left join on 1 table

Hello

I was wondering table just if possible to join the 1. The reason why Im asking that her because in my table, I have an activity_id and a parent_activity_id. I want to show the parent and the child in different columns. See below:

create table activity (
  activity_id number,
  parent_activity_id number
);



insert into activity values (12500, null);
insert into activity values (12501, null);
insert into activity values (12502, null);


insert into activity values (12503, 12500);
insert into activity values (12504, 12501);
insert into activity values (12505, 12502);

insert into activity values (12506, 12500);
insert into activity values (12507, 12501);
insert into activity values (12508, 12502);

If the result will be:

Parent	Child
12500	12503
12500	12506
12501	12504
12501	12507
12502	12505
12502	12508

Any help is appreciated. Thank you...

Kind regards

Thanks for posting of sample data. You need hierarchical query.

SQL> select connect_by_root(activity_id) parent_activity_id, activity_id
  2    from activity
  3   where connect_by_isleaf = 1
  4   start with parent_activity_id is null
  5  connect by parent_activity_id = prior activity_id;

PARENT_ACTIVITY_ID ACTIVITY_ID
------------------ -----------
             12500       12503
             12500       12506
             12501       12504
             12501       12507
             12502       12505
             12502       12508

6 rows selected.

Tags: Database

Similar Questions

Left join between two tables using two different conditions
I have following three tables with their data, as shown below.

CREATE TABLE TIREMASTERPROCESS_TEMP
(
PRODUCTIONCODE TANK (12 BYTES),
FIELDNAME CHAR (12 BYTES),
DATACHR VARCHAR2 (60 BYTE),
REVISIONNO TANK (3 BYTES),
DATANUM NUMBER (9.4)
)
Whether the table c. and its sample data are like

FIELDNAME DATACHR REVISIONNO DATANUM PRODUCTIONCODE
AB No. Nch 1 100 0
AB No. Nch 1 108 0
AB No.-of-Nch 1 1 0
Ass42 teased dishes 1 0
Ass42 BTDrumNo1 BTD-051 1 0
AB53 BTDrumNo1 BTD-051 104 0

CREATE TABLE materialcode
(
UPPERMATERIALCODE CHAR (20),
PROCESSNO TANK (3),
PROCESSADOPTDATE TANK (9)

)
Whether the table b. and its sample data are like

UPPERMATERIALCODE PROCESSNO PROCESSADOPTDATE
Ass42 1 20120717
AB53 108 20121121
111 20111104 AS05
104 20120928 AS30

CREATE TABLE BUILDINGSCHEDULEMASTER
(
BUILDINGSIZE TANK (5 BYTES),
GTCODE FLOAT (4 BYTES),
TIREPERCART NUMBER (3.0).
BUILDINGLOT NUMBER (3.0)
)
Whether table and its sample data are like

BUILDINGSIZE GTCODE TIREPERCART BUILDINGLOT
AB42A 4 12 ass42
AB53A 4 88 AB53
AS30A AS30 4 80
BF03A 1 90 BF03

Now, I need to get some data in these fields by using the suite of mappings.

« PR_ » || Trim (a.BUILDINGSIZE) | ' / MPL2' Processid,--PRIMARY KEY
TO_DATE (substr (NVL(b.PROCESSADOPTDATE,'19800101'), 7, 2) |) » /'|| SUBSTR (NVL(b.PROCESSADOPTDATE,'19800101'), 5, 2) | » /'|| SUBSTR (NVL(b.PROCESSADOPTDATE,'19800101'), 1, 4). (' 01:00:00 ',' dd-mm-yyyy hh24:mi:ss') starteff, to_date (SUBSTR (NVL(b.PROCESSADOPTDATE,'19800101'), 7, 2) |) » /'|| SUBSTR (NVL(b.PROCESSADOPTDATE,'19800101'), 5, 2) | » /'|| SUBSTR (NVL(b.PROCESSADOPTDATE,'19800101'), 1, 4). (' 01:00:00 ',' dd-mm-yyyy hh24:mi:ss') startDate.
b.PROCESSNO revisioncodeid,
a.BUILDINGLOT tirepercart ,
CASE WHEN c.FIELDNAME = 'BTDrumNo1' then c.DATACHR end drumtype1.
BOX WHEN (trim (C.DATACHR) = '1' and trim (C.FIELDNAME) = "No. Nch") and THEN click 'YES '.
ANOTHER 'NO '.
END may-BUG,
case
When c.FIELDNAME = 'Wavy'
AND c.DATACHR = 'Use' THEN on 'YES '.
When c.FIELDNAME = 'Wavy'
AND c.DATACHR <>'Use' THEN 'NO '.
fine wavy

Now for the tables A and B I have the simple join as condition

a.GTCODE = b.UPPERMATERIALCODE

But I have to use two different left join conditions to join the table B and C to calculate the RESP fields according to the condition.
Now, I have to use

(trim (b.UPPERMATERIALCODE)). » -'|| Trim (b.PROCESSNO) = Trim (c.PRODUCTIONCODE) | » -'|| Trim (c.REVISIONNO)

condition to get the data for the WAVY and DRUMTYPE1 fields.

But at the same time, I have to use

substr (Trim (b.UPPERMATERIALCODE), 1, 2). » -'|| Trim (b.PROCESSNO) = Trim (c.PRODUCTIONCODE) | » -'|| Trim (c.REVISIONNO)

conition to derive the CHAFER field.

