Join the two select queries

Similar Questions

• Join the two sql queries

  Hi all
  
  Thank you very much for all the kind support so far.
  
  I have two report (sql query)
  
  I want to add both the sql query
  
  1st sql query
  
  

  select distinct(a.item_number)
        ,a.quantity - b.quantity
  from QUANTITY_ONHAND_ATP a,BACKLOG_ATP_LT_CW b
  where a.item_number = b.item_number
  order by item_number

  2nd sql query
  
  

  select distinct(wb.item_number)
         ,wb.quantity - be.quantity
         ,c.quantity - d.quantity
  from BACKLOG_WEEK_BEFORE_ATP wb
      ,BACKLOG_ATP_ET_CW be
      ,BACKLOG_WEEK_AFTER_ATP c
      ,BACKLOG_ATP_GT_CW d
  where wb.item_number = be.item_number
     and c.item_number = d.item_number
     and wb.item_number = c.item_number
     and be.item_number = c.item_number
     and wb.item_number = d.item_number
     and be.item_number = d.item_number
  order by wb.ITEM_NUMBER

  In the 1st sql query I have 129 records and in the 2nd query sql, I have 14 records. I want to combine these two sql queries. If the item_number 1st sql query is not there in 2nd and then view it as to 1 sql only.
  
  Any help how to do that.
  
  Concerning
  
  Published by: User_Apex on July 15, 2011 01:21

  Use the NVL function:

  select q1.item_number, WEEK_BEFORE, nvl(CURRENT_WEEK,0) CURRENT_WEEK, nvl(WEEK_AFTER,0) WEEK_AFTER
  (...)
  

• Join the two trees connect by prior Start With and return only common records?

  Oracle 10g Release 2 (10.2)
  
  I have two tables which have structured data. The results, when running queries individually are correct, but I need to join tree a tree two to get only the common records between them.
  
  -Trees a
  SELECT ip_entity_name, entity_code, hier_level, entity_parent
  Of ip_hierarchy
  WHERE hier_level > = 3
  CONNECT BY PRIOR Entity_code = entity_parent
  START WITH entity_code = "MEWWD";
  
  -The two tree
  SELECT ip_entity_name, entity_code, hier_level, entity_parent
  Of ipt_hierarchy
  WHERE hier_level > = 3
  CONNECT BY PRIOR Entity_code = entity_parent
  START WITH entity_code = "IPNAM";
  
  
  If I understand correctly, the joints can not work with CONNECT BY / START WITH queries?
  
  A WITH clause is an option?
  
  If possible, I don't want to put a selection in a database to display object and join against other queries.
  
  Thank you.

  Hello

  jtp51 wrote:
  Oracle 10g Release 2 (10.2)
  ...
  If I understand correctly, the joints can not work with CONNECT BY / START WITH queries?

  Before Oracle 9 it was true. Since you're using Oracle 10, you can if you wish; but I'm guessing that you don't want in this case.

  A WITH clause is an option?

  If possible, I don't want to put a selection in a database to display object and join against other queries.

  Yes, a WITH clause that is an option. Viewed online, as Zhxiang has shown, are another option. Either way gives you a regular display effect without creating a database object.

  You did not show a sample and the results, so no one can tell if a join is really what you want. Other possibilities include INTERSECT or an IN subquery.

• Combine and join the two railways closed with a straight path

  Hello

  I have two way closed and I need to combine or join them with a straight path. When I selected all and do a right click for you join, he did not join. Please see my screenshot. Thank you.

  

  You cannot create Y-junctions.

  You can perform one of the two possbilities:

  Simply place the path open everywhere where you need and leave it there.

  convert all forms with object > path > describe stroke and then use the pathfinder functions.

• Join the two dataProviders

  I have a table with a secondary and two axis ArrayCollections because I want the series on the left axis to update independently of the series on the right axis. Flex graphics support as a dataProvider.

  How can I join two ArrayCollections to make a data provider?

  Copy the following code uses two data providers, or maybe I don't understand the question (maybe the postcode):

  
  
  
    
    
    
    
       
          
             
          
          
              
          
          
              
                  {h1Stroke}
              
              
                  {h2Stroke}
              
          
          
             
                  
                      
                  
  
                  
                     
                  
             
             
                  
                      
                  
                  
                      
                  
             
          
       
       
    
  
  

  If this post answers your question or assistance, please mark it as such. Thank you!

  http://www.stardustsystems.com
  Adobe Flex development and Support Services

• Joining the two points

  I would like to ask how to join two points with a line with actionscript? The points should be constantly in motion.

