How to get the index of the selected items in a listbox?

Similar Questions

• ListField - how to get the selected items

  Hi @all,

  I am running OS5 on a BB bold 9700 and development via eclipse.

  I tried to do a listfield and put it in a display of network manager, which works very well.

  As peter_strange did in a reply to a thread listfield, I tried to catch the click button on navigation through "makemenu.

  It works fine, but after processing the code according to the listfield (getindex), it shows a standard menu, which I don't want. I want just to get the index or the name of the current or selected fields and continue with the transformation by showing a new screen for example.

  In some other threads that I found excerpts concerning 'navigationclick', but I don't understand, what I have to do here and why. Th KB, I searched but I did find something to go further.

  Someone there who can help me with a small example?

  Thank you much in advance.

  CUA

  Michael

  You can create your own class or override her anonymously.

  new ListField (...) {replace the code of the method here}

  (blackberry is perhaps not the best way to start learning java...)

• How to get the selected row in a programmatic table of the ADF (table generated from a bean)

  Hi all

  
  

  We use JDeveloper Studio Edition Version 12.1.3.0.0 and deployed on GlassFish Server Open Source Edition 3.1.2.2 (build 5) and connect to the SQLServer database.

  
  

  How to get the selected line in a programmatic (using a SortableModel custom not a display object) ADF table (generated from a bean)?

  
  

  We are trying to get the selected row in a bean of a programmatic ADF table to retrieve data based on the selected line.

  
  

  Any idea?
  

  Well, you can use selectionListener to set the selected line to a variable of bean (but this bean must be in extended view or some superiors)

  Something like this: http://www.awasthiashish.com/2015/07/get-selected-row-singlemultiple-from.html

  Dario

• DVT:pivotFilterBar - how to get the selected values of the filter

  Hi all
  
  I have a question: how to get the selected values from the pivot table filter bar programmatically?
  
  I tried to use

  pivotTable.getDataModel().getDataAccess().getValueQDR(startRow, startCol, DataAccess.QDR_WITH_PAGE);

  but to the edge of the side DATA INCORRECTESdeclarations page, it seems that it will return the cached values.
  
  Environment: JDev 11.1.1.3.0 without tasks.
  
  Thank you
  Miroslaw

  Hello

  You can retrieve the value selected in the PivotFilterBar through the PivotFilterBar model, instead of dataaccess:

  Download the template of the bar pivot filter instance
  QueryDescriptior queryDescriptor = (QueryDescriptor) pivotFilterBar.getValue ();

  retrieve a list of criterion, each of them is used to fill each lov in the pivot filter bar
  ConjunctionCriterion conjunctionCriterion = queryDescriptor.getConjunctionCriterion ();
  List criterionList = conjunctionCriterion.getCriterionList ();
  for (int i = 0; i)<_criterionList.size(); i++)="">
  AttributeCriterion = (AttributeCriterion) criterionList.get (i) criterion.

  _selected is the currently selected value
  Selected object = criterion.getValues () .get (0);

  System.out.println (_selected);
  }

  Hope that helps,
  Chadwick

• How to get the selected DataGrid item?

  Hello
  
  I have a datagrid
  
  < mx:DataGrid = "10" XY = dataProvider "36" = "{acEmaillist}" width = "319" >
  < mx:columns >
  < mx:DataGridColumn headerText = "Full name" dataField = "cn" width = "150" / >
  < mx:DataGridColumn headerText = "Email" dataField = "mail" width = "150" / >
  < / mx:columns >
  < / mx:DataGrid >
  
  I want to select a name, click it, get the selected name and save it in a string variable. Please let me know how to get the selected name when I click it. Thank you very much.
  
  M

  This code can help.

  
  http://www.Adobe.com/2006/mxml"width ="100% ">
  
  Import mx.controls.DataGrid;
  Import mx.events.ListEvent;

  [Bindable]
  private var nameStr:String;

  public void getName(event:ListEvent):void {}
  var dg:DataGrid = DataGrid (event.target);
  nameStr = dg.selectedItem.cn;
  }
  ]]>
  
  
  
  Bob Smith
  [email protected]
  
  
  Ted Alan
  [email protected]
  
  
  Fred Tobs
  [email protected]
  
  

  
  
  
  
  
  
  
  

• How to get the selected text in a TextInput

  Hallo. I have a textinput, and when the event doubleclick on a part of the text is sent, I need to get the selected text, and then save it in a string... How can I do?

