How to get the year of Date data

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  I use only one task DAQmx to read the data. I get 4 data tables for 4 channels each table length is 200, every time, DAQmx Read happens.

  But I want to get the seal of these 200 samples per channel. How to get the seal of these samples, made me know.

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• How to get the difference in dates in days

  Hi friends,
  
  How to get the date difference between two dates exactly
  
  date2-date1 days exactly... shouyld rounded to the nearest value of...
  
  and one entire display i mean positive integer
  Select round ((sysdate) - to_date (date_start)), date_start days of per_periods_of_service
  
  This gives negative also result

  Hello

  776317 wrote:
  Hi friends,

  How to get the date difference between two dates exactly

  date2-date1 days exactly... shouyld rounded to the nearest value of...

  Date1 - date2 is the exact number of days is after date2 date1. (It is as accurate as possible, given that the DATEs do not have fractions of a second).

  and one entire display i mean positive integer
  Select round ((sysdate) - to_date (date_start)), date_start days of per_periods_of_service

  You want to probably get the exact number of days first, then ROUND this number:

  SELECT  ROUND (SYSDATE - TO_DATE (date_start, ...))   AS days
  FROM    per_periods_of_service; 
  

  Always pass arguments at least 2 to TO_DATE:
  (1) the string to be converted, and
  (2) a saying string how (1) is formatted

  This gives negative also result

  Right; If date1 is before date2 then date1 - date2 returns a negative number.
  If you want to never get a negative value, use ABS (date2 - date1). If it returns 4, then you know that one of the DATEs was 4 days before the other, but you won't know who was earlier.

  I hope that answers your question.
  If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) and also publish outcomes from these data.
  Explain, using specific examples, how you get these results from these data.
  Always tell what version of Oracle you are using.

• How to get the Application Build Date and time?

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• How to get the time to date?

  Hi Sir,
  
  I need to recover the time to date.
  
  ' like ' 2012-10-03 04:32.
  
  to retrieve the only time where it's 04:32
  
  What is the query for this?
  
  Thank you

  Hi user,

  You can use TO_CHAR function to obtain the hour alone

  SELECT TO_CHAR (TO_DATE ('2012-10-03 04:32:00', 'YYYY-MM-DD HH24:MI:SS'),
                  'HH24:MI:SS'
                 ) TI_ME
    FROM DUAL
  

  Thank you
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• How to get the difference in Date in years, months and days

  Select Sysdate-Birth_date from Employees;

  the query returns the number of days between two dates
  I want to convert this number in years, months and days
  Can someone help me please

  Hoek wrote:
  Try:

  SQL> with t as (
  2  select to_date('01-01-1980', 'dd-mm-yyyy') birthdate
  3  ,      to_date('05-05-2010', 'dd-mm-yyyy') today
  4  from   dual
  5  )
  6  --
  7  --
  8  --
  9  select extract(year from today)-extract(year from birthdate) years
  10  ,      extract(month from today)-extract(month from birthdate) months
  11  ,      extract(day from today)-extract(day from birthdate) days
  12  from   t;
  
  YEARS     MONTHS       DAYS
  ---------- ---------- ----------
  30          4          4
  
  1 row selected.
  

  (May need some adjustments, possibly using the LARGEST, but currently not as long)

  Indeed, a few adjustments...

  SQL> ed
  Wrote file afiedt.buf
  
    1  with t as (
    2    select to_date('31-01-2009', 'dd-mm-yyyy') birthdate
    3    ,      to_date('28-02-2010', 'dd-mm-yyyy') today
    4    from   dual
    5    )
    6  --
    7  --
    8  --
    9  select extract(year from today)-extract(year from birthdate) years
   10  ,      extract(month from today)-extract(month from birthdate) months
   11  ,      extract(day from today)-extract(day from birthdate) days
   12* from   t
  SQL> /
  
       YEARS     MONTHS       DAYS
  ---------- ---------- ----------
           1          1         -3
  
  SQL>
  

  Maybe something like this?

  SQL> ed
  Wrote file afiedt.buf
  
    1  with t as (select to_date('17-nov-2006','dd-mon-yyyy') as c_start_date, to_date('21-jan-2008','dd-mon-yyyy') as c_end_date from dual union all
    2             select to_date('21-nov-2006','dd-mon-yyyy'), to_date('17-feb-2008','dd-mon-yyyy') from dual union all
    3             select to_date('31-jan-2009','dd-mon-yyyy'), to_date('28-feb-2010','dd-mon-yyyy') from dual union all
    4             select to_date('21-jun-2006','dd-mon-yyyy'), to_date('17-jul-2008','dd-mon-yyyy') from dual
    5             )
    6  -- end of test data
    7  select c_start_date, c_end_date
    8        ,trunc(months_between(c_end_date, c_start_date) / 12) as yrs
    9        ,trunc(mod(months_between(c_end_date, c_start_date), 12)) as mnths
   10        ,trunc(c_end_date - add_months(c_start_date, trunc(months_between(c_end_date, c_start_date)))) as dys
   11* from t
  SQL> /
  
  C_START_DATE        C_END_DATE                 YRS      MNTHS        DYS
  ------------------- ------------------- ---------- ---------- ----------
  17/11/2006 00:00:00 21/01/2008 00:00:00          1          2          4
  21/11/2006 00:00:00 17/02/2008 00:00:00          1          2         27
  31/01/2009 00:00:00 28/02/2010 00:00:00          1          1          0
  21/06/2006 00:00:00 17/07/2008 00:00:00          2          0         26
  