  You can use joinF() to draw a line from x 1, y1 to x 2, y2:

  var canvas:MovieClip=this.createEmptyMovieClip("canvas",this.getNextHighestDepth());

  function joinF(x1:Number,y1:Number,x2:Number,y2:Number):Void {}

  {with (Canvas)}

  Clear();

  lineStyle(0,0xff0000);

  moveTo(x1,y1);

  lineTo(x2,y2);

  }

  }

• Join the two lines into one game

  Hi all
  
  I have a table with 1 column and records are as below. Below I show only the first 4 records to give an idea.
  
  Select cn from CSGL_AD_GROUP_OP_COMP_MEM_TEMP where rownum < 5;
  
  CN
  -------------------------------------------------------------------------------
  CN = JZJXEEW00072305, OU = computers to office, OR = Secured_Systems, OR = Computers, OR = ZJX_ARTCC, OR
  = FL, OR = ESA, OU = ATO, OU = LOB, DC = faa, DC = gov
  CN = JI90NTW00069990, OU = computers to office, OR = Secured_Systems, OR = Computers, OR = I90_TRACO, OR
  = TX, OR = CSA, OU = ATO, OU = LOB, DC = faa, DC = gov
  
  Now, the requirement is to concatenate the 1st and 2nd rank, concat 3rd and 4th rank, conact 5th and 6th next row and so on and put it in a new column in the same table if its possible, if not in a new table.
  
  How can I do this, can someone help me.
  
  Thank you

  Hello

  There are numerous valid aproaches, may be the last of them is more effective than the other in some cases:

  select
   c1.key
  ,C1.cn||C2.cn cn
  from
  CSGL_AD_GROUP_OP_COMP_MEM2 C1,
  CSGL_AD_GROUP_OP_COMP_MEM2 C2
  where
  C1.key+1=C2.key
  and
  mod(c1.key,2)=1
  
  select key, cn from (
  SELECT
   cn || LEAD (cn) OVER (ORDER BY key) cn
  ,key
  FROM    CSGL_AD_GROUP_OP_COMP_MEM2
  )
  where
  mod(key,2)=1
  
  select key, cn from (
  select *
  from
  CSGL_AD_GROUP_OP_COMP_MEM2 C1
  model
  dimension by (key)
  measures (cn)
  rules(
  cn[any] order by key=cn[cv()]||cn[cv()+1]
  )
  )
  where
  mod(key,2)=1
  

  concerning

• How to cut a Lightroom 3 catalog? And join the two together...

  I did wrong in a lot of work on a batch of images in the "bad" Lightroom Catalog I'm primarily a sports photographer and that you have all the stuff of sports in a catalog and stuff not athletes in another. And I put a major sporting event - 8000 photos - in the non-sports catalog. What should I do to get out and get back to the right? I guess I could separate them by duplication of the catalogue, opening one and delete the event and openness to others and remove all the rest, but this seems a bit lengthy. And if this is the only way, how then do the event separated from catalog items in the catalog of sport?

  I'm sure it must be simpler than it looks!

  Guy

  Select the images, or record or collections you want in your catalog to another

  .

  • Then go to file, export as catalog.
  • Do not export the negatives, then uncheck this box.
  • Give it a name.
  • Export it.
  • Open your catalog on the other.
  • Select file, import from catalog and import.
  • Job done.

• How do the query select outer join to a report of the APEX

  Hi all
  
  I'm Ann.
  
