How to find the name of the producer of my vidio card?

Similar Questions

• How to find the SCP to a java card

  Hello
  
  How will I know if a java card uses SCP01 and SCP02?
  Because I read the respose data returned by the Init setting command suite updated map, but it comes to send back more info back to entity of off - map:
  Main data of diversification 10 bytes
  2-byte key information
  Challenge map 8 bytes
  Cryptogram of card 8 bytes
  
  And in the same GP2.2 E.1.2.1 , it is written that
  This cryptogram of the card as well as the meter of the sequence, the challenge of the card, the secure channel protocol identifier,
  and other data are sent to the entity of off - map.
  I want to know how to find the SCP protocol identifier?
  
  In addition, it is written that:
  As the entity of off - map should now have the same information as the card used to generate the cipher of the card.
  It should be capable of generating the same session key and the cipher card even and performing a comparison.
  It is able to authenticate the card.
  
  Can someone explain please how to generate these keys and check the card?
  
  Thank you

  Umer says:
  I also found that the SCP is found in the Init-setting control response to date.

  It's also a good way to get the PCs?

  Yes. That's what I use. It does not give you the value of i (current hit is I = 15), but this is not a very big deal in practice (in my code anyway).

  See you soon,.
  Shane

• How to find the book, THE, Op units, Org (All) names and ID?

  How to find the book, THE, Op units, Org (All) names and ID?

  With regard to:

  Mr. Shahzad Saleem

  Please run the following query

  SELECT gl.NAME ledger_name, hou.NAME operating_unit_name,

  xep.NAME legal_entity_name

  Gl_ledgers gl, hr_operating_units hou, xle_entity_profiles xep

  WHERE gl.ledger_id = hou.set_of_books_id

  AND hou.default_legal_context_id = xep.legal_entity_id

• How to find the name of the Oracle database server?

  People,

  Hello. I installed Oracle Database 11 g 2 OS Oracle Linux 5. The installed directory is/home/user/OracleDB_Home and/home/user/OracleDB_Base.

  Host name is "mylinux". Name of the database instance is PT853.

  I use "mylinux" as the name of the database server, it does not work. I use another way to do as below:

  Export ORACLE_HOME = / home/user/OracleDB_Home

  Can I use "mylinux ORACLE_HOME" as the name of the database server, it does not work either.

  
  My question is:

  How to find the name of the database server Oracle with Oracle Linux 5 OS?

  
  Thank you.

  You must learn the basic of database Oracle.

  Please don't regard it not same as SQL server in terms of configuration.

  You never specify the database server name in Oracle.

  You specify the host name in only two places, 1) Tnsnames.ora/JDBC/ODBC (or any client you want to connect) and listener.ora) 2.

  There was nothing called specify the name of the Oracle database from an oracle database server.

  Concerning

  Anurag.

• How to find the session killed and computer name

  Hello
  
  At the time of the batch run killed .somebody this session without me knowing how to find the user particular db level or oslevel .de name which machine they killed how know at the OS level. but when I put the audit_trail = os only user SYSDBA activities are not checked the other activities of the user.
  
  The server is AIX and db version 11i provide the query for conclusion or os level.
  
  Thank you
  DBC.
  
  Published by: dbc001 on March 26, 2013 21:48

  check with who ever is privilleges to kill these perticluar session, if you have few users.
  It is not possible to findout without verification or error info... etc.
  Otherwise, restart these jobs perticluar and follow closely.

• How to find the current MovieClip

  Hello

  I create a flash file to display the products.

  Images and Product Details are stored in the XML file.

  Is what I'm trying to create something similar to the banner on http://www.gainfeeds.com/home

  Add to this is that products are going to be right scroll to the left automatically if there is no user interaction, and produced at the Center will remain highlighted.

  I created a long strip of coverage of products with a mask, the long strip continues to move give a scroll effect.

  Now my question is how to find the product that is currently at the center of the mask?

  
  Thank you.

  Alok Jain

  No there is no default name assigned to them.

  If you take the parent video clip and with for you apply a getChildNum() method, do not exactly know the syntax, you can take the children of the parent in sales responsibilities. 0,1,2,3,4,... etc.

  But this isn't something that will help a lot because you don't know what this number is.

