How to extract .csv for each table

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• How to find the child level for each table in a relational model?

  Earthlings,
  
  I need your help, and I know that, "Yes, we can change." Change this thread to a question answered.
  
  So: How to find the child level for each table in a relational model?
  
  I have a database of relacional (9.2), all right?
  

  .
       O /* This is a child who makes N references to each of the follow N parent tables (here: three), and so on. */
      /↑\ Fks
     O"O O" <-- level 2 for first table (circle)
    /↑\ Fks
  "o"o"o" <-- level 1 for middle table (circle)
     ↑ Fk
    "º"

  Tips:
  -Each circle represents a table;
  -Red no tables have foreign key
  -the picture on the front line of tree, for example, a level 3, but when 3 becomes N? How is N? That is the question.
  
  I started to think about the following:
  
  First of all, I need to know how to take the kids:

  select distinct child.table_name child
    from all_cons_columns father
    join all_cons_columns child
   using (owner, position)
    join (select child.owner,
                 child.constraint_name fk,
                 child.table_name child,
                 child.r_constraint_name pk,
                 father.table_name father
            from all_constraints father, all_constraints child
           where child.r_owner = father.owner
             and child.r_constraint_name = father.constraint_name
             and father.constraint_type in ('P', 'U')
             and child.constraint_type = 'R'
             and child.owner = 'OWNER') aux
   using (owner)
   where child.constraint_name = aux.fk
     and child.table_name = aux.child
     and father.constraint_name = aux.pk
     and father.table_name = aux.father;

  Thought...
  We will share!
  
  Thanks in advance,
  Philips
  
  Published by: BluShadow on April 1st, 2011 15:08
  formatting of code and hierarchy for readbility

  Have you looked to see if there is a cycle in the graph of dependence? Is there a table that has a foreign key to B and B has a back of A foreign key?

  SQL> create table my_emp (
    2    emp_id number primary key,
    3    emp_name varchar2(10),
    4    manager_id number
    5  );
  
  Table created.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  create table my_mgr (
    2    manager_id number primary key,
    3    employee_id number references my_emp( emp_id ),
    4    purchasing_authority number
    5* )
  SQL> /
  
  Table created.
  
  SQL> alter table my_emp
    2    add constraint fk_emp_mgr foreign key( manager_id )
    3         references my_mgr( manager_id );
  
  Table altered.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1   select level lvl,
    2          child_table_name,
    3          sys_connect_by_path( child_table_name, '/' ) path
    4     from (select parent.table_name      parent_table_name,
    5                  parent.constraint_name parent_constraint_name,
    6                  child.table_name        child_table_name,
    7                  child.constraint_name   child_constraint_name
    8             from user_constraints parent,
    9                  user_constraints child
   10            where child.constraint_type = 'R'
   11              and parent.constraint_type = 'P'
   12              and child.r_constraint_name = parent.constraint_name
   13           union all
   14           select null,
   15                  null,
   16                  table_name,
   17                  constraint_name
   18             from user_constraints
   19            where constraint_type = 'P')
   20    start with child_table_name = 'MY_EMP'
   21*  connect by prior child_table_name = parent_table_name
  SQL> /
  ERROR:
  ORA-01436: CONNECT BY loop in user data
  

  If you have a cycle, you have some problems.

  (1) it is a NOCYCLE keyword does not cause the error, but that probably requires an Oracle version which is not so far off support. I don't think it was available at the time 9.2 but I don't have anything old enough to test on

  SQL> ed
  Wrote file afiedt.buf
  
    1   select level lvl,
    2          child_table_name,
    3          sys_connect_by_path( child_table_name, '/' ) path
    4     from (select parent.table_name      parent_table_name,
    5                  parent.constraint_name parent_constraint_name,
    6                  child.table_name        child_table_name,
    7                  child.constraint_name   child_constraint_name
    8             from user_constraints parent,
    9                  user_constraints child
   10            where child.constraint_type = 'R'
   11              and parent.constraint_type = 'P'
   12              and child.r_constraint_name = parent.constraint_name
   13           union all
   14           select null,
   15                  null,
   16                  table_name,
   17                  constraint_name
   18             from user_constraints
   19            where constraint_type = 'P')
   20    start with child_table_name = 'MY_EMP'
   21*  connect by nocycle prior child_table_name = parent_table_name
  SQL> /
  
         LVL CHILD_TABLE_NAME               PATH
  ---------- ------------------------------ --------------------
           1 MY_EMP                         /MY_EMP
           2 MY_MGR                         /MY_EMP/MY_MGR
           1 MY_EMP                         /MY_EMP
           2 MY_MGR                         /MY_EMP/MY_MGR
  

  (2) If you try to write on a table and all of its constraints in a file and do it in a valid order, the entire solution is probably wrong. It is impossible, for example, to generate the DDL for MY_EMP and MY_DEPT such as all instructions for a table come first, and all the instructions for the other are generated second. So even if NOCYCLE to avoid the error, you would end up with an invalid DDL script. If that's the problem, I would rethink the approach.

