Insert query

Hi all

DB version: 10.2

I have table with 8 columns namely num1, num2, num3, num4, num5, num6, num7, num8. I have to insert all these column values in a table with a column "Num".
create table nums_tb
(
key char(16),
num1  char(16)
,num2  char(16)
,num3  char(16)
,num4  char(16)
,num5  char(16)
,num6   char(16)
,num7   char(16)
,num8   char(16)
)   ;

create table nums_tmp
(
num1  char(16)
)   ;

I have to insert all column values into nums_tmp. I have written query like this:

insert into nums_tmp
select * from (
select distinct num1
from  nums_tb

union
select distinct num2
from  nums_tb
union

select distinct num3
from  nums_tb
union

select distinct num4
from  nums_tb
union

select distinct num5
from  nums_tb
union

select distinct num6
from  nums_tb
union

select distinct num7
from  nums_tb
union

select distinct num8
from  nums_tb);
The nums_tb table contains 20 million records. So this insert takes a lot of time around 5 hours. Is there a better way to write this query to achieve the right?

Kind regards
SK

Is it possible that we can write the query to improve performance?

Put separate on the outer query not every query internal, using the union all in inline mode.

Use parallel DML. Consider using a manual sort area size.

alter session enable parallel dml;

insert /*+ parallel */
into nums_tmp
select distinct nums.num1
from (
  select num1 num1
  from  nums_tb
  union all
  select num2 num1
  from nums_tb
  union all
  select num3 num1
  from nums_tb
  union all
  select num4 num1
  from nums_tb
  union all
  select num5 num1
  from nums_tb
  union all
  select num6 num1
  from nums_tb
  union all
  select num7 num1
  from nums_tb
  union all
  select num8 num1
  from  nums_tb) nums;

Tags: Database

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    Phoenix

    the order of the values that you insert is different from the order of the array
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    ---
    Azadi Saryev
    SABAI - Dee.com
    http://www.SABAI-Dee.com

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    cpu_count integer 4
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    create_stored_outlines string
    cursor_bind_capture_destination memory of the string + tell
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    db_16k_cache_size big integer 0
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    db_create_online_log_dest_1 string
    db_create_online_log_dest_2 string
    db_create_online_log_dest_3 string
    db_create_online_log_dest_4 string
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    fast_start_parallel_rollback string LOW


    file_mapping boolean FALSE
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    Thanks in advance

    Firstly, thank you for posting the 10g implementation plan, which was one of the key things that we were missing.

    Second, you realize that you have completely different execution plans, so you can expect different behavior on each system.

    Your package of 10g has a total cost of 23 959 while your plan of 12 c has a cost of 95 373 which is almost 4 times more.  All things being equal, cost is supposed to relate directly to the time spent, so I expect the 12 c plan to take much more time to run.

    From what I can see the 10g plan begins with a scan of full table on DEALERS, and then a full scan on SCARF_VEHICLE_EXCLUSIONS table, and then a full scan on CBX_tlemsani_2000tje table, and then a full scan on CLAIM_FACTS table.  The first three of these analyses tables have a very low cost (2 each), while the last has a huge cost of 172K.  Yet once again, the first three scans produce very few lines in 10g, less than 1,000 lines each, while the last product table scan 454 K lines.

    It also looks that something has gone wrong in the 10g optimizer plan - maybe a bug, which I consider that Jonathan Lewis commented.  Despite the full table scan with a cost of 172 K, NESTED LOOPS it is part of the only has a cost of 23 949 or 24 K.  If the math is not in terms of 10g.  In other words, maybe it's not really optimal plan because 10g optimizer may have got its sums wrong and 12 c might make his right to the money.  But luckily this 'imperfect' 10g plan happens to run fairly fast for one reason or another.

    The plan of 12 starts with similar table scans but in a different order.  The main difference is that instead of a full table on CLAIM_FACTS scan, it did an analysis of index on CLAIM_FACTS_AK9 beach at the price of 95 366.  It is the only main component of the final total cost of 95 373.

    Suggestions for what to do?  It is difficult, because there is clearly an anomaly in the system of 10g to have produced the particular execution plan that he uses.  And there is other information that you have not provided - see later.

    You can try and force a scan of full table on CLAIM_FACTS by adding a suitable example suspicion "select / * + full (CF) * / cf.vehicle_chass_no...". "However, the tips are very difficult to use and does not, guarantee that you will get the desired end result.  So be careful.  For the essay on 12 c, it may be worth trying just to see what happens and what produces the execution plan looks like.  But I would not use such a simple, unique tip in a production system for a variety of reasons.  For testing only it might help to see if you can force the full table on CLAIM_FACTS scan as in 10g, and if the performance that results is the same.

    The two plans are parallel ones, which means that the query is broken down into separate, independent steps and several steps that are executed at the same time, i.e. several CPUS will be used, and there will be several readings of the disc at the same time.  (It is a mischaracterization of the works of parallel query how).  If 10g and 12 c systems do not have the SAME hardware configuration, then you would naturally expect different time elapsed to run the same parallel queries.  See the end of this answer for the additional information that you may provide.

