How to find the cumaltive for a distinct element in the same column

Similar Questions

• How to find the same column name in different tables in the same schema

  Hello
  
  I find the 'ename' column name in different tables in the same schema.
  
  Thank you
  Nr

  Hello

  Try this query

  Select column_name, table_name from user_tab_columns where column_name = 'ENAME ';

  Award points and end the debate, if your question is answered or mark if she was...

  Kind regards

  Lacouture.

• How to find the NULL columns in the table?

  Hello
  
  Please provide the query to search for null columns in the table. Here, all the rows in the table have same column as null. It will not change.
  
  Table
  ---------------
  C1 c2 c3 c4
  X C 10
  T D 20
  
  I want to know that C2 is the nullable column.
  Thanks in advance!
  
  Kind regards
  Florian...

  A variance more

  create or replace function is_nulled_column(tab varchar2, col varchar2) return varchar2 is
  cnt number:=1;
  begin
    execute immediate 'select count(1) from '||tab||' where '||col||' is not null and rownum=1' into cnt;
    return case when cnt=0 then 'Y' else 'N' end;
  end;
  

  and use:

  select
   c.OWNER,c.TABLE_NAME,c.COLUMN_NAME,c.NULLABLE,is_nulled_column(c.TABLE_NAME,c.COLUMN_NAME) all_nulls
  from all_tab_columns c
  where c.OWNER=user
  and c.TABLE_NAME like '%'
  order by c.OWNER,c.TABLE_NAME,c.COLUMN_ID
  

• How to find the child level for each table in a relational model?

  Earthlings,
  
  I need your help, and I know that, "Yes, we can change." Change this thread to a question answered.
  
  So: How to find the child level for each table in a relational model?
  
  I have a database of relacional (9.2), all right?
  

  .
       O /* This is a child who makes N references to each of the follow N parent tables (here: three), and so on. */
      /↑\ Fks
     O"O O" <-- level 2 for first table (circle)
    /↑\ Fks
  "o"o"o" <-- level 1 for middle table (circle)
     ↑ Fk
    "º"

  Tips:
  -Each circle represents a table;
  -Red no tables have foreign key
  -the picture on the front line of tree, for example, a level 3, but when 3 becomes N? How is N? That is the question.
  
  I started to think about the following:
  
  First of all, I need to know how to take the kids:

  select distinct child.table_name child
    from all_cons_columns father
    join all_cons_columns child
   using (owner, position)
    join (select child.owner,
                 child.constraint_name fk,
                 child.table_name child,
                 child.r_constraint_name pk,
                 father.table_name father
            from all_constraints father, all_constraints child
           where child.r_owner = father.owner
             and child.r_constraint_name = father.constraint_name
             and father.constraint_type in ('P', 'U')
             and child.constraint_type = 'R'
             and child.owner = 'OWNER') aux
   using (owner)
   where child.constraint_name = aux.fk
     and child.table_name = aux.child
     and father.constraint_name = aux.pk
     and father.table_name = aux.father;

  Thought...
  We will share!
  
  Thanks in advance,
  Philips
  
  Published by: BluShadow on April 1st, 2011 15:08
  formatting of code and hierarchy for readbility

  Have you looked to see if there is a cycle in the graph of dependence? Is there a table that has a foreign key to B and B has a back of A foreign key?

  SQL> create table my_emp (
    2    emp_id number primary key,
    3    emp_name varchar2(10),
    4    manager_id number
    5  );
  
  Table created.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  create table my_mgr (
    2    manager_id number primary key,
    3    employee_id number references my_emp( emp_id ),
    4    purchasing_authority number
    5* )
  SQL> /
  
  Table created.
  
