Join with full pivot

Similar Questions

• [8i] need help with full outer join combined with a cross join...

  I can't understand how to combine a full outer join with a different type of join... is it possible?
  
  Here are some create table and insert for examples of database:

  CREATE TABLE     my_tab1
  (     record_id     NUMBER     NOT NULL     
  ,     workstation     VARCHAR2(4)
  ,     my_value     NUMBER
       CONSTRAINT my_tab1_pk PRIMARY KEY (record_id)
  );
  
  INSERT INTO     my_tab1
  VALUES(1,'ABCD',10);
  INSERT INTO     my_tab1
  VALUES(2,'ABCD',15);
  INSERT INTO     my_tab1
  VALUES(3,'ABCD',5);
  INSERT INTO     my_tab1
  VALUES(4,'A123',5);
  INSERT INTO     my_tab1
  VALUES(5,'A123',10);
  INSERT INTO     my_tab1
  VALUES(6,'A123',20);
  INSERT INTO     my_tab1
  VALUES(7,'????',5);
  
  
  CREATE TABLE     my_tab2
  (     workstation     VARCHAR2(4)
  ,     wkstn_name     VARCHAR2(20)
       CONSTRAINT my_tab2_pk PRIMARY KEY (workstation)
  );
  
  INSERT INTO     my_tab2
  VALUES('ABCD','WKSTN 1');
  INSERT INTO     my_tab2
  VALUES('A123','WKSTN 2');
  INSERT INTO     my_tab2
  VALUES('B456','WKSTN 3');
  
  CREATE TABLE     my_tab3
  (     my_nbr1     NUMBER
  ,     my_nbr2     NUMBER
  );
  
  INSERT INTO     my_tab3
  VALUES(1,2);
  INSERT INTO     my_tab3
  VALUES(2,3);
  INSERT INTO     my_tab3
  VALUES(3,4);

  And, the results that I want to get:

  workstation     sum(my_value)     wkstn_name     my_nbr1     my_nbr2
  ---------------------------------------------------------------
  ABCD          30          WKSTN 1          1     2
  ABCD          30          WKSTN 1          2     3
  ABCD          30          WKSTN 1          3     4
  A123          35          WKSTN 2          1     2
  A123          35          WKSTN 2          2     3
  A123          35          WKSTN 2          3     4
  B456          0          WKSTN 3          1     2
  B456          0          WKSTN 3          2     3
  B456          0          WKSTN 3          3     4
  ????          5          NULL          1     2
  ????          5          NULL          2     3
  ????          5          NULL          3     4

  I tried a number of different things, google my problem and no luck yet...

  SELECT     t1.workstation
  ,     SUM(t1.my_value)
  ,     t2.wkstn_name
  ,     t3.my_nbr1
  ,     t3.my_nbr2
  FROM     my_tab1 t1
  ,     my_tab2 t2
  ,     my_tab3 t3
  ...

  So, what I want, it's a full outer join of t1 and t2 on workstation and a cross join of one with the t3. I wonder if I can't find examples of it online because it is not possible...
  
  Note: I'm stuck dealing with Oracle 8i
  
  Thank you!!

  Hello

  The query I posted yesterday is a little more complex that it should be.
  My_tab2.workstation is unique, there is no reason to make a separate subquery as mt1. We can join my_tab1 to my_tab2 and get the SUM in a subquery.

  SELECT       foj.workstation
  ,       foj.sum_my_value
  ,       foj.wkstn_name
  ,       mt3.my_nbr1
  ,       mt3.my_nbr2
  FROM       (     -- Begin in-line view foj for full outer join
            SELECT        mt1.workstation
            ,        SUM (mt1.my_value)     AS sum_my_value
            ,        mt2.wkstn_name
            FROM        my_tab1   mt1
            ,        my_tab2   mt2
            WHERE        mt1.workstation     = mt2.workstation (+)
            GROUP BY   mt1.workstation
            ,        mt2.wkstn_name
                          --
                  UNION ALL
                          --
            SELECT      workstation
            ,      0      AS sum_my_value
            ,      wkstn_name
            FROM      my_tab2
            WHERE      workstation     NOT IN (     -- Begin NOT IN sub-query
                                             SELECT      workstation
                                     FROM      my_tab1
                                     WHERE      workstation     IS NOT NULL
                                   )     -- End NOT IN sub-query
         ) foj     -- End in-line view foj for full outer join
  ,       my_tab3  mt3
  ORDER BY  foj.wkstn_name
  ,       foj.workstation
  ,       mt3.my_nbr1
  ,       mt3.my_nbr2
  ;
  

  Thanks for posting the CREATE TABLE and INSERT statements, and very clear expected results!

  user11033437 wrote:
  ... So, what I want, it's a full outer join of t1 and t2 on workstation and a cross join of one with the t3.

  She, exactly!
  The trickiest part is when and how get SUM (my_value). You could address the question of exactly what my_tab3 must be attached to a cross that's exactly what should look like the result set of the full outer join between my_tab1 and my_tab2 to. To do this, take your desired results, remove columns that do not come from the outer join complete and delete duplicate rows. You will get:

  workstation     sum(my_value)     wkstn_name
  -----------     -------------   ----------
  ABCD          30          WKSTN 1
  A123          35          WKSTN 2
  B456          0          WKSTN 3
  ????          5          NULL          
  

  So the heart of the problem is how to get these results of my_tab1 and my_tab2, which is done in the subquery FOJ above.

  I tried to use auto-documenté in my code names. I hope you can understand.
  I could spend hours explaining the different parts of this query more in detail, but I don't know that I would lose some of that time, explain things that you already understand. If you want an explanation of the specific element (s), let me know.

• [PIVOT] amount to combine with other pivot?

  Hello.

