How to write an outer join

Similar Questions

• How to specify an outer join in the query designer

  I quickly built a large query with the query designer, and it works very well, but does not produce 9 disks on 2200 - so I need to change to an outer join.
  
  My problem is that I can't find a way to specify an outer join. I tried to change the query, query builder formed, but it won't let me.
  
  I know that I can capture the query, edit and run it in sql developer and that works fine, but I want to use the Query Builder as it is the fastest way I know to quickly add and remove items - my users don't know exactly what that it to include.
  
  I know it's kind of a trivial question, but I searched the forum, manual, the web and no luck
  
  Thanks for any help you can give
  
  Glenn

  Hi Glenn,.

  When you use the query designer to create the sql statement, you must click on the empty box to the right of the fields in each table to create the join. When you are finished, you should see a line drawn between the two tables. Click on this line, and a small window appears allowing you to select inner outer or right outer joins, left.

  When the report was created, however, you must change the statement. For example, if you use the query designer to join DEPT at EMP based on the DEPTNO field on the two tables, you get:

  select      "DEPT"."DEPTNO" as "DEPTNO",
        "DEPT"."DNAME" as "DNAME",
        "DEPT"."LOC" as "LOC",
        "EMP"."EMPNO" as "EMPNO",
        "EMP"."ENAME" as "ENAME",
        "EMP"."JOB" as "JOB",
        "EMP"."MGR" as "MGR",
        "EMP"."HIREDATE" as "HIREDATE"
   from      "EMP" "EMP",
        "DEPT" "DEPT"
   where   "DEPT"."DEPTNO"="EMP"."DEPTNO"
  

  This is to change:

  select      "DEPT"."DEPTNO" as "DEPTNO",
        "DEPT"."DNAME" as "DNAME",
        "DEPT"."LOC" as "LOC",
        "EMP"."EMPNO" as "EMPNO",
        "EMP"."ENAME" as "ENAME",
        "EMP"."JOB" as "JOB",
        "EMP"."MGR" as "MGR",
        "EMP"."HIREDATE" as "HIREDATE"
   from      "EMP" "EMP"
        LEFT OUTER JOIN "DEPT" "DEPT" ON "DEPT"."DEPTNO"="EMP"."DEPTNO"
  

  Andy

• use an outer join in RowMatch

  Hello world

  I have an Obj from view to both entities like this:

  SELECT t1.rowno, t2.type

  OF table_ t1, t2 from table_2

  WHERE t1.rowno (+) = t2.rowno

  and t1.userId (+) =: bindVar

  table_1 (Rowno, UserID)

  table_2 (Rowno, type)

  I have a table on this view of Obj on my page, when I add a new line of this view Obj, this line showed in the table while he should not appear (depending on where the view clause Obj).

  according to this post https://forums.oracle.com/thread/2576480 I can use RowMatch, but here I don't know how to use an outer join in RowMatch.

  
  

  Habib
  

  
  

  Post edited by: Habib.Eslami

  I guess that joy cannot use matching line in this case as it only lines matching already in memory, but without an outer join. This must be done before.

  What you can try is to build the sql criteria yourself and add it to the query.  An example on how to do this at http://wp.me/pcBZk-5O

  The example shows how to add a sql custom as a criterion.

  Timo

• Outer join without outer join

  I'm trying to do is to learn how to do an outer join without specifying the outer join complete, right or left. Why? For most of the reasons for performance and gain a better understanding of the Oracle.
  Thank you
  
  Charles.

