How to find the NULL columns in the table?

Similar Questions

• How to find the table in a schema, if I only have a particular column name

  Hi all
  
  Ideal if some1 could help me, I know not a column name and I need to find the table that actually holds this column paricular name I know.
  
  is it possible to find this particular table with SQL?
  
  Thank you
  Rahul

  Select the table TABLE_NAME from user_tab_columns where column_name = 'COLUMN_NAME '.

• How to find the tables that are used in a procedure

  Hello
  I need to write a SQL to find (user_source) procedures or triggers (from user_triggers), whose code contains the registerd tables in a table X.
  In other words, I have a table X with files having a column containing tables. I want to write a SQL to obtain these (proc, package and triggers) container objects or use the tables inside
  Can you help me?
  Thank you!

  Mark1970 wrote:
  Hello
  I need to write a SQL to find (user_source) procedures or triggers (from user_triggers), whose code contains the registerd tables in a table X.
  In other words, I have a table X with files having a column containing tables. I want to write a SQL to obtain these (proc, package and triggers) container objects or use the tables inside
  Can you help me?
  Thank you!

  I don't know if I understand your problem, but have you had a glance at the data dictionary views USER_DEPENDENCIES or ALL_DEPENDENCIES?

  It has classified hard dependencies of objects.
  If a table is used directly (not in dynamic SQL code in a string) in an object PL/SQL, the dependency is available in the stated points of view.

• How to find the tables placed only on pages.

  Hi experts,

  I find all the tables in the document (no XML Indd file.) .indd There is only a certain number of tables. And a table in the master page also. Now I'm trying to get back only the tables except the master page. How can I got it?

  I used the following code. But it is not working properly.

  var myTables is app.activeDocument.stories.everyItem () .tables;.

  App.Select(mytables[0]);

  var myTableCount = myTables.length;

  Alert (myTableCount);

  for (var i = 0; i < myTableCount; i ++) {}

  var myTableObj = myTables [i];

  Alert (myTableObj.parent);

  Try

  {

  var myTableObj.parent.parentPage.name = XXX;

  If (xxx.match("^[0-9]+$"))

  {

  Alert ('table');

  myTableObj.label = 'table' +(i+1);

  }

  on the other

  {

  Alert ("Master Page table");

  }

  }

  catch (e)

  {

  Alert (e.message);

  }

  }

  Always throw catch loop...

  Can someone guide me...!

  Thank you and best regards,

  Vel.

  Hi Peter,.

  Finally, I close with the codes below. It make me fight a lot...

  var pagelen = app.activeDocument.pages.length;

  Alert (pagelen);

  for (var i = 0; i)<>

  {

  var pageitemlen = app.activeDocument.pages [i].pageItems.length;

  for (var j = 0; j)<>

  {

  v var = app.activeDocument.pages [i] .pageItems [j] .tables;

  Alert (v.Length);

  for (var x = 0; x)<>

  {

  App.Select (v [x]);                                                      Here, I can select.

  App.Selection [0] .label = "table" + count;

  Count ++;

  myTables.push (v [i]);

  }

  }

  }

  Peter, thank you very much for your time in Golden for my problem...

  With respect,

  Vel.

• How to find the table?

  Hello
  
  I have a java Apps to connect to a database of GR 11, 2.
  When I clicked on a "billing" module, I don't 'a number' 1,641.00 error in java logs that cause billing does not be generated.
  I don't even enter this value. I don't know if this error at the level of the table or during analysis on the coast of java it fetch a numeric variable placeholder.
  I simply assume that it is at the database level. And assuming that I am the only user in the database.
  How can I get this operation with the 1,641.00 value and determine which table was is inserted to the error? In V$ SQLAREA maybe?
  

