Join natural vs using the Clause

Similar Questions

• Selection of the list of clients using the clause "EXISTS".

  Dear all,

  I have 3 tables, say,

  TABLE1:

   

  CUST_CODE

  (PRIMARY KEY)

  CUST_NAME

  CUST_COUNTRY_CODE

  CUST_CITY_CODE

  CUST_AREA_CODE

  A

  CUST1

  COU1

  CIT1

  A1

  B

  CUST2

  COU2

  CIT2

  A2

  C

  CUST3

  COU2

  CIT2

  A3

  D

  CUST4

  COU3

  CIT4

  A4

  E

  CUST5

  COU3

  CIT5

  A5

  TABLE2

   

  STOCK_SYS_ID

  (PRIMARY KEY)

  STOCK_CUSTOMER_CODE

  STOCK_CUSTOMER_

  COU_CODE

  STOCK_

  CUSTOMER_

  CIT_CODE

  STOCK_

  CUSTOMER_

  ARE_CODE

  STOCK_DOC_

  CREATED

  1

  A

  [Leaving empty as we have reference only to the customers and the date here...]

  10/15/2015

  2

  B

  15/09/2015

  3

  A

  16/08/2015

  4

  C

  18/08/2015

  5

  E

  22/07/2015

  6

  C

  31/01/2015

  7

  A

  15/10/2014

  TABLE 3

   

  AREA_CODE	AREA_COUNTRY_CODE	AREA_CITY_CODE
  A1

  COU1

  CIT1

  A2

  COU2

  CIT2

  A3

  COU3

  CIT2

  A4

  COU3

  CIT3

  A5

  COU4

  CIT5

  How can I find the list of clients of TABLE1, which are present in TABLE2 by 2015 and have country-city-zone, both correct mapping as specified in section TABLE3 using the clause "EXISTS".

  Is that my output will be like,

   

  CUST_CODE (ONLY CORRECT CUSTOMER CODES)

  CUST_NAME

  A

  CUST1

  B

  CUST2

  
  

  Thanks in advance,

  Séverine Suresh
  

  Hello

  So, you want to see 3 columns in table1 correspond to 3 columns in t3.  It is not enough for only 1 column equal:

  Area_Code must be equal

  country_code and must be equal

  city_code and must be equal.

  Here's a way to encode that, by using the EXISTS operator in a WHERE clause:

  SELECT cust_no, cust_name

  FROM table1 t1

  WHEN THERE IS)

  SELECT 0

  Table 3 T3

  WHERE t3.area_code = t1.cust_area_code

  AND t3.area_country_code = t1.cust_country_code

  AND t3.area_city_code = t1.cust_city_code

  )

  ;

  I hope that answers your question.

  If not, please post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and the results you want to start from these data (otherwise what you've posted already).

  Explain, using specific examples, how you get these results from these data.

  Always say what version of Oracle you are using (for example, 11.2.0.2.0).

  See the FAQ forum: Re: 2. How can I ask a question on the forums?

• PL/SQL parameter in fusion by using the clause

  Hi all

  I need to create a procedure where I use the Merge clause. However, by using the condition, I have to put value user_define (V_LOCALE_CD). This value checks table of locale and then to make a match with table of flex_labels_test.

  There is no specific requirement and I don't have the test data.

  My only question how do I use user set the value using the condition. Here is the procedure I created as follows.

  create or replace the PROCEDURE UPSERT_FLEX_LABEL_3 (V_LOCALE_CD IN VARCHAR2,

  V_VALUE IN VARCHAR2,

  V_FIELDVALUE IN VARCHAR2,

  V_FIELDNAME IN VARCHAR2,

  V_TABLENAME IN VARCHAR2,

  N_FLEX_TYPE NUMBER,

  V_COLOR IN VARCHAR2 DEFAULT NULL,

  N_IMAGE_LIBRARY_ID IN THE NUMBER DEFAULT NULL,

  N_HIERARCHY_ID IN DEFAULT NUMBER 5237260000000000001,

  N_IS_INHERITED IN THE DEFAULT NUMBER 1)

  AS

  L_COUNT NUMBER;

  NUMBER OF N_LOCALE_ID;

  NUMBER OF NN_HIERARCHY_ID: = 5237260000000000001;

  NUMBER OF NN_IS_INHERITED: = 1;

  NUMBER OF INSERTCOUNT;

  UPDATECOUNT NUMBER;

  NUMBER OF ERR_CODE;

  ERR_MSG VARCHAR2 (100);

  BEGIN

  -SELECT ID IN N_LOCALE_ID OF PLACES WHERE LOCALE_CD = V_LOCALE_CD;

  / * IT WILL CHECK DUPLICATES, IF THEY ARE PRESENT, THEN IT WILL UPDATE RECORD ELSE IT WILL INSERT A NEW RECORD * /.

