Suggest the Sql query to get the years, months, days of the two dates.

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• SQL query to get the number of days monthwise

  Hello
  I'm new to sql, can someone please tell me query to find the number of days between the two dates months wise.
  say
  FIRSTDATE last date
  21/03/2011-25/06/2011
  
  March April May June
  9 22 23 18

  Hello

  Welcome to the forum!

  Here's one way:

  WITH     all_dates     AS
  (
       SELECT     start_date + LEVEL - 1     AS a_date
       FROM     (
                 SELECT     TO_DATE ('21/03/2011', 'DD/MM/YYYY')     AS start_date
                 ,     TO_DATE ('25/06/2011', 'DD/MM/YYYY')     AS end_date
                 FROM     dual
            )
       CONNECT BY     LEVEL     <= end_date + 1 - start_date
  )
  SELECT       TO_CHAR ( TRUNC (a_date, 'MONTH')
              , 'fmMonth YYYY'
              )               AS month
  ,       COUNT (*)               AS num_days
  FROM       all_dates
  WHERE       a_date - TRUNC (a_date, 'IW')     < 5
  GROUP BY  TRUNC (a_date, 'MONTH')
  ORDER BY  TRUNC (a_date, 'MONTH')
  ;
  

  What is a 'working day '? I guess you mean every day except Saturday or Sunday, but the query aboveare sometimes figures less than you have asked:

  MONTH             NUM_DAYS
  --------------- ----------
  March 2011               9
  April 2011              21
  May 2011                22
  June 2011               18
  

  Are a few days working on Saturday or Sunday? How do you get the 22 working days in April 2011 and 23 in may?

  SQL is good at obtaining results with a variable number of rows, but you have to say exactly the desired number of columns when you write the query.
  If you really need the output of the way you said, with any number of columns, then watch in swing or a grouping of the chain . See the FAQ forum
  https://forums.Oracle.com/forums/Ann.jspa?annID=1535
  "4. How can I convert rows to columns.

• SQL query to get the numbers from 0 to 99

  How can we write a sql query to get values from 0 to 99... This should not come from any table

  SELECT LEVEL - 1
    FROM  DUAL
    CONNECT BY LEVEL <= 100
  /
  

  SY.

• difference between two dates in the year/month/day in Obiee

  Hi gurus,

  I know this question have been asked and answered several times but I have a requirement that is a little different, then the previous ones.

  I want to calculate the difference between two dates in OBIEE10g in year/month/day format similar to the below SQL output

  SQL > select end_date, start_date,

  trunc (months_between (end_date, start_date) / 12) years.

  months of mod (trunc (months_between (end_date, start_date)), 12).

  End_date - add_months (start_date, trunc (months_between (end_date, start_date))) days

  t

  Thanks in advance

  SK

  Search for this

  "TIMESTAMPDIFF IN THE FORM OF MTHS # YEARS."

  or else

  To get the current mandate of employees since the date of hiring in the form of # years # mths or # year (s) # month (s)

  Concat (concat (cast (TIMESTAMPDIFF (SQL_TSI_Month, "Employee attributes". (((' ' Hiring last Date employee ", CURRENT_DATE) / 12 as char),"Year (s)"), concat (cast (MOD (TIMESTAMPDIFF (SQL_TSI_Month,"Employee attributes". (((((' ' Hiring last Date employee ", CURRENT_DATE), 12) as char), 'Month (s)'))

  Concat (concat (CAST (TIMESTAMPDIFF (SQL_TSI_YEAR, "Employee attributes". (((' ' Hiring last Date employee ", CURRENT_DATE) as CHAR),"Year (s)"), concat (cast (MOD (TIMESTAMPDIFF (SQL_TSI_Month,"Employee attributes". (((((' ' Hiring last Date employee ", CURRENT_DATE), 12) as char), 'Mth (s)'))

• The date system in the taskbar indicates the year, month, day (as in the army). How can I read the day, month, year?

  The date system in the taskbar indicates the year, month, day (as in the army). How can I read the day, month, year?