  Another option would be a scalar subquery in the select part, as:

  SQL> select * from t;
  
          ID DESCR
  ---------- ----------
           1 T One
           2 T Two
           3 T Three
  
  SQL> select * from t1;
  
          ID DESCR
  ---------- ----------
           1 T1 One
           2 T1 Two
  
  SQL> select t.*, t1.descr t1_descr
    2  from t
    3     left join t1
    4        on t.id = t1.id;
  
          ID DESCR      T1_DESCR
  ---------- ---------- ----------
           1 T One      T1 One
           2 T Two      T1 Two
           3 T Three
  
  SQL> select t.*, (select t1.descr
    2               from t1
    3               where t.id = t1.id) t1_descr
    4  from t;
  
          ID DESCR      T1_DESCR
  ---------- ---------- ----------
           1 T One      T1 One
           2 T Two      T1 Two
           3 T Three
  

  This can be faster if the correlated T1 column is indexed, and there is a "large" number of records in t which do not correspond with t1.

  John

• How to write a join

  I use an access database. I have a strat_data_call table that has the fields rec_no, agency, due_dt name and a table named ccd_data_call with the strat_rec_no, user_id fields. When an action takes place in a particular record in the strat_data_call an account of this action is inserted in the table ccd_data_call with the rec_no field inserted in the strat_rec_no field and the cookie.user_id is insertered in the user_id.
  
  I need list all records in the strat_data_call table that have no matching records that have been placed in the ccd_data_call table by the user who is signed on (cookie.user_id). The rec_no can be in the table ccd_data_call numerious times but cannot be there once for any particular user.
  
  How I'd write sql to display this. I tried several different joints, but none works.
  Thank you
  

  MKT,

  Try:

  Select *.
  Of s strat_data_call
  Left Outer Join ccd_data_call c
  On s.rec_no = c.strat_rec_no
  Where c.user_id is Null

  SWIFT

• full outer join: how to get without null values?

  full outer join: how to get without null values?

  Hello

  Please go well this url

  http://asktom.Oracle.com/pls/asktom/f?p=100:11:999478429860455:P11_QUESTION_ID:6585774577187

  Thank you
  Prakash P

• How to convert the Null value to 0 after the outer join?

  Hello guys
  
  My requirement is in fact 2 of outer join tables (that's how), and I got the outer join works very well, so in my report, I have values null of measures in another table of facts as a result of the outer join...
  
  Is there a way I can convert these nulls to 0?
  
  I realized that the null value is not stored in the table, it is just following the outer join because the NULL do not match records in other... So by default, I'm expected to get NULL values...
  
  Is there way to present these nulls to 0?
  
  Thanks a lot for your advice

  In response, the syntax will be:

  IFNULL (, 0)

  try and let us know how you go.
  See you soon
  Alastair

• How to manage the update/insert in display with Outer Join object?

  Hello

  I have a problem in the treatment of update/insert in the original Version that contains two EOs with right outer join. The first EO values are inserted before and I want if second values EO already exists, it will update and if not a new record created.

  Error when I commit after entering values is: ' entity line with null key is not found in SecondEO. "

  What is the solution?

  Thank you
  

  Hello

  Make sure that your view object, you have included the key attributes of the two entity objects.

  Kind regards

  Saif Khan.

• How do the query select outer join to a report of the APEX

  Hi all
  
  I'm Ann.
  
  I have a select statement that is used to calculate statistics for a month (October 2012 in this example)
  Select ph.phase_number
  sum ((case
  WHEN ph.date_finished IS NULL or ph.date_finished > last_day (TO_DATE (' ' Oct 2012 ', ' MY YYYY' "))
  THEN last_day (TO_DATE (' ' Oct 2012 ', ' MY YYYY' "))
  Of OTHER ph.date_finished
  END)
  (-ph.date_started + 1) / count (def.def_id) as avg_days
  Ph phase_membership
  inner join court_engagement this on ph.mpm_eng_id = ce.engagement_id
  join in-house defendant def on ce.defendant_id = def.def_id
  where def.active = 1
  and ph.date_started < = last_day (TO_DATE (' ' Oct 2012 ', ' MY YYYY' "))
  and ph.active = 1
  and UPPER (ce.court_name) LIKE '% '.
  Rollup Group (phase_number)
  ;
  