  I have a select statement that is used to calculate statistics for a month (October 2012 in this example)
  Select ph.phase_number
  sum ((case
  WHEN ph.date_finished IS NULL or ph.date_finished > last_day (TO_DATE (' ' Oct 2012 ', ' MY YYYY' "))
  THEN last_day (TO_DATE (' ' Oct 2012 ', ' MY YYYY' "))
  Of OTHER ph.date_finished
  END)
  (-ph.date_started + 1) / count (def.def_id) as avg_days
  Ph phase_membership
  inner join court_engagement this on ph.mpm_eng_id = ce.engagement_id
  join in-house defendant def on ce.defendant_id = def.def_id
  where def.active = 1
  and ph.date_started < = last_day (TO_DATE (' ' Oct 2012 ', ' MY YYYY' "))
  and ph.active = 1
  and UPPER (ce.court_name) LIKE '% '.
  Rollup Group (phase_number)
  ;
  
  The result is as below
  Phase_Number AVG_DAYS
  Phase One 8.6666666666666667
  Phase two 14.6
  Phase three 12
  11.4615365
  
  I have another list of selection mainly the list of months between two date value.
  Select to_char (which_month, 'LUN YYYY') as display_month
  de)
  Select add_months (to_date (' ' August 2012 ', ' MY YYYY' "), rownum-1) which_month
  of object
  where
  rownum < = months_between (to_date (' ' Oct 2012 ', ' MY YYYY' "), add_months (to_date (' ' August 2012", "MY YYYY"), - 1))
  order of which_month)
  
  The query result is as below
  
  DISPLAY_MONTH
  
  AUGUST 2012
  SEP 2012
  OCT 2012
  
  Is it possible I can join these two select statement above to generate a comparable result:
  
  Days of month Phase number Avg
  August 2012 Phase One 8.666
  Sep 2012 Phase One 7.66
  Oct 2012 Phase One 5,66
  August 2012 Phase two 8.666
  Sep 2012 Phase two 7.66
  Oct 2012 Phase two 5,66
  August 2012 Phase three 8.666
  Sep 2012 Phase three 7.66
  Oct 2012 Phase three 5,66
  
  Or
  Days of month Phase number Avg
  August 2012 Phase One 8.666
  August 2012 Phase two 7.66
  August 2012 Phase three 5,66
  Sep 2012 Phase One 8.666
  Sep 2012 Phase two 7.66
  Sep 2012 Phase three 5,66
  Oct 2012 Phase One 8.666
  Oct 2012 Phase two 7.66
  Oct 2012 Phase three 5,66
  
  And it can be controlled by Phase number or month.
  My other colleague suggested I should use a left outer join, but after having tried many ways, I'm still stuck.
  
  I tried select is
  Select a.display_month, b.* in)
  Select to_char (which_month, 'LUN YYYY') as display_month
  de)
  Select add_months (to_date (' ' August 2012 ', ' MY YYYY' "), rownum-1) which_month
  of object
  where
  rownum < = months_between (to_date (' ' Oct 2012 ', ' MY YYYY' "), add_months (to_date (' ' August 2012", "MY YYYY"), - 1))
  order which_month)) a left outer join
  
  (Select to_char (ph.date_finished, 'MY YYYY') as join_month, ph.phase_number)
  sum ((case
  WHEN ph.date_finished IS NULL or ph.date_finished > last_day (TO_DATE (a.display_month, 'MY YYYY'))
  THEN last_day (TO_DATE (a.display_month, 'MY YYYY'))
  Of OTHER ph.date_finished
  END)
  (-ph.date_started + 1) / count (def.def_id) as avg_days
  Ph phase_membership
  inner join court_engagement this on ph.mpm_eng_id = ce.engagement_id
  join in-house defendant def on ce.defendant_id = def.def_id
  where def.active = 1
  and ph.date_started < = last_day (TO_DATE (a.display_month, 'MY YYYY'))
  and ph.active = 1
  and UPPER (ce.court_name) LIKE '% '.
  To_char (ph.date_finished, 'MY YYYY'), group (phase_number) rollup) b
  On a.display_month = b.join_month
  
  but then I get an error
  SQL error: ORA-00904: "A." "" DISPLAY_MONTH ": invalid identifier
  
  I need to view a report on the APEX with option for people to download at least format CSV.
  Already 1 inteactive report in the page, so I don't think adds another interactive report without using the iframe trick.
  
  If any of you have any ideas, please help.
  
  Thank you very much.
  
  Ann

  Hello Ann,.

  Frank has done a very good job. I am also impressed.

  Is in regard to your correction to his question, the problem is on this replacement you did

  last_day(TO_DATE(am.which_month,'MON YYYY'))
  

  AM.which_month is already a date type, and you don't need to convert it to this day.
  Here is the correct way:

  last_day(am.which_month)
  

  There are also sometimes with the data you've posted have no line for this month. So I also added a function NVL to display 0 under avg_days for these cases.