  SQL> alter table my_emp
    2    add constraint fk_emp_mgr foreign key( manager_id )
    3         references my_mgr( manager_id );
  
  Table altered.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1   select level lvl,
    2          child_table_name,
    3          sys_connect_by_path( child_table_name, '/' ) path
    4     from (select parent.table_name      parent_table_name,
    5                  parent.constraint_name parent_constraint_name,
    6                  child.table_name        child_table_name,
    7                  child.constraint_name   child_constraint_name
    8             from user_constraints parent,
    9                  user_constraints child
   10            where child.constraint_type = 'R'
   11              and parent.constraint_type = 'P'
   12              and child.r_constraint_name = parent.constraint_name
   13           union all
   14           select null,
   15                  null,
   16                  table_name,
   17                  constraint_name
   18             from user_constraints
   19            where constraint_type = 'P')
   20    start with child_table_name = 'MY_EMP'
   21*  connect by prior child_table_name = parent_table_name
  SQL> /
  ERROR:
  ORA-01436: CONNECT BY loop in user data
  

  If you have a cycle, you have some problems.

  (1) it is a NOCYCLE keyword does not cause the error, but that probably requires an Oracle version which is not so far off support. I don't think it was available at the time 9.2 but I don't have anything old enough to test on

  SQL> ed
  Wrote file afiedt.buf
  
    1   select level lvl,
    2          child_table_name,
    3          sys_connect_by_path( child_table_name, '/' ) path
    4     from (select parent.table_name      parent_table_name,
    5                  parent.constraint_name parent_constraint_name,
    6                  child.table_name        child_table_name,
    7                  child.constraint_name   child_constraint_name
    8             from user_constraints parent,
    9                  user_constraints child
   10            where child.constraint_type = 'R'
   11              and parent.constraint_type = 'P'
   12              and child.r_constraint_name = parent.constraint_name
   13           union all
   14           select null,
   15                  null,
   16                  table_name,
   17                  constraint_name
   18             from user_constraints
   19            where constraint_type = 'P')
   20    start with child_table_name = 'MY_EMP'
   21*  connect by nocycle prior child_table_name = parent_table_name
  SQL> /
  
         LVL CHILD_TABLE_NAME               PATH
  ---------- ------------------------------ --------------------
           1 MY_EMP                         /MY_EMP
           2 MY_MGR                         /MY_EMP/MY_MGR
           1 MY_EMP                         /MY_EMP
           2 MY_MGR                         /MY_EMP/MY_MGR
  

  (2) If you try to write on a table and all of its constraints in a file and do it in a valid order, the entire solution is probably wrong. It is impossible, for example, to generate the DDL for MY_EMP and MY_DEPT such as all instructions for a table come first, and all the instructions for the other are generated second. So even if NOCYCLE to avoid the error, you would end up with an invalid DDL script. If that's the problem, I would rethink the approach.

  -Generate the DDL for all tables without constraint
  -Can generate the DDL for all primary key constraints
  -Can generate the DDL for all unique key constraints
  -Can generate the DDL for all foreign key constraints

  This is not solidarity all the DOF for a given in the file object. But the SQL will be radically simpler writing - there will be no need to even look at the dependency graph.

  Justin

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• How to find the value max and min for each column in a table 2d?

  How to find the value max and min for each column in a table 2d?

  For example, in the table max/min for the first three columns would be 45/23, 14/10, 80/67.

  Thank you

  Chuck,

  With color on your bars, you should have enough experience to understand this.

  You're a loop in the table already.  Now you just need a function like table Max and min. loop.  And you may need to transpose the table 2D.

• How to find the password for my Motorola Wireless?

  How to find the password for my Motorola Wireless?

  How to connect another computer to the Motorola Wireless?

  ... and now my computer won't connect to the wireless...

  Now would be a good time to use the instructions of the Setup Guide quick Motorola SBG940.

  ... I think I'll call my cable provider then!

  It may be better to talk to someone on the phone instead of trying to communicate via typed messages repeated as some of the information in the previous messages typed always seem to be lost in translation.

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  I am using the Forum to get a new code to the printer and the printer shows homepage that's on, but now I don't know how to find the e-mail address for my computer.

  Hello

  In the front of the printer, go to configuration. Locate and enter the Web Services. Aprove any step to activate the service... leave the system a few minutes to complete your registration, a page will be printed automatically with the code printer and directions to select the email address of hpeprint.com.