  SYSUSER - 263293-40-1 2012-07-10 11:08:25,578 [http-6700-1] INFO  (support.context.CacheManager) Registering cache 'BusinessObjectInfoCache'
  SYSUSER - 263293-41-1 2012-07-10 11:08:25,859 [http-6700-2] ERROR (api.service.ServiceExecutionPolicy) Rollback: Read failed
  java.lang.NumberFormatException: Not a number: 1,641.00
       at com.ibm.icu.math.BigDecimal.bad(BigDecimal.java:3894)

  Thank you very much
  Kins

  >
  apps itself has no problem.
  >
  I have to disagree. If the application is to throw an exception and the journal contains her not the information necessary for you tell what is causing the exception, and then the application has ALSO a problem.

  java.lang.NumberFormatException: Not a number: 1,641.00
       at com.ibm.icu.math.BigDecimal.bad(BigDecimal.java:3894)
  

  Add additional record to the app to catch the exception and discover the connection, the request and the record that causes the error.

  Troubleshoot, to gather information when the problem actually occurs and work your way backwards.

  If you say that the problem did not exist before the developer made the change then prove it by running the old code against the same data. If it works then the problem is with the change that made the developer.

• How to find the table - is - this normal table or external table?

  Hello
  
  
  Regardless of DML operations in normal and reading tables only access tables outside, is there a way to find the specified table is regular table or the external table?
  
  Thanks in advance.
  
  Suresh.

  One possibility would be to query the ALL_EXTERNAL_TABLES data dictionary view. If there is a line in ALL_EXTERNAL_TABLES to the table, wondering (I assume you know that you query a table, a view, or a synonym), it is an external table. Otherwise, it's an ordinary table.

  Justin

• How to find the value max and min for each column in a table 2d?

  How to find the value max and min for each column in a table 2d?

  For example, in the table max/min for the first three columns would be 45/23, 14/10, 80/67.

  Thank you

  Chuck,

  With color on your bars, you should have enough experience to understand this.

  You're a loop in the table already.  Now you just need a function like table Max and min. loop.  And you may need to transpose the table 2D.

• How to find the primary key columns in the tables in MS Access using SQL queries

  How to find the primary key columns in the tables in MS Access using SQL queries

  Hello

  This is the forum for Windows Vista programs related issues.

  For better assistance, please try instead the Forums in SQL Server .

  Thank you! Vincenzo Di Russo - Microsoft MVP Windows Internet Explorer, Windows Desktop Experience & security - since 2003. ~ ~ ~ My MVP profile: https://mvp.support.microsoft.com/profile/Vincenzo

• How to find the size of the downloaded image on a column of type blob in a table?

  How to find the size of the downloaded image on a column of type blob in a table?

  Vidya,

  You can use the built in function dbms_lob.getlength to get the length (size) of a LOB column or a bfile type.
  Check out this link.

  http://download.Oracle.com/docs/CD/B10501_01/AppDev.920/a96612/d_lob2.htm#1008995

• How to find the number of data items in a file written with the ArryToFile function?

  I wrote a table of number in 2 groups of columns in a file using LabWindows/CVI ArrayToFile... Now, if I want to read the file with the FileToArray function so how do I know the number of items in the file. during the time of writing, I know how many elements array to write. But assume that I want the file to be read at a later time, then how to find the number of items in the file, so that I can read the exact number and present it. Thank you all

  Hello

  I start with the second question:

  bytes_read = ReadLine (file_handle, line_buffer, maximum_bytes);

  the second argument is the buffer to store the characters read, so it's an array of characters; It must be large enough to hold maximum_bytes the value NULL, if char [maximum_butes + 1]

  So, obviously the number of lines in your text tiles can be determined in a loop:

  Open the file

  lines = 0;

  While (ReadLine () > 0)

  {

  lines ++;

  }

  Close the file

• How to find the date item was my favorites on Mozilla Firefox

  on system moot bookmark how to find the date of the bookmark?

  In bookmarks menu select organize bookmarks to open the bookmarks library. In the bookmarks library, click views, and then display the columns and then added. This will display a column showing when a bookmark has been added.

• How to find the path of a file

  Hello

  I have Windows 7 Starter.

  The search utility can be used to search for files by using the ' * ' wildcard, but unfortunately it does not show the path for no results.

  I would like to know how to find the path of a file of my choice.