  -Generate the DDL for all tables without constraint
  -Can generate the DDL for all primary key constraints
  -Can generate the DDL for all unique key constraints
  -Can generate the DDL for all foreign key constraints

  This is not solidarity all the DOF for a given in the file object. But the SQL will be radically simpler writing - there will be no need to even look at the dependency graph.

  Justin

• How to get LASTDAY for each month between data dates...

  Hi friend
  
  I have a doubt, how to get LASTDAY for each month between data dates...
  
  for ex:
  My contribution will be like this
  date = 01/12/2011
  To date = 14/04/2011
  
  And I need an output like
  31/01/2011
  28/02/2011
  31/03/2011
  
  is it possible to achieve through sql query in oracle
  Thanks in advance for all friends to help him

  Hello

  Something like this (assuming that the dates are originally VARCHAR2s):

  SQL> var dt_start varchar2(10)
  SQL> var dt_end varchar2(10)
  SQL> exec :dt_start := '12-01-2011'
  
  PL/SQL procedure successfully completed
  
  SQL> exec :dt_end := '14-04-2011'
  
  PL/SQL procedure successfully completed
  
  SQL>
  SQL> select last_day(
    2           add_months(
    3             trunc(to_date(:dt_start,'DD-MM-YYYY'),'MM'),
    4             level-1
    5           )
    6         ) as result
    7  from dual
    8  connect by level <= months_between(to_date(:dt_end,'DD-MM-YYYY'), to_date(:dt_start,'DD-MM-YYYY'))
    9  ;
  
  RESULT
  -----------
  31/01/2011
  28/02/2011
  31/03/2011
   
  

  If the dates are already of the date data type, simply remove the to_date function.

• Are there records of the sys the timestamp of change for each table?

  I noticed that the sys "object" records just the creation and the timestamp of DDL operation.
  But I need the timestamp of change (for example, insert, update, delete, etc.) for my paintings. Otherwise, I fear that I must create the trigger for each table it's hard work.

  You can use scn_to_timestamp (max (ora_rowscn)) for the dml changes

• Requirement of Beeping - how to get subtotals for each combination of 2 columns val

  Hi gurus, Experts and all,.
  
  Help me please with my reporting requirement, on how to code this in PIF. Thank you.
  
  Requirement: I need to get the subtotals for each value of the combination of two columns.
  
  Columns example: team group AMOUNT
  
  Sample column values: placed Team1 100
  Group b... Team2... 200
  
  GroupA - Team1 Subtotals = 500 (value of the sample only)
  GroupA - Team2 Subtotals = 400 (value of the sample only)
  Group b - Team1 Subtotals = 600 (value of the sample only)
  Group b - Team2 Subtotals = 200 (value of the sample only)
  
  GrandTotal = 1700
  
  Thank you.
  
  Jean Paul
  BEEP newbie
  
  Published by: user10955574 on October 28, 2010 05:40

  
   -  - 
  
  

  output for data

  GROUPA - TEAM1 - 200
  GROUPB - TEAM1 - 300
  GROUPC - TEAM2 - 400
  GROUPD - TEAM2 - 500
  GROUPA - TEAM3 - 600
  GROUPB - TEAM3 - 700
  GROUPC - TEAM4 - 800
  GROUPD - TEAM4 - 900
  GROUPA - TEAM5 - 1000
  

• How to create buttons for each slide in the slide show

  I currently have a slideshow with prev and next buttons.

  but I would add buttons numbered for each slide to image-base.

  with a static number for the current slide has a circle colorful around this number.

  I can create static number with circle colored in Photoshop, and add a layer,

  but it's a lot to do this for all the numbers work.

  Is there a better way to create the numbers highlighted for the current slide?

  For the numbered buttons that link to the slides not active, I can create numbers in Photoshop and import images into Flash.

  then convert to symbols and assigns actions to them,

  But it's also plenty to do for all the numbers work.

