How to truncate the value to the nearest integer

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• number rounded to the nearest integer in Excel

  Hello everyone.

  I use an entry in the file of worksheet to export my Excel (csv format) table, but it rounds the number to the nearest integer.

  

  How can I solve this problem?

  My VI is uploadet

  Thanks in advance

  Orlando

  
  

• How to truncate the output of the field in the column "LONG".

  Hi all

  I have been asked to retrieve all records from a table with a column that has been initially formatted with the format "LONG".

  How can I truncate the output of this area without having to show the Junk characters?

  Very appreciated

  JR

  Wrong forum!

  This forum is ONLY for questions/problems on Sql Developer and your question has NOTHING to do with this product.

  Please mark the thread ANSWERED and repost it in the SQL/PL/SQL forum.

  SQL and PL/SQL

  When you repost you must SHOW an example of what you are wanting to do. You should also explain what you mean by 'LONG Format' - I have never heard such a thing.

• How to truncate the query

  Hello

  with this sql:

  SELECT c.country_name, l.city
  FROM countries c, locations l
  

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• How to truncate the number

  Hi all,
  I hope if anyone knows a function to truncate the '+ 1' phone number. We have created a new custom field to the value in the phone field. The question we face is the new value, it will contain three new values (Plus 1 and a space) "+ 1".
  
  Can update us the default value expression while it:
  a. truncate "+ 1".
  b. remove all spaces in the phone number
  
  Thank you
  
  PS: I tried TRIM (CONNECTING '+ 1' < phPhone >). But I get an error!

  I would use a workflow (maybe two, depending on whether you need it to operate on events 'new' and 'Edit'). You can use a combination of the IIR, left, and Len to get what you need. For example:

  IIf (left (, 3) = "+ 1", on the right (, Len ()-3),)

  Chris

• How to find the nearest point to polyline

  Hello
  
  I find the point closest to my point of view standing on a polyline. I have Oracle Locator installed, but my data is not in a format locator. Is it possible to do using the functionality of the telecommunications service provider with, for example, the polyline and permanent values of coordinates of points in a space variable by calling some localization features?
  
  Or I must coordinate data in a spatial 'permit' table, create the spatial index, etc. and then call a procedure Locator.
  
  Tamas

  Luke,

  Thanks for the reference.

  When the data is converted, the Summit nearest to find an object of sdo_geometry could be done this way (of, of course, for the most part):

  select f.vertex_id,f.dist,f.min_dist,f.a_vertex
    from (select p.vertex_id,
                 sdo_geom.sdo_distance(p.the_point,p.a_vertex,0.005) as dist,
                 min(sdo_geom.sdo_distance(p.the_point,p.a_vertex,0.005)) over (order by sdo_geom.sdo_distance(p.the_point,p.a_vertex,0.005) asc) as min_dist,
                 p.the_point,
                 p.a_vertex
            from (select t.id as vertex_id,
                         mdsys.sdo_geometry(2001,NULL,mdsys.sdo_point_type(358615,5407047,null),null,null) as the_point,
                         mdsys.sdo_geometry(2001,NULL,mdsys.sdo_point_type(t.x,t.y,t.z),null,null) as a_vertex
                    from table(sdo_util.getVertices(
                              MDSYS.SDO_GEOMETRY(2002,null,null,MDSYS.SDO_ELEM_INFO_ARRAY(1,2,1),MDSYS.SDO_ORDINATE_ARRAY(362253.9,5409676.63,355608.12,5407615.16,358063.37,5407673.48,355276.53,5407361.08,360471.08,5408880.79,362483.4,5406024.69,362359.16,5408840.11,354570.21,5406219.18,360204.62,5405849.14,359214.51,5408283.5,358761.06,5406683.88,356739.05,5405590.46,358615.79,5407047.29,355978.02,5407326.33,356240.87,5409898.7,363159.35,5405510.46,358588.81,5406536.54,354822.42,5408643.75,357690.2,5408872.57,359839.29,5407253.86,355236.29,5409711.53,355342.54,5407448.87,360290.53,5405111.51,354677.02,5407916.83,361651.27,5409178.26,361730.18,5407553.5,357402.33,5409065.5,361546.51,5407278.41,361915.65,5408942.57,361974.74,5405464.91,357794.3,5406979.33,356106.58,5405481.32,357604.96,5407407.72,360718.31,5406765.8,359745.49,5406568.16,363005.29,5407557.46,355844.01,5407095.47,362749.66,5405041.82,359714.13,5408898.69,354509.69,5406113.6,360041.59,5406204.24,360380.17,5408751.21,356621.4,5409603.06,355156.27,5405401.98,354441.35,5409090.68,356376.45,5407472.81,363877.1,5405582.72,361883.83,5409696.17,356363.41,5406434.53,362078.96,5406617.37,362714.59,5409800.2,362703.49,5408513.33,358317.64,5408170.64,359294.27,5409197.53,360240.93,5406333.84))
                              )) t
                  ) p
          ) f
    where f.dist = f.min_dist;
  

  I hope this helps.

  Simon

• How to truncate the table using SQLJ

  Here is a snippet of code SQLJ trying to truncate a table before filling with new records.
  
  However, while the class compiles fine, I get an error PLS-00103 on execution.
  