  It's weird, in my version (Windows 7 Pro), it shows much more than that.

• How to count the number of Sundays between the two dates

  Hello
  
  I want the number of Sundays between the two dates
  
  example of
  
  number of number of Sundays between 4 January 2013 ' and April 30, 2013 "in a select query, I have to include this as a sub query in my select statement.

  nordine B wrote:
  Hi Frank,.
  Have 1 doubt...

  In many countries the week could me "Monday". How the application handles it?
  Or did I get something wrong?

  Help, please!

  For ' IW'(ISO week) early in the day is always Monday...

  It's so simple - calculate the weeks between two dates based on Monday... This is the number of Sundays...

  NEXT_DAY is another option...

  SQL> with dd as
    2  (
    3      select TO_DATE('01-04-2013','dd-mm-yyyy') fdt, TO_DATE('30-04-2013','dd-mm-yyyy') ldt from dual
    4  )
    5  SELECT       fdt,ldt,
    6            (next_day(ldt,'sunday')-next_day(fdt-1,'sunday'))/7 sdays
    7  FROM         dd;
  
  FDT       LDT            SDAYS
  --------- --------- ----------
  01-APR-13 30-APR-13          4
  

  Published by: JAC on May 2, 2013 12:20

• OBIEE 11.1.1.6.6 - analysis shows the two dates instead of a guest

  Hi all

  my analysis shows somehow the two dates instead of a guest.

  How can it be?

  Tell me please what additional information should I include for you to help me.

  OBIEE 11.1.1.6.6

  UPD: prompt screenshots

  http://Marchello.CCX-grads.org/IMG/BI_prompt_001.PNG

  http://Marchello.CCX-grads.org/IMG/BI_prompt_002.PNG

  I started to use the dashboard to display analysis, now issue additional date disappeared.

• Migrated virtual machine appears in the two data stores

  Hi all

  A bit of background on our installation first. servers ESX 3.5 vcenter 4.0 (just improved 2.5) + 2 + 2 data warehouses configured in 1 box of MSA.

  Here is what happened. I've migrated a VM from A to B data store using "Migrate" in vSphere client on vCenter.

  On the vSphere client, virtual machine displays now two data warehouses. In the browser data store, the vme even appears in the two data stores. Datastore shows 20 GB to 20 GB provisioned and 0 GB to 20 GB used. B displays 20 of 20 put into service and used 20 20 GB.

  Migration seems to have succeeded. I migrated about 10 other vm and they reside only on a data store. All virtual machines are working properly. I tried to migrate the computer back to A virtual. He showed only a data store. But the problem appeared again when I migrated the vm to B. I tried to move the virtual machine back and forth between servers ESX, no difference.

  Any ideas? The virtual machine is working well, and it is not necessarily a critical problem. But it's annoying, because I intend to reorganize the data store has and the fear it could cause a problem.

  Thank you so much in advance!

  anything mounted on the CD/DVD drive, as an ISO which can be on A Datastore?

• SQL query to get the items for which transactions have not been saved

  Hi people,

  Have a small doubt I want to compile a SQL query in the inventory where I get these items for what transactions do not have been recorded during a period of at least one specified number of days.

  The days might be 30 days or 2 months depends on. If I want to get those items for which no transactions were reported for lets say 30 days. Could someone give me an idea of how to go about this thing? I use r12. I came up with the following query, but it gives a lot of records. The commented parts of this query is only commented on
  

  
  

  SELECT DISTINCT msi.segment1,

  MSI. Description,

  MSI.primary_uom_code,

  MSI.inventory_item_id

  MSI mtl_system_items_b / *,.

  mtl_material_transactions mmt * /.