  Is there a better way to create numbered slide buttons inactive?

  I would also like to have a function to hover over the numbered buttons,

  It changes from plain image from number to number with circle colorful as I want to use for the current slide.

  How can I assign a hover button symbol function, which will load another image or symbol?

  Try to think in terms of having reusable symbols.  Think what it through before you try it.

  Use a movieclip instead of a button symbol.  Have a dynamic textfield in this movieclip to the number and value of the textfield object to not be selectable.  Have a picture of this movieclip where it highlighted as one (selected) and the movieclip go there where you are on this slide.

  Use the textfield for the number - assign dynamically so that you don't have to import an image for it.  Use as many of these clips that you need for all your buttons.

  Have functions that reset all buttons at the same time so that when you move to a new slide, selected earlier dates back to mormal... following with setting one newly selected in his "selected" frame

• How to give rownumber for each group

  Hai All
  
  I use the function group to separate and in this group, I need to give rownumber to each departure of members of Group 1 and when a group is on the needs in number to start new 1
  
  
  For example
  
  There are 3 Department and it is separated by the function of group by Department and here I need to give the line number. And the line number must be separated for each group
  
  Thanks and greetings
  
  Srikkanth.M

  How about using...

  ROW_NUMBER() OVER (partition by GROUP order by X)
  

  If this is not the case, how about post you some sample data and the output you want from these data.

  In addition, your version of Oracle

  select * from v$version;
  

• How to give rownum for each group in forms6i

  Hai All
  
  I have to use the line for each individual group number if it is possible in oracle forms6i
  
  I used this feature and get an error, the function is
  
  ROW_NUMBER() over (partition by bar code, order by code bardate bar)
  
  
  and if it is possible to use decode function in oracle forms6i
  
  Thanks for giving good solutions
  
  Thanks and greetings
  
  Srikkanth.M

  Same question but different title :)

  Yes, you can use function in 6i to decode

  Bangoura
  [My Oracle Blog | http://baigsorcl.blogspot.com/]

• How to use partitioning for large table

  Hello
  
  ******************
  Oracle 10 g 2/Redhat4
  RAC database
  ASM
  *******************
  
  I have a TRACE table that will also grow very fast, in fact, I 15,000,000 lines.
  
  TRACES (IDENTIFICATION NUMBER,
  NUMBER OF COUNTRY_NUM
  Timestampe NUMBER,
  MESSAGE VARCHAR2 (300),
  type_of_action varchar (20),
  CREATED_TIME DATE,
  DATE OF UPDATE_DATE)
  
  Querys who asked for this table are and make a lot of discs!
  
  --------------------------------------------------------
  Select count (*) as y0_
  TRACES this_
  where this_. COUNTRY_NUM =: 1
  and this_. TIMESTAMP between: 2 and: 3
  and lower (this_. This MESSAGE) as: 4;
  ---------------------------------------------------------
  SELECT *.
  FROM (SELECT this_.id,
  this_. TIMESTAMP
  Traces this_
  WHERE this_. COUNTRY_NUM =: 1
  AND this_. TIMESTAMP BETWEEN: 2 AND: 3
  AND this_.type_of_action =: 4
  AND LOWER (this_. MESSAGE) AS: 5
  ORDER BY this_. TIMESTAMP DESC)
  WHERE ROWNUM < =: 6;
  -----------------------------------------------------------
  
  I have 16 distinct COUNTRY_NUM in the table and the TIMESTAMPE is a number that the application is inserted into the table.
  
  My question is the best solution to resolve this table is to use partitioninig for a smal parts?
  I have need of a partitioning using a list by date (YEAR/month) and COUNTRY_NUM, is there a better way for her?
  
  NB: for an example of TRACES in my test database
  
  1 Select COUNTR_NUM, count (*) traces
  Group 2 by COUNTR_NUM
  3 * order by COUNTR_NUM
  SQL > /.
  
  COUNTR_NUM COUNT (*)
  
  194716 1
  3 1796581
  4 1429393
  5 1536092
  6 151820
  7 148431
  8 76452
  9 91456
  10 91044
  11 186370
  13 76
  15 29317
  16 33470

  Hello

  Yes and part is that you can remove the whole score once you don't need "of them. I think you should be good to go. Let me know if you have any other questions.

  Concerning

• How to enter comments for each photo?  Preparation of photos for sale at the auction house.

