How to get the record for the top 3 of aggregate column

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  How to build the top users page with which users are more recently logged_in to the application? Similar to the picture here

  

  --

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  Venky_prs wrote:

  How to build the top users page with which users are more recently logged_in to the application? Similar to the picture here

  

  Create a report of region using a query like:

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  How to get the column name for a particular column value.
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  commit;
  
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     c1 SYS_REFCURSOR;
  BEGIN
     OPEN c1 FOR
     SELECT col2,
            col3
     FROM   test
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• How to get the Max value with other columns data also.

  Suppose that a query is covered with the data as

  Time of ID
  01 07/12/2014
  02 07/05/2014
  03 16/07/2014
  04 07/07/2014

  I need to get the ID and time to time max.
  that is, should I get
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  Frank mentioned links
  

  
  

  WITH test_data (id, time) LIKE)

  SELECT 01, to_date('2014/07/12','yyyy-mm-dd') FROM dual

  UNION ALL

  SELECT 02, to_date('2014/07/16','yyyy-mm-dd') FROM dual

  UNION ALL

  SELECT 03, to_date('2014/07/16','yyyy-mm-dd') FROM dual

  UNION ALL

  SELECT 04, to_date('2014/07/07','yyyy-mm-dd') FROM dual

  )

  SELECT id, time

  go (select id,

  time,

  Max (Time) on latest_time (order by time lines between unbounded preceding and following unbounded)

  of test_data

  )

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  Hello.
  
  I wonder if there is a way to get a query (no pl/sql code) a list of columns with a separator between them.
  
  I know I can get that without separators with an expression of cursor:

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    3  union
    4  select 1 col1, 'b' col2 from dual
    5  union
    6  select 1 col1, 'c' col2 from dual
    7  union
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    9  union
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   11  union
   12  select 2 col1, 'd' col2 from dual
   13  union
   14  select 2 col1, 'z' col2 from dual
   15  )
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   17  group by col1
   18  /
  
        COL1 COL2_LIST
  ---------- --------------------
           1 CURSOR STATEMENT : 2
  
  CURSOR STATEMENT : 2
  
  C
  -
  a
  b
  c
  
           2 CURSOR STATEMENT : 2
  
  CURSOR STATEMENT : 2
  
  C
  -
  a
  c
  d
  z

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  ---------- --------------------
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           2 a;c;d;z

  I don't know how to manage a cursor expression without using a pl/sql function block. Can it be done using analytical functions?
  
  Thanks in advance.

  Hello

  This is called 'aggregation of chain.
  This site:

  http://asktom.Oracle.com/pls/asktom/f?p=100:11:0:P11_QUESTION_ID:2196162600402

  shows different ways to do this, including the SYS_CONNECT_BY_PATH solution which gave Blushadow.

  I got a lot of use of the first solution on this page, the function defined by the user STRAGG, that you can copy.

  Once you have installed STRAGG, your query is simply

  SELECT    col1
  ,         STRAGG (col2)     AS col2_list
  FROM      test_table
  GROUP BY  col1;
  

  The query above do not put items in a particular order.

  On Oracle 10 (and more) you can have a similar function, the WM_CONCAT (property WMSYS), already installed.
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• How to get multiple records in a line and a different column

  Hi all
  
  I am using oracle database 11g
  
  and I have a two table table_1, table_2
  table_1 has columns
  
  emp_no
  first name
  middle_name
  last_name
  E-mail
  
  and table_2 have columns
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  phone_type
  Phone_Number
  
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  1001 652341536 EMG
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  1003 WEMG 5332621456
  1004 59612356 EMG
  
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  $sid

  Hi Sid,

  Under query will be help for you...

  SELECT tab1.emp_no
  *, first name *.
  *, middle_name *.
  *, last_name *.
  *, email *.
  *, mobile t2.phone_number *.
  *, t3.phone_number officeno *.
  OF tab1
  *, (SELECT Emp_no *)
  *, phone_number *.
  Of THE tab2
  WHERE phone_type = "MOB") t2
  *, (SELECT Emp_no *)
  *, phone_number *.
  Of THE tab2
  WHERE phone_type = "WEMG") t3
  WHERE tab1.emp_no = t3.emp_no
  AND tab1.emp_no = t2.emp_no;

  Thnks,
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