How to write a query for the following scenario
Hi I have a table as follows which have values of column as belowcolumn1 column2 column3 column4 column5 column6 column7 column8
10000 10 1 7 15 10 9 0
10001 11 2 7 19 0 8 1
10002 12 3 9 8 7 15 0Here, in case I get a first and third ranks.
(Column1, Column2, Column3) is the primary key for the table
Help, please
Hena
with data as
(
select 10000 as column1, 10 as column2, 1 as column3, 7 as column4, 15 as column5, 10 as column6, 9 as column7, 0 as column8 from dual union all
select 10001, 11, 2, 7, 19, 0, 8, 1 from dual union all
select 10002, 12, 3, 9, 8, 7, 15, 0 from dual
)
select * from data
where 7 in (column4, column5, column6, column7, column8)
and 15 in (column4, column5, column6, column7, column8)
/
COLUMN1 COLUMN2 COLUMN3 COLUMN4 COLUMN5 COLUMN6 COLUMN7 COLUMN8
---------------------- ---------------------- ---------------------- ---------------------- ---------------------- ---------------------- ---------------------- ----------------------
10000 10 1 7 15 10 9 0
10002 12 3 9 8 7 15 0
Edited because requirement changed while displaying the solution
Published by: Cyn on October 30, 2009 15:27
Tags: Database
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Seems pretty good, higher settings are well "propagated" down with the LAST_VALUE function. But, I don't understand why the use of FIRST_VALUE and oppposite command does not give the same result. A little more play with the last query to get the final result of a given unit code:SQL> WITH hierarchy 2 AS 3 ( 4 SELECT ou.unit_code, 5 LEVEL AS lvl 6 FROM organization_unit ou 7 START WITH 8 ou.unit_code = '20-01' 9 CONNECT BY 10 ou.unit_code = PRIOR ou.parent_unit_code 11 ) 12 SELECT h.*, 13 p.param1 AS param1_raw, 14 LAST_VALUE (p.param1 IGNORE NULLS) OVER (ORDER BY h.lvl DESC) AS param1_with_last, 15 FIRST_VALUE(p.param1 IGNORE NULLS) OVER (ORDER BY h.lvl ASC) AS param1_with_first, 16 p.param2 AS param2_raw, 17 LAST_VALUE (p.param2 IGNORE NULLS) OVER (ORDER BY h.lvl DESC) AS param2_with_last, 18 FIRST_VALUE(p.param2 IGNORE NULLS) OVER (ORDER BY h.lvl ASC) AS param2_with_first, 19 p.param3 AS param3_raw, 20 LAST_VALUE (p.param3 IGNORE NULLS) OVER (ORDER BY h.lvl DESC) AS param3_with_last, 21 FIRST_VALUE(p.param3 IGNORE NULLS) OVER (ORDER BY h.lvl ASC) AS param3_with_first, 22 p.param4 AS param4_raw, 23 LAST_VALUE (p.param4 IGNORE NULLS) OVER (ORDER BY h.lvl DESC) AS param4_with_last, 24 FIRST_VALUE(p.param4 IGNORE NULLS) OVER (ORDER BY h.lvl ASC) AS param4_with_first 25 FROM hierarchy h 26 LEFT JOIN org_unit_parameters p 27 ON h.unit_code = p.unit_code 28 ORDER BY h.lvl DESC; UNIT_CODE LVL PARAM1_RAW PARAM1_WITH_LAST PARAM1_WITH_FIRST PARAM2_RAW PARAM2_WITH_LAST PARAM2_WITH_FIRST PARAM3_RAW PARAM3_WITH_LAST PARAM3_WITH_FIRST PARAM4_RAW PARAM4_WITH_LAST PARAM4_WITH_FIRST ---------- ---- -------------------- -------------------- -------------------- -------------------- -------------------- -------------------- -------------------- -------------------- -------------------- -------------------- -------------------- -------------------- 00000 3 Default value Default value Value from 20 Default value Default value Value from 20-01 Default value Default value Value from 20 {null} {null} {null} 20 2 Value from 20 Value from 20 Value from 20 Value from 20 Value from 20 Value from 20-01 Value from 20 Value from 20 Value from 20 {null} {null} {null} 20-01 1 {null} Value from 20 {null} Value from 20-01 Value from 20-01 Value from 20-01 {null} Value from 20 {null} {null} {null} {null}
Works well!SQL> SELECT * 2 FROM 3 ( 4 WITH hierarchy 5 AS 6 ( 7 SELECT ou.unit_code, 8 LEVEL AS lvl 9 FROM organization_unit ou 10 START WITH 11 ou.unit_code = '20-01' 12 CONNECT BY 13 ou.unit_code = PRIOR ou.parent_unit_code 14 ) 15 SELECT h.*, 16 LAST_VALUE (p.param1 IGNORE NULLS) OVER (ORDER BY h.lvl DESC) AS param1, 17 LAST_VALUE (p.param2 IGNORE NULLS) OVER (ORDER BY h.lvl DESC) AS param2, 18 LAST_VALUE (p.param3 IGNORE NULLS) OVER (ORDER BY h.lvl DESC) AS param3, 19 LAST_VALUE (p.param4 IGNORE NULLS) OVER (ORDER BY h.lvl DESC) AS param4 20 FROM hierarchy h 21 LEFT JOIN org_unit_parameters p 22 ON h.unit_code = p.unit_code 23 ORDER BY h.lvl 24 ) 25 WHERE ROWNUM = 1; UNIT_CODE LVL PARAM1 PARAM2 PARAM3 PARAM4 ---------- ---- -------------------- -------------------- -------------------- -------------------- 20-01 1 Value from 20 Value from 20-01 Value from 20 {null}
