How to use order by with hierarchical query

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  I have a requirement as follows
  
  EMPID ENAME SAL JOB
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  SQL>  with e as (select 10 as empid, 'RAJ KAMAL' as ename, 'MANAGER' as job, 25000 as sal from dual union all
             select 20, 'KAMAL RAJ NAYAK', 'CLERK', 4000 from dual union all
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             select 50, 'ASHUTOSH IMKAL', 'DEVELOPER', 10000 from dual union all
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  ---
  ---
  select *
  from e
   where regexp_like(ename,'(^| )ka(.*)( |$)','i')
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       EMPID ENAME           JOB               SAL
  ---------- --------------- ---------- ----------
          10 RAJ KAMAL       MANAGER         25000
          20 KAMAL RAJ NAYAK CLERK            4000
  
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• Help with hierarchical query

  I'm trying to parse each string inside of individual characters. For this, I used the link by the hierarchical query clause. I am not able to use connect by correctly. Here is my example.

  with the CBC as)

  Select 1: the nurse, 'abc' double union all Str

  Select 2: the nurse, '123' Str of all union double

  Select 3: the nurse, "pqr xyz" dual union all Str

  Select option 4: the nurse, 'john doe' double Str

  )

  Select the level, homobasidiomycetes, substr(s.str,level,1) as chr

  s of the CBC

  connect nocycle level < = length (homobasidiomycetes)

  /

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  with the CBC as)

  Select 1: the nurse, 'abc' double union all Str

  Select 2: the nurse, '123' Str of all union double

  Select 3: the nurse, "pqr xyz" dual union all Str

  Select option 4: the nurse, 'john doe' double Str

  )

  Select distinct level, homobasidiomycetes, substr(s.str,level,1) as chr

  s of the CBC

  connect nocycle level < = length (homobasidiomycetes)

  order by str, level

  /

  For a large data set I could end up with several million rows before the separate would lead. So, how can I restrict the connection by clause to go within each line.

  Assuming that the AI is the primary key, you could do this:

  with src as (
    select 1 as rn, 'abc' as str from dual union all
    select 2 as rn, '123' as str from dual union all
    select 3 as rn, 'pqr xyz' as str from dual union all
    select 4 as rn, 'john doe' as str from dual
  )
  select level,
        s.str,
        substr(s.str,level,1) as chr
  from src s
  connect by level <= length(s.str)
            and prior rn = rn
            and prior dbms_random.value is not null;
  

  See DBMS_RANDOM.value in a hierarchical solution for string to table? for an exchange of views around the case.

• Hierarchical data, how to aggregate over levels in hierarchical query?

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  I hope someone can help me.
  
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  What version of Oracle you are on?

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  with t (id, parent_id, build_in, build_out) as (
  select 1, null, null, null from dual union all
  select 2, 1, 2010, 2012 from dual union all
  select 3, 2, 2011, 2013 from dual union all
  select 4, 2, 2013, null from dual
  )
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  from t
  where parent_id is null
  union all
  select root_id, t.id, t.parent_id
  , greatest(nvl(t.build_in,0), nvl(b.build_in,0))
  , least(nvl(t.build_out,9999), nvl(b.build_out,9999))
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  1       3     2          2011      2012      
  

  With a hierarchical query by using the syntax connection, you could do something like

  select * from (
  select connect_by_root id as root, id
  , greatest(nvl(build_in,0), nvl(prior build_in,0)) as max_in, least(nvl(build_out,9999), nvl(prior build_out,9999)) as min_out
  from t
  start with parent_id is null
  connect by parent_id = prior id
  )
  where max_in < min_out
  ;
  

  but it is not powerful enough. This version compares the dates between a current and previous levels, but the recursive subquery is to compare the dates in the current level for the winners of the comparisons to the previous level. Not sure if it's an important distinction for your needs, however.

  If you are on 11.2 I advise to use the recursive subquery factoring. If this isn't the case, you can try the link by version.

  Kind regards
  Bob

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