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• How to get the year and month of a whole year

  Hello
  
  I have a list of selection and when the user selects the list values are like this 201101,201102,201103
  
  I tried like this
  
  
  declare
  T_DATE varchar2 (25);
  Start
  because me in 1.12 loop
  Select TO_CHAR (ADD_MONTHS (SYSDATE, + 1), "YYYYMM") in the double T_DATE;
  dbms_output.put_line (V_DATE);
  end loop;
  end;
  
  But its bad and I can not get clear idea where to change the code
  
  Thanks and greetings
  Srikkanth.M

  Srikkanth.M wrote:
  Hello

  I have a list of selection and when the user selects the list values are like this 201101,201102,201103

  If you want to list for the current year from Jan 201101,201102, 201103... 201112, then try this

  DECLARE
    v_Date  VARCHAR2(25);
    n_month NUMBER;
  BEGIN
    SELECT extract (MONTH FROM sysdate) INTO n_month FROM dual;
    FOR i IN 1..12
    LOOP
      SELECT TO_CHAR(ADD_MONTHS(SYSDATE, (i-n_month)), 'YYYYMM')
      INTO v_date
      FROM dual;
      dbms_output.put_line(v_date);
    END LOOP;
  END;
  

  Vivek L

• How to get the Date, month, year of the DateTimePicker

  Hi, I am using the DateTimePicker.

  There are several question about this command:

  1. how to get the Date, month and year?

  -With the help of myDateTime.value, I get this string ' Wed May 08 14:45 ICT 2013 '-> I have to manually analyze this? Because I need in format yyyy/mm/dd. Or can set the format of dateTimePicker.value?

  2 format on dateTimePicker self (on the user interface) is d/m/YY, I can't change to another format?

  Thank you

  dateTimePicker.value return a QDateTime not a string.

  https://developer.BlackBerry.com/Cascades/reference/bb__cascades__datetimepicker.html#property-value

  See more:

  https://developer.BlackBerry.com/Cascades/reference/QDateTime.html#date

  https://developer.BlackBerry.com/Cascades/reference/QDate.html

  You can get

  day = dateTimePicker.value.date().day()
  month = dateTimePicker.value.date().month()
  year= dateTimePicker.value.date().year()
  dateYYYYMMDD = dateTimePicker.value.date().toString(Qt::ISODate)
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• How to get the date for the first Monday of each month

  Dear members,
  
  How to get the date for the first Monday of each month.
  
  I wrote the following code
  
  SELECT decode (to_char (trunc (sysdate + 30, 'MM'), 'DAY'), 'MONDAY', trunc (sysdate + 30, 'MM'), NEXT_DAY (trunc (sysdate + 30, 'MM'), "LUN")) FROM DUAL
  
  But he looks at complex bith.
  
  Abhishek
  
  Published by: 9999999 on 8 March 2013 04:30

  Use the IW format - it will make independent NLS solution. And all you need is truncated 7^th day of each month using IW:

  select  sysdate current_date,
          trunc(trunc(sysdate,'mm') + 6,'iw') first_monday_the_month
    from  dual
  /
  
  CURRENT_D FIRST_MON
  --------- ---------
  08-MAR-13 04-MAR-13
  
  SQL> 
  

  Here is the list of the first Monday of the month of this year:

  with t as(
            select  add_months(date '2013-1-1',level-1) dt
              from  dual
              connect by level <= 12
           )
  select  dt first_of_the_month,
          trunc(dt + 6,'iw') first_monday_the_month
    from  t
  /
  
  FIRST_OF_ FIRST_MON
  --------- ---------
  01-JAN-13 07-JAN-13
  01-FEB-13 04-FEB-13
  01-MAR-13 04-MAR-13
  01-APR-13 01-APR-13
  01-MAY-13 06-MAY-13
  01-JUN-13 03-JUN-13
  01-JUL-13 01-JUL-13
  01-AUG-13 05-AUG-13
  01-SEP-13 02-SEP-13
  01-OCT-13 07-OCT-13
  01-NOV-13 04-NOV-13
  
  FIRST_OF_ FIRST_MON
  --------- ---------
  01-DEC-13 02-DEC-13
  
  12 rows selected.
  
  SQL> 
  

  SY.

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  Hi all
  
  I am beginner in Java and JSP
  
  I'm JSP search form (VO) where I need to set a default value for the start_date - 7 days
  
  OK I get this display today date but how to get that displays a date-7 days?
  
  
  < %
  DateFormat df = new SimpleDateFormat ("JJ. MM.yyyy");
  Date date = new Date();
  String default = 'StartDate =' + df.format (new Date());
  % >
  
  ID
  Thank you

  Simple approach if you're not worried about leap years: -.

  Date todayMinus7 = new Date(System.currentTimeMillis() - 7 * 24 * 60 * 60 * 1000);
  

  Alternatively take a look at the GregorianCalendar class and the add() method.

• How to get the last date of 3 days for the current month?

  Hello. Guy

  How to get the last date of 3 days for the current month?

  MY OUTPUT WOULD LOOK LIKE THIS

  JANUARY 29, 2016

  JANUARY 30, 2016

  JANUARY 31, 2016

  
  

  GUYS HELP ME / / /...
  

  SQL > select last_day (sysdate) - level + 1 double connect by level<= 3="" order="" by="">

  LAST_DAY)

  ---------

  29 JANUARY 16

  30 JANUARY 16

  31 JANUARY 16

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