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For the purposes of reproducibility, here is the code to create the structure and data:
Here is the format of my paintings and a few samble data:CREATE TABLE organization_unit ( unit_code VARCHAR2(5 CHAR) NOT NULL PRIMARY KEY, unit_name VARCHAR2(100 CHAR) NOT NULL, parent_unit_code VARCHAR2(5 CHAR) ); CREATE TABLE org_unit_parameters ( unit_code VARCHAR2(5 CHAR) NOT NULL PRIMARY KEY, param1 VARCHAR2(100 CHAR), param2 VARCHAR2(100 CHAR), param3 VARCHAR2(100 CHAR), param4 VARCHAR2(100 CHAR) ); -- Inserting data INSERT INTO organization_unit (unit_code, unit_name, parent_unit_code) VALUES ('00000', 'Top level', NULL); INSERT INTO organization_unit (unit_code, unit_name, parent_unit_code) VALUES ('10', 'L2 unit #10', '00000'); INSERT INTO organization_unit (unit_code, unit_name, parent_unit_code) VALUES ('10-01', 'L3 unit #10-01', '10'); INSERT INTO organization_unit (unit_code, unit_name, parent_unit_code) VALUES ('10-02', 'L3 unit #10-02', '10'); INSERT INTO organization_unit (unit_code, unit_name, parent_unit_code) VALUES ('20', 'L2 unit #20', '00000'); INSERT INTO organization_unit (unit_code, unit_name, parent_unit_code) VALUES ('20-01', 'L3 unit #20-01', '20'); INSERT INTO organization_unit (unit_code, unit_name, parent_unit_code) VALUES ('20-02', 'L3 unit #20-02', '20'); INSERT INTO ORG_UNIT_PARAMETERS (unit_code, param1, param2, param3) VALUES ('00000', 'Default value', 'Default value', 'Default value'); INSERT INTO ORG_UNIT_PARAMETERS (unit_code, param2, param3) VALUES ('10', 'Value from 10', 'Value from 10'); INSERT INTO ORG_UNIT_PARAMETERS (unit_code, param3) VALUES ('10-01', 'Value from 10-01'); INSERT INTO ORG_UNIT_PARAMETERS (unit_code, param4) VALUES ('10-02', 'Value from 10-02'); INSERT INTO ORG_UNIT_PARAMETERS (unit_code, param1, param2, param3) VALUES ('20', 'Value from 20', 'Value from 20', 'Value from 20'); INSERT INTO ORG_UNIT_PARAMETERS (unit_code, param2) VALUES ('20-01', 'Value from 20-01'); INSERT INTO ORG_UNIT_PARAMETERS (unit_code, param2) VALUES ('20-02', 'Value from 20-02'); COMMIT;Hi, Bruno.
You almost had it!
Take your query that gets good results for a single node. Remove the START WITH clause so that it does the same thing for each node. You will need to add CONNECT_BY_ROOT to remember what node you started with in each case and PARTITION BY calling value in all the LAST_VALUE function:WITH hierarchy AS ( SELECT ou.unit_code AS ancestor_unit_code, LEVEL AS lvl, CONNECT_BY_ROOT ou.unit_code AS descendant_unit_code FROM organization_unit ou CONNECT BY ou.unit_code = PRIOR ou.parent_unit_code ) , got_params AS ( SELECT h.descendant_unit_code AS unit_code , h.lvl , LAST_VALUE (p.param1 IGNORE NULLS) OVER ( PARTITION BY h.descendant_unit_code ORDER BY lvl DESC ) AS param1 , LAST_VALUE (p.param2 IGNORE NULLS) OVER ( PARTITION BY h.descendant_unit_code ORDER BY lvl DESC ) AS param2 , LAST_VALUE (p.param3 IGNORE NULLS) OVER ( PARTITION BY h.descendant_unit_code ORDER BY lvl DESC ) AS param3 , LAST_VALUE (p.param4 IGNORE NULLS) OVER ( PARTITION BY h.descendant_unit_code ORDER BY lvl DESC ) AS param4 FROM hierarchy h LEFT OUTER JOIN org_unit_parameters p ON h.ancestor_unit_code = p.unit_code ) SELECT unit_code, param1, param2, param3, param4 FROM got_params WHERE lvl = 1 ;Output:
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Thanks for posting the CREATE TABLE and INSERT statements; It is very useful.
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My laptop is a HP Pavilion n210se. Technical support/manual/drivers on its product page link is broken.
Cannot find the model in the support/drivers of hp's global site download section.
How can I get the card reader to work? (assuming that the unknown device is a card reader)
Hello
Please find the select network given below link and download the driver.
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How can I contact Sandisk for the support of my device warranty refurbishing Fuze e280?
How can I contact Sandisk for the support of my device warranty refurbishing Fuze e280? It came without a manual or an other such info...
I called SanDisk to 866-726-3475. They gave me a case # and took me through the steps to retrieve and format the e280. They did not go to any purchase information. After following the instructions, the e280 worked like new.
Thank you
E C Yarter
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