  WHERE / * msi.inventory_item_id = mmt.inventory_item_id

  AND msi.organization_id = mmt.organization_id

  AND NVL ((SELECT SUM (transaction_quantity)

  OF mtl_onhand_quantities

  WHERE inventory_item_id = msi.inventory_item_id),

  0) = 0

  AND TRUNC (mmt.transaction_date) < = SYSDATE - & D

  AND * / NOT EXISTS (SELECT *)

  OF mtl_material_transactions mmt

  WHERE msi.inventory_item_id = mmt.inventory_item_id

  AND msi.organization_id = mmt.organization_id

  AND TRUNC (mmt.transaction_date) < SYSDATE - & D);

  Hi fatimakhellil

  Try the following code and mark it as correct if your problem be resolved.

  SELECT DISTINCT msi.segment1,

  MSI. Description,

  MSI.primary_uom_code,

  MSI.inventory_item_id,

  MSI.organization_id,

  Ms.secondary_inventory_name,

  (select max (transaction_date) in the mtl_material_transactions where msi.inventory_item_id = inventory_item_id

  AND msi.organization_id = organization_id) last_transaction_date

  OF mtl_system_items_b msi.

  Ms. mtl_secondary_inventories

  WHERE ms.organization_id (+) = msi.organization_id

  AND msi.source_subinventory = ms.secondary_inventory_name (+)

  AND NOT EXISTS (SELECT *)

  OF mtl_material_transactions mmt

  WHERE msi.inventory_item_id = mmt.inventory_item_id

  AND msi.organization_id = mmt.organization_id

  AND mmt.subinventory_code = ms.secondary_inventory_name

  AND mmt.organization_id = ms.organization_id

  AND TRUNC (mmt.transaction_date) BETWEEN TRUNC (SYSDATE - & d) AND TRUNC (SYSDATE))

• SQL query to get the NULL records after the last matching flag

  I have a xx1 table with id and flag columns. So I want the data in this table, after the last flag matched. I want that data to id 7 in the rooms. Even if the id 2,3,5 are null flag 'Y' was at 6. ID so I need a query to get the data of the xx1 table after the last correspondence flag (from 7 to 9 id).

  SQL > create table xx1

  2 (identification number,

  3 flag varchar2 (10));

  Table created.

  SQL > insert into xx1 values (1, 'Y');

  1 line of creation.

  SQL > insert into values xx1 (2, null);

  1 line of creation.

  SQL > insert into values xx1 (3, null);

  1 line of creation.

  SQL > insert into xx1 values (4, 'Y');

  1 line of creation.

  SQL > insert into values xx1 (5, null);

  1 line of creation.

  SQL > insert into xx1 values (6, 'Y');

  1 line of creation.

  SQL > insert into values xx1 (7, null);

  1 line of creation.

  SQL > insert into values xx1 (8, null);

  1 line of creation.

  SQL > insert into values xx1 (9, null);

  1 line of creation.

  SQL > select * from xx1.

  FLAG OF THE ID

  ---------- ----------

  1. IS

  2

  3

  4. IS

  5

  6. IS

  7

  8

  9

  9 selected lines.

  SQL >

  Hello

  user11164339 wrote:

  Hi Frank - when I run the query, I don't see the results data.

  I get

  FLAG OF THE ID

  ----- ----------

  7

  8

  9

  What you do differently?

• IOM sql Query to get the status of the failed task

  Hello world
  
  We have an obligation as we need to get the status of a particular task (say Create User in OID - Completed\Rejected status resource) for the particular user. We are able to get the status of the provisioed of resources to the user but not the status of the special mission which is trigerred for the user.can someone put some light on it. We must have the SQL query to do this.
  
  Thanks in advance.
  