  Here is my corrected query:

  DEFINE startmonth = "Aug 2012";
  DEFINE endmonth   = "Oct 2012";
  WITH  all_months  AS
  (
     SELECT ADD_MONTHS(to_date('&startmonth','MON YYYY'), ROWNUM-1) AS which_month
     ,      ADD_MONTHS(to_date('&startmonth','MON YYYY'), ROWNUM  ) AS next_month
     from all_objects
     where
     rownum <= months_between(to_date('&endmonth','MON YYYY'), add_months(to_date('&startmonth','MON YYYY'), -1))
  )
  SELECT TO_CHAR (am.which_month, 'Mon YYYY')  AS month
       , ph.phase_number
       , NVL(sum ( (CASE
                   WHEN ph.date_finished IS NULL OR ph.date_finished > last_day(am.which_month)
                   THEN last_day(am.which_month)
                   ELSE ph.date_finished
                END
               ) - ph.date_started + 1
             ) / count(def.def_id), 0) as avg_days
    FROM all_months am
         LEFT OUTER JOIN  a_phase_membership  ph  PARTITION BY (ph.phase_number)
            ON  am.which_month <= ph.date_started
            AND am.next_month  >  ph.date_started
            AND ph.date_started <= last_day(am.which_month)  -- May not be needed
            AND ph.active = 1
         LEFT OUTER JOIN  a_engagement  ce
            ON  ph.mpm_eng_id = ce.engagement_id
            AND ce.court_name IS NOT NULL  -- or something involving LIKE
         LEFT OUTER join  a_defendant     def
            ON  ce.defendant_id = def.def_id
            AND def.active = 1
   GROUP BY ROLLUP(phase_number, am.which_month)
   ORDER BY  am.which_month
          ,  ph.phase_number
  ;
  
  The output is:
  MONTH    PHASE_NUMBER           AVG_DAYS
  -------- -------------------- ----------
  Aug 2012 PHASE ONE                     0
  Aug 2012 PHASE THREE                   0
  Aug 2012 PHASE TWO                     0
  Sep 2012 PHASE ONE                    12
  Sep 2012 PHASE THREE                   1
  Sep 2012 PHASE TWO                     9
  Oct 2012 PHASE ONE                     8
  Oct 2012 PHASE THREE                   0
  Oct 2012 PHASE TWO                    14
           PHASE ONE                    11
           PHASE THREE                   1
           PHASE TWO                  11.5
                                9.71428571
  

  I don't know if that's really what you want. In the case check it and let me know.

  Kind regards.
  Al

• Join the path several times

  Hello

  I'm pretty new to Illustrator, but I'm learning by doing kind of guy.

  I created paths making triangles out of lines.

  I want to fill them with a solid, color that works when I join them.

  But here's the problem, if I join a triangle, I can't reach the other is because they share a path.

  as this < I > if I join one ' < I "> I can't use the right path more to create the second triangle.". "

  Is there a way to get around this or do I have him all over again

  Thanks in advance

  Before you create the first triangle, select the shared side and press command + C, command-F to paste a duplicate in place.

  Or, just select the two ends of the triangle without a third side and press command + J to join the two ends, thus creating the side missing.

• Join the 2 queries with common group by column

  IAM trying to reach the results of 2 queries. Myu first query returns as follows.

  

  Like, second

  

  I need to show together and I wrote the request to the below:

  Select b.br_id, count (b.mech_code), sum (b.labour_cost), count (a.received_by) in table2 b, table1: a group of b.br_id;

  But it doesn't show any errors or shows no results. It just continues the treatment forever. Plese help

  Just joined the group two by queries later

  Select

  b.br_id

  b.cnt_mech_code

  b.sum_lc

  a.cnt_rcvd

  de)

  Select

  b.br_id

  count (b.mech_code) cnt_mech_code

  sum (b.labour_cost) sum_lc

  from table2 b

  B.br_id group

  ) b

  , (

  Select

  Count (a.received_by) cnt_rcvd

  Table 1A

  A.br_id group

  ) a

  where

  b.br_id = a.br_id

• Left join of the two tables and multiple values into a single value separated by commas

  Hello

  I have following tables with their structures and their data as below.

  CREATE TABLE 'BETODI '. "" BETINFO ".