  Your expertise is very welcome and necessary for what seems like a simple problem, for which I can't find an answer.
  
  import java. IO;
  import java.sql. *;
  
  public class FadsDirListing
  {
  public static getContentsList (String directory) Sub throws SQLException
  {
  *#sql {FADS_DIR_CONTENTS TRUNCATE TABLE}; * - WHY NOT THIS STATEMENT?
  File [] files = new File (directory) .listFiles ();
  for (int i = 0; (file! = null) & & (I < files.length); (++ I)
  {
  File f = files;
  String filName = f.getName ();
  long filSize = f.length ();
  ModDate timestamp = new Timestamp (f.lastModified ());
  String filType = f.isDirectory ()? "D" : "F";
  
  {INSERT #sql
  IN FADS_DIR_CONTENTS (FILE_SIZE, TYPE_DE_FICHIER, FILE_NAME, LAST_MODIFIED)
  VALUES (: filName,: filSize,: filType,: ModDate)
  };
  #sql {COMMIT
  };
  }
  }
  }
  
  Thank you for your help - I appreciate it very much.
  
  Dave

  You must run a command DDL by NDS. If you wrap it in a PL/SQL block and use NDS to run it, it should work.

  
  
  BEGIN
  
  EXECUTE IMMEDIATE "DDL STATEMENT";
  
  END;
  
  

• How to truncate the table in a pl/sql block

  Hello guys, I'm trying to truncate a table that includes data using a pl/sql block, so if the table has even a single row then the truncate should run. to do this, I wrote the following code
  
  
  declare
  number num.
  Start
  Select count (*) in the num from table_name;
  If num > 0 then
  truncate table table_name;
  end if;
  end;
  
  Now, when I execute the pl/sql block, I get the following error.
  
  PLS-00103: encountered the symbol "TABLE" when the expected in the following way:
  
  When I run the truncate without pl/sql command, it runs very well.
  
  Can someone please where I'm wrong.
  
  Thank you
  
  Published by: 969224 on April 23, 2013 08:08

  969224 wrote:
  Hello guys, I'm trying to truncate a table that includes data using a pl/sql block, so if the table has even a single row then the truncate should run. to do this, I wrote the following code

  declare
  number num.
  Start
  Select count (*) in the num from table_name;
  If num > 0 then
  truncate table table_name;
  end if;
  end;

  Now, when I execute the pl/sql block, I get the following error.

  PLS-00103: encountered the symbol "TABLE" when the expected in the following way:

  When I run the truncate without pl/sql command, it runs very well.

  Can someone please where I'm wrong.

  Thank you

  Published by: 969224 on April 23, 2013 08:08

  DDL is not allowed directly within PL/SQL procedures.

  You must (ab) use EXECUTE IMMEDIATE issuing the DDL

• How to truncate the first part of the ID

  My problem is the following.
  In my application, I create a new field. I want that this field corresponds to the number 6 of the SR N.
  How should I do?
  Sostantially if the SR N. 485218-305439087 it's my field must be 439087 (the last 6 number of N.SR).
  Thank you
  With regard to the Vale

  The expression of the new field should be left ([], 6)

  Cordially Catalina Valadez

• How Photoshop converts the RGB 16-bit values to 15-bit and 8-bit?

  Can someone please help me understand what rounding of diet or another algorithm is used when Photoshop reduced a 16-bit color 8-bit?

  For example, the two colors (was and B) are the colours of 16-bit swatch taken directly from a file of the ACO:

  A16 = (61603, 60948, 58982)

  B16 = (58326, 57015, 52428)

  Photoshop displays the values of "16-bit" (acutally 15 bits) as well:

  A15 = (30802, 30474, 29491)

  B15 = (29163, 28508, 26214)

  It seems that the 15-bit values are the result of the division by two and rounded to the nearest integer.

  With 8-bit, it's another story although:

  A8 = (240, 237, 229)

  B8 = (222, 227, 204)

  Now, if we divide the 16-bit value by 256, the following:

  A8_float = (240.6, 238,1, 230,4)

  B8_float = (227,8, 222,7, 204.8)

  It's a similar story during the allocation of the 15 by 128 bit values. No system rounding or truncation will get the same answers as Photoshop for 8 bit I see. What I can't work, it's how Photoshop calculates these figures. It's the division of integers, floating point division with rounding or truncation? I'm puzzled. Help, please.

  -> range 32768-65535: (32768 * x + 32767) / 65535

  Not quite dividing by 2, otherwise you miss the white point.

  32768-> 255 range: (255 * x + 16384) / 32768

  With the exception of dithering, it is all simple mathematics.

• How to get exact values.

  Hi Forum,

  I'm trying to get the page Width and Height of margin as a text in the slug area.

  When I have less pagewidh with pagemargin, I am getting the values in fractions like that.

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  When I draw a rectangle box to check the width and height, the spectacle of palette measures exactly like that... 177,44

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  var myTextFrame = myDocument.textFrames.add ();

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  var mWidth = parseFloat (myPageWidth - myX1 - myX2);

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  Thank you.

  Math.Round () always round to the nearest whole number (integer).  So suggestion of Jarek use Math.round in a particular way... it is not rounded mWidth directly - it is multiplying mWidth by 100, rounded to the nearest integer and then dividing by 100. This gives you exactly 2 decimal places of accuracy.  If you want 1 decimal place, use 10 instead of 100.  If you want 3 decimals, use 1000.

  Point number to a general routine to round off a float to an individual is the number of decimal places:

  rounding to a number of decimal places (tomaxxi)

  Number.prototype.doRound = {function (roundDec)}

  var roundMulit = Math.pow(10,roundDec);

  return Math.round(this*roundMulit) /roundMulit;

  };

  If you put the above code snippet at the beginning of your script, and then in the main part of your script you can just do this:

  mWidth = mWidth.doRound (3);

  If you want to round up more than 3 decimal places.

  As a general rule, you want to only do this in the user interface code, because there is a good chance that the will (in this case mWidth) number of rounding precision, not LOSE GAIN accuracy, when you round to a number of digits after the decimal point. (Explain exactly why this is true, it's a discussion more).

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  Hi NiCoder,

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