  THX

  Max

  Hi Maximist,

  Below is the code snippet to get the selected text in TextInput on double click event:

  http://www.Adobe.com/2006/mxml '.

  Layout = "vertical".

  verticalAlign = "middle".

  backgroundColor = "white" >

  Import mx.controls.Alert;

  private void textInput_doubleClick(evt:MouseEvent):void {}

  Alert.Show (String (evt.target.text) .slice (evt.target.selectionBeginIndex, evt.target.select ionEndIndex));

  }

  ]]>

  Text = "the Bullfighter is out the path of the bull charge at the last moment, drawing the cheers of the spectators."

  doubleClickEnabled = "true".

  doubleClick = "textInput_doubleClick (event); "/ >

  Hope this will help you.

  Thanks and greetings

  ------------------------------------------------------------------------------------

  Pooja Kuber | [email protected] | www.infocepts.com

  ------------------------------------------------------------------------------------

• How to get the 'selection' illuminated

  I have a vista 64. I had a few printing problem which I found out wasa because google chrom. I had one tech outside and the problem has been corrected. However, I have an impression left of problem that I hope someone can help me with. I'm trying to print part of a page. I am the part children and then go to the print page. However, I cannot print print the part because the only 'all' and 'pages' are turned on. "selection is not lit, so I can't click. Can someone tell me how to recover the 'selection '.

  Hey, Dolores,.

  Your computer is configured to display pages in full screen? When this happens press F11 on your keyboard and see if the button reduce reappears.

• DropDownList - how to get the selected value

  I have the next dropdownlist control:

  Select.dd = Select.gMain.add('dropdownlist',undefined,FinalElements);
      Select.dd.onChange = notifyMe();
  

  and the notifyMe() function

  function notifyMe()
  {
      alert(this.selection);
  }
  

  I need to use the value of the selected item in the menu dropdown. So for now I'm just an alert. However, nothing happens, when I change the selection in the drop-down list. How can I fix?

  Hey!

  Change this:

  Select.dd.onChange = notifyMe();
  

  to do this:

  Select.dd.onChange = notifyMe;
  

  --

  tomaxxi

  http://indisnip.WordPress.com/

• How to get the selected values from the shuttle

  Hello
  
  Please tell me how to get the values of the option chosen by the shuttle leading the list.
  
  Thank you

  Check out this link and that this might help you.

  Attack-shuttle leak problem

  Thank you
  -Anil
  http://oracleanil.blogspot.com/

• Determine the index of the selected items in a ListBox?

  Hello

  I can't find a simple/direct method to determine the index of the selected item in a list box.

  I feel I'm missing something, but I can't seem to figure out who (if any) returns an index number if you use it with the recall of .onChange for a ListBox control.

  The following code implements that I need, but is not particularly efficient or elegant and can get confused if you introduce multiple lists to check.

  Any suggestions to reproduce this behavior, even with the best code would be appreciated.

  Thank you!

  var RES = ' palette {text: 'Example-list' properties: {resizable: true}-} ".

  NLP: Panel {orientation: 'row', preferredSize: [400 600]------}

  list1: ListBox {preferredSize: [400 550], properties: {multiselect: true, numberOfColumns:2, showHeaders:true, columnTitles: ["list 1", "item 0"]}}, \

  }}"

  var win = new Window (res)

  Win.Show)

  for (i = 0; i < 10; i ++) {}

  var line = win.pnl.list1.add ("point", "Same entry")

  row.subItems [0] .text = ' paragraph '+ i}.

  Win.PNL.List1.OnChange = function() {}

  var tempArray = new Array()

  for (i = 0; i < win.pnl.list1.items.length; i ++) {}

  If (win.pnl.list1.items [i] .selected == true) {tempArray.push (i)}

  }

  selectedRow = win.pnl.list1.items var [tempArray [0]] .text

  var selectedRowSubitem = win.pnl.list1.items [tempArray [0]] .subItems [0]

  Alert ("selection:" + tempArray + "\n posted content:" + selectedRow + "\t" + selectedRowSubitem)

  }

  .. .in the same time, that should be enough

  win.pnl.list1.onChange = function() {
       alert(this.selection.index); // for this to work set, multiselect:false
  }
  

  I guess you already tried and the result is 'undefined', the reason is that you have this property

  multiselect:true
  

  in this case, the selection returns an array

  this.selection[0].index;
  

  I'd give you the first selected item, even if you only have a single element selected, for all selected items to loop through all the elements in the selection table.

  not sure if the wonderful guide Peter explains this (explained in the Guide to the tools), but you should read it too, he has tons of info.