  Kind regards
  MKN

  Hello
  Use this query to get the status of the task, also check the cooments

  SELECT USR. USR_LOGIN, OSI. SCH_KEY, ANN. SCH_STATUS, STA. STA_BUCKET OF
  OSI, CHS, STA, MIL, TOS, PKG, OUEDRAOGO, USR, OBJ, OST
  WHERE OSI.MIL_KEY = MIL.MIL_KEY
  AND ANN. SCH_KEY = OSI. SCH_KEY
  AND STA. STA_STATUS = SCH. SCH_STATUS
  AND TOS. PKG_KEY = PKG. PKG_KEY
  AND MIL. TOS_KEY = TOS. TOS_KEY
  AND OUÉDRAOGO. USR_KEY = USR. USR_KEY
  AND OUÉDRAOGO. OST_KEY = OST. OST_KEY
  AND OST. OBJ_KEY = OBJ. OBJ_KEY
  AND OSI. ORC_KEY = OUEDRAOGO. ORC_KEY
  AND OBJ. OBJ_NAME = "User AD".
  AND OST. OST_STATUS = "Provisioning" - filter accordinglly
  AND STA. STA_BUCKET = 'pending' - filter accordinglly
  AND PKG. PKG_NAME = "AD User" - filter accordinglly
  AND MIL.MIL_NAME = 'System' - filter accordinglly Validation
  ;
  Thank you
  Kuldeep

• SQL query to get the dates between two dates

  Hello

  We have a chart with start date and end date... Now I need to get all the dates between the start date and end date...

  Table looks to below...

  Create the table date_table (start_date, end_date date);

  The table data will be as below:

  start_date end_date

  January 1, 2013 January 4, 2013

  February 1, 2013 February 3, 2013

  ...............          .................

  ...............          ..................

  ...............           .................

  May 1, 2013 may 3, 2013

  
  

  I want a result like below...

  
  

  holiday_dates

  January 1, 2013

  January 2, 2013

  January 3, 2013

  January 4, 2013

  February 1, 2013

  February 2, 2013

  February 3, 2013

  .................

  .................

  .................

  .................

  May 1, 2013

  May 2, 2013

  May 3, 2013

  
  

  Can anyone help... ?
  

  Ramesh9158 wrote:

  Hello

  Your query will not work for our case...

  First... We do not know the number of rows in the table... If we cannot use the union...

  Second... hard coding of dates... but we do not know what could be that goes back in the table... it could be no matter what it takes not only as appearing to the interpreter...

  Hey riri.

  My code will work everywhere I use with with union all statement to create the example data.

  Try the query:

  -The main query

  Select d1 + row_number() over (partition by iden) - stopped by iden holiday 1

  Of

  connect by level<= d2="" -="" d1="" +="">

  and prior iden iden =

  and prior sys_guid() is not null

  ----

  Ramin Hashimzade

• Need for SQL query to get the result.

  Region	Month	Trx type	Summary of the resolution
  AMERICAS	-13 may	Adjustments	Fix
  EMEA	-13 may	Adjustments	Incorrect
  AMERICAS	-13 may	Credit memo	Incorrect
  EMEA	-13 may	Invoice	Fix
  AMERICAS	-13 may	Credit memo	Fix
  OFD	-13 may	Adjustments	Fix
  AMERICAS	-13 may	Invoice	Incorrect
  DVL	-13 may	Adjustments	Fix
  DVL	-13 may	Adjustments	Fix
  OFD	-13 may	Adjustments	Fix

  Above my Table and here is the result required. Similarly for other regions as well. Can someone help me with the SQL query?

  Region	Summary of the resolution	Setting	Credit memo	Invoice	Total general
  AMERICAS	Fix	1	1		2
  	Incorrect	0	1	1	2

  Like this?

  SQL > select * from transaction_audit;

  MTH TRX_TYPE REGION BOARD
  -------- ------ ----------- ---------
  AMERICAS-13 may SETTINGS CORRECT
  EMEA-13 may INCORRECT ADJUSTMENT
  AMERICAS-13 may CREDIT MEMO INCORRECT
  EMEA-13 may INVOICE CORRECT
  AMERICAS-13 may CREDIT MEMO CORRECT
  OFD-13 may SETTINGS CORRECT
  AMERICAS-13 may INVOICE INCORRECTE
  LAD-13 may SETTINGS CORRECT
  LAD-13 may SETTINGS CORRECT
  OFD-13 may SETTINGS CORRECT

  10 selected lines.