  The result is as below
  Phase_Number AVG_DAYS
  Phase One 8.6666666666666667
  Phase two 14.6
  Phase three 12
  11.4615365
  
  I have another list of selection mainly the list of months between two date value.
  Select to_char (which_month, 'LUN YYYY') as display_month
  de)
  Select add_months (to_date (' ' August 2012 ', ' MY YYYY' "), rownum-1) which_month
  of object
  where
  rownum < = months_between (to_date (' ' Oct 2012 ', ' MY YYYY' "), add_months (to_date (' ' August 2012", "MY YYYY"), - 1))
  order of which_month)
  
  The query result is as below
  
  DISPLAY_MONTH
  
  AUGUST 2012
  SEP 2012
  OCT 2012
  
  Is it possible I can join these two select statement above to generate a comparable result:
  
  Days of month Phase number Avg
  August 2012 Phase One 8.666
  Sep 2012 Phase One 7.66
  Oct 2012 Phase One 5,66
  August 2012 Phase two 8.666
  Sep 2012 Phase two 7.66
  Oct 2012 Phase two 5,66
  August 2012 Phase three 8.666
  Sep 2012 Phase three 7.66
  Oct 2012 Phase three 5,66
  
  Or
  Days of month Phase number Avg
  August 2012 Phase One 8.666
  August 2012 Phase two 7.66
  August 2012 Phase three 5,66
  Sep 2012 Phase One 8.666
  Sep 2012 Phase two 7.66
  Sep 2012 Phase three 5,66
  Oct 2012 Phase One 8.666
  Oct 2012 Phase two 7.66
  Oct 2012 Phase three 5,66
  
  And it can be controlled by Phase number or month.
  My other colleague suggested I should use a left outer join, but after having tried many ways, I'm still stuck.
  
  I tried select is
  Select a.display_month, b.* in)
  Select to_char (which_month, 'LUN YYYY') as display_month
  de)
  Select add_months (to_date (' ' August 2012 ', ' MY YYYY' "), rownum-1) which_month
  of object
  where
  rownum < = months_between (to_date (' ' Oct 2012 ', ' MY YYYY' "), add_months (to_date (' ' August 2012", "MY YYYY"), - 1))
  order which_month)) a left outer join
  
  (Select to_char (ph.date_finished, 'MY YYYY') as join_month, ph.phase_number)
  sum ((case
  WHEN ph.date_finished IS NULL or ph.date_finished > last_day (TO_DATE (a.display_month, 'MY YYYY'))
  THEN last_day (TO_DATE (a.display_month, 'MY YYYY'))
  Of OTHER ph.date_finished
  END)
  (-ph.date_started + 1) / count (def.def_id) as avg_days
  Ph phase_membership
  inner join court_engagement this on ph.mpm_eng_id = ce.engagement_id
  join in-house defendant def on ce.defendant_id = def.def_id
  where def.active = 1
  and ph.date_started < = last_day (TO_DATE (a.display_month, 'MY YYYY'))
  and ph.active = 1
  and UPPER (ce.court_name) LIKE '% '.
  To_char (ph.date_finished, 'MY YYYY'), group (phase_number) rollup) b
  On a.display_month = b.join_month
  
  but then I get an error
  SQL error: ORA-00904: "A." "" DISPLAY_MONTH ": invalid identifier
  
  I need to view a report on the APEX with option for people to download at least format CSV.
  Already 1 inteactive report in the page, so I don't think adds another interactive report without using the iframe trick.
  
  If any of you have any ideas, please help.
  
  Thank you very much.
  
  Ann

  Hello Ann,.

  Frank has done a very good job. I am also impressed.

  Is in regard to your correction to his question, the problem is on this replacement you did

  last_day(TO_DATE(am.which_month,'MON YYYY'))
  

  AM.which_month is already a date type, and you don't need to convert it to this day.
  Here is the correct way:

  last_day(am.which_month)
  

  There are also sometimes with the data you've posted have no line for this month. So I also added a function NVL to display 0 under avg_days for these cases.