  I have this statement in my 11g database:

  WITH my_data AS
         (    SELECT    'pave'
                     || MOD( LEVEL
                           , 2
                            )
                       AS pave_name
                   , MOD( LEVEL
                        , 2
                         )
                       AS pave_version_nr
                   ,    'Cogr'
                     || FLOOR(   (  1
                                  + LEVEL )
                               / 2
                              )
                       cogr_name
                   , LEVEL AS value_init
                   , 2 AS value_delivery
                   , 'fakjfhajhfkajöfdsgaösfdghöaoifdsgöafsghöa' AS coin_names
                FROM DUAL
          CONNECT BY LEVEL < 9)
    SELECT *
      FROM (SELECT ROW_NUMBER( )
                     OVER( PARTITION BY cogr_name
                           ORDER BY
                             pave_name
                           , pave_version_nr
                          )
                     AS set_id
                 , cg.*
              FROM my_data cg                                                                                                               --
                             )
  ORDER BY cogr_name;
  

  where this result:

  PAVE_NAME PAVE_VERSION_NR COGR_NAME VALUE_DELIVERY COIN_NAMES VALUE_INIT SET_ID

  ---------- ---------- --------------- --------- ---------- -------------- -----------------------------------------

  1 pave0 0 Cogr1 2 2 fakjfhajhfkajofdsgaosfdghoaoifdsgoafsghoa

  2 pave1 1 Cogr1 1 2 fakjfhajhfkajofdsgaosfdghoaoifdsgoafsghoa

  1 pave0 0 Cogr2 4 2 fakjfhajhfkajofdsgaosfdghoaoifdsgoafsghoa

  2 pave1 1 Cogr2 2 3 fakjfhajhfkajofdsgaosfdghoaoifdsgoafsghoa

  1 pave0 0 6 Cogr3 2 fakjfhajhfkajofdsgaosfdghoaoifdsgoafsghoa

  2 pave1 1 Cogr3 2 5 fakjfhajhfkajofdsgaosfdghoaoifdsgoafsghoa

  1 pave0 0 Cogr4 2 8 fakjfhajhfkajofdsgaosfdghoaoifdsgoafsghoa

  2 pave1 1 Cogr4 2 7 fakjfhajhfkajofdsgaosfdghoaoifdsgoafsghoa

  For each separate COGR_NAME, I need to compare, VALUE_INIT, VALUE_DELIVERY and COIN_NAMES.

  so my desired output is:

  PAVE_NAME_1 PAVE_VERSION_NR_1 COGR_NAME_1 VALUE_INIT_1 VALUE_DELIVERY_1 COIN_NAMES_1 PAVE_NAME_2 PAVE_VERSION_NR_2 COGR_NAME_2 VALUE_INIT_2 VALUE_DELIVERY_2 COIN_NAMES_2

  ----------- ----------------- ----------- ------------ ---------------- ----------------------------------------- ----------- ----------------- ----------- ------------ ---------------- -----------------------------------------

  pave0 0 Cogr1 2 2 fakjfhajhfkajofdsgaosfdghoaoifdsgoafsghoa pave1 1 Cogr1 1 2 fakjfhajhfkajofdsgaosfdghoaoifdsgoafsghoa

  pave0 0 Cogr2 4 2 pave1 fakjfhajhfkajofdsgaosfdghoaoifdsgoafsghoa 1 Cogr2 2 3 fakjfhajhfkajofdsgaosfdghoaoifdsgoafsghoa

  pave0 0 Cogr3 2 6 fakjfhajhfkajofdsgaosfdghoaoifdsgoafsghoa pave1 1 Cogr3 2 5 fakjfhajhfkajofdsgaosfdghoaoifdsgoafsghoa

  pave0 0 Cogr4 8 2 pave1 fakjfhajhfkajofdsgaosfdghoaoifdsgoafsghoa 1 Cogr4 2 7 fakjfhajhfkajofdsgaosfdghoaoifdsgoafsghoa

  I tried a solution COGR_NAME and max() uses groups to keep (dense_rank last/first order of set_id) but it does not work with COIN_NAMES which is really a CLOB.

  So I guess it's possible with the pivoting of the query but any other solution is also welcome...

  Good bye

  DPT

  Hello

  One way is with a self-join, like this:

  WITH got_analytics AS

  (

  SELECT d. *- or whatever the desired columns

  ROW_NUMBER () OVER (PARTITION BY cogr_name

  ORDER BY pave_name

  pave_version_nr

  ) AS set_id

  , COUNT (*) OVER (PARTITION BY cogr_name

  ) AS n_rows

  OF my_data d

  )

  SELECT a1.*, a2. *- or other columns of your choice

  Got_analytics A1

  JOIN a2 ON a1.cogr_name = a2.cogr_name got_analytics

  WHERE a1.set_id = 1

  AND a2.set_id = a2.n_rows

  ORDER BY a1.cogr_name

  ;

• 2135 HP all-in one: cannot print full Page A4, but can scan A4 with FULL Page

  Hi HP & friends,.

  Hello I am using 2135 HP all-in-one printer with windows 7 64 bit,

  I have some problems, and maybe I need your help to solve my problem.

  First of all, I'm trying to scan or copy the test page, I can't scan A4 paper with full size and then I'm trying to reset the configuration on the scan of the letter in A4 format and voila I can scan using A4 format with full screen.

  But my problem occurs when I try to use the file that I scan to be printed, I have a cut off area or empty the bottom of the page. Hmm I have a set configuration with A4 before printing the document.

  I am trying to attach images to show on my problem.

  

  Thanks for the attention and the solution

  Concerning

  Spoiler (Highlight to read)

  

  

  Hello

  Your printer model do not support a full borderless printing, must not exceed the specified margin and it is a limitation of the hardware.

  You can find his record of handling of paper below:

  Borderless printing: No
  http://www8.hp.com/in/en/products/printers/product-detail.html?oid=7174564#!tab=specs
  

  Minimum printer margins are 2.96 mm high, right and 14.5 mm (1.45 cm) for the lower left margins and margins of the page, the printer cannot exceed and to print on these margins, see the section called paper handling > margins below:

  http://support.HP.com/us-en/product/HP-DeskJet-ink-advantage-2130-all-in-one-printer-series/7174559/model/7174560/document/c04616318/

  Kind regards

  Shlomi

• join with condition

  Hi all

  Is there a possible way to cross the join with condition?

  I want something like this:

  Table A: custid, accu_id, sum

  CustID, accu_id unique =

  CustomerID amount accu_id

  10 25 400

  10 35 447

  10 29 420

  20 30 510

  30 35 472

  .

  .

  .

  Table b: accu_id, description

  accu_id description

  shoes 25

  Book 29

  30 computer

  pen 35

  Note: in table A, it is a mismatch of the accu_id values that do not use. Please, take into account this.

  I want to see all the columns in the TABLE B for each custid in A. TABLE (something like cross join but with ONE article.) The following query does not work.