  BEGIN

  Merge into fl flex_labels_test

  using (select locale id where locale_cd = V_LOCALE_CD) L

  on (l.id = fl.locale_id)

  When matched then

  GAME UPDATE

  HIERARCHY_ID = NVL (N_HIERARCHY_ID, NN_HIERARCHY_ID),

  IS_INHERITED = NVL (N_IS_INHERITED, NN_IS_INHERITED),

  FLEX_TYPE = N_FLEX_TYPE,

  VALUE = V_VALUE,

  IMAGE_LIBRARY_ID = N_IMAGE_LIBRARY_ID,

  COLOR = V_COLOR

  WHERE TABLENAME = V_TABLENAME

  AND FIELDNAME = V_FIELDNAME

  AND FIELDVALUE = V_FIELDVALUE

  When not matched then

  INSERT (HIERARCHY_ID, ID_PARAMETRES_REGIONAUX, IS_INHERITED, FLEX_TYPE, TABLENAME, FIELDNAME, FIELDVALUE, VALUE, IMAGE_LIBRARY_ID, COLOR)

  VALUES (NVL (N_HIERARCHY_ID, NN_HIERARCHY_ID), N_LOCALE_ID, NVL (N_IS_INHERITED, NN_IS_INHERITED), N_FLEX_TYPE, V_TABLENAME, V_FIELDNAME, V_FIELDVALUE, V_VALUE, N_IMAGE_LIBRARY_ID, V_COLOR);

  UPDATECOUNT: = NUMBER OF ROWS SQL %;

  EXCEPTION

  WHILE OTHERS THEN

  ERR_CODE: = SQLCODE;

  ERR_MSG: = SUBSTR (SQLERRM, 1, 200);

  DBMS_OUTPUT. PUT_LINE ("ERRORS" |) ERR_CODE | ' AND ' | ERR_MSG);

  END;

  COMMIT;

  DBMS_OUTPUT. PUT_LINE ('RECORD INSERTCOUNT =' |) NVL(INSERTCOUNT,0));

  DBMS_OUTPUT. PUT_LINE (' UPDATECOUNT RECORD ='|) NVL(UPDATECOUNT,0));

  EXCEPTION

  WHEN NO_DATA_FOUND THEN

  RAISE_APPLICATION_ERROR (-20001, "ID NOT FOUND REGIONAL SETTINGS");

  END;

  I guess that's what I was looking for. Thank you guys for your efforts.

  FUSION using parameter variables

• Cannot be joined lines when using the line Segment tool

  So unfortunately, I've updated to the latest version of Illustrator Cc (V19.2.1). And to my horror, I can no longer draw a line (with the line segment tool) then draw another line, coming from the previous those anchor point. When I try to shoot immediately. He's trying to turn the line rather than create a line joining... anyway to change that or am I stuck with it?

  (Also, I use windows currently..)

  http://Tinypic.com/player.php?v=iqc0mc & s = 9 #. Vr5gifJ95hE

  I don't know if you can say/see/see in the video, but here's the process that I'm following departure using the line-drawing the line-> > segment trying to draw a line from that anchor point (and that is the question, when I'm doing it automatically, it assumes I want to transform the line)-> changes to the tool selection and clicks on the line to deselect-> goes back and finishes object, repeating the process.

  Help me please... I'm desperate...

  It is these new life forms, a few disadvantages too with the rectangle tool, ellipse etc. tool.

  to go back to the old behavior

  Object > shape > expand the form, do a deed for him, or do what I did a hotkey (Windows 7).

  Edit > keyboard shortcuts > Menu commands > object > shape > expand the form , then in the first box to the right click in it, select and press a key on the keyboard, I choose F9, OK and name.

  It's an extra step, having to have a finger on the mouse and the other on the keyboard for each line. but I can't think otherwise.

• How to use the clause type conditionally create new lines

  This question is just for learning - no object other than to start real world to create versions of some queries known to learn how to measure the performance of the MODEL clause clause of the MODEL versions.

  The question is: How can you write a STANDARD clause that pivots (updates) ONLY the lines that actually need to rotate and do NOT change the lines that have no value and cannot be rotated.

  I found a good site that has about two dozen example articles on different pieces. This first link is the beginning of the series.

  SQL features tutorials - Clause TYPE

  http://www.sqlsnippets.com/en/topic-11663.html

  This link is to a clause of FAQ of BluShadow MODEL version "how to convert rows to columns."

  Line - MODEL method string

  http://www.sqlsnippets.com/en/topic-11987.html

  The solution to this link uses this line of source:

  POSITION KEY VAL

  --- ---------- ----------

  R08 0 v1, v2, v3,.

  and this result set:

  POSITION KEY VAL

  --- ---------- ----------

  R08 1 v1

  R08 2 v2

  R08 3 v3

  The reason why it produces that result set is this clause of the statement of MODEL

  RETURN THE UPDATED LINES

  If you comment on this article, you will see that the original lines are all in position 0. This means that the solution reproduced EACH SOURCE LINE even if there is only one item in the list of values.

  Thus, even a line source with a single value (for example, the r01 'a') will be updated and updated this line is returned.

  For a large number of data sources with only a few lines that actually need to rotate it would be a great performance of infringement.

  This is the sample data source

  with t as (button 1, 'a' value 'abc' col2, col3 'def' of the double
  Select Union all 2, 'b', 'ghi', 'jkl' from dual
  Union all select 3, 'c, d, e, 'mno', 'pqr' from dual.
  Union all select 4, 'f', 'stu', 'vwx' from dual
  )
  Select the key, value, col2, col3
  t

  KEY, VALUE, COL2, COL3
  1, a, abc, def
  2, b, GHI, jkl
  3, "c, d, e, mno, pqr.
  4, f, stu, vwx

  Lines 1, 2 and 4 only have a value of (a, b, c respectively.

