Hypertexe Instance Graph - meaning of the red arrow between objects

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  How can it be possible? I tried to use flags, but does not work for some reason any. I could also use synchronize (obj2) 1 wire and synchronize (obj1) in Thread2 - but that leads to a dead end
  

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       public static void main(String[] args){
            
            final ObjectClass1 obj1 = new ObjectClass1();
            final ObjectClass2 obj2 = new ObjectClass2();
            //final boolean obj1Callable = false;
            //final boolean obj2Callable = false;
            Thread t1 = new Thread(new Runnable(){
                 public void run(){
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                                          System.out.println(Thread.currentThread().getName());
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                                          obj1.methodA();
                                          obj1.methodB();
                                          System.out.println("Trying to call Object2 methods");
                                          if(obj2.obj2Callable == true){
                                               obj2.methodC();
                                               obj2.methodD();
                                          }
                                     }
                                     catch(InterruptedException ex){
                                          System.out.println("Error occurred: " + ex.getMessage());
                                     }
                                          
                                
                                                    
                      }
                 }
                 
            });
            
            Thread t2 = new Thread(new Runnable(){
                 public void run(){
                      //System.out.println("This is Thread2 ");
                      synchronized(obj2){
                           obj2.obj2Callable = true;
                           obj1.obj1Callable = false;
                           try{
                                Thread.sleep(1000);
                                // We could call methods on obj2 here
                                System.out.println(Thread.currentThread().getName());
                                obj2.methodC();
                                obj2.methodD();
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                                     obj1.methodA();
                                     obj1.methodB();
                                }
                                
                                //System.out.println(Thread.currentThread().getName());
                                
                           }
                           catch(InterruptedException ex){
                                System.out.println("Error occurred: " + ex.getMessage());
                           }
                                                    
                      }
                 }
                 
            });
            
            t1.start();
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       }
       
       private static class ObjectClass1{
            public boolean obj1Callable;
            public void methodA(){
                 System.out.println("ObjectClass1: methodA() ");
            }
            public void methodB(){
                 System.out.println("ObjectClass1: methodB() ");
            }
       }
       private static class ObjectClass2{
            public boolean obj2Callable;
            public void methodC(){
                 System.out.println("ObjectClass2: methodC() ");
            }
            public void methodD(){
                 System.out.println("ObjectClass2: methodD() ");
            }
       }
       
  }

  Edited by: njguy March 1, 2011 20:01
  
  Edited by: njguy March 1, 2011 20:26
  
  Edited by: njguy March 1, 2011 20:37

  has njguy writes:
  jverd: according to your suggestion, I coded that follows, but do you not think that this would lead to a dead end for sure.

  If you are coding according to my suggestions, deadlock will be impossible.

  Please see the order in which I get the locks
  Thread1: {obj1, obj2} and Thread2: {obj2 obj1} which is the case perfect deadlock.

  This is exactly the opposite of my suggestion, and I even stated explicitly that if you do this, you define yourself in deadlock.

  What I said:

  1. you avoid deadlock so that any thread that needs to acquire lock1 both QL2 always does in a consistent order, like first on lock1, then inside this block synchronization, sync on QL2. If a son not {lock1 {QL2}} and the other not {QL2 {lock1}}, that's how you get blocked.

  Sorry if I wasn't clear enough. All threads need to acquire locks in the same order:

  //  ----- What I suggested ---
  // T1
  sync (lock1) {
    sync (lock2) {
      // stuff
    }
  }
  
  // T2
  sync (lock1) {
    sync (lock2) {
      // stuff
    }
  }
  
  // ---- What I said not to do, but you did ---
  // T1
  sync (lock1) {
    sync (lock2) {
      // stuff
    }
  }
  
  // T2
  sync (lock2) {
    sync (lock1) {
      // stuff
    }
  }
  

  Edited by: jverd March 2, 2011 09:23

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