  Here is my corrected query:

  DEFINE startmonth = "Aug 2012";
  DEFINE endmonth   = "Oct 2012";
  WITH  all_months  AS
  (
     SELECT ADD_MONTHS(to_date('&startmonth','MON YYYY'), ROWNUM-1) AS which_month
     ,      ADD_MONTHS(to_date('&startmonth','MON YYYY'), ROWNUM  ) AS next_month
     from all_objects
     where
     rownum <= months_between(to_date('&endmonth','MON YYYY'), add_months(to_date('&startmonth','MON YYYY'), -1))
  )
  SELECT TO_CHAR (am.which_month, 'Mon YYYY')  AS month
       , ph.phase_number
       , NVL(sum ( (CASE
                   WHEN ph.date_finished IS NULL OR ph.date_finished > last_day(am.which_month)
                   THEN last_day(am.which_month)
                   ELSE ph.date_finished
                END
               ) - ph.date_started + 1
             ) / count(def.def_id), 0) as avg_days
    FROM all_months am
         LEFT OUTER JOIN  a_phase_membership  ph  PARTITION BY (ph.phase_number)
            ON  am.which_month <= ph.date_started
            AND am.next_month  >  ph.date_started
            AND ph.date_started <= last_day(am.which_month)  -- May not be needed
            AND ph.active = 1
         LEFT OUTER JOIN  a_engagement  ce
            ON  ph.mpm_eng_id = ce.engagement_id
            AND ce.court_name IS NOT NULL  -- or something involving LIKE
         LEFT OUTER join  a_defendant     def
            ON  ce.defendant_id = def.def_id
            AND def.active = 1
   GROUP BY ROLLUP(phase_number, am.which_month)
   ORDER BY  am.which_month
          ,  ph.phase_number
  ;
  
  The output is:
  MONTH    PHASE_NUMBER           AVG_DAYS
  -------- -------------------- ----------
  Aug 2012 PHASE ONE                     0
  Aug 2012 PHASE THREE                   0
  Aug 2012 PHASE TWO                     0
  Sep 2012 PHASE ONE                    12
  Sep 2012 PHASE THREE                   1
  Sep 2012 PHASE TWO                     9
  Oct 2012 PHASE ONE                     8
  Oct 2012 PHASE THREE                   0
  Oct 2012 PHASE TWO                    14
           PHASE ONE                    11
           PHASE THREE                   1
           PHASE TWO                  11.5
                                9.71428571
  

  I don't know if that's really what you want. In the case check it and let me know.

  Kind regards.
  Al

• How create/update files when the original Version is based on a query of outer join?

  Hi gurus,
  
  
  I created a custom page where I use a table-style area where I question my VO records, based on a query of outer join. This query contains my table looks, where I would like to insert/update records, and joined the table of standard elements, which is external with my custom table.
  
  When I now question my files in the t, I have a record for each record in the table section, which is ok, but when I 'Refresh' some fields of my custom table and attempt to commit, I get the message "unable to complete the transaction on record. Cause: The record has been deleted by another user. "Action: cancel the transaction and re - query records to get new data.
  The reason why because a record is to be inserted rather than updating because in fact there is not yet in my custom table.
  
  The reason why I'm using the outer join, is because I don't want the user to create a record for each item one by one.
  There is no work around for this?
  
  Thanks in advance!
  
  
  BR
  Guy

  Hello
  You can try this.

  In your EntityImpl.java to extend OAPlsqlEntityImpl.

  Override the updateRow() method and coding your insert statement to insert into a table custom here.
  Don't forget, you must ignore the lines for which your custom table columns are null

  -Idris

• confusion of outer join

  Hello
  
  Can someone tell me please the difference between these two motions.
  