  For example, when you create the child movieclips, xml-based, I assume you are using a statement. So in this statement when creating each movieClip, fi do you something like "var m:MovieClip = new MovieClip();"also do the following"$m.name ="mc"+ i". ""

  You want to do this because the name "m" is valid only as long as the scope of the valid function is. Once the training starts again you loose any reference to the old "m" and a new one is created. So for future reference the movieClips outside the function that creates, you name them.

  After that you can call from anywhere (given that you set the path to access the parent corectly) like this: "parentMovieClip.getChildByName("m3")" If you want to target a third, or using any name you give in the creation of statement.

• How to find the velocity of an incremental encoder

  I use the RE22I encoder which can give up to 8192 pulses per revolution, I have A, B, Z reports that I use an fpga as a controller Please help me.

  How to find the speed of the encoder using these signals I'm going to have a clock in the fpga sysytem will help.

  Start by looking at the information on Wikipedia on the rotary encoders and a book on encoders OR white.  These articles will give you a basic understanding of the encoder and the signals it produces.

  With proper decoding, you can get the direction and momentum of each of the points on your encoder 8192.  If the tree can reverse (same vibration on one point unique all-in-mnearly stationary), full decoding must be used.  If data are only of interest while the tree turns in a direction and speed will not close to zero, a simple decoding can be used.  Decoding of a quadrature encoder is a good way to learn to use a state machine.  Signals A and B can exist in only four possible combinations, but the possible transitions to do interesting things.

  Define DECODING is a purely logical exercise and it is a simple coding in LabVIEW, such as a state machine.  There are examples, Desing Patterns, or project templates (depending on your version of LV) that come with LV to help you get started.

  By using the channels A and B you can update your calculation of velocity 8192 times per turn.  With the help of Z you get only an update by the revolution. You use depends on your application.  The pulse of Z is also useful to define a reference position for the measurement of phase angle.

  Lynn

• How to find the position of the VI icon currently run on the block diagram of the appellant

  Dear forum,

  I am currently trying to use a LabVIEV VI as a simple sequencer: several (very slow) actions must run one after the other. Each action is represented by a Sub - VI, some actions are executed several times. My task is to view the Subvi somehow executing.

  My first intention (just manipulate the icon of the VI running with 'Icon.Get VI as Image data' / 'Icon.Set VI of Image data' invoke nodes) has failed, because it changes all instances of the VI icon. If you use the same VI several times, all these VI icons are changed (see here: http://forums.ni.com/t5/LabVIEW/How-to-change-animate-icon-of-currently-running-VI/m-p/3120754/highl... )

  My current approach is to use an image of the block diagram (with "VI: block diagram: get resized Image ' call method) in a picture of the front panel control and working within this control. But for this I need to know the position of the icon of the VI running. I know that I can assess the limits and Position via the properties GObj, but how to find the VI running (note that a VI can be installed several times on the block diagram, so the name of the VI is not unique)? IMHO the easiest way might be if a VI might find its icon on the block of the appellant diagram itself when it is run...

  It is clear that this position is not yet the position on the photo, but this conversion is a small piece of work...

  Kind regards

  cpschnuffel

  
  

• Does anyone know how to find the ip address of someone who is to be a nuiscance?

  Does anyone know how to find the ip address of a person who uses different names to communicate with you. A member of the family has problems with someone who does this.  Thank you in advance, I know one of the guys will help me.

  Hi, Ros,

  Use the e-mail headers

  http://www.johnru.com/Active-WHOIS/trace-email.html

• How to find the snid? If it is removed or deleted from this sticker on the back?

  How to find the snid and sn & id of the laptop if it is removed or deleted this sticker on the back?

  My laptop is acer ferrari 1000

  Tools Information as SIW system reports the product name and serial number IF this information is stored somewhere in the computer.

  I don't know what you mean by 'id', but for example, all the following values are reported by SIW:

  Manufacturer
  Name of the product
  Version
  Serial number
  Type of machine
  Infrared (IR) supported
  DMI system UUID
  UUID

• How to find the path of a file

  Hello

  I have Windows 7 Starter.

  The search utility can be used to search for files by using the ' * ' wildcard, but unfortunately it does not show the path for no results.

  I would like to know how to find the path of a file of my choice.

  For example, I record a radio on the internet, which is then saved as "MP3". Now, I want to edit such a file, but I need to know where the file is actually stored. Simply access within a 'library' does not show me where the file is actually located.