  Select * from a right join B on A.accu_id = B.accu_id;

  10-25

  10-29

  10-30

  10-35

  20-25

  20-29

  20-30

  20-35

  30 25

  30 29

  30 30

  30-35

  What should I do for this?

  Thanks in advance

  Use partition outer join:

  with a (too)

  Select double union all 10 custid, accu_id 25, amount 400

  Select 10,35,447 from all the double union

  Select 10,29,420 from all the double union

  Select 20,30,510 from all the double union

  Select double 30,35,472

  ),

  b like)

  Select accu_id 25, "shoe" description of all the double union

  Select 29, 'book' from dual union all

  Select 30, 'computer' from dual union all

  Select 35, 'pen' from dual

  )

  Select a.custid,

  a.accu_id,

  a.amount,

  b.

  a

  by (a.custid) partition

  right join

  b

  On a.accu_id = b.accu_id

  order of a.custid,

  a.accu_id

  /

  AMOUNT ACCU_ID CUSTID DESCRIPT
  ---------- ---------- ---------- --------
  10 25 400 shoe
  10 29 420 book
  10 35 447 pen
  10 computer
  20 30 510 computer
  shoe 20
  book 20
  20                       pen
  30 35 472 pen
  30 shoe
  30 book

  AMOUNT ACCU_ID CUSTID DESCRIPT
  ---------- ---------- ---------- --------
  30 computer

  12 selected lines.

  SQL >

  SY.

• Trouble with the pivot and the columns that contain numbers/spaces

  Hello
  
  I have trouble with the pivot statement.
  How could I do this just for columns that are numbers?
  How could I do this just for columns that contain spaces?
  
  Can someone please help?
  
  
  based on the documentation of Carsten Czarski
  http://SQL-PLSQL-de.blogspot.com/2007/08/kreuztabellen-in-Oracle11g-SQL-pivot.html
  
  essentially to help:
  --------------------
  Select deptno, sum (clerk), sum (salesman), sum (manager)
  of (emp) pivot
  Sum (SAL) of EMPLOYMENT
  in ("CLERK" as a 'CLERK', 'SELLER' as 'SELLER', 'MANAGER' as 'MANAGER')
  )
  Deptno group
  --------------------
  DEPTNO SUM (CLERK) SUM (SALESMAN) SUM (MANAGER)
  ---------- ---------- ------------- ------------
  30 950 5600 2850
  20 1900 2975
  10-1300-2450
  
  
  
  I tried to run at my own table:
  
  NAME MONAT WERT
  -------------------------------------------------- ---------- ----------
  5 Antarctica 404,84
  Asia 7 106,41
  Oceana 2 456,96
  4 the Europe 426,23
  9 Antarctic 537,56
  Europe 9 832,58
  The South America 12 662,41
  Europe 4 422,27
  America of the North 7 312,19
  America of the North 10 148,92
  
  10 selected lines.
  
  
  But running:
  --------------------
  SELECT name, sum (1), sum (2), sum (3), sum (4), sum (5), sum (6), sum (7), sum (8), sum (9), sum (10), sum (11), sum (12)
  (pivot) apex_wksp.demo_pivot2
  Sum (Wert) for monat
  in ('1 ', '2', ' 3', '4 ', '5', '6', '7',' 8 ', ' 9',' 10', ' 11 ', ' 12')
  )
  Group by name
  ;
  --------------------
  led to:
  Antarctica 1 2 3 4 5 6 7 8 9 10 11 12
  North America 1 2 3 4 5 6 7 8 9 10 11 12
  Oceana 1 2 3 4 5 6 7 8 9 10 11 12
  The South America 1 2 3 4 5 6 7 8 9 10 11 12
  Europe 1 2 3 4 5 6 7 8 9 10 11 12
  Asia 1 2 3 4 5 6 7 8 9 10 11 12
  6 selected lines.
  
  
  not quite what I expected.
  
  
  
  
  
  In addition,
  --------------------
  Select monat, sum (Antarctica), sum (North America), sum (Oceana), sum (South America), sum (Europe), sum (Asia)
  (pivot) apex_wksp.demo_pivot2
  Sum (Wert) name
  ("Antarctic", "North America", "Oceana", "South America", "Europe", "Asia")
  )
  Group by name
  ;
  ---------------------
  ORA 907 results
  
  
  
  I know what the problem is - but how do I do it right?
  
  
  using double quotes or replace (ing) space with just underscores seems to garble sql for the unreadable.
  
  
  
  
  Help, please.
  
  
  
  Thanks in advance,
  Michael Weinberger

  Attention to the rotated default column alias:

  SQL> with demo_pivot2 as (
    2                       select 'Antarctica' name,5 monat,404.84 wert from dual union all
    3                       select 'Asia',7,106.41 from dual union all
    4                       select 'Oceana',2,456.96 from dual union all
    5                       select 'Europe',4,426.23 from dual union all
    6                       select 'Antarctica',9,537.56 from dual union all
    7                       select 'Europe',9,832.58 from dual union all
    8                       select 'South America',12,662.41 from dual union all
    9                       select 'Europe',4,422.27 from dual union all
   10                       select 'North America',7,312.19 from dual union all
   11                       select 'North America',10,148.92 from dual
   12                      )
   13  select name, sum("'1'"),sum("'2'"),sum("'3'"),sum("'4'"),sum("'5'"),sum("'6'"),sum("'7'"),sum("'8'"),sum("'9'"),sum("'10'"),sum("'11'"),sum("'12'")
   14  from demo_pivot2 PIVOT (
   15  sum(wert) for monat
   16  in ('1','2','3','4','5','6','7','8','9','10','11','12')
   17  )
   18  group by name
   19  ;
  
  NAME          SUM("'1'") SUM("'2'") SUM("'3'") SUM("'4'") SUM("'5'") SUM("'6'") SUM("'7'") SUM("'8'") SUM("'9'") SUM("'10'") SUM("'11'") SUM("'12'")
  ------------- ---------- ---------- ---------- ---------- ---------- ---------- ---------- ---------- ---------- ----------- ----------- -----------
  Antarctica                                                    404.84                                      537.56
  North America                                                                       312.19                            148.92
  Oceana                       456.96
  South America                                                                                                                                 662.41
  Europe                                              848.5                                                 832.58
  Asia                                                                                106.41
  
  6 rows selected.
  
  SQL> 
  

  SY.

• How to get previews of lower quality when working with Full-HD?