• To access the selected items in a ListBox control

  In LabVIEW 2010, I have a ListBox control. How can I get a list of the objects that the user selected in the ListBox?

  I don't see any method, property or event that would provide this information.

  Thank you.

  The value of the ListBox are the indexes of the selected items.

  If you allow the user to select "0 or more' items, the data type will change in a table."

  To get the names of the selected items (I guess that is what you want), you should India property 'element names.

  Tone

• How to get the selected layers?

  Hi, how can I use the SDK for a list of the layers that are selected by the user when the plugin is activated?

  Let's talk terminology.

  an "activation" on a layer effect is not really the process of events.

  When an effect is used firstly to æ session, this is the function GlobalSetup()

  is called.

  This is the most 'activated' like thing in the effect by applying the process.

  This function is called only once per session (in general) and data

  allocated to it is shared between all instances.

  then, whenever a new instance is applied, the specific instance

  Function SeqeunceSetup() is called.

  It is the only clue you get tell you that a new instance is created.

  Unfortunately, in the course of this appeal you still cannot check the layer on which

  the effect will be applied, as at that time there AE still because preparations

  and has not done this topic yet. (try to get the effect layer will

  give an error)

  so when you say "on" I'm assuming you mean "applied".

  If an instance of the effect is already present in an economy effect, you get not one

  Call of SequenceSetup(), but a SequenceResetup() call instead. (or Unflatten())

  now, to detect if another instance is present on a layer, you must analyze

  This layer effects and check each because it is installed a key. (and match

  to you, of course)

  you will need to use:

  AEGP_GetLayerNumEffects

  AEGP_GetLayerEffectByIndex

  AEGP_GetInstalledKeyFromLayerEffect

  and now you hit the real problem.

  an effect cannot remove another effect of the same layer, sure it is. It will be

  very probably launch an error message as AE manages all the layer effects

  and suddenly; y an is missing.

  You can solve that by using a CEAP separated with a slow hook and make the

  deletion, or all just throwing your own message to the user by saying

  You cannot have two and set a flag on the second instance of turn it off

  process.

• How to get the select button event Radio in my co

  Hello
  
  I want to get the the radio button selection event in my co, how do I get the event?

  Hello

  841475 wrote:
  I want to get the the radio button selection event in my co, how do I get the event?

  -There is no case of option button.
  -you need to explicitily set the event for the option button.

  Action: FirePaatialAction
  Event: RadioEvent

  -Discover the event in co by code below:

  If ("RadioEvent". Equals (PageContext.GetParameter (EVENT_PARAM)))
  {
  -In the case of a radio button. :))
  }

  Concerning
  Meher Irk

• How to get the selected values of the af:selectManyChoice in the bean support

  Hello
  
  I have a selectManyChoice with a list of static, as shown below.
  At the click of the button, is called a method in the bean support. I want to get the list of the values selected by the method of the bean.
  How to do the same thing.
  

  <af:panelFormLayout id="pfl1" fieldWidth="50%" labelWidth="50%">
          <af:selectManyChoice label="Days" id="smc1"
                               binding="#{Bean.addDaysChoice}">
            <af:selectItem label="Monday" value="MON" id="si17"/>
            <af:selectItem label="Tuesday" value="TUE" id="si13"/>
            <af:selectItem label="Wednesday" value="WED" id="si15"/>
            <af:selectItem label="Thursday" value="THU" id="si14"/>
            <af:selectItem label="Friday" value="FRI" id="si11"/>
            <af:selectItem label="Saturday" value="SAT" id="si16"/>
            <af:selectItem label="Sunday" value="SUN" id="si12"/>
          </af:selectManyChoice>        
            <af:commandButton text="Button"
                              actionListener="#{bean.callSomeMethod}"
                              id="cb1"/>  
  <af:panelFormLayout/>

  Thank you
  Ajay
  
  Published by: Ajay on January 31, 2011 06:26

  Hello

  What about setting the property "value" of the selectManyChoice, and then point to a method of the managed bean (setter/accessor for a variable of type list)?

  Frank

• How to get the 'selected text '? leave a string

  If I highlight text in a text string, I want to be able to copy it to the Clipboard.

  I have already created an event that uses the Application of reference to 'write the Clipboard' now I need to give it the selected text.

  How do I do that?

  Here's a way to do it.

  Ben64