  How to discover all paths where a particular file format?

  I hope to receive a response to this request.

  Kind regards

  Rayt333

  An option for the search utility see the paths for all of its results, would be useful.

  Hi Ray

  Overall view for the search folder for Detailsof Windows Explorer , by using the View Menu on the right side of the toolbar.

  Click on the last name column heading and select the folder item.

  If you do not see the folder item, click other, scroll and select the folder item. This will add the folder column.

  Use the left mouse button to drag the folder column to the left, next to the column name .

  Now, when you perform a search, the folder column will show the path of each file found.

  Concerning

• How to find the location of a file or folder in windows 7

  I have a few games on my computer. I can't find the location of the original file for them however. What I find is that they are in the 'games' folder that is included with windows 7. However, the whole files are not there. Only a little bit of information for the game is stored here. What I need to know is: how to find the original location? I tried the search bar "search programs and files" under the start menu, but the only place that appears is the Games folder. I need to know this, because I want to try modding my game called "Civilization 4. Can you please help?

  Try this...

  Start button > in the search box, type the name of the gam, i.e. of Civilization 4 > (do NOT press enter) > top left corner, you see the name "Civilization 4 '?

  If so, right click on it > click Open File Location > the game exe file show be on the highlighted list > right click it > click on create a shortcut.

  Happens to you?

• How to find the 'society of the IP '?

  Hi all.

  I am beginner Eloqua10, and I have a question.

  Could you tell me how to find the 'intellectual property society '?

  ('Intellectual property society' is the name of the company Eloqua derived from the IP address of the visitor).

  I guess that there is a 'society of IP"in a preview, but I couldn't find that.

  Please help me.

  Regards ,

  Matsui

  Hi Matsui,

  The field you are looking for, is a field of account.

  

  When you select fields in reports, then select 'IP address of the company' in the areas of account.

  I guess it could help you.

  Kind regards

  Eloqua Expert

• How to find the ID of the existing contact?

  I need to update an existing contact in Eloqua, but to do that I need to find the ID of the contact.

  I know how to get the ID of the contact after it is created the first time, but once it is already created how to find the code.

  How do I do that?

  Here is my code that I use to update, I just need to solve for '?

  EloquaAPI. DynamicEntity [dynamicEntities] = new EloquaAPI. DynamicEntity [1] ;

  dynamicEntities [0] = new EloquaAPI. DynamicEntity ();

  dynamicEntities [0]. EntityType = entityType;

  dynamicEntities [0]. Id = "???";

  dynamicEntities [0]. FieldValueCollection is new EloquaAPI. DynamicEntityFields ();

  dynamicEntities [0]. FieldValueCollection.Add ("C_GUID1", GUID);

  dynamicEntities [0]. FieldValueCollection.Add ("C_FirstName", FirstName.Trim ());

  dynamicEntities [0]. FieldValueCollection.Add ("C_LastName", LastName.Trim ());

  dynamicEntities [0]. FieldValueCollection.Add ("C_EmailAddress", Email.Trim ());

  dynamicEntities [0]. FieldValueCollection.Add ('C_Type1', 'Contact');

  EloquaAPI. UpdateResult [] result = service. Update (dynamicEntities);

  Joey

  Hi Joey,

  If you do not already have the id of the contact, then you will need to use the. Function Query() to get it – most commonly ask you based on the email address.  For this call API documentation is here:

  http://www.eloquatrainingcenter.com/Portal/documentation/API/content/API_Reference/Entity_Operations/query.htm

  The example code in this page is not large (without having to download the entire sample application), but here's a basic use (VB.net):

  Dim contactId As Integer = 0

  Dim etContact As New ELQService.EntityType
  etContact.Type = 'Base '.
  etContact.Name = "Contact".

  Dim result = are. Query (etContact, "C_EmailAddress ="[email protected]"", {"Id"}, 1, 50)
  If result. TotalRecords > 0 then contactId = result. Entities (0). ID

  Chris

• How to find the age of a child and snapshot number snapshot for a virtual machine.

  Hi all

  How to find the age of a snapshot for a virtual machine child count and snapshot.

