How to make HTTP GET request socket?

I want to use socket make HTTP GET, but I always got the error 501 return.

Result:

501 method not implemented

Method not implemented

to / index.html unsupported.

Apache/2.0.52 (CentOS) Server at li43-231.members.linode.com Port 80

Code:

streamConnection =
(StreamConnection) Connector.Open (getURL (3) + APN_STR, Connector.READ_WRITE);

create DataOuputStream on the top of the socket connection
outputStream = streamConnection.openOutputStream ();
dataOutputStream = new DataOutputStream (outputStream);

Send the HTTP request
dataOutputStream.writeChars ("GET/index.html http/2.0\n");
dataOutputStream.writeChars ("host: badev.liveblockauctions.com\n");
dataOutputStream.writeChars("User-Agent:BlackBerry/3.2.1\n");
dataOutputStream.writeChars("Content-Language:en-US\n\n");

dataOutputStream.flush ();

create DataInputStream on top of the socket connection
inputStream = streamConnection.openInputStream ();
dataInputStream = new DataInputStream (inputStream);

retrieve the content of the requested server Web page
int inputChar;
int size = 0;
StringBuffer results = new StringBuffer();
While ((inputChar = dataInputStream.read ())! = - 1) {}
size ++;
Results.Append ((Char) inputChar);
}

JDE 4.6 and blackberry "BOLD".

Any suggestion?

Thank you very much!

Tags: BlackBerry Developers

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Thank you

There are many many posts similar to this on this forum.

Connectivity on the BlackBerry is not simple. You have to work at home. If you need to do research to figure out how to do it.

There are tutorials and videos on this site and many other forum posts for you to watch.

I suspect that this thread will give you a good taste as well as links to other locations for you to review:

http://supportforums.BlackBerry.com/T5/Java-development/connecting-your-BlackBerry-http-and-socket-c...

How to make http post in the Webcenter Portal Application?

Hi all

We have a requirement in which we must train to an external URL.

We have created a Taskflow bounded with page fragment. Added a button on the page fragment and had to form POST to an external URL the button click. Expected features, the URL of the external site will open in the same tab.

But we can not directly use html form tag in the page jspx because it cannot have two form elements.

Example code snippet that we use:

" < form id ="meetingPost"action =" http://XYZ/reg.aspx "

method = "POST" >

< input type = "hidden" name = "userId" value = "12345" / >

< / make >

We have tried to do this programmatically as below. But it does not work.

JSPX code:

<? XML version = "1.0" encoding = "UTF - 8"? >

" < = xmlns:jsp jsp:root ' http://Java.Sun.com/JSP/page "version ="2.1" "

xmlns:f=" http://Java.Sun.com/JSF/core "

xmlns:h=" http://Java.Sun.com/JSF/HTML "

' xmlns:af = ' http://xmlns.Oracle.com/ADF/faces/rich "> "

< jsp:directive.page contentType = text/html"; Charset = UTF - 8 "/ >

< f: view >

< af:document id = "d1" >

< af:form id = "f1" >

< af:region value = "#{bindings." TestTF1.regionModel}"id ="r1"/ >

< / af:form >

< / af:document >

< / f: view >

< / jsp:root >

JSFF code:

<? XML version = "1.0" encoding = "UTF - 8"? >

" < = xmlns:jsp jsp:root ' http://Java.Sun.com/JSP/page "version ="2.1" "

' xmlns:af = ' http://xmlns.Oracle.com/ADF/faces/rich "" "

xmlns:f=" http://Java.Sun.com/JSF/core ">

< af:resource type = "javascript" >

function postToURL (url) {}

var form = createElement ('form');

form.setAttribute ("method", "POST");

form.setAttribute ("action", url);

Form._submit_function = form.submit;

form.appendChild (document.createElement ("input", {type: "hidden", name: "userId", value: "12345"}));

document.body.appendChild (form);

Form._submit_function ();

}

< / af:resource >

< af:panelGroupLayout id = "pgl1" layout = "horizontal" >

< af:commandButton text = "Submit" id = "cb1".

actionListener = "#{pageFlowScope.SampleBean.postToCvent}" > < / af:commandButton >

< / af:panelGroupLayout >

< / jsp:root >

Managed Bean Code:

	{} public void postToCvent (ActionEvent actionEvent)
	FacesContext fctx = FacesContext.getCurrentInstance ();
	String url = " " http://XYZ/reg.aspx ";
	ExtendedRenderKitService service = Service.getRenderKitService (fctx, ExtendedRenderKitService.class);
	StringBuffer script = new StringBuffer();
	script. Append ("postToURL('");
	script. Append (URL);
	script. Append("')"); "
	service.addScript (fctx, script.toString ()); }

Thank you

Bharat

Abhijit salvation,

sendRedirect don't GET, POST.

in any case I solved the problem by substituting the attribute action for af:form using java script and adds input fields on the fly and able to reach the POST form to an external URL.

JavaScript (test.js file):

function postToCvent (event) {}

If (event! = null) {}

Get the source Customer attribute

var url = event.getSource () .getProperty ('url');

var userId = event.getSource () .getProperty ("userId");

Get the form by Id element, it will be af:form Id

var form = AdfPage.PAGE.findComponentByAbsoluteId ("mform");

If (form! = null) {}

formId var = form.getClientId ();

document.getElementById (formId) .setAttribute ("method", "POST");

document.getElementById (formId) .setAttribute ("action", url);

Create and add the input field to your

var hiddenField1 = document.createElement ("input");

hiddenField1.setAttribute ("type", "hidden");

hiddenField1.setAttribute ("name", "userId");

hiddenField1.setAttribute ("value", username);

document.getElementById (formId) .appendChild (hiddenField1);

SubmitForm

document.getElementById (formId) .submit ();

}