How to query a hierarchical structure (Director and employee)

Hi all
I use the Oracle 10 g R2 database.
Suppose I have this structure
EMP_ID               EMP_NAME          MANAGER_ID
1                    KING               
2                    STEVE               1
3                    FRANK               2
What I want, that is when I get any EMP_ID, I want to get all the Manager of his first and the last record is the employee in the leaf of the hierarchy in the query.

For example, when I ask EMP_ID = 2, I want to get this result
EMP_ID               EMP_NAME          MANAGER_ID
1                    KING               
2                    STEVE               1
and when I search EMP_ID = 3, I want to get this result:
EMP_ID               EMP_NAME          MANAGER_ID
1                    KING               
2                    STEVE               1
3                    FRANK               2
How to write this query? 
with xx as
(
select 1 eid, 'KING' emp_name, NULL mid from dual UNION ALL
select 2 eid, 'STEVE' emp_name, 1 mid from dual UNION ALL
select 3 eid, 'FRANK' emp_name, 2 mid from dual
)
select *
        from xx
    start with eid = 2
    connect by eid = PRIOR mid
order by eid;

Output:

1     KING
2     STEVE     1

With emp_id = 3

with xx as
(
select 1 eid, 'KING' emp_name, NULL mid from dual UNION ALL
select 2 eid, 'STEVE' emp_name, 1 mid from dual UNION ALL
select 3 eid, 'FRANK' emp_name, 2 mid from dual
)
select *
        from xx
    start with eid = 3
    connect by eid = PRIOR mid
order by eid;

Output:

1     KING
2     STEVE     1
3     FRANK     2

Tags: Database

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