How to identify the last instance of a dynamic table row

Similar Questions

• How to view the last element in a dynamic table 1 d

  Hello..

  I want to display the value of the last element in a dynamic array 1 d... / I mean... If I stop the vi race, I need to display the last element of the array... How can I do this?

  and is it possible to use a button to start the vi... instead of using the Run button on the face before of the vi?

  An array of index!.  Size of table allows to determine the size of your array, subtract 1, that feed into the terminal array of Index index.

  You start the VI running somehow.  It can be assigned to run when opening.  Assuming that what you want is a way to type values in a front panel, press a GO button you created on the front panel, then have the real part of the VI to run.  You can use a structure of the event.  Or put a while loop at the beginning with a small wait next statement which basically just asks the GO button.  When you press this button, the Boolean value true stops the whole loop and allows the program to move on the main body of your program.

• How to select the last 20 transactions in a table

  Hi guys,.
  I have a table named INOUT with following columns
  
  EMPLOYEECODE VARCHAR2
  DATE OF THE RESPONDENT
  
  
  each day employees now their me 'in '. then entered came and came in this table. If we want to select the last 20 EMPLOYEECODE in this table that make their selves 'in '. How to choose that? just 20 last employees who traded. Help, please

  Hello

  This is called a Query Top - N , you want to choose elements of N (N = 20, in this case) from the top of a sorted list.
  Here's a way to do it:

  WITH     got_r_num     AS
  (
       SELECT       emloyeecode
       ,       MAX (intime)     AS latest_intime     -- If wanted
       ,       RANK () OVER (ORDER BY  MAX (intime)  DESC)
                      AS r_num
       FROM       inout
       GROUP BY  employeecode
  )
  SELECT     employeecode
  ,     latest_intime          -- If wanted
  ,     r_num               -- If wanted
  FROM     got_r_num
  WHERE     r_num     <= 20
  ;
  

  That actaully could take more than 20 people: If there be a tie, it includes any person who is entitled to be in the top 20. If you want exactly 20 people, then add the columns of tiebreaker to analytical or use ROW_NUMBER instead of RANK ORDER BY clause.

• How to select the last 3 records in a table?

  I have a table named HRM_ATTENDANCE
  as follows

  Name         Type         Nullable Default Comments 
  ------------ ------------ -------- ------- -------- 
  LEAVEDATE    DATE                                   
  EMPLOYEECODE VARCHAR2(8)                            
  LEAVETYPE    VARCHAR2(4)                            
  APPROVEDBY   VARCHAR2(8)  Y                         
  FEEDBY       VARCHAR2(8)  Y                         
  FEEDTIME     DATE         Y                         
  REMARKS      VARCHAR2(50) Y 

  the table contains the record of leave of employees as follows

  LEAVEDATE   EMPLOYEECODE LEAVETYPE APPROVEDBY FEEDBY   FEEDTIME    REMARKS
  ----------- ------------ --------- ---------- -------- ----------- --------------------------------------------------
  6/1/2013    00001        CL  
  6/3/2013    00001        EL                                         
  6/5/2013    00001        CPL    
  6/7/2013    00001        SL 
  6/9/2013    00001        CL                                        

  I want to select the last 3 leaves (records) to employeecode "00001" so I don't know the what are the dates of the leave. in easy words I want to choose the folder where leavedate > = 5 June 2013 ", but I don't know any dates."

  Select * from HRM_ATTENDANCE where rownum<=3 order="" by="" leavedate="">

• How to hide all instances of subform (via a click event of the button) except the last instance.

  When my form is rendered, it can contain multiple 'case' of a subform full page.  So basically, I have a subform labeled "Info" that spans a full page. Depending on how the form is used when a new instance is added to the document it essentially new creates an entire page.

  What I'm trying to hide all instances of subform ("Info"), except the LAST instance that is always on the last page.

  Theoretically, by hiding all previous subform instances (for example, 1-4) and keep only the last instance, it will reduce the number of pages 5-to-1.

  Hope it makes sense.

  SO I guess I need a way to get the number of instances of complete subform, then hide all instances, but the last instance (via a button click).

  Thanks in advance for your help.

  I belive I've thought about it.

• Check the last instance of a textfield is not null

  I have a repeating subform that includes a textfield for the user to enter his name. When the user clicks a button e-mail customized to send the form, I first want to check if the last instance of this field is filled (non-null). I don't care about previous instances only the last instance. Custom e-mail button is pushed down below each instance of the subform is always just below the last instance of the repeating subform. Is it possible to refer to the last instance of a field in the subform when I do not know how many instances are created?

  Thank you

  Hi DKinsley,

  I think that the code and the following steps will solve your problem.

  (1) in order to know the last instance, you must find the number of available instances. This can be achieved with the following code.

  var totalRowInstances = xfa.resolveNode ("form. Name.txtName").instanceManager.count;

  (2) to access the last value of the index,

  lastIndex var = totalRowInstances-1;

  [Since the index always starts with 0]

  var lastIndexNameCheck = xfa.resolveNode ("form. ("Name [" + lastIndex + '] '). txtName.rawValue;

  If (lastIndexNameCheck! = null)
  {
  do something
  }
  on the other
  {
  do something
  }

  Please Note: here, form - refers to the root node, name - refers to the subform, txtName - made reference in the name of a text field.

  Please let me know if this helped.

  Thank you
  VJ

• How can identify the real space in my SGPT123 Tablet?