  I work with Full-HD video, but I don't have to preview the files (rendering) to be too the 1920 x 1080. It takes a lot of disk space and a lot of time to make the preview files.

  Is it possible to ensure a lower quality? For example, resolution 720 x 405 would be sufficient.

  But when I want to make a permanent export, I need to get the Full HD video.

  Thank you!

  Use a custom sequence and change previews as you wish.

• Left Join with a subquery

  Hey everybody!
  
  I have some difficulty in trying to create a SQL query.
  
  I have the following tables:
  
  -Table Products: Product list
  CREATE TABLE (PRODUCTS)
  PRODUCT_ID INTEGER NOT NULL,
  KEY ("PRODUCT_ID") PRIMARY CONSTRAINT 'PK_PRODUCTS '.
  );
  
  -Orders table: Decreed this product
  CREATE TABLE ORDERS)
  ORDER_ID INTEGER NOT NULL,
  PRODUCT_ID INTEGER NOT NULL, / * FK PRODUCTS (PRODUCT_ID) * /.
  KEY ("ID_PEDIDO") PRIMARY CONSTRAINT 'PK_ORDERS '.
  );
  
  -Orders_Approval table: register when an order is approved
  CREATE TABLE ORDERS_APPROVAL)
  ORDER_ID INTEGER NOT NULL, / * FK ORDERS (ORDER_ID) * /.
  APPROVAL_DATE DATE NOT NULL,
  USER_ID INTEGER,
  KEY("ORDER_ID","APPROVAL_DATE") PRIMARY CONSTRAINT 'PK_ORDERS_APPROVAL '.
  );
  
  -Table Orders_ApprovalData: Register more details on the amenities of the order
  CREATE TABLE ORDERS_APPROVAL_DETAILS)
  APPROVALDET_ID INTEGER NOT NULL,
  ORDER_ID INTEGER NOT NULL, / * FK ORDERS_APPROVAL (ORDER_ID) * /.
  APPROVAL_DATE DATE NOT NULL, / * FK ORDERS_APPROVAL (APPROVAL_DATE) * /.
  KEY ("APPROVALDET_ID") PRIMARY CONSTRAINT 'PK_ORDERS_APPROVAL_DETAILS '.
  );
  
  The thing is that an order may OU cannot be approved. Thus, there could be no record of an order in ORDERS_APPROVAL.
  
  In addition, an order can have more than one approval.
  
  Here is the data that I use:
  
  /===========\
  | PRODUCTS |
  |===========|
  | PRODUCT_ID |
  |===========|
  | 1.
  |===========|
  | 2.
  |===========|
  | 3.
  \===========/
  
  /========================\
  | ORDERS |
  |========================|
  | ORDER_ID | PRODUCT_ID |
  |===========|============|
  | 27. 1.
  |===========|============|
  | 28. 2.
  |===========|============|
  | 29. 3.
  \===========|============/
  
  /=========================================\
  | ORDERS_APPROVAL |
  |=========================================|
  | ORDER_ID | APPROVAL_DATE | USER_ID.
  |===========|================|============|
  | 27. 01/10/2009 | 56.
  |===========|================|============|
  | 27. 04/10/2009 | 96.
  |===========|================|============|
  | 29. 03/10/2009 | 77.
  \===========|================|============/
  
  /=============================================\
  | ORDERS_APPROVAL_DETAILS |
  |=============================================|
  | APPROVALDET_ID | ORDER_ID | APPROVAL_DATE |
  |================|===========|================|
  | 1. 27. 01/10/2009 |
  |================|===========|================|
  | 2. 27. 04/10/2009 |
  |================|===========|================|
  | 3. 29. 03/10/2009 |
  \================|===========|================/
  I need to create a query that returns the data in all tables, but for orders with more than one certification,
  the query must return only the last record. It is also necessary return orders that have not yet been approved.
  
  My first query looked like this:
  
  SELECT
  *
  Of
  ORD IN ORDERS,
  PRODUCT PROD,
  ORDERS_APPROVAL ORDAPPROV,
  ORDERS_APPROVAL_DETAILS ORDAPPDET
  WHERE
  PROD. PRODUCT_ID = DSB. PRODUCT_ID
  AND ORDAPPROV. ORDER_ID (+) IS DSB. ORDER_ID
  AND ORDAPPDET. ORDER_ID (+) IS ORDAPPROV. ORDER_ID
  AND ORDAPPDET. DATA_APPROVAL_DATE (+) IS ORDAPPROV. APPROVAL_DATE
  
  PS: I use the Oracle 8 syntax because it's the server I'll use. In addition, I can't change the design of database.
  
  This query returns the data in table all. Because I used LEFT JOIN "(+)" to join the table orders_approval with the orders table, I am able to see even the orders with no approval.
  
  But this way, I see also two approvals for order 27 (with the data above, this order was approved twice). I need to reach my paintings in the last approval for each order is but should be a left join so I can see the orders with no approval.
  
  I tried this way:
  
  SELECT
  *
  Of
  ORD IN ORDERS,
  PRODUCT PROD,
  ORDERS_APPROVAL ORDAPPROV,
  ORDERS_APPROVAL_DETAILS ORDAPPDET
  WHERE
  PROD. PRODUCT_ID = DSB. PRODUCT_ID
  AND ORDAPPROV. ORDER_ID (+) IS DSB. ORDER_ID
  --Also added the line below
  AND ORDAPPROV. APPROVAL_DATE = (SELECT MAX (APPROVAL_DATE) OF ORDERS_APPROVAL WHERE THE ORDER_ID = ORDAPPROV. ORDER_ID)
  AND ORDAPPDET. ORDER_ID (+) IS ORDAPPROV. ORDER_ID
  AND ORDAPPDET. DATA_APPROVAL_DATE (+) IS ORDAPPROV. APPROVAL_DATE
  
  But in this way, as I am specifying I want only records with approval equal to date at the latest for each order, I do not see the order without approval.
  