  Only line 3 must rotate. It contains "c, d, e" and which must become 3 lines in the result set

  Value of the key, col2 col3
  1 an abc def
  2B ghi jkl
  3 c mno, pqr
  3 d mno, pqr
  3 e mno, pqr
  4 f stu vwx

  The nut of the problem is that if the clause 'RETURN UPDATED ROWS' is used, then the lines 1, 2 and 4 must be updated in order to be returned in the result set. And if this clause is NOT used, then line 3 must be updated by 'c', d, e 'c' and two new product lines: one line for a ' and one for 'e '.

  How can you do this with the TYPE clause without the help of the clause "Return LINES UPDATE"? I don't have a solution to sample showing what I tried because I can't understand what it takes to even try.

  I have a solution that uses "RETURN UPDATED ROWS" but I want to compare this performance to the exercise, when this clause is NOT used.

  We ask BluShadow to add the solution of MODEL clause to this FAQ with other similar solutions.

  Like this?

  SQL > with t as
  () 2
  3 select the 1 key, 'a' val, 'abc' col2, col3 'def' of the double

  
  Select 4 Union all 2, 'b', 'ghi', 'jkl' from dual
  5 union all select 3, 'c, d, e, 'mno', 'pqr' from dual.
  Select 6 Union all the 4 'f', 'stu', 'vwx' from dual
  7)
  8. Select the key
  9, key_1
  10, val
  11, regexp_substr (val, ' [^,] +', 1, key_1) val_new
  12, col2
  13, col3
  14 t
  model 15
  16 partition by (key)
  dimension (1 key_1) 17
  18 measures (val, col2, col3, (length (val) - length (replace (val, ",")) + 1) as len)
  19 rules
  (20)
  21 val [for 1 to increment of len key_1 [1] 1] = val [1]
  22, col2 [for 1 to increment of len key_1 [1] 1] = col2 [1]
  23, col3 [for 1 to increment of len key_1 [1] 1] = col3 [1]
  24)
  25 order
  26 by key
  27, key_1;

  KEY KEY_1 VAL VAL_N NECK NECK
  ---------- ---------- ----- ----- --- ---
  1 1 has an abc def
  2 b 1 b ghi jkl
  3 1 c, d, e c mno pqr
  3 2 c, d, e d mno pqr
  3 3 c, d, e e mno pqr
  4 1 f f stu vwx

  6 selected lines.

• Update a table using the clause

  Hello

  I want to update a table using the selected values.

  Cases in the sample:

  
  

  create table as empsalary)

  Select 1 as empid, 0 in the wages of all the double union

  Select option 2, the double 0);

  Data update are as follows

  with saldata as

  (

  Select 1 as empid, 5000 as wages, 500 as double pf

  Union of all the

  Select option 2, 10000,1000 like double pf

  )

  Select empid, salary saldata

  I tried the following query but does not work

  updated set of empsalary table (empid, salary) =

  (

  Select * from)

  with saldata as

  (

  Select 1 as empid, salary, 500 5000 as pf Union double all the

  Select option 2, 10000,1000 like double pf

  )

  Select empid, salary saldata

  ) sl

  where sl.empid = empsalary.empid

  )

  I use oracle 10g.

  Help, please.

  Krishna Devi wrote:

  Hello

  I want to update a table using the selected values.

  Cases in the sample:

  create table as empsalary)

  Select 1 as empid, 0 in the wages of all the double union

  Select option 2, the double 0);

  Data update are as follows

  with saldata as

  (

  Select 1 as empid, 5000 as wages, 500 as double pf

  Union of all the

  Select option 2, 10000,1000 like double pf

  )

  Select empid, salary saldata

  I tried the following query but does not work

  updated set of empsalary table (empid, salary) =

  (

  Select * from)

  with saldata as

  (

  Select 1 as empid, salary, 500 5000 as pf Union double all the

  Select option 2, 10000,1000 like double pf

  )

  Select empid, salary saldata

  ) sl

  where sl.empid = empsalary.empid

  )

  I use oracle 10g.

  Help, please.

  Thanks for posting creates table and test data.

  The error message would have helped because it's pretty obvious that this is the problem:

  Update table empsalary

  *

  ERROR on line 1:

  ORA-00903: invalid table name

  Just remove the word "table".

• ORA-19102: literal string XQuery waited while xmltable reading using the clause of passage

  Hello

  I have the following XML in the column tmp_xml in the tmp_medimail_accounts table:

  " < = xmlns:env env:Envelope ' http://schemas.xmlsoap.org/SOAP/envelope/ ">

  < env:Header / >

  < env:Body >

  " < its: findAccountByCriteriaResponse xmlns: its = ' http://session.kernel.CMP.com/ ">

  < return >

  < detailedInfo > accounts found: 1 < / detailedInfo >

  < operationResult > MPROXY_RESULT_OK < / operationResult >

  < value >

  < authCertificate / >

  < autocertificationActive / >

  < boolAck > true < / boolAck >

  < caDomain > BE_AUTO < / caDomain >

  < certified > false < / certified >

  < City > BELSELE < / City >

  < commercialAction / >

  < country / >

  < description > MediMail 3.7.4 < / description >

  other < dmi > < / dmi >

  < emailForward > false < / emailForward >

  < enabled > true < / enabled >

  < encCertificate / >

  medidoc < encodingType > < / encodingType >

  < etk / >

  < fax > LDAP this field is masked by the SECURITYFILTER < / fax >

  PC < firstName > < / name >

  < inami > 72091883000 < / inami >

  < institution > pc sint hieronymus < / institution >

  < language > NL < / language >

  < name > sint-hieronymus < / lastName >

  < lastconnectiondate > 20140115090051Z < / lastconnectiondate >

  < localeStr / >

  PC.Sint - hieronymus of < connection > < / login >

  < mail > [email protected] < / mail >

  < mexiAddress > pc.sint-hieronymus.72091883@BE_AUTO < / mexiAddress >

  < mexiBackup / >

  < mobilephone > LDAP this field is masked by the SECURITYFILTER < / mobilephone >