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• How to find the age of a child and snapshot number snapshot for a virtual machine.

  Hi all

  How to find the age of a snapshot for a virtual machine child count and snapshot.

  This code snippet should help... Assuming that you have the following entries:

  VM (VC:VirtualMachine)

  snapshot (VC:VirtualMachineSnapshot)

  System.log("====== Snapshot details for VM: "+snapshot.config.name+" ======");
  var snapshotTrees = vm.snapshot.rootSnapshotList;
  System.log("Snapshot Tree Count: "+snapshotTrees.length);
  for each (snapshotTree in snapshotTrees){
      showSnapshotInfo(snapshotTree, snapshot);
  }
  
  function showSnapshotInfo(snapshotTree, selectedSnapshot){
      if(selectedSnapshot == snapshotTree.snapshot){
          System.log("====================");
          System.log("Name: "+snapshotTree.name);
          System.log("Id: "+snapshotTree.id);
          System.log("Description: "+snapshotTree.description);
          System.log("createTime: "+snapshotTree.createTime);
          System.log("quiesced: "+snapshotTree.quiesced);
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          System.log("");
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          }
      }
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  During the passage of one of my virtual machines, here is an example of output I get:

  [2014-06-12 15:19:21.493] [I] Snapshot Tree Count: 1
  [2014-06-12 15:19:21.493] [I] ====================
  [2014-06-12 15:19:21.494] [I] Name: before upgrade to 5.0.1
  [2014-06-12 15:19:21.494] [I] Id: 31
  [2014-06-12 15:19:21.494] [I] Description:
  [2014-06-12 15:19:21.495] [I] createTime: Mon Mar 19 2012 13:48:57 GMT-0400 (EDT)
  [2014-06-12 15:19:21.495] [I] quiesced: false
  [2014-06-12 15:19:21.495] [I] replaySupported: null
  [2014-06-12 15:19:21.495] [I] backupManifest: null
  [2014-06-12 15:19:21.496] [I] snapshot id: snapshot-83
  [2014-06-12 15:19:21.496] [I] state: poweredOff
  [2014-06-12 15:19:21.496] [I] childSnapshotList length: 1
  [2014-06-12 15:19:21.496] [I]
  [2014-06-12 15:19:21.497] [I] ====================
  [2014-06-12 15:19:21.497] [I] Name: Before 5.1 upgrade
  [2014-06-12 15:19:21.497] [I] Id: 36
  [2014-06-12 15:19:21.497] [I] Description:
  [2014-06-12 15:19:21.498] [I] createTime: Fri Sep 21 2012 21:59:58 GMT-0400 (EDT)
  [2014-06-12 15:19:21.498] [I] quiesced: false
  [2014-06-12 15:19:21.498] [I] replaySupported: null
  [2014-06-12 15:19:21.498] [I] backupManifest: null
  [2014-06-12 15:19:21.499] [I] snapshot id: snapshot-84
  [2014-06-12 15:19:21.499] [I] state: poweredOff
  [2014-06-12 15:19:21.499] [I] childSnapshotList length: 1
  [2014-06-12 15:19:21.499] [I]
  [2014-06-12 15:19:21.500] [I] ====================
  [2014-06-12 15:19:21.500] [I] Name: Before Named Instance
  [2014-06-12 15:19:21.500] [I] Id: 37
  [2014-06-12 15:19:21.501] [I] Description:
  [2014-06-12 15:19:21.501] [I] createTime: Mon Nov 11 2013 13:40:46 GMT-0500 (EST)
  [2014-06-12 15:19:21.501] [I] quiesced: false
  [2014-06-12 15:19:21.501] [I] replaySupported: null
  [2014-06-12 15:19:21.502] [I] backupManifest: null
  [2014-06-12 15:19:21.502] [I] snapshot id: snapshot-236
  [2014-06-12 15:19:21.502] [I] state: poweredOff
  [2014-06-12 15:19:21.502] [I]
  

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