  Select *.
  from T1, T2
  where T1. C1 = T2. C1 (+)
  and T1. C2 = 'Y ';
  
  Select *.
  from T1, T2
  where T1. C1 = T2. C1 (+)
  and T1. C2(+) = « Y » ;
  
  I'm just confused why add an outer join in case of checking the values of constant?
  
  I know that the concept of outer join is make no corresponding data on the part of the table. But when external associate a constant value which corresponds to the average?
  
  Please specify.
  
  And one more thing... If I want to check two values, how can I write the query below correctly?
  
  Select *.
  from T1, T2
  where T1. C1 = T2. C1 (+)
  and T1. C2 (+) ('y', 'NA');
  
  
  
  
  Thank you
  VInod

  http://asktom.Oracle.com/pls/Apex/f?p=100:11:0:P11_QUESTION_ID:897774300346615341 #901884400346525375

• Outer join problem - revisited

  Hello
  I'm starting a new thread since my previous post was an inaccurate representation of the problem I have.
  
  I have data that looks like this.
  
  create table cour_off (offNum number, varchar2 (10) courseId, start_date date);
  create table activity (number oid, courseId varchar2 (10));
  create table ncr_course (course_oid number, incept_date date, expiry_date date);
  
  insert into cour_off values (1, 'MAT101', to_date (' 15 / 05/2012 ', ' DD/MM/YYYY'));
  Insert in activity values (10, 'MAT101');
  insert into ncr_course values (10, to_date (' 01 / 05/2012 ', ' DD/MM/YYYY'), to_date (' 10 / 05/2012 ', ' DD/MM/YYYY'));
  
  When I write the query using ANSI notation, the query works fine. 1 form is returned with a NULL value for the incept_date column.
  
  Select activity.courseId, ncr_course.incept_date
  of cour_off
  Join the activity on cour_off.courseId = activity.courseId
  activity.Oid left join ncr_course = ncr_course.course_oid
  and cour_off.start_date between ncr_course.incept_date
  and ncr_course.expiry_date
  where cour_off.offNum = 1
  
  However, when the style non ANSI query as shown below, no records are returned.
  
  Select activity.courseId, ncr_course.incept_date
  activity, cour_off, ncr_course
  where cour_off.offNum = 1
  and cour_off.courseId = activity.courseId
  and activity.oid = ncr_course.course_oid (+)
  and cour_off.start_date between ncr_course.incept_date and ncr_course.expiry_date
  
  I would like to know how I can resolve the application of style not ANSI so that the 1 record is returned.
  
  Thank you!

  Well, native Oracle outer join does not allow outside join two tables, to do something like:

  select courseId, ncr_course.incept_date
  from (
        select activity.courseId,
               activity.oid,
               cour_off.start_date
          from cour_off, activity
          where cour_off.offNum = 1
            and cour_off.courseId = activity.courseId
       ), ncr_course
  where oid = ncr_course.course_oid(+)
  and start_date between ncr_course.incept_date(+) and ncr_course.expiry_date(+)
  /
  
  COURSEID   INCEPT_DA
  ---------- ---------
  MAT101
  
  SQL> 
  

  SY.

• Help with sql FULL OUTER JOIN

  Hi all
  I need assistance with SQL FULL OUTER JOIN.
  
  How to write with FULL OUTER JOIN, the query.
  I tried like
  
  
  I have 3 different queries.
  
