How to show the Str() value in hexadecimal

Hello

I use the following command in a vi and would like to see a presentation of Hex.

"My number is" + str (number1 + number2)

The parameters Number1 and number2 are in hexadecimal, but the result of str is the decimal value.

Is there a way to force to be displayed in hexadecimal?

I tried str ((number1 + number2), "%$.13f"), but it did not work.  I always get a decimal value.

(I'm not really "understand the meaning of this formatting.  I saw somewhere and thought it might do the job)

Can someone give an explanation to this formatting?

Thank you

Rafi

The desired format is %x. The format specifiers are specified using LabVIEW.

Format specifier syntax

Elements of syntax format specifiers

Tags: NI Software

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