  For example, I record a radio on the internet, which is then saved as "MP3". Now, I want to edit such a file, but I need to know where the file is actually stored. Simply access within a 'library' does not show me where the file is actually located.

  How to discover all paths where a particular file format?

  I hope to receive a response to this request.

  Kind regards

  Rayt333

  An option for the search utility see the paths for all of its results, would be useful.

  Hi Ray

  Overall view for the search folder for Detailsof Windows Explorer , by using the View Menu on the right side of the toolbar.

  Click on the last name column heading and select the folder item.

  If you do not see the folder item, click other, scroll and select the folder item. This will add the folder column.

  Use the left mouse button to drag the folder column to the left, next to the column name .

  Now, when you perform a search, the folder column will show the path of each file found.

  Concerning

• How to find the different languages of an indd Document?

  Dear friends,

  I use multi-language books. How to find the language in the following list (just I want find option only).

  1. English: UK
  2. German: The old rules

  It is possible to find/replace option. Please suggest a friend

  Thanks in advance

  Hi Karthik,

  Try this,

  app.findTextPreferences = null;

  app.findTextPreferences.appliedLanguage = "English UK:";

  var ukText = app.activeDocument.findText ();

  app.findTextPreferences = null;

  for (var i = 0; i)<>

  $.writeln (ukText [i] .silence);

  app.findTextPreferences.appliedLanguage = "German: old Rules ';

  var gerText = app.activeDocument.findText ();

  app.findTextPreferences = null;

  for (var j = 0; j)<>

  $.writeln (gerText [j] .silence);

• How to find the value dated the same day in the last year

  I want to know how to find the value dated the same day in the last year.

  I use now, there is the function with the year and the result is

  Year	Rev	There are Rev
  2011	3000
  2012	4000	3000
  2013	2000	4000
  2014	5000	2000

  It works but it's not that I want. I'm trying to add the column date (Ex.20140101) in my report but it'snot work.

  I want to show:

  Date	Rev	There are Rev
  20110112	200
  20120112	100	200
  20130112	300	100
  20140112	500	300

  If use (< degree >, < time_dim >. < date >, 365), it works but does not correct 100%

  Please help me...

  Thank you very much

  Check this link cool - bi.com

• How to find the age of a child and snapshot number snapshot for a virtual machine.

  Hi all

  How to find the age of a snapshot for a virtual machine child count and snapshot.

  This code snippet should help... Assuming that you have the following entries:

  VM (VC:VirtualMachine)

  snapshot (VC:VirtualMachineSnapshot)

  System.log("====== Snapshot details for VM: "+snapshot.config.name+" ======");
  var snapshotTrees = vm.snapshot.rootSnapshotList;
  System.log("Snapshot Tree Count: "+snapshotTrees.length);
  for each (snapshotTree in snapshotTrees){
      showSnapshotInfo(snapshotTree, snapshot);
  }
  
  function showSnapshotInfo(snapshotTree, selectedSnapshot){
      if(selectedSnapshot == snapshotTree.snapshot){
          System.log("====================");
          System.log("Name: "+snapshotTree.name);
          System.log("Id: "+snapshotTree.id);
          System.log("Description: "+snapshotTree.description);
          System.log("createTime: "+snapshotTree.createTime);
          System.log("quiesced: "+snapshotTree.quiesced);
          System.log("replaySupported: "+snapshotTree.replaySupported);
          System.log("backupManifest: "+snapshotTree.backupManifest);
          System.log("snapshot id: "+snapshotTree.snapshot.id);
          System.log("state: "+snapshotTree.state.value);
          var childSnapshotList = snapshotTree.childSnapshotList;
          if(childSnapshotList != null){
              System.log("childSnapshotList length: "+snapshotTree.childSnapshotList.length);
          }
          System.log("");
      }
      if(snapshotTree.childSnapshotList != null){
          System.log("Children found: "+snapshotTree.childSnapshotList.length);
          for each (childSnapshotTree in snapshotTree.childSnapshotList){
              showSnapshotInfo(childSnapshotTree, selectedSnapshot);
          }
      }
  }
  