  This code snippet should help... Assuming that you have the following entries:

  VM (VC:VirtualMachine)

  snapshot (VC:VirtualMachineSnapshot)

  System.log("====== Snapshot details for VM: "+snapshot.config.name+" ======");
  var snapshotTrees = vm.snapshot.rootSnapshotList;
  System.log("Snapshot Tree Count: "+snapshotTrees.length);
  for each (snapshotTree in snapshotTrees){
      showSnapshotInfo(snapshotTree, snapshot);
  }
  
  function showSnapshotInfo(snapshotTree, selectedSnapshot){
      if(selectedSnapshot == snapshotTree.snapshot){
          System.log("====================");
          System.log("Name: "+snapshotTree.name);
          System.log("Id: "+snapshotTree.id);
          System.log("Description: "+snapshotTree.description);
          System.log("createTime: "+snapshotTree.createTime);
          System.log("quiesced: "+snapshotTree.quiesced);
          System.log("replaySupported: "+snapshotTree.replaySupported);
          System.log("backupManifest: "+snapshotTree.backupManifest);
          System.log("snapshot id: "+snapshotTree.snapshot.id);
          System.log("state: "+snapshotTree.state.value);
          var childSnapshotList = snapshotTree.childSnapshotList;
          if(childSnapshotList != null){
              System.log("childSnapshotList length: "+snapshotTree.childSnapshotList.length);
          }
          System.log("");
      }
      if(snapshotTree.childSnapshotList != null){
          System.log("Children found: "+snapshotTree.childSnapshotList.length);
          for each (childSnapshotTree in snapshotTree.childSnapshotList){
              showSnapshotInfo(childSnapshotTree, selectedSnapshot);
          }
      }
  }
  

  During the passage of one of my virtual machines, here is an example of output I get:

  [2014-06-12 15:19:21.493] [I] Snapshot Tree Count: 1
  [2014-06-12 15:19:21.493] [I] ====================
  [2014-06-12 15:19:21.494] [I] Name: before upgrade to 5.0.1
  [2014-06-12 15:19:21.494] [I] Id: 31
  [2014-06-12 15:19:21.494] [I] Description:
  [2014-06-12 15:19:21.495] [I] createTime: Mon Mar 19 2012 13:48:57 GMT-0400 (EDT)
  [2014-06-12 15:19:21.495] [I] quiesced: false
  [2014-06-12 15:19:21.495] [I] replaySupported: null
  [2014-06-12 15:19:21.495] [I] backupManifest: null
  [2014-06-12 15:19:21.496] [I] snapshot id: snapshot-83
  [2014-06-12 15:19:21.496] [I] state: poweredOff
  [2014-06-12 15:19:21.496] [I] childSnapshotList length: 1
  [2014-06-12 15:19:21.496] [I]
  [2014-06-12 15:19:21.497] [I] ====================
  [2014-06-12 15:19:21.497] [I] Name: Before 5.1 upgrade
  [2014-06-12 15:19:21.497] [I] Id: 36
  [2014-06-12 15:19:21.497] [I] Description:
  [2014-06-12 15:19:21.498] [I] createTime: Fri Sep 21 2012 21:59:58 GMT-0400 (EDT)
  [2014-06-12 15:19:21.498] [I] quiesced: false
  [2014-06-12 15:19:21.498] [I] replaySupported: null
  [2014-06-12 15:19:21.498] [I] backupManifest: null
  [2014-06-12 15:19:21.499] [I] snapshot id: snapshot-84
  [2014-06-12 15:19:21.499] [I] state: poweredOff
  [2014-06-12 15:19:21.499] [I] childSnapshotList length: 1
  [2014-06-12 15:19:21.499] [I]
  [2014-06-12 15:19:21.500] [I] ====================
  [2014-06-12 15:19:21.500] [I] Name: Before Named Instance
  [2014-06-12 15:19:21.500] [I] Id: 37
  [2014-06-12 15:19:21.501] [I] Description:
  [2014-06-12 15:19:21.501] [I] createTime: Mon Nov 11 2013 13:40:46 GMT-0500 (EST)
  [2014-06-12 15:19:21.501] [I] quiesced: false
  [2014-06-12 15:19:21.501] [I] replaySupported: null
  [2014-06-12 15:19:21.502] [I] backupManifest: null
  [2014-06-12 15:19:21.502] [I] snapshot id: snapshot-236
  [2014-06-12 15:19:21.502] [I] state: poweredOff
  [2014-06-12 15:19:21.502] [I]