  I have a historical photo collection b & w preparation for the auction.  How to catalogue each photo with custom comments?  I have LR 4.4

  You will need to type this info in this field in the metadata Panel.  I assume that you want to use the legend, perhaps Title fields, two fields must be empty for you to enter custom text. If you select all images and enter the text, all the images Gets the same data. So think about what you want to pop over there and if you can do so at the same time, or if you will need to do frame-by-frame.

• [JS CS3] how to extract information from scriptsList table

  Hi all,

  just a silly question: How can I extract scriptList property filePath and fileName and display it in an alert box?

  Ah, that should have been

  for (i = 0; i< f.length;="">

  f instead of s. You will see the path names starting with a dash of turnings (~), which is js pointing to the folder of the user. You can learn more about records and their names in the JS tool guide, see in respect of aid in the ESTK Help menu.

  app.scriptPreferences.scriptsList returns the scripts in the folder of the user and the application folder. app.scriptPreferences.scriptFolder returns only the scripts in the user folder. Mmm - I think that this is the case, anyway. Try before you buy.

  Peter

• How to add folio for each starting line of page

  Dear friend,

  I've been trying to script.

  In the Document every pages of first line and the first word before that I want add folio (page number).  Please suggest a friend. How to complete this script coding.

  Please see my requirement in the screenshot below.

  

  Please help friends.

  Thanks in advance

  Try this

  for (p = 0; p

  {

  try {}

  app.activeDocument.pages [f] .textFrames [0] .lines [0] .insertionPoints [0] .silence = "";

  }

  {catch (e)}

  }

• How to use RIDC for query Tables content WebCenter

  Hi all
  
  Can we use content query API RIDC WebCenter 11g Tables.if yes then how can I achieve this?
  
  I'm newbie

  is always found in the oracle doc

  http://docs.Oracle.com/CD/E21764_01/doc.1111/e11011/c05_core.htm#BABBABBF
  and this also

  http://jonathanhult.com/blog/2012/07/RIDC-versus-CIS/

• How to make replace() for each symbol in the string instead of the first meeting only?

  Hello!

  This is my simple test script:

  var str = ' re | PLA | ce »;

  var strRep str.toString () = replace (' | ', '-');

  Alert (strRep);

  I'd get a re-pla-this result string.

  But I didn't get my only first symbol replaced:

  

  Can you advise me please, how to get all the symbols replaced?

  Thank you!

  Thank you very much, Xavier!

  Just for reference, this line will work perfectly:

  Alert (str.toString () replace (new RegExp ("|", "g"), '-'));

• Count for each table

  Hello
  
  I try to count (*) for all the table owned by a user
  I have the following error
  
  What's wrong?
  Thank you
  

  declare

  2 i the number;
  3 t_owner varchar2 (20);
  4 t_table_name varchar2 (20);
  5. start
  6 t in (select * from all_tables where owner = "MISAMM")
  7 loop
  8 t_owner: = t.owner;
  9 t_table_name: = t.table_name;
  10 dbms_output.put_line (' :'|| Table t_table_name);
  11 dbms_output.put_line (' owner :'|| t_owner);
  12 select count (*) in I of t_owner.t_table_name;
  14 dbms_output.put_line ('Table :'|| t.table_name |) "lines :'|| TO_CHAR (i));
  15 end loop;
  16 end;
  17.
  Select count (*) in I of t_owner.t_table_name;
  *
  ERROR on line 12:
  ORA-06550: line 12, column 37:
  PL/SQL: ORA-00942: table or view does not exist
  ORA-06550: line 12, column 1:
  PL/SQL: SQL statement ignored
  
  
  Elapsed time: 00:00:00.01

  Hello

  The names of the tables come display of metadata dynamically. Thus, you should use "immediate execution".

  declare
    i            number;
    t_owner      varchar2(20);
    t_table_name varchar2(20);
  begin
    for t in (select * from all_tables where owner = 'MISAMM')
    loop
      t_owner      := t.owner;
      t_table_name := t.table_name;
      dbms_output.put_line('Table:' || t_table_name);
      dbms_output.put_line('Owner:' || t_owner);
      execute immediate 'select count(*) from ' || t_table_name
        into i;
      dbms_output.put_line('Table:' || t.table_name || ' rows:' || to_char(i));
    end loop;
  end;
  /
  

  Also, I wonder why you are not satisfied with the "num_rows" user_tables and all_tables column?