  During the passage of one of my virtual machines, here is an example of output I get:

  [2014-06-12 15:19:21.493] [I] Snapshot Tree Count: 1
  [2014-06-12 15:19:21.493] [I] ====================
  [2014-06-12 15:19:21.494] [I] Name: before upgrade to 5.0.1
  [2014-06-12 15:19:21.494] [I] Id: 31
  [2014-06-12 15:19:21.494] [I] Description:
  [2014-06-12 15:19:21.495] [I] createTime: Mon Mar 19 2012 13:48:57 GMT-0400 (EDT)
  [2014-06-12 15:19:21.495] [I] quiesced: false
  [2014-06-12 15:19:21.495] [I] replaySupported: null
  [2014-06-12 15:19:21.495] [I] backupManifest: null
  [2014-06-12 15:19:21.496] [I] snapshot id: snapshot-83
  [2014-06-12 15:19:21.496] [I] state: poweredOff
  [2014-06-12 15:19:21.496] [I] childSnapshotList length: 1
  [2014-06-12 15:19:21.496] [I]
  [2014-06-12 15:19:21.497] [I] ====================
  [2014-06-12 15:19:21.497] [I] Name: Before 5.1 upgrade
  [2014-06-12 15:19:21.497] [I] Id: 36
  [2014-06-12 15:19:21.497] [I] Description:
  [2014-06-12 15:19:21.498] [I] createTime: Fri Sep 21 2012 21:59:58 GMT-0400 (EDT)
  [2014-06-12 15:19:21.498] [I] quiesced: false
  [2014-06-12 15:19:21.498] [I] replaySupported: null
  [2014-06-12 15:19:21.498] [I] backupManifest: null
  [2014-06-12 15:19:21.499] [I] snapshot id: snapshot-84
  [2014-06-12 15:19:21.499] [I] state: poweredOff
  [2014-06-12 15:19:21.499] [I] childSnapshotList length: 1
  [2014-06-12 15:19:21.499] [I]
  [2014-06-12 15:19:21.500] [I] ====================
  [2014-06-12 15:19:21.500] [I] Name: Before Named Instance
  [2014-06-12 15:19:21.500] [I] Id: 37
  [2014-06-12 15:19:21.501] [I] Description:
  [2014-06-12 15:19:21.501] [I] createTime: Mon Nov 11 2013 13:40:46 GMT-0500 (EST)
  [2014-06-12 15:19:21.501] [I] quiesced: false
  [2014-06-12 15:19:21.501] [I] replaySupported: null
  [2014-06-12 15:19:21.502] [I] backupManifest: null
  [2014-06-12 15:19:21.502] [I] snapshot id: snapshot-236
  [2014-06-12 15:19:21.502] [I] state: poweredOff
  [2014-06-12 15:19:21.502] [I]
  

• How to find the child level for each table in a relational model?

  Earthlings,
  
  I need your help, and I know that, "Yes, we can change." Change this thread to a question answered.
  
  So: How to find the child level for each table in a relational model?
  
  I have a database of relacional (9.2), all right?
  

  .
       O /* This is a child who makes N references to each of the follow N parent tables (here: three), and so on. */
      /↑\ Fks
     O"O O" <-- level 2 for first table (circle)
    /↑\ Fks
  "o"o"o" <-- level 1 for middle table (circle)
     ↑ Fk
    "º"

  Tips:
  -Each circle represents a table;
  -Red no tables have foreign key
  -the picture on the front line of tree, for example, a level 3, but when 3 becomes N? How is N? That is the question.
  
  I started to think about the following:
  
  First of all, I need to know how to take the kids:

  select distinct child.table_name child
    from all_cons_columns father
    join all_cons_columns child
   using (owner, position)
    join (select child.owner,
                 child.constraint_name fk,
                 child.table_name child,
                 child.r_constraint_name pk,
                 father.table_name father
            from all_constraints father, all_constraints child
           where child.r_owner = father.owner
             and child.r_constraint_name = father.constraint_name
             and father.constraint_type in ('P', 'U')
             and child.constraint_type = 'R'
             and child.owner = 'OWNER') aux
   using (owner)
   where child.constraint_name = aux.fk
     and child.table_name = aux.child
     and father.constraint_name = aux.pk
     and father.table_name = aux.father;

  Thought...
  We will share!
  