  Hello

  How can identify the real space in my Xperia Tablet? I can see only 10.0 GB, if suppose has 16 GB, where's the rest?

  A space is medical, the Android operating system and recovery Partition.

• C: drive is running out of space, even if I moved everything I could to the E: drive. How to identify the "space Eater"?

  I moved all my data to the other disk. I was installing new programs on the other disk. Yet, the space on drive C: (37 GB) keeps becoming 'used '. Free space now is 2%. How to identify the "space Monster" which takes more and more the training?

  37GB is size sorry for C:.  My minimum recommendation for everything that came out at the time of and after Windows Vista is 60 GB.

  JDiskReport
  http://www.jgoodies.com/freeware/JDiskReport/index.html

• How iterate/identify the screens of the application stack

  Hi all

  1. work on the version of BB storm (9500/9530 Simulator) is v4.7.0.75
  2 opportunity BB JDE 4.7

  3. the request is:

  In my application I have screens showns one based on the click number, how can I display no matter which screen every time I required.i tell how fetch/identify the battery and display.

  Thanks in advance

  Ratna

  I donno what are your exact needs...

  If you want to load screens on selcting a menuitem from the GUI go to create menuItem.

  In the case depends on certain conditions of your application then just use

  try
    {
         UiApplication.getUiApplication().pushScreen(TestScreen);
    }
  
  catch(Exception e)
  {
  // PUSH screen fails because the screen was already pushed.
  // remove the screens from top of the required screen.
  while(UiApplication.getUiApplication().getActiveScreen() != TestScreen)
  
    {
       UiApplication.getUiApplication().popScreen();
    }
  }
  

• How to get the last date of 3 days for the current month?

  Hello. Guy

  How to get the last date of 3 days for the current month?

  MY OUTPUT WOULD LOOK LIKE THIS

  JANUARY 29, 2016

  JANUARY 30, 2016

  JANUARY 31, 2016

  
  

  GUYS HELP ME / / /...
  

  SQL > select last_day (sysdate) - level + 1 double connect by level<= 3="" order="" by="">

  LAST_DAY)

  ---------

  29 JANUARY 16

  30 JANUARY 16

  31 JANUARY 16

• How to identify the virtual copies (in my records) that have already been deleted a collection

  Hello!

  I keep looking for an answer to this anywhere on the web and 3 books, but can't find the answer...

  How to identify the virtual copies (in my records) that have already been deleted a collection?

  Here's the workflow, and where I'm stuck.

  1. I chose a picture and put it in a collection.

  2. I did a whole bunch of virtual photos in the collection copies that I tried different modifications.

  3. after and during a lot of changes, I have a lot of virtual copies removed from my collection because I decided against the changes after doing some comparisons.

  4. when I went the folders to select my next picture to work away and so to add to the collection, I discovered that each of my virtual copies was in the original folder, even if I had deleted from my collection.

  5. I really don't want these virtual copies deleted to be in my home folder.  They were virtual copies of trial and error and I wanted them to really just be thrown out.

  6. how to identify these virtual copies removed-from-the-collection in my folder?  File names all look the same, and besides, I want to be absolutely certain that I have selected the right ones.  Some of the changes were very minor and would be difficult to see without laboriously go through them one by one.

  Thank you very much!!

  Anne

  No easy answer on fixing the mess other than an individual inspection of the virtual copy can't watching the Images/Edit history to determine which ones that you no longer need.

  But to help prevent the problem in the future: when you are working from a collection, you must use ALT + return back to remove a copy of Photo or virtual catalog. With just the key DELETE or BACKSPACE only deletes the photo from the collection.

• How to take the last 7 digits of a varchar column

  How to take the last 7 digits of a varchar2 colum

  COL1

  12345678

  12345

  1234567890123

  1234567

  Out put should be as below

  COL1

  2345678

  12345

  7890123

  1234567

  everything built in function or in any other way please

  Hello

  assuming that the entry contains only numbers, as in the example, the addition of 7 spaces to the left and selecting the 7 last characters toured:

  with dataset as

  (select col1 from column_value

  table

  (dbmsoutput_linesarray

  ("12345678"

  '12345 '.

  '1234567890123'

  "1234567".

  )

  )

  )

  Select col1

  , substr (lpad (", 7,' ') | col1-7) col1_last7

  of the dataset

  /

  COL1 COL1_LAST7

  -------------------- --------------------

  12345678 2345678

  12345 12345

  1234567890123 7890123

  1234567 1234567

  Rob

• How long is the last free trial?

  How long is the last free trial before purchising?

  The free trial for 30 days.

  Concerning

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• How to get the last day of a month for every 2 months for a given period?

  Hello

  Can is it some please let me know how to get the last day, last day of the week, the weekend last day, last Monday, one month for every 2 months for a given period?

  Thanks in advance.

  Try the below

  SELECT LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))) lastday.

  BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'SAT '.

  SO LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))-1

  WHERE TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'Sun '.

  THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))-2

  Of OTHER LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  END as lastweekday,

  BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') IN ('Sam', 'SUN')

  THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  Of OTHER LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  -(TO_NUMBER (TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))),' from)) - 1).

  END as lastweekendday,

  BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'MY

  THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  Of OTHER NEXT_DAY (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), "LUN")-7

  END AS lastmonday

  FROM (SELECT SYSDATE startdate,

  SYSDATE + 300 enddate

  THE DOUBLE)

  CONNECT BY LEVEL<=>

• How to identify the iSCSI nodes?

  How to identify the iSCSI nodes?

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