  I tried again, with a left join like this:
  
  SELECT
  *
  Of
  ORD IN ORDERS,
  PRODUCT PROD,
  ORDERS_APPROVAL ORDAPPROV,
  ORDERS_APPROVAL_DETAILS ORDAPPDET
  WHERE
  PROD. PRODUCT_ID = DSB. PRODUCT_ID
  AND ORDAPPROV. ORDER_ID (+) IS DSB. ORDER_ID
  --Also added the line below
  AND ORDAPPROV. APPROVAL_DATE (+) = (SELECT MAX (APPROVAL_DATE) OF ORDERS_APPROVAL WHERE THE ORDER_ID = ORDAPPROV. ORDER_ID)
  AND ORDAPPDET. ORDER_ID (+) IS ORDAPPROV. ORDER_ID
  AND ORDAPPDET. DATA_APPROVAL_DATE (+) IS ORDAPPROV. APPROVAL_DATE
  
  But I get a syntax error. Oracle said that it is not possible to do a join with a subquery.
  
  If anyone knows how I can bring all this data?
  
  Thanks in advance.
  
  Published by: user9936895 on 05/10/2009 09:42: tried to fix the predetermined data schema.

  Hello

  Welcome to the forum!

  A scalar, such as subquery

  (SELECT MAX(APPROVAL_DATE) FROM ORDERS_APPROVAL WHERE ORDER_ID=ORDAPPROV.ORDER_ID)
  

  is allowed in a WHERE clause, but not as a condition of outer join, as you discovered.

  A workaround is the query expression so that it is not part of the outer join condition, which invlove in May (as in this case), adding another subquery. In the following query, the table of orders_approval in your original OF Division is replaced with online view, which uses the exact same scalar subquery in the WHERE clause. The online display will only contain one line per order_id (assuming that there is no link with for last approval_date).

  SELECT
       *
  FROM
       orders               ord,
       products          prod,
       (     -- Begin in-line view ORDAPPROV of last approval_date only
       SELECT     *       -- or list the columns needed in main query
       FROM     orders_approval         oa
       WHERE     approval_date = (
                      SELECT  MAX (approval_date)
                      FROM     orders_approval
                      WHERE     order_id     = oa.order_id
                      )
       )                ordapprov,
       orders_approval_details ordappdet
  WHERE
       prod.product_id               = ord.product_id
  AND     ordapprov.order_id (+)          = ord.order_id
  AND     ordappdet.order_id (+)          = ordapprov.order_id
  AND     ordappdet.approval_date (+)     = ordapprov.approval_date
  ;
  

  Thank you for including CREATE TBAL statements; It is very useful.
  You want to be even more useful in the future? Post INSERT statements for the sample data. That will make it easier for people to respond and easier for them to test their ideas.

• Left Outer Join with sum

  Dear elders,
  
  
  
  Firstly, sorry if my question is considered to be 'very novice' but I have this problem of confusion.
  
  Can I use the left outer join with summary?
  For example:
  
  Work table

  JobCode      JobGroupCode      
  111A         1100              
  112B         1100               
  113C         1100
  121A         1200
  333F         3300               

  Table No.

  JobGroupCode    ParentCode
  1100            1000
  1200            1000
  1300            1000
  3300            3000

  Activity table

  Jobcode      Mandays
  111A         5
  112B         7
  113C         3

  I want to choose with this result

  Job.JobCode    Job.JobGroupCode     JobGroup.Parentcode       Mandays
  111A           1100                 1000                      5
  112B           1100                 1000                      7               
  113C           1100                 1000                      3
  121A           1200                 1000                      0
  333F           3300                 3000                      0

  All I did was:

  select j.jobcode, j.jobgroupcode, jg.parentcode, sum(a.mandays)
    from job j
   inner join jobgroup jg on j.jobgroupcode = jg.jobgroupcode
    left join activity a on j.jobcode = a.jobcode
   group by j.jobcode, j.jobgroupcode, jg.parentcode

  and I got was only jobcode activity table, not exactly what I want to get all the work table jobcode. Could you please tell me, where I was wrong?
  
  result

  Job.JobCode    Job.JobGroupCode     JobGroup.Parentcode       Mandays
  111A           1100                 1000                      5
  112B           1100                 1000                      7               
  113C           1100                 1000                      3

  Thank you very much.
  
  Published by: user11197113 on May 25, 2009 03:31
  
  Published by: user11197113 on May 25, 2009 03:32

  Hello (and welcome!).

  Edit

  OK, try this:

  select j.jobcode, j.jobgroupcode, jg.parentcode, NVL(sum(a.mandays),0)
    from job j
   inner join jobgroup jg on j.jobgroupcode = jg.jobgroupcode
    left join activity a on j.jobcode = a.jobcode
   group by j.jobcode, j.jobgroupcode, jg.parentcode
  

  That will give you this:

  JOBC JOBG PARE SUM(A.MANDAYS)
  ---- ---- ---- --------------
  111A 1100 1000              5
  112B 1100 1000              7
  113C 1100 1000              3
  121A 1200 1000              0
  333F 3300 3000              0
  

  These are real results of your test data.

• Outer join with a constant

  Outer join when made between the columns of the two tables is easy to understand and I'm familiar with it. But when it comes to the same join with a constant, my head starts spinning... you guys can help me with this? I would appreciate that show you with examples.
  Thanks a ton.

  Hello

  >
  Ok... I want to understand the output of the last sql statement given here.
  ...
  Select * from a, b
  where col_a (+) = col_b
  and col_a (+) = 1

  It shows put it is as follows
  col_a, col_b
  1 1
  2 NULL
  NULL NULL

  Joining means: 'display all rows in table b and the corresponding rows in the table one '.
  Since it is an outer join, it also means "view b lines even if there is no corresponding row in a.

  Thus, the output contains 3 lines, which correspond to the 3 lines in b.
  Only one of them (the one with col_b = 1) had a game in a.col_a, if the column is NULL in the other lines.

  With the sample data you posted, you will get the same results without condition

  and     col_a (+) = 1
  

  If you want to understand what makes this condition, use some examples of data where this condition would fail.
  For example, add this line to the table a:

  insert into a values (2);
  

  and run your original query (including the)

  and     col_a (+) = 1
  

  ). what output you get? You get the same exact results you did without the new line in a.

  In other words, the b line where col_b = 2 has still no matches in the table has.
  True, there is now a line of table where col_a = 2, but which does not constitute a game. A match is defined by two conditions:

  where   col_a (+) = col_b
  and     col_a (+) = 1
  

  in order to have a pair of lines which meets only the first condition

  where   col_a (+) = col_b
  

  is not enough.