    But I would be very suspicious of the hardware configuration of the two systems.  Maybe 10 g system has 16-core processors or more and 100's of discs in a matrix of big drives and maybe the 12 c system has only 4 cores of the processor and 4 disks.  That would explain a lot about why the 12 c takes hours to run when the 10 g takes only 30 minutes.

    Remember what I said in my last reply:

    "Without any contrary information I guess the filter conditions are very low, the optimizer believes he needs of most of the data in the table and that a table scan or even a limited index scan complete is the"best"way to run this SQL.  In other words, your query takes just time because your tables are big and your application has most of the data in these tables. "

    When dealing with very large tables and to do a full table parallel analysis on them, the most important factor is the amount of raw hardware, you throw the ball to her.  A system with twice the number of CPUS and twice the number of disks will run the same parallel query in half of the time, at least.  It could be that the main reason for the 12 c system is much slower than the system of 10g, rather than on the implementation plan itself.

    You may also provide us with the following information which would allow a better analysis:

    • Row counts in each tables referenced in the query, and if one of them are partitioned.
    • Hardware configurations for both systems - the 10g and the 12 a.  Number of processors, the model number and speed, physical memory, CPU of discs.
    • The discs are very important - 10g and 12 c have similar disk subsystems?  You use simple old records, or you have a San, or some sort of disk array?  Are the bays of identical drives in both systems?  How are they connected?  Fast Fibre Channel, or something else?  Maybe even network storage?
    • What is the size of the SGA in both systems?  of values for MEMORY_TARGET and SGA_TARGET.
    • The fact of the CLAIM_FACTS_AK9 index exist on the system of 10g.  I guess he does, but I would like that it confirmed to be safe.

    John Brady

  • Looking for a better style or a way to write the INSERT statement, possible with brand of continuation

    Honestly, I really looked everywhere for this.

    The problem is that, while tinkering in SQL Developer and knowing that in the spreadsheet I can just execute individual instructions by placing the cursor on the SQL statement I want to run I tried to do an INSERT query that would allow me to run an INSERT statement for... Well many inserts.

    I thought I could use a brand of continuation but nothing I've tried has worked.

    INSERT INTO

    HF_easy_drinks

    VALUES

    ("Blackthorn", "tonic water", 1.5, 1.0, "pineapple juice", "mix with ice").

    ("Blue Moon", "soda", 1.5 "Blueberry Juice",. 75, "mix with ice, strain")

    ;


    I ended up doing just individual INSERT statements, which was not as convenient.

    INSERT INTO HF_easy_drinks

    VALUES ('Blackthorn', 'tonic water', 1.5, 1.0, "pineapple juice", "mix with ice");

    INSERT INTO HF_easy_drinks

    VALUES ('Blue Moon', 'soda', 1.5, 'Blueberry Juice',. 75, "mix with ice");

    Hello

    Perhaps you might prefer "an" insert like this:

    INSERT INTO hf_easy_drinks (x, y, z,...)
    SELECT "Blackthorn", "tonic water", 1.5, 1.0, "pineapple juice", "mix with ice" OF THE double
    UNION ALL SELECT 'Blue Moon', 'soda', 1.5, 'Blueberry Juice',. 75, "mix with ice, strain ' FROM dual
    SELECT UNION ALL... OF the double
    SELECT UNION ALL... OF the double
    ;

    Best regards

    Bruno Vroman.

  • A map of OWB (service line) SQL query

    If I trace a session, run a map OWB (base line), the trace file contains the actual SQL query?

    The problem with me is that when I execute this rank - based OWB card, is throw me an error CursorFetchMapTerminationRTV20007, BUT (most time consuming) when I take on the intermediate SQL insert query, it works very well (and also in a very short time)

    The executing State = COMPLETE

    message = text ORA-06502: PL/SQL: digital or value error: character string buffer too small

    CursorFetchMapTerminationRTV20007 = message text

    N ° of task errors = 0

    N ° task warnings = 2

    N ° errors = 1

    Since this card OWB (truncate insert) is the line in function of where I can't back-end of the generated pl/sql package request OWB so I was wondering if I trace the session, check the trace file, maybe I'll able to see the exact SQL query generated. But I wanted to confirm the same.

    Yes, the real run SQL in session will be in the trace file.

  • Insert records from a single to two related tables table

    DB - 10G
    OS - XP

    We have thousands of records delimited by commas that we want to insert in a normalized table structure.

    I created a group of test data that can be found at the end of this post.


    I have csv files that look like this;

    Donald, huey
    Dewey, Donald
    Donald, louie

    And I want that data to be inserted into a table separate two like that;

    table named PARENTS
    parent_name PK
    1 donald

    Table named for CHILDREN
    child_name fk PK
    1 1 huey
    1 2 dewey
    1 3 louie


    I built an insert query that looks like this;

    INSERT ALL
    IN parents (parent_id, parent_name) VALUES (parents_seq.nextval, parent_name)
    IN children (children_id, parent_id, child_name) VALUES (children_seq.nextval, parents_seq.nextval, child_name)
    SELECT parent_name, child_name
    SOURCES;

    And this has resulted in the following:

    Table named PARENTS
    PK child_name
    1 DONALD
    2 DONALD
    3 DONALD

    Table named PARENTS
    child_name fk PK
    1 1 HUEY
    2 2 DEWEY
    3 3 LOUIE

    Anyone have any ideas on how I could accomplish this task?