  < niss / >

  < oldIP / >

  < oldSystemId > 720918 < / oldSystemId >

  < packageName > M < / packageName >

  This LDAP is hidden by the SECURITYFILTER field < password > < / password >

  < pin / >

  < pkey / >

  < pkeyehealth / >

  < main > false < / main >

  < principalUserName / >

  the province <>FLANDRE_ORIENTALE < / province >

  < registrationDate > 20101213093341Z < / registrationDate >

  < role > HOSPITAL < / role >

  < sender > true < / sender >

  < senderInvisible > true < / senderInvisible >

  < subscriptiondocs > false < / subscriptiondocs >

  This LDAP is hidden by the SECURITYFILTER field < phone > < / phone >

  < improved / >

  < userpublic / >

  < usetranscodor > true < / usetranscodor >

  < version / >

  < / value >

  < / return >

  < / its: findAccountByCriteriaResponse >

  < / env:Body >

  < / env:Envelope >

  I want to read the XML column and display it as a relational table.  I have the following SQL code:

  Select x.*

  of tmp_medimail_accounts t

  xmltable)

  xmlnamespaces ('http://schemas.xmlsoap.org/soap/envelope/"as" env" )

    , ' http://session.kernel.CMP.com/ ' as 'his'

  )

  , ' env:Envelope / env:Body / its: findAccountByCriteriaResponse return value '

  in passing t.tmp_xml

  path of varchar2 (30) columns "firstName", firstName

  path varchar2 (30) LastName "lastName."

  rizivnr varchar2 (11) path 'inami ',.

  path of varchar2 (50) address "mexiAddress."

  path of varchar2 (100) email "mail."

  Gemeente varchar2 (50) path 'city') x;

  But I have error: ORA-19102: literal string XQuery WAITED

  Can someone help me?

  Best regards, Hans

  Hello

  What is your version of the database?

  It looks like an old problem related to the CURSOR_SHARING parameter.

  See if the solution given here helps: How to use a web service xml document

• How to use the clause type without hard-coding the values inside?

  Query

  Select acct_no,

  gl_code,

  CASE

  WHEN entry_type_label ("earned INCOME") THEN

  "Recipes".

  ON THE OTHER

  "Deferred income of credit."

  END as entry_type_label,

  CASE

  WHEN entry_type_label IN ("opening balance") THEN

  "Opening balance".

  WHEN entry_type_label ("deferred revenue CREDIT") THEN

  "The amount of the invoice.

  WHEN entry_type_label ("earned INCOME") THEN

  "Recipes".

  WHEN entry_type_label IN ('closing balance") THEN

  "Closing balance.

  ON THE OTHER

  "Deferred income of credit."

  END tag as,

  entry_type_no,

  orig_chg_start_date,

  period_no,

  -amt as amt

  of revrec_test

  WHERE acct_no = 1788562

  AND IN (2, 4) entry_type_no (acct_no model dimension,

  gl_code,

  entry_type_label,

  entry_type_no,

  orig_chg_start_date,

  period_no) measures (amt) rules upsert

  all (amt 1788562,

  ' NON-10011561',

  "Opening balance"

  2,

  2 OCTOBER 17 08.30.00 AM'.

  190 = 0,

  AMT 1788562,

  ' NON-10011561',

  "Closing balance."

  2,

  2 OCTOBER 17 08.30.00 AM'.

  190 = amt 1788562,

  ' NON-10011561',

  "Deferred income of credit."

  2,

  2 OCTOBER 17 08.30.00 AM'.

  190 - amt 1788562,

  "WON-10011561',

  "Revenue."

  4,

  2 OCTOBER 17 08.30.00 AM'.

  190,

  AMT 1788562,

  ' NON-10011561',

  "Opening balance"

  2,

  2 OCTOBER 17 08.30.00 AM'.

  191 = amt 1788562,

  ' NON-10011561',

  "Closing balance."

  2,

  2 OCTOBER 17 08.30.00 AM'.

  190,

  AMT 1788562,

  ' NON-10011561',

  "Deferred income of credit."

  2,

  2 OCTOBER 17 08.30.00 AM'.

  191 = 0,

  AMT 1788562,

  ' NON-10011561',

  "Closing balance."

  2,

  2 OCTOBER 17 08.30.00 AM'.

  191 =.

  (amt 1788562, "UNEARNED-10011561',"Opening balance", 2,")

  2 October 17 08.30.00 AM', 191 + amt 1788562, "UNEARNED-10011561',

  ("'Revenue deferred credit', 2, 08.30.00 October 2, 17 h", 191)-amt

  1788562,

  "WON-10011561',

  "Revenue."

  4,

  2 OCTOBER 17 08.30.00 AM'.

  191,

  AMT 1788562,

  ' NON-10011561',

  "Opening balance"

  2,

  2 OCTOBER 17 08.30.00 AM'.

  192 = amt 1788562,

  ' NON-10011561',

  "Closing balance."

  2,

  2 OCTOBER 17 08.30.00 AM'.

  191,

  AMT 1788562,

  ' NON-10011561',

  "Deferred income of credit."