  (

  VARCHAR2 (8 BYTE) "CURRENTPRESS."

  ENABLE 'TYPEIDCONTAINER' VARCHAR2 (30 BYTE) NOT NULL

  )

  INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A24G', 'PMC');

  INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A24D', 'Pensky-MARTENS');

  INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ("A25D", "CMP");

  INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A25G', 'PMC');

  INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A26D', 'PMC');

  INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A26G', 'PMC');

  INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ("A32G", "V-BFC3");

  INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A32D', "V-BFC2");

  CREATE TABLE 'BETODI '. "" BETMASTER ".

  (

  ACTIVATE THE "CUREPRESS" TANK (5 BYTES) NOT NULL,

  ACTIVATE THE "TYPE" VARCHAR2 (5 BYTE) NOT NULL,

  NUMBER (5.0) "LASTPCIRIM".

  )

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A24', '45 M 8', 15);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A25', 42 16', 15);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ("A26", 16' 45, 15);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ("A27", '45 M 34', 16);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A28', '45 M 34', 16);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A29', '45 M 34', 16);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A30', '45MCH', 15);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ("A31", "45MCH", 16);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A32', '45MCH', 16);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A33', '45MCH', 16);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ("A34", "45MCH", 16);

  These two tables have left join as

  BETMASTER. CUREPRESS = substr (BETINFO. CURRENTPRESS, 1, 3)

  now I want to have the data in the two tables with fields Curepress, Lastpcirim, typeidcontainer.

  Also something like

  Make a group of typeidcontainer if this value is greater than 1 by press separated the values of semicolon (;)

  So, for example above, we should be given as

  A24 PMC 15; PENSKY-MARTENS

  A25 15 PMC

  A26 15 PMC

  A27 16 (NULL)

  A28 16 (NULL)

  A30 15 (NULL)

  A31 16 (NULL)

  A32 16 BFC2-V; V BFC3

  A33 16 (NULL)

  A34 16 (NULL)

  How could do?

  My current request is as

  Select distinct Curepress, lastpcirim, typeidcontainer

  BETMASTER STD left join INF BETINFO

  on the trim (STD. CUREPRESS) = substr (trim (INF. CURRENTPRESS), 1, 3)

  but I am unable to get the values separated by commas.

  Any help would be appreciated.

  Thank you

  Mahesh.

  Hi, Mahesh,

  If you want to only 1 row of output for each distinct combination of currentpress and lastpcirim?  This sounds like a job for GROUP BY.

  And you want the row to contain a list of all different typidcontainers-delimited?  This sounds like a job for the aggregate LISTAGG function.

  WITH joined_data AS

  (

  SELECT DISTINCT

  MST.curepress, mst.lastpcirim, inf.typeidcontainer

  OF betmaster STD

  LEFT JOIN betinfo ON TRIM (mst.curepress) inf = SUBSTR (TRIM (inf.currentpress)

  1

  3

  )

  )

  SELECT curepress, lastpcirim

  LISTAGG (typeidcontainer, ',')

  THE Group (ORDER BY typeidcontainer) AS container_list

  OF joined_data

  Curepress GROUP, lastpcirim

  ;

  Unfortunately, you can't say LISTAGG (DISTINCT ...), so you should always get the separate containers how you already are.  (Note that the subquery is just what you posted).

  Thanks for posting the CREATE TABLE and INSERT statements; It is very useful.  Don't forget to tell what version of Oracle you are using.  LISTAGG was new in Oracle 11.2.

  Why not add CHECK constraints (and perhaps triggers) to your tables, so that curepress and currentpress are not stored with the head or trailing spaces?  Then you wouldn't need to use the PAD in queries like this, and your code would be simpler and more effective.

• using outer joins if the two column is null? Use only (+)

  Hi all

  create the table xxc_tr_num (tl_number number, tr_no number tl_no_id);

  insert into xxc_tr_num values (123,100,222);

  insert into xxc_tr_num values (124,100,333);

  create the table xxc_od_tab (tl_number number, tl_id number);

  insert into xxc_od_tab values (123,001);

  insert into xxc_od_tab values (null, null);

  create table xxc_oth_tab (name varchar2 (10), number of tl_id);

  insert into xxc_oth_tab values('abc',,001);

  insert into xxc_oth_tab values (null, null);

  Wait it out put

  tr_no tl_no_id name

  100 222 abc

  100 333

  using outer joins if the two column is null? use only please of outer joins

  And I tried to use outer joins on both tl_id column but not get values and I use have County (tr_no ) > 1

  Rajesh123 wrote:

  Thank you Kiss it is not possible to use having clause?