  Query q: SELECT emp_id LN.emp_id.
  Sum (LN_amount) loan_amt
  MY_LON_TAB LN
  WHERE LN_amount > 20000
  LN.emp_id GROUP;
  
  
  
  Query b: SELECT PLN. EMP_ID emp_id,
  Sum (PLAN_AMOUNT) plan_amt
  FROM PLN MY_PLAN_TAB
  where PLAN_AMOUNT <>0
  GROUP BY PLN. EMP_ID;
  
  
  Query C:
  
  SELECT FLX. EMP_ID emp_id,
  SUM (PRORATE_AMOUNT) PRORATE_AMT
  OF MY_FLX_TAB FLX
  WHERE PRORATE_AMOUNT <>0
  FLX GROUP. EMP_ID;
  
  
  Suppose that the different subquery above 3 a, b, c respectively. each subquery with emp_id and respective amount.
  
  like a.emp_id, a.loan_amt
  b.emp_id, b.plan_amt
  c.emp_id, c.prorate_amt
  
  I show all the empid with their amount respective.
  schenario: If an account made, but not vice-versa b
  and B have record, but not vice versa c
  and a credit record but not vice versa c
  
  first: I have external is associated with the A and B
  Second: join external then complete the total outcome of (a & b) with c
  but empid c just as empty.
  
  
  My output is:
  
  emp_id a.loan_amt, b.plan_amt c.prorate_amt
  101 5000 null null
  102 4500 null 2000
  103 6700 null null
  
  
  How to solve the foregoing to the ANSI (FULL OUTER JOIN) method.
  Please suggest me.
  
  Thanks in advance...
  PKM

  Hello

  It is very difficult for anyone to say what you're doing wrong if they do not know what you are doing. Post your code FULL OUTER JOIN.
  My best guess is:

  WITH     a     AS
  (
       SELECT     ...      -- What you posted as query a
  )
  ,     b     AS
  (
       SELECT     ...      -- What you posted as query b
  )
  ,     c     AS
  (
       SELECT     ...      -- What you posted as query c
  )
  SELECT     COALESCE ( a.emp_id
             , b.emp_id
             , c.emp_id
             )     AS emp_id
  ,     ...     -- whatever other columns you want
  FROM          a
  FULL OUTER JOIN     b  ON     b.emp_id =            a.emp_id
  FULL OUTER JOIN     c  ON     c.emp_id = COALESCE (a.emp_id, b.emp_id)
  ;
  

  I hope that answers your question.
  If not, post a small example (CREATE TABLE and INSERT statements) data for all tables and the results expected from these data (if not what you have already posted).

• How to write table values to analog channel?

  Hi all

  If I have a table of values, is it possible to write these values as an analog voltage and then stop writing when he arrives at the end of the table? If so, how does do this?

  I have attached my code that generates a table of frequency swept sinusoidal voltages and I write that out to my analog channel, when I consult my output however, I get the same display of sinusoidal repetitive time and time again. I expect for example:

  writing of wave of 1 Hz, 2 Hz, 3 Hz etc...

  but I'm getting the 1 Hz wave over and over again, I selected samples in the sample clock and pretty much done a lot of trial and error and still no luck . Any help would be appreciated!

  Daniel

  Hi Daniel!

  Take a look at this example (you can find examples of LabVIEW):

  Gen CONT tension Wfm - Int Clk - no Regeneration.vi

  Here is an another VI I did (see table). It is slightly different from the example of the LV and it should help you.

  It could be that useful...

  Julien

• How do I apply to join the xbox live team?

  How do I apply to join the xbox live team? and maybe I could speak one by email to find out more information? I was talking to an admin and he told me to apply here but idk how... It would be great if I got an answer: 3

  Hello

  XBox Live Enforcement Team?

  Answers has no influence on the XBox or XBox Live If you need to contact them.

  XBox - Support
  http://support.Xbox.com/en-us/pages/default.aspx

  XBox - Contact us (support)
  http://support.Xbox.com/en-us/contact-us

  XBox - Forums Support - and my XBox Live account (top-right)
  http://forums.Xbox.com/

  Xbox technical support phone number

  • Toll-free: (800) 4MY-XBOX or (800) 469-9269

  I hope this helps.

  Rob Brown - Microsoft MVP<- profile="" -="" windows="" expert="" -="" consumer="" :="" bicycle=""><- mark="" twain="" said="" it="">