  2,

  2 OCTOBER 17 08.30.00 AM'.

  192 = 0,

  AMT 1788562,

  ' NON-10011561',

  "Closing balance."

  2,

  2 OCTOBER 17 08.30.00 AM'.

  192 =.

  (amt 1788562, "UNEARNED-10011561',"Opening balance", 2,")

  2 October 17 08.30.00 AM', 192 + amt 1788562, "UNEARNED-10011561',

  "Revenue deferred credit", 2, 08.30.00 2 October 17: "(, 192)-amt"

  1788562,

  "WON-10011561',

  "Revenue."

  4,

  2 OCTOBER 17 08.30.00 AM'.

  192,

  AMT 1788562,

  ' NON-10011561',

  "Opening balance"

  2,

  2 OCTOBER 17 08.30.00 AM'.

  193 = amt 1788562,

  ' NON-10011561',

  "Closing balance."

  2,

  2 OCTOBER 17 08.30.00 AM'.

  192,

  AMT 1788562,

  ' NON-10011561',

  "Deferred income of credit."

  2,

  2 OCTOBER 17 08.30.00 AM'.

  193 = 0,

  AMT 1788562,

  ' NON-10011561',

  "Closing balance."

  2,

  2 OCTOBER 17 08.30.00 AM'.

  193 =.

  (amt 1788562, "UNEARNED-10011561',"Opening balance", 2,")

  2 October 17 08.30.00 AM', 193 + amt 1788562, "UNEARNED-10011561',

  ("Revenue deferred credit", 2, 08.30.00 2 October 17: ', 193)-amt

  1788562,

  "WON-10011561',

  "Revenue."

  4,

  2 OCTOBER 17 08.30.00 AM'.

  193)

  ORDER BY period_no, entry_type_no;

  The query above works fine. But I hardcoded the values. I want to do the same operation for the other account number which will have different non periodical. How can I reach it?

  Thanks in advance.

  And why do you need a model for that? If I understand the reqs OK:

  with t as)

  Select acct_no,

  "U-11561' gl_code,

  "Deferred income credit ' entry_type_label,.

  2 entry_type_no,

  orig_chg_start_date,

  period_no,

  Max)

  case entry_type_no

  When 2 then - amt

  0 otherwise

  end

  ) amt,.

  Description of the "invoice."

  2 weight

  from table_one

  Acct_no group,

  orig_chg_start_date,

  period_no

  Union of all the

  Select acct_no,

  gl_code,

  entry_type_label,

  entry_type_no,

  orig_chg_start_date,

  period_no,

  -amt,

  Description "paid the Bill."

  3 weight

  from table_one

  where entry_type_no = 4

  Union of all the

  Select acct_no,

  "U-11561' gl_code,

  "Deferred income credit ' entry_type_label,.

  2 entry_type_no,

  orig_chg_start_date,

  period_no,

  AMT 0,.

  case lvl

  When 1 then 'account opening. "

  of other "close account."

  description of the end,

  case lvl

  When 1 then 1

  another 99

  end weight

  from table_one,.

  (select level lvl from dual connect by level<=>

  Acct_no group,

  orig_chg_start_date,

  period_no,

  LVL

  )

  Select acct_no,

  gl_code,

  entry_type_label,

  entry_type_no,

  orig_chg_start_date,

  period_no,

  case

  what weight (sum) (1.99) can

  case weight

  When 2 then amt

  When 3 then - amt

  0 otherwise

  end

  )

  During)

  acct_no partition

  order of period_no,

  weight

  )

  AMT else

  AMT of end,

  Description

  t

  order of acct_no,

  period_no,

  weight

  /

  ACCT_NO GL_CODE ENTRY_TYPE_LABEL ENTRY_TYPE_NO ORIG_CHG_START_DATE PERIOD_NO AMT DESCRIPTION
  ------- ---------------------------- ----------------------- ------------- --------------------- --------- ---------- ---------------
  1001 U-11561 deferred revenue credit 2 2 October 17 08.30.00 AM 100 0 opening account
  1001 U-11561 deferred revenue credit 2 Bill October 2, 17 08.30.00 AM 100 44
  E-11561 1001 recipes 4 08.30.00 2 October 17: 100 13.87 paid invoice

  1001 U-11561 deferred revenue credit 2 2 October 17 08.30.00 AM 100 30.13 closing account
  1001 U-11561 deferred revenue credit 2 2 October 17 08.30.00 AM 101 30.13 opening account
  1001 U-11561 deferred revenue credit 2 2 October 17 08.30.00 AM 101 0 Bill
  E-11561 1001 recipes 4 08.30.00 2 October 17: 101 14,35 paid invoice

  1001 U-11561 deferred revenue credit 2 2 October 17 08.30.00 AM 101 15.78 closing account
  1001 U-11561 deferred revenue credit 2 2 October 17 08.30.00 AM 102 15.78 opening account
  1001 U-11561 deferred revenue credit 2 2 October 17 08.30.00 AM 102 Bill 0
  E-11561 1001 recipes 4 08.30.00 2 October 17: 102 14.83 invoice paid

  1001 U-11561 deferred revenue credit 2 2 October 17 08.30.00 AM 102.95 close account
  1001 U-11561 deferred revenue credit 2 2 October 17 08.30.00 AM 103.95 opening account
  1001 U-11561 deferred revenue credit 2 2 October 17 08.30.00 AM 103 Bill 0
  E-11561 1001 recipes 4 08.30.00 2 October 17: 103.95 invoice paid