  Thanks in advance,
  Philips
  
  Published by: BluShadow on April 1st, 2011 15:08
  formatting of code and hierarchy for readbility

  Have you looked to see if there is a cycle in the graph of dependence? Is there a table that has a foreign key to B and B has a back of A foreign key?

  SQL> create table my_emp (
    2    emp_id number primary key,
    3    emp_name varchar2(10),
    4    manager_id number
    5  );
  
  Table created.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  create table my_mgr (
    2    manager_id number primary key,
    3    employee_id number references my_emp( emp_id ),
    4    purchasing_authority number
    5* )
  SQL> /
  
  Table created.
  
  SQL> alter table my_emp
    2    add constraint fk_emp_mgr foreign key( manager_id )
    3         references my_mgr( manager_id );
  
  Table altered.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1   select level lvl,
    2          child_table_name,
    3          sys_connect_by_path( child_table_name, '/' ) path
    4     from (select parent.table_name      parent_table_name,
    5                  parent.constraint_name parent_constraint_name,
    6                  child.table_name        child_table_name,
    7                  child.constraint_name   child_constraint_name
    8             from user_constraints parent,
    9                  user_constraints child
   10            where child.constraint_type = 'R'
   11              and parent.constraint_type = 'P'
   12              and child.r_constraint_name = parent.constraint_name
   13           union all
   14           select null,
   15                  null,
   16                  table_name,
   17                  constraint_name
   18             from user_constraints
   19            where constraint_type = 'P')
   20    start with child_table_name = 'MY_EMP'
   21*  connect by prior child_table_name = parent_table_name
  SQL> /
  ERROR:
  ORA-01436: CONNECT BY loop in user data
  

  If you have a cycle, you have some problems.

  (1) it is a NOCYCLE keyword does not cause the error, but that probably requires an Oracle version which is not so far off support. I don't think it was available at the time 9.2 but I don't have anything old enough to test on

  SQL> ed
  Wrote file afiedt.buf
  
    1   select level lvl,
    2          child_table_name,
    3          sys_connect_by_path( child_table_name, '/' ) path
    4     from (select parent.table_name      parent_table_name,
    5                  parent.constraint_name parent_constraint_name,
    6                  child.table_name        child_table_name,
    7                  child.constraint_name   child_constraint_name
    8             from user_constraints parent,
    9                  user_constraints child
   10            where child.constraint_type = 'R'
   11              and parent.constraint_type = 'P'
   12              and child.r_constraint_name = parent.constraint_name
   13           union all
   14           select null,
   15                  null,
   16                  table_name,
   17                  constraint_name
   18             from user_constraints
   19            where constraint_type = 'P')
   20    start with child_table_name = 'MY_EMP'
   21*  connect by nocycle prior child_table_name = parent_table_name
  SQL> /
  
         LVL CHILD_TABLE_NAME               PATH
  ---------- ------------------------------ --------------------
           1 MY_EMP                         /MY_EMP
           2 MY_MGR                         /MY_EMP/MY_MGR
           1 MY_EMP                         /MY_EMP
           2 MY_MGR                         /MY_EMP/MY_MGR
  

  (2) If you try to write on a table and all of its constraints in a file and do it in a valid order, the entire solution is probably wrong. It is impossible, for example, to generate the DDL for MY_EMP and MY_DEPT such as all instructions for a table come first, and all the instructions for the other are generated second. So even if NOCYCLE to avoid the error, you would end up with an invalid DDL script. If that's the problem, I would rethink the approach.

  -Generate the DDL for all tables without constraint
  -Can generate the DDL for all primary key constraints
  -Can generate the DDL for all unique key constraints
  -Can generate the DDL for all foreign key constraints

  This is not solidarity all the DOF for a given in the file object. But the SQL will be radically simpler writing - there will be no need to even look at the dependency graph.

  Justin