:TableName:COMPANY156"}
     

  2. Now, how I want to split the show list view in qml and string as the follwing

     Success stories

     EmpID = 157

     TableName = COMPANY156

  3. Please tell the concept of cutting a string and show the result in qml

  I can get the result of the follwing method:

  {"RegistrationResult":["Registered Success","Empid":"157","TableName":"COMPANY156"]}
   
  

  But I do not know how to split the string for a first... Help, please...

  svmrajesh wrote:

  1. ,......"Registered Success:Empid:157:TableName:COMPANY156"}

  Take a look at QString docu

  Just do something like

  myString.split(':')

  and you get a QStringList and this QStringList is directly mapped to a table in QML JavaScript

• How to divide the amount of import control program command line

  Hi Experts

  Divide the amount of command-line client 102000 99000 and 3000.

  I used following scripts, but he just updated the quantity on the line, but do not add a new line for the remaining quantity.

  1 INSERT IN oe_headers_iface_all
  (
  order_source_id,
  orig_sys_document_ref,
  org_id,
  ORDER_NUMBER,
  CUSTOMER_PO_NUMBER,
  SOLD_TO_ORG_ID,
  CLIENT_NAME,
  CUSTOMER_NUMBER,
  OPERATION_CODE,
  created_by,
  CREATION_DATE,
  last_updated_by,
  last_update_date,
  CHANGE_SEQUENCE,
  FORCE_APPLY_FLAG
  )
  VALUES)
  0,
  "LT_TEST7,"
  204,
  67081,
  "4500007067-01',
  1290
  "Networks of c. a.",
  '1143 ',
  "UPDATE."
  -1,
  SYSDATE,
  -1,
  SYSDATE,
  1,
  « Y »
  );
  
  2. INSERT IN oe_lines_iface_all
  (
  order_source_id,
  orig_sys_document_ref,
  orig_sys_line_ref,
  orig_sys_shipment_ref,
  org_id,
  ORDERED_QUANTITY,
  ORDER_QUANTITY_UOM,
  PRICING_QUANTITY,
  PRICING_QUANTITY_UOM,
  SOLD_TO_ORG_ID,
  REQUEST_DATE,
  INVENTORY_ITEM,
  created_by,
  CREATION_DATE,
  last_updated_by,
  last_update_date,
  operation_code,
  CHANGE_SEQUENCE,
  CHANGE_REASON
  )
  VALUES)
  0,
  "LT_TEST7,"
  "LT_TESTLINE7,"
  "OE_ORDER_LINES_ALL810289.1,"
  204,
  99000,
  "Ea."
  99000,
  "Ea."
  1290
  AUGUST 13, 2014 '.
  "AS54888,"
  -1,
  SYSDATE,
  -1,
  SYSDATE,
  "UPDATE."
  1,
  'FR '.
  );
  
  3. INSERT IN oe_lines_iface_all
  (
  order_source_id,
  orig_sys_document_ref,
  orig_sys_line_ref,
  orig_sys_shipment_ref,
  org_id,
  ORDERED_QUANTITY,
  ORDER_QUANTITY_UOM,
  PRICING_QUANTITY,
  PRICING_QUANTITY_UOM,
  SOLD_TO_ORG_ID,
  REQUEST_DATE,
  INVENTORY_ITEM,
  created_by,
  CREATION_DATE,
  last_updated_by,
  last_update_date,
  operation_code,
  CHANGE_SEQUENCE,
  SPLIT_FROM_LINE_REF,
  SPLIT_FROM_SHIPMENT_REF,
  CHANGE_REASON
  )
  VALUES)
  0,
  "LT_TEST7,"
  "LT_TESTLINE7,"
  "OE_ORDER_LINES_ALL810289.1,"
  204,
  3000,
  "Ea."
  3000,
  "Ea."
  1416,
  "05 - SEP - 2014."
  "AS54888,"
  -1,
  SYSDATE,
  -1,
  SYSDATE,
  "INSERT."
  1,
  "LT_TESTLINE7,"
  "OE_ORDER_LINES_ALL810289.1,"
  'FR '.
  );

  
  

  Any advice?

  
  

  Christy
  

  Hi all

  The problem was resolved after customer compensation request_id in the header and line, thanks for your help.

  Christy

• How to assign the ID of group for each group in the SQL query.

  Hi all

  I want to assign the ID of group for each group (group ID of series). I tried with the row_number function but did not work for my requiredment. Here is my sample data and my requirement.

  Col1

  A

  A

  A

  A

  A

  B

  C

  D

  D

  D

  D

  E

  E

  E

  F

  G

  G

  G

  I want to get number of each column with ID group assign to it value. Here is my example output

  Col1	County	Group ID
  A	5	1
  A	5	1
  A	5	1
  A	5	1
  A	5	1
  B	1	2
  C	1	3
  D	4	4
  D	4	4
  D	4	4
  D	4	4
  E	3	5
  E	3	5
  E	3	5
  F	1	6
  G	3	7
  G	3	7
  G	3	7

  Select col1, count (1) NTC (col1 partition).

  ROW_NUMBER() over (partition by col1 by col1 order) tbl_test grp_id.

  Please help me solve this problem.

  SELECT

  COL1,

  COUNT (*) ON MYCOUNT (COL1 PARTITION).

  DENSE_RANK () OVER (ORDER BY COL1) GROUPID

  Of

  T1;