    This is some sample data;

    [code]
    Parents_seq SEQUENCE DROP;
    Sources_seq SEQUENCE DROP;
    Children_seq SEQUENCE DROP;
    Sources of DROP TABLE.
    DROP TABLE children;
    Parents of DROP TABLE;

    CREATE SEQUENCE PARENTS_SEQ MINVALUE MAXVALUE 1 1000000000000000000000000000 INCREMENT OF 1 START WITH 1 CACHE 20 ALL NOCYCLE.

    CREATE THE PARENTS TABLE
    (THE NUMBER (8) OF PARENT_ID NOT NULL)
    PARENT_NAME VARCHAR2 (50 CHAR) NOT NULL,
    CONSTRAINT PARENTS_PK PRIMARY KEY (PARENT_ID)
    );

    create or replace
    PARENTS_BI RELAXATION
    FRONT
    INSERT OR UPDATE PARENTS
    FOR EACH START OF LINE

    IF THE INSERTION

    IF: NEW. PARENT_ID IS NULL THEN
    SELECT PARENTS_SEQ.nextval IN: NEW. PARENT_ID FROM dual;
    END IF;

    END IF;

    END;
    /


    CREATE SEQUENCE SOURCES_SEQ MINVALUE MAXVALUE 1 1000000000000000000000000000 INCREMENT OF 1 START WITH 1 CACHE 20 ALL NOCYCLE.

    CREATE TABLE SOURCES
    (THE NUMBER (8) OF SOURCE_ID NOT NULL)
    PARENT_NAME VARCHAR2 (50 CHAR) NOT NULL,
    CHILD_NAME VARCHAR2 (50 CHAR) NOT NULL,
    CONSTRAINT SOURCES_PK PRIMARY KEY (SOURCE_ID)
    );

    create or replace
    SOURCES_BI RELAXATION
    FRONT
    INSERT OR UPDATE ON SOURCES
    FOR EACH START OF LINE

    IF THE INSERTION

    IF: NEW. SOURCE_ID IS NULL THEN
    SELECT SOURCES_SEQ.nextval IN: NEW. SOURCE_ID FROM dual;
    END IF;

    END IF;

    END;
    /

    INSERT INTO SOURCES (PARENT_NAME, CHILD_NAME) VALUES ('DONALD', 'HUEY');
    INSERT INTO SOURCES (PARENT_NAME, CHILD_NAME) VALUES ('DONALD', 'DEWEY');
    INSERT INTO SOURCES (PARENT_NAME, CHILD_NAME) VALUES ('DONALD', 'LOUIE');
    Commit;


    CREATE SEQUENCE CHILDREN_SEQ MINVALUE MAXVALUE 1 1000000000000000000000000000 INCREMENT OF 1 START WITH 1 CACHE 20 ALL NOCYCLE.

    FAST * CREATE TABLE *.
    CREATE TABLE CHILDREN
    (CHILDREN_ID NUMBER OF NON-NULL
    , PARENT_ID NUMBER NOT NULL
    CHILD_NAME VARCHAR2 (50 CHAR) NOT NULL,
    CONSTRAINT CHILDREN_PK PRIMARY KEY (CHILDREN_ID)
    );

    create or replace
    CHILDREN_BI RELAXATION
    FRONT
    INSERT OR UPDATE ON CHILDREN
    FOR EACH START OF LINE

    IF THE INSERTION

    IF: NEW. CHILDREN_ID IS NULL THEN
    SELECT CHILDREN_SEQ.nextval IN: NEW. CHILDREN_ID FROM dual;
    END IF;

    END IF;

    END;
    /

    [code]

    Looks like it's a way to do this:

    insert into parents (parent_name) select distinct parent_name from sources;

select *
  from parents;
PARENT_ID              PARENT_NAME
---------------------- --------------------------------------------------
1                      DONALD

insert into children (parent_id, child_name)
select p.parent_id, s.child_name
  from sources s
  join parents p
    on (s.parent_name = p.parent_name);

select *
  from children;

CHILDREN_ID            PARENT_ID              CHILD_NAME
---------------------- ---------------------- --------------------------------------------------
1                      1                      HUEY
2                      1                      DEWEY
3                      1                      LOUIE

  • Insert time consuming

    I have an insert query that inserts into a fairly small table which takes up to 3 minutes to complete. The table has only 52 k in there files. Other tables in this database can be inserted into at least 1 second.

    Race explain the plan on the insert gives only 1 line which is not very useful and which basically said the execution should be very fast.

    My question is, if I really want to get to the heart of oracle 11g and debugging, what should the tools that I use or what should I look at to know why this insertion takes so long?

    If you can, turn off the trigger, then check the time of insertion.

Maybe you are looking for

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