  1001 U-11561 deferred revenue credit 2 2 October 17 08.30.00 AM 103 0 closing account
  1002 U-11561 deferred revenue credit 2 17 November 13 09.30.00 AM 104 0 opening account
  1002 U-11561 deferred revenue credit 2 17 November 13 09.30.00 AM 60 104 Bill
  1002 fixed costs recurring revenue COA Code 4 09.30.00 November 17, 13 h 104 9.13 invoice paid

  1002 U-11561 deferred revenue credit 2 17 November 13 09.30.00 AM 104 50.87 closing account
  1002 U-11561 deferred revenue credit 2 17 November 13 09.30.00 AM 105 50.87 opening account
  1002 U-11561 deferred revenue credit 2 December 20, 13 09.30.00 AM 105 50.87 opening account
  1002 U-11561 deferred revenue credit 2 09.30.00 December 20, 13 h 105 19.24 invoice
  1002 U-11561 deferred revenue credit 2 17 November 13 09.30.00 AM 105 0 Bill
  1002 fixed costs recurring revenue COA Code 4 09.30.00 November 17, 13 h 105 44,91 paid invoice

  1002 fixed costs recurring revenue COA Code 4 December 20, 13 09.30.00 AM 105 - 7.82 Bill paid

  1002 fixed costs recurring revenue COA Code 4 09.30.00 December 20, 13 h 105 3.93 invoice paid

  1002 U-11561 deferred revenue credit 2 17 November 13 09.30.00 AM 105 29.09 closing account
  1002 U-11561 deferred revenue credit 2 December 20, 13 09.30.00 AM 105 29.09 closing account
  1002 U-11561 deferred revenue credit 2 17 November 13 09.30.00 AM 106 29.09 opening account
  1002 U-11561 deferred revenue credit 2 December 20, 13 09.30.00 AM 106 29.09 opening account
  1002 U-11561 deferred revenue credit 2 December 20, 13 09.30.00 AM 106 0 Bill
  1002 U-11561 deferred revenue credit 2 17 November 13 09.30.00 AM 106 0 Bill
  1002 fixed costs recurring revenue COA Code 4 09.30.00 November 17, 13 h 106 44,91 paid invoice

  1002 fixed costs recurring revenue COA Code 4 09.30.00 December 20, 13 h 106 11.75 invoice paid

  1002 fixed costs recurring revenue COA Code 4 December 20, 13 09.30.00 AM - 23.47 106 paid

  1002 U-11561 deferred revenue credit 2 17 November 13 09.30.00 AM 106-4.1 closing account
  1002 U-11561 deferred revenue credit 2 December 20, 13 09.30.00 AM 106-4.1 closing account
  1002 U-11561 deferred revenue credit 2 December 20, 13 09.30.00 AM 107 - 4.1 opening account
  1002 U-11561 deferred revenue credit 2 17 November 13 09.30.00 AM 107 - 4.1 opening account
  1002 U-11561 deferred revenue credit 2 17 November 13 09.30.00 AM 107 Bill 0
  1002 U-11561 deferred revenue credit 2 December 20, 13 09.30.00 AM 107 Bill 0
  1002 fixed costs recurring revenue COA Code 4 December 20, 13 09.30.00 AM - 13.69 107 paid invoice

  1002 fixed costs recurring revenue COA Code 4 November 17, 13 09.30.00 AM 107 35.91 invoice paid

  1002 fixed costs recurring revenue COA Code 4 09.30.00 20 December 13 AM 107 6,86 invoice paid

  1002 U-11561 deferred revenue credit 2 17 November 13 09.30.00 AM 107 - 33.18 closing account
  1002 U-11561 deferred revenue credit 2 December 20, 13 09.30.00 AM 107 - 33.18 closing account

  47 selected lines.

  SQL >

  SY.

• Cases identified in a clause Where using the clause

  Oracle Database 11 g Release 11.2.0.1.0 - 64 bit Production
  PL/SQL Release 11.2.0.1.0 - Production
  "CORE 11.2.0.1.0 Production."
  AMT for Linux: Version 11.2.0.1.0 - Production
  NLSRTL Version 11.2.0.1.0 - Production
  
  Hello
  
  I have an APEX application I need to build a SQL statement to a LOV (list of values). I hid filed that contains the type of customer that may be an 'R' or 'B '. The query must be able to display two sets of different results depending on the type of customer 'R' or 'B '.
  
  If the customer type is 'R', then:

  SELECT drg_descr d, drg_code r
  FROM distance_ranges
  WHERE  drg_min_miles IN (0,5)
  ORDER BY drg_min_miles

  If the customer type is 'B', then:

  SELECT drg_descr d, drg_code r
  FROM distance_ranges
  WHERE  drg_min_miles IN (0,5,10,15,20)
  ORDER BY drg_min_miles

  Can someone help me with what I think should be a case statement?
  
  Thank you
  Joe

  Try,

  SELECT drg_descr d, drg_code r
    FROM distance_ranges
   WHERE ( (drg_min_miles IN (0, 5)
        AND param_cust_type = 'R')
       OR  (drg_min_miles IN (0, 5, 10, 15, 20)
        AND param_cust_type = 'B'))
  ORDER BY drg_min_miles
  

  G.