  SQL > select region
  2, resolution_summary
  3, count (decode (trx_type, "ADJUSTMENTS", trx_type)) adjustments
  4, County (decode (trx_type, 'HAVING', trx_type)) credit_memo
  5, County (decode (trx_type, "BILL", trx_type)) Bill
  transaction_audit 6
  Group 7
  8 by region
  9, resolution_summary
  10 Decree
  11 by region
  12, resolution_summary
  13.

  REGION TAKE ADJUSTMENTS CREDIT_MEMO INVOICE
  -------- --------- ----------- ----------- ----------
  CORRECT THE AMERICAS 1 1 0
  0 1 1 INCORRECT AMERICAS
  EMEA CORRECT 0 0 1
  INCORRECT EMEA 1 0 0
  DAL ADDRESS 2 0 0
  OFD CORRECT 2 0 0

  6 selected lines.

  SQL >

• SQL query to get the range of Date values

  Hello
  
  The database is Oracle11i.
  
  I'm looking for a way to generate a list of the dates of a fixed date in the past (could be hardcoded) at the time of the day (sysdate).
  
  In other words, if the fixed date is June 19, 2011, and assuming today ' today is June 24, 2011 the SQL must be able to generate the
  
  Next: -.
  
  June 19, 2011
  June 20, 2011
  June 21, 2011
  June 22, 2011
  June 23, 2011
  June 24, 2011
  
  And the constraint is that I can not make any change to the database in question. I can only shoot a (SELECT) SQL query. NO.
  
  use time dimension type of approach (time dimension is not available here) and no procedure, etc. from PL/SQL. Is it possible?
  
  Thank you

  Jaimeen Shah wrote:
  Hello

  The database is Oracle11i.

  I'm looking for a way to generate a list of the dates of a fixed date in the past (could be hardcoded) at the time of the day (sysdate).

  In other words, if the fixed date is June 19, 2011, and assuming today ' today is June 24, 2011 the SQL must be able to generate the

  Next: -.

  June 19, 2011
  June 20, 2011
  June 21, 2011
  June 22, 2011
  June 23, 2011
  June 24, 2011

  And the constraint is that I can not make any change to the database in question. I can only shoot a (SELECT) SQL query. NO.

  use time dimension type of approach (time dimension is not available here) and no procedure, etc. from PL/SQL. Is it possible?

  Thank you

  SQL> def date_start = '13/11/2010'
  SQL> def date_end   = '22/11/2010'
  SQL> with
    2    data as (
    3      select to_date('&date_start', 'DD/MM/YYYY') date1,
    4             to_date('&date_end',   'DD/MM/YYYY') date2
    5      from dual
    6    )
    7  select to_char(date1+level-1, 'DD/MM/YYYY') the_date
    8  from data
    9  connect by level <= date2-date1+1
   10  /
  THE_DATE
  ----------
  13/11/2010
  14/11/2010
  15/11/2010
  16/11/2010
  17/11/2010
  18/11/2010
  19/11/2010
  20/11/2010
  21/11/2010
  22/11/2010
  

• Need a sql query to get several dates in rows

  Hi all

  I need a query to get the dates of the last 7 days and each dates must be in a line...

  but select sysdate double... gives a line...

  Output of expexcted

  Dates:

  October 1, 2013

  30 sep-2013

  29 sep-2013

  28 sep-2013

  27 sep-2013

  26 sep-2013

  Try:

  SQL > SELECT sysdate-7 + LEVEL FROM DUAL

  2. CONNECT BY LEVEL<=>

  3 * ORDER BY 1 DESC

  SQL > /.

  SYSDATE-LEVEL 7 +.

  -----------------------------

  October 1, 2013 13:04:52

  30 - Sep - 2013 13:04:52

  29 - Sep - 2013 13:04:52

  28 - Sep - 2013 13:04:52

  27 - Sep - 2013 13:04:52

  26 - Sep - 2013 13:04:52

  25 - Sep - 2013 13:04:52

  7 selected lines.