  You need to understand the functioning of the group. If you will not be asked this question.

  Check this box

  SQL> select tr_no,
    2         tl_no_id,
    3         count(*)
    4    from xxc_tr_num a,
    5         xxc_od_tab b,
    6         xxc_oth_tab c
    7   where a.tl_number = b.tl_number(+)
    8     and b.tl_id = c.tl_id(+)
    9   group
   10      by tr_no
   11       , tl_no_id;
  
       TR_NO   TL_NO_ID   COUNT(*)
  ---------- ---------- ----------
         100        333          1
         100        222          1
  

  See what returns the count? You have grouped according to TR_NO and TL_NO_ID. You must take into consideration the TL_NO_ID just put COUNT (TR_NO) does not increase the NUMBER of the whole group. To get the NUMBER on the whole group, I used the analytical function and did. Like this, see the number of the analytical function here

  SQL> select tr_no,
    2         tl_no_id,
    3         count(*),
    4         count(*) over(partition by tr_no)
    5    from xxc_tr_num a,
    6         xxc_od_tab b,
    7         xxc_oth_tab c
    8   where a.tl_number = b.tl_number(+)
    9     and b.tl_id = c.tl_id(+)
   10   group
   11      by tr_no
   12       , tl_no_id;
  
       TR_NO   TL_NO_ID   COUNT(*) COUNT(*)OVER(PARTITIONBYTR_NO)
  ---------- ---------- ---------- ------------------------------
         100        222          1                              2
         100        333          1                              2
  

  So to answer your question, yes you can't do in the HAVING clause...

• Please help me with the Alternative of queries to replace the UNION ALL for two queries

  Hi all

  I have the query to retrieve assets employees salary count and in so far as below:

  Select ename, emp_no, sum (sal_till_2010), sum (sal_till_2014) of

  (select emp_no, ename, salary as sal_till_2010, 0 as sal_till_2014 of employee e1

  where effective_date < = 1 January 2010 ' and not exists (select 1 from e2 employee_deletion where e2.emp_no = e1.emp_no and e2.deletion_date < = January 1, 2010 "")

  UNION ALL

  Select ename, emp_no, 0 as sal_till_2010, salary as employee e1 sal_till_2014 - here is a dummy 0 salary until 2010 for the union of all the

  where effective_date < = 1 January 2014 "and not exists (select 1 from e2 employee_deletion where e2.emp_no = e1.emp_no and e2.deletion_date < = 1 January 2014") "

  Group of emp_no, ename;

  In this query, I get the total salary until 2010 and until 2014 in the employee table, dates are dynamically passed to the procedure, and this can change.

  But assume the date above and let me know the alternative of queries to improve performance because I use Union ALL and read the same table twice in the above query.

  Advice me with request to read the table once to fetch the same data as the above query.

  Thanks in advance.

  
  

  Hello

  Thanks for the display of the data of the sample; It's very useful!

  I think OP wants something like this:

  WITH cutoff_dates AS

  (

  SELECT TO_DATE (January 1, 2010 ', ' DD/MM/YYYY') AS cutoff_date, 2010 UNDER the label OF dual UNION ALL

  SELECT TO_DATE (1 January 2014 ', "DD/MM/YYYY"), double 2014

  )

  SELECT e.emp_no, e.ename

  , NVL (SUM (CASE WHEN c.label = 2010 THEN e.salary END), 0) AS sal_till_2010

  , NVL (SUM (CASE WHEN c.label = 2014 THEN e.salary END), 0) AS sal_till_2014

  E employee

  JOIN cutoff_dates c ON e.effective_date<=>

  WHERE DOES NOT EXIST)

  SELECT 1

  Of employee_deletion ed

  WHERE ed.emp_no = e.emp_no

  AND ed.deletion_date<=>

  )

  E.emp_no GROUP, e.ename

  ORDER BY e.emp_no

  ;

  Output of your sample data:

  EMP_NO ENAME SAL_TILL_2010 SAL_TILL_2014

  ---------- ------ ------------- -------------

  1 Mickey 450 0

  2 Donald 750 0

• JOIN the question... Join two tables without omitting lines

  I came across a problem that should be an easy fix (I hope), but I'm having a hard time to come up with a solution.

