How to view a report according to another region, the elements are filled.

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  < empty >

  < project >

  < empty >

  < Estimated effort >.

  < Estimated effort >

  < Job description >

  < empty >

  < project >

  < empty >

  < Estimated effort >

  < Estimated effort >

  < Job description >

  < empty >

  < project >

  < empty >

  < Estimated effort >

  < Estimated effort >

  < Job description >

  < empty >

  < project >

  < empty >

  < Estimated effort >

  < Estimated effort >

  Is it possible to create this type of report?

  Syed

  MikeKutz wrote:

  Use TO_CHAR() to 'calculate' the day of the week.  Then, use this value.

  1. WITH e
  2. (
  3. SELECT consultant, client, project
  4. the task, effort
  5. TO_CHAR(date_,'Day') day_of_week
  6. billable
  7. OF trial_3_details
  8. -WHERE date_ between ____ and ____
  9. )
  10. SELECT *.
  11. E
  12. PIVOT (sum (effort)
  13. FOR that day_of_week IN ('Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday')
  14. )

  Note that you actually need to use 'fmDay' as the mask of format of date with this approach. Using of 'Day' will result in all the day_of_week values be padded with blanks to the length of the longest value (Wednesday), then this will be the only match value in the pivot:

  SQL> with t as (
    2    select
    3        to_char(trunc(sysdate) + (level - 1), 'Day') d
    4      , round(dbms_random.value(0, 100), 2) z
    5    from
    6        dual
    7          connect by level <= 10)
    8  select
    9      *
  10  from
  11      t
  12  pivot (
  13      sum(z)
  14      for d in ('Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday'));
  
    'Monday'  'Tuesday' 'Wednesday' 'Thursday'  'Friday' 'Saturday'  'Sunday'
  ---------- ---------- ----------- ---------- ---------- ---------- ----------
                              83.23
  

  Using "fmDay" avoids filling and the pivot works according to the needs:

  SQL> with t as (
    2    select
    3        to_char(trunc(sysdate) + (level - 1), 'fmDay') d
    4      , round(dbms_random.value(0, 100), 2) z
    5    from
    6        dual
    7          connect by level <= 10)
    8  select
    9      *
  10  from
  11      t
  12  pivot (
  13      sum(z)
  14      for d in ('Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday'));
  
    'Monday'  'Tuesday' 'Wednesday' 'Thursday'  'Friday' 'Saturday'  'Sunday'
  ---------- ---------- ----------- ---------- ---------- ---------- ----------
      60.16    125.09      44.17      77.5      3.63      82.89      26.22
  

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