How to find the middle name of any column NAME

I wrote under request

why this market not could you please help me?

Select substr (ename, instr (ename,' ', 1, 1), instr (ename, ' ', 1.2)) of e1

InStr, primary function must return the first position of the space and

2 nd instr, function should return 2nd space

so we can specify in substr function to extract the form position of string from this place to that place

It would be very useful that you explain the reason

Best regards

Prem kumar

Select

-case when length (substr (ename, instr (ename,' ', 1.2))) = length (ename) then

(case when length (substr (name, instr (ename,' ', 1.1))) = length (ename) then null)

of another substr (ename, instr (ename,' ', 1, 1) + 1) end)

of another substr (ename, instr (ename,' ', 1, 1) + 1, instr(ename,' ',1,2)-instr(ename,' ',1,1)-1)

end middle_name

of e1;

Select

-case when length (substr (ename, instr (ename,' ', 1.2))) = length (ename) then

(case when length (substr (ename, instr (ename,' ', 1.1))) = length (ename) then null)

of another substr (ename, instr (ename,' ', 1, 1) + 1) end)

of another substr (ename, instr (ename,' ', 1, 1) + 1, instr(ename,' ',1,2)-instr(ename,' ',1,1)-1)

end middle_name

from (select 'asw nag raj' ename of double)

Union

Select "raj asw ght" double

Union

Select 'raj asw dfjadf Tom' from dual) e1;

Tags: Database

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