  Basically I have two tables, one with the actual amounts with the budget. I have to write a sql statement select that joins these tables together and includes all of their lines. I was able to join the tables by using JOIN, LEFT JOIN and RIGHT JOIN, but it always fails the lines I need.

  Below, I have examples of my tables (AMOUNT_TABLE and BUDGET_TABLE). For simplicity, I built the examples to show the same values in the first four columns, with the 5th and 6th columns (SUB_ACCOUNT, AMOUNT, BUDGET) as the only values that are different. My actual tables are not quite that simple, but I don't think it was relavent to this issue.

  AMOUNT_TABLE

  FISCAL_YEAR	PERIOD	ACCT_UNIT	ACCOUNT	SUB_ACCOUNT	AMOUNT
  2013

  111111555555000010020131111115555551000100201311111155555520001002013111111555555300010020131111115555554000100

  BUDGET_TABLE

  FISCAL_YEAR	PERIOD	ACCT_UNIT	ACCOUNT	SUB_ACCOUNT	BUDGET
  2013

  1111115555553000200201311111155555540002002013111111555555500020020131111115555556000200

  Here's what I hope. Note that SUB_ACCOUNTs 0000, 1000, and 2000 show without budget amounts since there is not a corresponding line in the BUDGET_TABLE. And same for SUB_ACCOUNTs 5000 and 6000, they show budgets with no amount because there is not a corresponding line in the AMOUNT_TABLE.

  (exit)

  FISCAL_YEAR	PERIOD	ACCT_UNIT	ACCOUNT	SUB_ACCOUNT	AMOUNT	BUDGET
  2013	1	11111	555555	0000	100	0
  2013	1	11111	555555	1000	100	0
  2013	1	11111	555555	2000	100	0
  2013	1	11111	555555	3000	100	200
  2013	1	11111	555555	4000	100	200
  2013	1	11111	555555	5000	0	200
  2013	1	11111	555555	6000	0	200

  If all goes well, my question is clear. Any help on this would be greatly appreciated. Thanks in advance.

  Use the join ANSI - FULL OUTER JOIN syntax:

  with amount_table like)

  Select fiscal_year 2013, 1 period, 11111 acct_unit, 555555, 0000 sub_account, amount 100 of all the double union

  Select 2013,1,11111,555555,1000,100 from all the double union

  Select 2013,1,11111,555555,2000,100 from all the double union

  Select 2013,1,11111,555555,3000,100 from all the double union

  Select double 2013,1,11111,555555,4000,100

  ),

  budget_table like)

  Select 1 time, 11111 acct_unit, account 555555, sub_account 3000, 2013 fiscal_year, budget of 200 Union double all the

  Select 2013,1,11111,555555,4000,200 from all the double union

  Select 2013,1,11111,555555,5000,200 from all the double union

  Select double 2013,1,11111,555555,6000,200

  )

  Select nvl (a.fiscal_year, b.fiscal_year) fiscal_year,

  period of NVL (a.period, b.period),

  NVL (a.acct_unit, b.acct_unit) acct_unit.

  account of NVL (a.Account, b.Account),

  NVL (a.sub_account, b.sub_account) sub_account.

  Amount NVL(a.amount,0),

  NVL(b.budget,0) budget

  of amount_table one

  full join

  budget_table b

  on)

  a.Fiscal_Year = b.fiscal_year

  and

  a.period = b.period

  and

  a.acct_unit = b.acct_unit

  and

  a.Account = b.account

  and

  a.sub_account = b.sub_account

  )

  /

  FISCAL_YEAR PERIOD ACCT_UNIT ACCOUNT SUB_ACCOUNT AMOUNT BUDGET
  ----------- ---------- ---------- ---------- ----------- ---------- ----------
  2013 1 11111 555555 0 100 0
  2013 1 11111 555555 1000 100 0
  2013 1 11111 555555 2000 100 0
  2013 1 11111 555555 3000 100 200
  2013 1 11111 555555 4000 100 200
  2013 1 11111 555555 6000 0 200
  2013 1 11111 555555 5000 0 200

  7 selected lines.

  SQL >

  SY.