• HELP SQL (auto / full outer join with date corresponding)

  I'm having a hard time get this query nailed... hoping someone can help me sorted.

  create table tab1 (identification number,

  date of eff_date,

  Code1 varchar2 (2),

  Code2 varchar2 (2)

  )

  /

  insert into tab1 values (2, to_date('2015-01-14','YYYY-MM-DD'), 'DAT', 'AS');

  insert into tab1 values (2, to_date('2015-03-19','YYYY-MM-DD'), 'DAT', 'AS');

  insert into tab1 values (2, to_date('2015-08-28','YYYY-MM-DD'), 'DAT', 'AS');

  insert into tab1 values (2, to_date('2015-11-12','YYYY-MM-DD'), 'DAT', 'AS');

  insert into tab1 values (2, to_date('2015-01-03','YYYY-MM-DD'), "DAT", "AE");

  insert into tab1 values (2, to_date('2015-03-14','YYYY-MM-DD'), "DAT", "AE");

  insert into tab1 values (2, to_date('2015-04-18','YYYY-MM-DD'), "DAT", "AE");

  insert into tab1 values (2, to_date('2015-09-14','YYYY-MM-DD'), "DAT", "AE");

  insert into tab1 values (2, to_date('2015-01-14','YYYY-MM-DD'), "DAT", "BS");

  insert into tab1 values (2, to_date('2015-02-14','YYYY-MM-DD'), "DAT", "BS");

  insert into tab1 values (2, to_date('2015-03-14','YYYY-MM-DD'), "DAT", "BS");

  insert into tab1 values (2, to_date('2015-05-14','YYYY-MM-DD'), 'DAT', 'BE');

  insert into tab1 values (3, to_date('2015-09-16','YYYY-MM-DD'), 'DAT', 'AS');

  insert into tab1 values (3, to_date('2015-04-16','YYYY-MM-DD'), "DAT", "AE");

  tab1

  ID, date, code 1, code2

  2. DID DAT 2015-01-14

  2. DID DAT 2015-03-19

  2. DID DAT 2015-08-28

  2. DID DAT 2015-11-12

  2 AE DAT 2015-01-03

  2 AE DAT 2015-03-14

  2 AE DAT 2015-04-18

  2 AE DAT 2015-09-14

  2 BS DAT 2015-01-14

  2 BS DAT 2015-02-14

  2 BS DAT 2015-03-14

  BE DAT 2 2015-05-14

  3. DID DAT 2015-09-16

  3 AE DAT 2015-04-16

  What I need to do...

  1 auto join to match EI for each partition ID

  2. THAT the date must be less than or equal to the date of the AE and when there is more then a line corresponding to this criterion has chosen the date of closest EI of the date of the ACE.

  3. it must be a full outer join because I want to show all lines, even if it is not a match.  There is a beginning, but not record end end gold but no record of departure

  4. If there is an AE line for many AS lines (the SA date is less then equals the date of EI) then join this AE line to all 3 rows of ACE

  5. the same rules for BS and BE.

  result should look like this.

  ID, date, code 1, id_1 code2, date_1, code1_1, code2_1

  2 2015-01-14 DAT AS 2 AE DAT 2015-03-14

  2 2015-03-19 DAT AS 2 AE DAT 2015-04-18

  2 2015-08-28 DAT AS 2 AE DAT 2015-09-14

  2 2015-11-12 DAT DID ZERO ZERO ZERO ZERO

  NO NO NO NO 2 AE DAT 2015-01-03

  2015-01-2 14 DAT BS 2 BE DAT 2015-05-14

  2015-02-2 14 DAT BS 2 BE DAT 2015-05-14

  2015 03-2 14 DAT BS 2 BE DAT 2015-05-14

  3 2015-09-16 DAT DID ZERO ZERO ZERO ZERO

  NO NO NO NO 3 AE DAT 2015-04-16

  My attempt was somewhat along these lines (dealing only with SA / combos AE) but it does not manage the many scenarios one (req 4).

  Select a.*, b.* from

  (select row_number () on the rn (partition by a.id order a.eff_date), a.*)

  of tab1 where a.code2 = 'AS') a

  full outer join

  (select row_number () on the rn (b.eff_date order by b.id partition), b.*)

  tab1 b where b.code2 = 'Æ') b

  on a.id = b.id

  and a.rn = b.rn

  and a.eff_date < = b.eff_date

  Hello

  owbdev99 wrote:

  I'm having a hard time get this query nailed... hoping someone can help me sorted.

  create table tab1 (identification number,

  date of eff_date,

  Code1 varchar2 (2),

  Code2 varchar2 (2)

  )

  /

  insert into tab1 values (2, to_date('2015-01-14','YYYY-MM-DD'), 'DAT', 'AS');

  ...

  Thanks for posting the CREATE TABLE and INSERT.  I know it can be a lot of trouble.  You want to get answers that work, not you?  Make sure that the statements you post too much work.  Test (and, if necessary, attach) your statements before committing.  You said code1 be VARCHAR2, but all the instructions insertion have values of 3 characters for code1.

  You are on the right track, with an analytical function, but ROW_NUMBER solves this problem.  1 "THAT line" could correspond to the 1st, 2nd, 3rd or any other line 'AE' and vice versa.  Try to use the analytical MIN function instead or ROW_NUMBER, like this:

  WITH got_next_e_date AS

  (

  SELECT id, eff_date, code1, code2

  MIN (CASE

  WHEN SUBSTR (code2, 2) = 'E '.

  THEN eff_date

  END

  ) OVER (PARTITION BY ID.

  , SUBSTR (code2, 1, 1)

  ORDER BY eff_date DESC

  ) AS next_e_date

  OF tab1

  )

  s AS

  (

  SELECT *.

  OF got_next_e_date

  "WHERE SUBSTR (code2, 2) s ="

  )

  e

  (

  SELECT *.

  OF got_next_e_date

  WHERE SUBSTR (code2, 2) = 'E '.