• using the WITH Clause

  The sql statement is
  
  Select ename, job
  from emp, dept
  where emp.deptno = dep.deptno
  and emp.deptno = 10
  Union
  Select ename, job
  from emp, dept
  where emp.deptno = dep.deptno
  and emp.deptno = 20
  
  the statement above using the WITH Clause
  
  WITH dept10 AS
  (select ename, job, hiredate, sal, comm, dname, emp.deptno
  from emp, dept
  where emp.deptno = dept.deptno
  and emp.deptno = 10)
  dept20 AS
  (select ename, job, hiredate, sal, comm, dname, emp.deptno
  from emp, dept
  where emp.deptno = dept.deptno
  and emp.deptno = 20)
  SELECT *.
  OF dept10
  UNION
  SELECT *.
  OF dept20
  
  Correct me if I'm wrong...
  
  Thank you

  Hello

  SeenuGuddu wrote:
  the Question is how u would provide the statement above by using the Clause

  The answer is that the question is meaningless. You will not use a WITH clause for this work.

  Because you must use a WITH clause to get the same results as the first query, I think the best way would be:

  WITH     unnecessary_sub_query     AS
  (
       select DISTINCT
                  ename, job
  --     ,      hiredate, sal, comm, dname,emp.deptno     -- these columns are not in the original query
       from      emp
       ,      dept
       where      emp.deptno = dept.deptno
       and      emp.deptno IN (10, 20)
  )
  SELECT  *
  FROM     unnecessary_sub_query;
  

  is this correct using Clause WITH or correct me

  No, it's not ok to make queries more complex or slow they need to do.
  In addition to the extra columns, it seems that the second query that you posted (the one who has a WITH clause) produces the same results as the first request.

• Joins of tables in the inventory

  Hi all

  Can you please give me the join conditions (request format as where to use an outer join or internal)?

  mtl_material_transactions,

  mtl_system_items_b,

  mtl_parameters

  mtl_item_locations,

  mtl_serial_numbers,

  mtl_lot_numbers

  Here's the sql code.

  We do not have the serial controlled items so I have all the data to validate this sql.

  You need to add a large number of columns in the place where clause change conditions.

  each table has some kind of column field or flag status.

  You can figure that out based on the configuration of your company.

  ======

  Select * from

  mtl_material_transactions mmt,

  MSI mtl_system_items_b,

  mtl_parameters mp,

  mil mtl_item_locations

  mtl_serial_numbers msn,

  mtl_lot_numbers CHF million

  where

  MMT.inventory_item_id = msi.inventory_item_id

  and

  MMT.organization_id = msi.organization_id

  and

  MMT.organization_id = mp.organization_id

  and

  -Outer join MIL incase you don't have parameters of Articles Locators

  MMT.inventory_item_id = mil.inventory_item_Id

  and

  MMT.organization_id = mil.organization_id

  and

  -an outer join on MSN snack items are not control series

  MMT.inventory_item_id = msn.inventory_item_id

  and

  MMT.organization_id = msn.current_organization_id

  and

  -an outer join on mln point snack is not the outer join

  MMT.inventory_item_id = mln.inventory_item_id

  and

  MMT.organization_id = mln.organization_id

  -settings

  and msi.segment1 = «& itemnumber»

  and mmt.organization_id = &org_id;

  =====================

  NOTE: not all run great sql open, it will never be over. Having so many outer joins will not use the index unless you spend in the settings I have used at least.

  all the best.

• Update a record questioned using the parameter

  Hi all
  
  Have someone to help me to update an interviewed record of forms. It's like that when I use ID to search for the details, I want to update the record you are searching.
  
  Arif

  Hi Arif,
  Here you're doing something complicated with you.

  1 UCID_PARAM and USERCREATION are 2 revenge in the same form
  2 UCID_PARAM contain column UCID which is the primary key of the table usercreation. I used this block to pass

  The blockk UCID_PARAM here is the database block and why you must pass the value as a parameter because as you say it is primary key and foreign key in the block. Then why do you use search mechanism Assembly. I mean just create relationship between UCID_PARAM and USERCREATION block or if he joins then just use the method ENTER_QUERY and EXECUTE_QUERY. I understand because if you enter a value in the UCID_PARAM block and goes to the block of detail and do EXECUTE_QUERY by selecting a WHERE CLAUSE.

  So, what's going to happen here. System takes into account that you are inserting record in UCID_PARAM. So, there is a field that is not null, then the error is coming.

  Just use the default behavior of your forms. Or if you really want to use this method. Next, create a block of data non-base to pass the parameter. Do not use UCID_PARAM as the database block.

  And one more thing, I noticed in your this clause

  set_block_property ('USERCREATION', onetime_where, 'UCID =' |) ': UCID_PARAM. UCID');

  It should be

  set_block_property('USERCREATION',onetime_where,'UCID='||:FORM_FIELD_NAME);

  I hope it is clear now.

  -Clément

• Question about the order of evaluation of the clause WHERE CLAUSE when the Oracle OF the syntax used to join tables

  Hello

  Oracle version: 11.1.0.7.0 - 64 bit

  I read the documentation online at joins. The page is avialable here: joins at

  My question is about the join order of evaluation of the conditions in clause and the conditions of those

  are not the join conditions and are placed in the WHERE clause.

  Consider the following pseudocode

  SELECT

  T1. Col1,

  T2.Col1

  Of

  Table1 t1 LEFT OUTER JOIN table2 t2

  WE

  (condition_expression1)

  WHERE

  (condition_expression2)

  Is it correct to say that if there is no column on the status of join (condition_expression1) in condition_expression2, then condition_expression2 is executed before condition_expression1? In other words, oracle always trying to filter based on the WHERE clause individually each table as much as possible before joining them based on the conditions on the article?

