How to take the second row under the first line

Dear Sir

take my table like that name stock and times

STOCK Header 2 Header 3
A20301:3002:00
A20302:4003:00
A20303:0204:00
A20305:0006:00

the cry of output be like below

STOCK 1 2 3
A20300:4000:0201:00

1 column is

02:40 - 02:00

column 2 is

03:02-03:00

column 3 is

05:00 - 04:00

Kind regards

Hello

You can use the analytical function of LEAD (or GAL) to get the difference between hours.

For the results in the form of 3 columns in 1 line (rather than 1 column on 3 rows) calculates the LEAD in a subquery.  In the same auxiliary request, you can use the function ROW_NUMBER analytic number lines 1, 2 and 3.  The main query then use this value to rotate out of the subquery.

Depending on your data, your needs and your version of Oracle, it will be something like this:

WITH got_analytics AS

(

SELECT stock

LEAD (header_2) (PARTITION OF BOUILLON

ORDER BY header_2

) - header_3 AS time_diff

ROW_NUMBER () (PARTITION OF BROTH

ORDER BY header_2

) AS r_num

FROM my_table

)

SELECT *.

OF got_analytics

PIVOT (MIN (time_diff)

FOR r_num (1, 2, 3)

)

;

I hope that answers your question.

If this isn't the case, please post a small example data (CREATE TABLE and only relevant columns, INSERT statements) and also publish outcomes from these data.

Explain, using specific examples, how you get these results from these data.

Make sure that your sample data reflect important aspects of your actual data.  For example, in your actual data, you have probably different values in the column actions. Always say what version of Oracle you are using (for example, 11.2.0.2.0).

See the FAQ forum: https://forums.oracle.com/message/9362002#9362002

Tags: Database

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