  )

  SELECT s.id

  s.eff_date

  s.code1

  s.code2

  e.id AS id_1

  e.eff_date AS eff_date_1

  e.code1 AS code1_1

  e.code2 AS code2_1

  S

  FULL OUTER JOIN e ON s.id = e.id

  AND s.next_e_date = e.eff_date

  AND SUBSTR (s.code2, 1, 1) = SUBSTR (e.code2, 1, 1)

  ORDER OF NVL (s.id, e.id)

  , NVL (SUBSTR (s.code2, 1, 1)

  , SUBSTR (e.code2, 1, 1)

  )

  s.eff_date

  ;

  Out (as you asked):

  ID EFF_DATE CODE1, CODE2 ID_1 EFF_DATE_1 CODE1_1 CODE2_1

  --- ---------- ----- ----- ----- ---------- ------- -------

  2 2015-01-14 DAT AS 2 AE DAT 2015-03-14

  2 2015-03-19 DAT AS 2 AE DAT 2015-04-18

  2 2015-08-28 DAT AS 2 AE DAT 2015-09-14

  2. DID DAT 2015-11-12

  2 AE DAT 2015-01-03

  2015-01-2 14 DAT BS 2 BE DAT 2015-05-14

  2015-02-2 14 DAT BS 2 BE DAT 2015-05-14

  2015 03-2 14 DAT BS 2 BE DAT 2015-05-14

  3. DID DAT 2015-09-16

  3 AE DAT 2015-04-16

  I guess code2 is always 2 characters, and the 2nd character is always ' or 'E '.

  I assume that the combination [id, eff_date, code2] is unique.

  If these assumptions are wrong, you need a few minor changes, but nothing big.

• Join with count() question, please help!

  Hi all
  
  I have this problem (probably simple) that I can't solve... I have 2 tables (tbl_system_engineer and tbl_task_request) here... (only relevant columns are listed below)
  
  tbl_system_engineer
  -id NUMBER
  -full_name VARCHAR2
  
  tbl_task_request
  -tr_number NUMBER
  -submitted_on_date DATE (date of work was presented)
  -ass_comp_date DATE (date of task must be performed)
  -closed_date DATE (date of task was officially closed)
  -applicant NUMBER (the id of system engineer, the person who created this task)
  
  The request is meant to summarize how many of the tasks of engineers system is as follows:
  -"past completion date" - how many tasks have tbl_task_request.closed_date > tbl_task_request.ass_comp_date SYSDATE or > tbl_task_request.ass_comp_date for the engineer
  -' The completion Date approach' - how many tasks have a tbl_task_request.ass_comp_date in this month, but not "past date of completion" of the engineer
  -The calendar"- how many tasks have a tbl_task_request.ass_comp_date > the end of the month SYSDATE and year
  
  Result set lines are supposed to look like...
  'System engineer full name', after the completion date County, approaching County end date, the time count
  
  
  Help, please!

  Hello

  Welcome to the forum!

  This is an example of a Pivot , where you want to GROUP BY a combination of columns and some columns appear different, not different rows as columns.
  The way to do that is to GROUP BY the expressions for which you want to tidy and use CASE expressions for others.
  For example:

  SELECT       e.full_name
  ,       COUNT ( CASE
                 WHEN  r.closed_date     > r.xyz_comp_date
                 OR    SYSDATE          > r.xyz_comp_date
                 THEN  1
                END
              )     AS overdue
  ,       COUNT ( CASE
                 WHEN  xyz.comp_date     <  ADD_MONTHS ( TRUNC(SYSDATE, 'MONTH')
                                                    , 1
                                           )
                 AND   r.closed_date     <= r.xyz_comp_date
                 AND   SYSDATE          <= r.xyz_comp_date
                 THEN  1
                END
              )     AS approaching
  ,       COUNT ( CASE
                 WHEN  xyz.comp_date     >= ADD_MONTHS ( TRUNC(SYSDATE, 'MONTH')
                                                    , 1
                                           )
                 THEN  1
                END
              )     AS on_schedule
  FROM       tbl_system_engineer     e
  JOIN       tble_task_request     r     ON     r.requestor     = e.id
  GROUP BY  e.full_name
  ;
  

  I do not have the versions of your tables, so I can't really test this. I suspect that some consideration for the NULL values must be added to the conditions of the CASE.
  If post you a small example data (CREATE TABLE and only relevant columns, INSERT statements) so people can test their ideas.

  Sometimes, especially when the columns are mutually exclusive, it is more simple calculate a value in a subquery, saying which column of output each line is associated with. That the calculated value is then used in the CASE expressions very simple in the main query,

  Among the features of this awkward site are ithat ir replaces what he thinks are naughty words with s.  I suspect that it happened in your message.  I guess that all of the columns with * are the same, for which I substituted above.

• Inner join with an asymmetric column: plan not optimized SQL

  Hello
  
  I think that it is a FAQ, but I was unable to get a useful answer by Googling.
  
  Oracle version is 11.2.0 on Sparc64.
  
  Consider the following code:
  

  drop table x;
  PROMPT
  PROMPT Populate x with some users. Note the iduser PK
  PROMPT
  
  create table x as
  select 1 iduser, 'PUBLIC' owner from dual
  union
  select 2 iduser, 'SYSTEM' owner from dual
  union
  select 3 iduser, 'XDB' owner from dual
  union
  select 4 iduser, 'APPQOSSYS' owner from dual
  union
  select 5 iduser, 'SYS' owner from dual
  union
  select 6 iduser, 'OUTLN' owner from dual
  union
  select 7 iduser, 'DBSNMP' owner from dual
  /
  
  alter table x add constraint pk_x primary key(iduser);
  
  
  PROMPT
  PROMPT Create a table y from all_objects, but using the previous iduser 
  PROMPT as foreign key (owner column is not needed). Note the index
  PROMPT on column iduser
  PROMPT
  
  drop table y
  /
  create table y as
  select x.iduser, all_objects.*
  from all_objects, x
  where x.owner = all_objects.owner
  and x.owner in  ( 'PUBLIC', 'SYSTEM', 'XDB', 'APPQOSSYS',
      'SYS', 'OUTLN', 'DBSNMP')
  /
  alter table y drop column owner;
  alter table y add constraint y_fk foreign key(iduser) references x;
  create index idx_y on y(iduser);
  
  PROMPT
  PROMPT Take some stats. X stats are irrelevant, I think
  PROMPT
  exec dbms_stats.gather_table_stats( -
      USER, -
      'Y', -
      estimate_percent => DBMS_STATS.AUTO_SAMPLE_SIZE, -
      degree => DBMS_STATS.DEFAULT_DEGREE, -
      cascade => true, -
      method_opt => 'FOR COLUMNS IDUSER SIZE AUTO', -
      granularity => 'ALL' -
  )
  exec dbms_stats.gather_table_stats( -
      USER, -
      'X', -
      estimate_percent => DBMS_STATS.AUTO_SAMPLE_SIZE, -
      degree => DBMS_STATS.DEFAULT_DEGREE, -
      cascade => true, -
      method_opt => 'FOR COLUMNS IDUSER SIZE AUTO', -
      granularity => 'ALL' -
  )
  
  set autotrace trace exp
  
  PROMPT
  PROMPT APPQOSSYS has only 5 objects (well, your output may vary, but it should by
  PROMPT very similar), but the following query ignore the index and do a full scan on Y
  PROMPT
  select x.*, y.*
  from x, y
  where x.owner = 'APPQOSSYS'
  and y.iduser = x.iduser
  /
  
  PROMPT
  PROMPT Virtually, equivalent to the previous one. But the explain plan is very different
  PROMPT and the index is used
  PROMPT
  
  select y.*
  from x, y
  where x.owner = 'APPQOSSYS'
  and y.iduser = 4
  /
  
  set autotrace off

  The result is:
  

  ............................ [snip] .........................
  