  Thanks in advance,

  Hello

  dariyoosh wrote:

  Hello

  Oracle version: 11.1.0.7.0 - 64 bit

  I read the documentation online at joins. The page is avialable here: joins at

  My question is about the join order of evaluation of the conditions in clause and the conditions of those

  are not the join conditions and are placed in the WHERE clause.

  Consider the following pseudocode

  SELECT

  T1. Col1,

  T2.Col1

  Of

  Table1 t1 LEFT OUTER JOIN table2 t2

  WE

  (condition_expression1)

  WHERE

  (condition_expression2)

  Is it correct to say that if there is no column on the status of join (condition_expression1) in condition_expression2, then condition_expression2 is executed before condition_expression1? In other words, oracle always trying to filter based on the WHERE clause individually each table as much as possible before joining them based on the conditions on the article? ...

  The reverse is actually closer to the truth, but we can't really make general statements like that.

  SQL is not a language of the proceedings.  Looking at the code SQL, we could say that the code does, but we cannot say much about how that code it.  In other words, SQL is a language that describes the results you get, not the way to get them.

  The optimizer will do everything what he thinks is faster if it does not change the results.  If any order in which they are applied (in outer joins or CONNECT BY queries, for example), then think of the join is done first, and the value of the WHERE clause is applied to the result of the join.

  Here is a query looks very much like you posted:

  SELECT d.deptno

  e.ename, e.sal

  OF scott.dept d

  LEFT OUTER JOIN scott.emp e ON e.deptno = d.deptno

  WHERE e.sal > = 3000

  ORDER BY d.deptno

  ;

  Output:

  DEPTNO ENAME SAL

  ---------- ---------- ----------

  10 KING 5000

  20 FORD 3000

  20 3000 SCOTT

  The scott.dept table contains deptnos 30 and 40; Why are they not in the result set?  The query behaves as if the outer join is made first (production 15 rows), then the WHERE clause has been applied.  All lines with deptno = 30 had sals down han 3000 and all single line with deptno = 40 was NULL in the sal column, then these lines are excluded (as well as other lines of deptnos 10 and 20), and only 3 lines above are left.

• use the ansi join syntax

  From what I've been reading is preferable to use the new syntax (don't know how is it news)

  The ANSI join syntax was new to Oracle in Oracle 8i in 1998 - that is 15 years old.

  It can produce more readable code and is also much more readable and less human-source of errors for outer joins.

  The ANSI format allows an outer join between several tables in a way the old (+) syntax specific to oracle does not and introduced the JOIN FULL OUTER you should use very rarely.

  You should not use NATURAL JOIN in code - add columns not related to the tables involved can give very different results.

  There have not been important bugs for ANSI joins in Oracle from Oracle 10.2 set up about 8 years ago.

  As Paul says, the part on should be the criteria to join between the tables. Did clause should be the filtering of the joined tables.

  So assuming start_date and end_date in_property_id are variable

  SELECT resv_num, unit_date

  OF p_resv_unit ru

  INNER JOIN p_pm_unit_night pun

  ON pun.resv_unit_id = ru.resv_unit_id

  WHERE pun.property_id = in_property_id

  AND pun.unit_date BETWEEN start_date AND end_date

  AND pun.pm_unit_num = cvUnitNum;

  If start_date and end_date are the columns of p_resv_unit the query would be:

  SELECT resv_num, unit_date

  OF p_resv_unit ru

  INNER JOIN p_pm_unit_night pun

  ON pun.resv_unit_id = ru.resv_unit_id AND pun.unit_date BETWEEN ru.start_date AND ru.end_date

  WHERE pun.property_id = in_property_id

  AND pun.pm_unit_num = cvUnitNum;

  Inner join queries work with criteria in the wrong place, but they are harder to read. Outer joins do not work unless you put the criteria in the right place.

• using the JOIN

  Hi all

  on the 11g R2,.

  How to rewrite the following using OUTER JOIN:

  SELECT Ouvrages.*, exemplaires.numero

  Books, best

  WHERE the ouvrages.isbn = exemplaires.isbn;

  Thank you

  Hello

  user10274093 wrote:

  Hi all

  on the 11g R2,.

  How to rewrite the following using OUTER JOIN:

  SELECT Ouvrages.*, exemplaires.numero

  Books, best

  WHERE the ouvrages.isbn = exemplaires.isbn;

  Thank you

  The query you posted is an inner join.  Outer join will not give the same results.

  Which type of outer join you want?

  1. A version that includes all the lines of the works, even if they have no corresponding row in the copies
  2. A version that includes all the lines of the copies, even if they have no corresponding row in the works
  3. A version that includes all rows from both tables, even if they have no corresponding row in the other table

  If you want to than option 1 (all lines of books, even if they have no corresponding row in the copies), and then

  SELECT Ouvrages.*, exemplaires.numero

  Books

  LEFT OUTER JOIN best ON ouvrages.isbn = exemplaires.isbn

  ;

  If you would like option 2, then first put copies into the FROM clause.

  If you would like option 3, then use FULL OUTER JOIN instead of LEFT OUTER JOIN.

  I hope that answers your question.

  If this isn't the case, please post a small example data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and the results desired from these data.

  Explain, using specific examples, how you get these results from these data.

  Always say what version of Oracle you are using (for example, 11.2.0.2.0).

  See the FAQ forum: Re: 2. How can I ask a question on the forums?