  ( EXPLAIN PLAN OF FIRST QUERY)
  
  Execution Plan
  ----------------------------------------------------------
  Plan hash value: 1702571549
  
  ---------------------------------------------------------------------------
  | Id  | Operation          | Name | Rows  | Bytes | Cost (%CPU)| Time     |
  ---------------------------------------------------------------------------
  |   0 | SELECT STATEMENT   |      |   559 | 58136 |   142   (1)| 02:23:19 |
  |*  1 |  HASH JOIN         |      |   559 | 58136 |   142   (1)| 02:23:19 |
  |*  2 |   TABLE ACCESS FULL| X    |     1 |     9 |     2   (0)| 00:02:02 |
  |   3 |   TABLE ACCESS FULL| Y    | 55883 |  5184K|   139   (0)| 02:20:47 |
  ---------------------------------------------------------------------------
  
  Predicate Information (identified by operation id):
  ---------------------------------------------------
  
     1 - access("Y"."IDUSER"="X"."IDUSER")
     2 - filter("X"."OWNER"='APPQOSSYS')
  
  
  
  ( EXPLAIN PLAN OF SECOND QUERY)
  
  Execution Plan
  ----------------------------------------------------------
  Plan hash value: 2241001346
  
  -------------------------------------------------------------------------------------
  | Id  | Operation                   | Name  | Rows  | Bytes | Cost (%CPU)| Time     |
  -------------------------------------------------------------------------------------
  |   0 | SELECT STATEMENT            |       |    10 |   950 |     2   (0)| 00:02:02 |
  |   1 |  TABLE ACCESS BY INDEX ROWID| Y     |    10 |   950 |     2   (0)| 00:02:02 |
  |*  2 |   INDEX RANGE SCAN          | IDX_Y |    10 |       |     1   (0)| 00:01:01 |
  -------------------------------------------------------------------------------------
  
  Predicate Information (identified by operation id):
  ---------------------------------------------------
  
     2 - access("Y"."IDUSER"=4)

  Well, the question is very simple: is it possible to get the first query to take the index and to avoid complete analysis? With no clues, of course.
  
  All of your advice and comments will be welcome. Thanks in advance.
  
  Best regards

  jjuanino wrote:

  Well, the question is very simple: is it possible to get the first query to take the index and to avoid complete analysis? With no clues, of course.

  All of your advice and comments will be welcome. Thanks in advance.

  This is a limit known optimizer - no realistic solution.

  The optimizer can recognize with the help of a histogram iduser on table column is very unevenly distributed, but there is not a generic strategy to recognize what owner on the table of X corresponds to what iduser on the table of Y.

  An approach that can help - even if I do not remember seeing documented is to rewrite the query with a subquery and use the / * + precompute_subquery * / tip.
  I have not tried with your data, but something like:

  select * from y
  where iduser in (
      select /*+ precompute_subquery */ x.iduser
      from x
      where owner = 'APPQSYS'
      )
  ;
  
  Regards
  Jonathan Lewis
  
  P.S.  Found a reference note by Tanel Poder: http://blog.tanelpoder.com/2009/01/23/multipart-cursor-subexecution-and-precompute_subquery-hint/
  

• Firefox 18.0.2 aligns with full screen in Windows 7 (32 bit) even when I slide sideways. Anyone else seeing this?

  Windows 7 align on the net somewhere around 15 FF (FF drag window to the left or right edge of the desktop) has stopped working. FF now aligns only on the full screen. It's really a pain since I often have two Windows Open (FF at the request of the half, such as excel or outlook open in the other half). I keep hope it is fixed with the next version, but I see that this problems with 18.0.2.

  Safe mode is a good suggestion. Snap of half-screen FF has worked in safe mode. I then jumped back to normal mode and started disabling add until I figured out that you caused the problem (FindBar Tweak 0.5.5). All better now. Thank you!

• How can satellite P500-024 - I do a new partition with full disk space?

  Hello

  I just bought the Satellite P500-024 and it came with 640 GB HARD drive.

  I just found when clicking on * my computer * which is the HARD drive is cut to the drive C: and D: drive. How can I add the D drive half of the HARD drive on the C: drive of priority so there because I then a full accese 640GO HDD in a chase without cutting 50-50?

  The reason why I ask this is because I noticed when I turn on the laptop it takes ages and maybe a bit slower due to the fact that it is half of the hard drive on drive C. So I want to know how it is easy to add them together into one so that I can get fast and pure to my new Satellite P500-024 performance.

  Thank you.

  Hi tagvic!

  First of all I must say that the two partitions have nothing to do with the slow start procedure on your laptop. Your laptop will be no faster if I you have only one partition, made it s! In addition, the second partition is required for Toshiba HDD recovery option. You know about it?

  HARD drive recovery option is really nice. You can restore factory in a few minutes. For it pour l' utiliser use go from the advanced boot menu, and then select Repair my computer. Then, you can select this option and follow the instructions on the screen. The first partition will be deleted, and after that it will have installed an image of factory settings. This means that you return to the same state that you started the laptop, the first time. The operating system preinstalled with already all the drivers and tools are installed.

  In my view, there is another reason for the slow start to the top. You should try to remove Toshiba Tempro. On my computer it causes a slow start too, and after removing the laptop started much faster.
  I can also recommend you to clean the system using CCleaner and defragment the HARD drive. Removal of startup programs folder that you don't need and try another program like AntiVir AntiVirus.

  I hope I could help a bit.