And for this reason I am come so many duplicates and do not correct results for JUNEBUG, WAVY, DRUMTYPE1, and STARTDATE field.

I need some advice as how can I do so that I get the correct results without duplicates for the PRIMARY KEY.

Thank you

Mahesh
It would have been easier to answer if you gave us your example query that gives incorrect results - which both show us what you are doing and give us a starting point.
Insert instructions for data, rather than only the data would have helped too, making it more quick to test this point.
You do not show what you have done with your two outer join criteria, but I think you need to list TIREMASTERPROCESS_TEMP in your query twice, with alias names. Here's what I did:
```
select a.BUILDINGSIZE, a.GTCODE, b.PROCESSNO ,  c1.FIELDNAME, c1.DATACHR, C2.FIELDNAME, C2.DATACHR
, CASE WHEN c1.FIELDNAME='BTDrumNo1' then c1.DATACHR end drumtype1
, CASE WHEN (trim(c2.DATACHR) = '1' and trim(c2.FIELDNAME) = 'No-of-Nch') THEN 'YES' ELSE 'NO' END CHAFER
, case when c1.FIELDNAME='Wavy' AND c1.DATACHR='Use' THEN 'YES'
       when c1.FIELDNAME='Wavy' then 'NO' else null end wavy
from BUILDINGSCHEDULEMASTER        A
join materialcode b on a.GTCODE=b.UPPERMATERIALCODE
left outer join TIREMASTERPROCESS_TEMP c1
   ON trim(b.UPPERMATERIALCODE)||'-'||trim(b.PROCESSNO) = trim(c1.PRODUCTIONCODE)||'-'||trim(c1.REVISIONNO)
left outer join TIREMASTERPROCESS_TEMP c2
   ON substr(trim(b.UPPERMATERIALCODE),1,2)||'-'||trim(b.PROCESSNO) = trim(c2.PRODUCTIONCODE)||'-'||trim(c2.REVISIONNO)
```
C1 is an alias for the TIREMASTERPROCESS_TEMP line which is necessary for drumtype1 and wavy, c2 is an alias for the TIREMASTERPROCESS_TEMP line required for JuneBug. There was some minor errors in your calculations of field I tried to correct.

The results are:
```
BUILD GTCO PRO FIELDNAME    DATACHR    FIELDNAME    DATACHR    DRUMTYPE1  CHA WAV
----- ---- --- ------------ ---------- ------------ ---------- ---------- --- ---
AB53A AB53 108                         No-of-Nch    1                     YES
AB42A AB42 1   BTDrumNo1    BTD-051    No-of-Nch    1          BTD-051    YES
AB42A AB42 1   Wavy         NotUse     No-of-Nch    1                     YES NO
AS30A AS30 104                                                            NO
```
Hope this helps,
David

Left join on 3 tables
I have 3 tables to know

CUREPRESSMASTER,
CUREBLDGMACHINECONDITION,
NAMINGMASTER

with the structure of each table as
CUREPRESSMASTER: -.
CUREPRESS CHAR (5)
PRESSTYPE TANK (8)
CURINGGROUP CHAR (2)

examples of data
"CUREPRESS" "PRESSTYPE'"CURINGGROUP ".
'M02' "HAM OF 63.5" "31".
"M03" "HAM OF 63.5" "31".
"M04" "HAM OF 63.5" "31".
"M05" "HAM OF 63.5" "31".
"M06" "63.5" "31".
"M07" "HAM OF 63.5" "31".
"S03" "63.5" "31".
"S04" "HAM OF 63.5" "31".
"S05" "HAM OF 63.5" "31".

CUREBLDGMACHINECONDITION: -.
GROUPID (2) TANK
MACHINENAME CHAR (5)
DATA01 CHAR(10)
DATA02 CHAR(10)
Samples: -.

'GROUPID' "MACHINENAME" "DATA01" "DATA02.
'30' 'M03' "63.5" "UNDER".
'30' 'M04""63.5""UNDER ".
'30' 'M05""63.5""UNDER ".
'30' 'M06""63.5""UNDER ".
'30' 'M07""63.5""UNDER ".
"30" "M08" "63.5" "UNDER".

NAMINGMASTER: -.
IETS1 CHAR (1)
CLASSEMENT2 CHAR (2)
CERTIFICATE3 TANK (2)
NAMING2 CHAR (10)

Samples: -.
"IETS1" "CLASSEMENT2" "CERTIFICATE3'"NAMING2 ".
"0' '52" "31" "281".
'0' '69' "31" "110".
'2' '30' "31" "TBR".
"3' '30'"31""TIRE PLANT. "
"0' '51" "31" "261".
"A" "30" "31" "RP".
"A" "31" "31" "RP".
"H'" ""31""MTRLBhind. "
"J"     "01"     "31"     ""
"L"     "01"     "31"     ""
"G"     " "     "31"     ""
"8" "" "31" "CambioMedi."

Now, I want to have all the rows of the table CUREPRESS left join with two other tables as specified below.
CUREPRESSMASTER. CUREPRESS = CUREBLDGMACHINECONDITION. MACHINENAME
CUREPRESSMASTER. CURINGGROUP = NAMINGMASTER. CERTIFICATE3.

Now I want to select the following columns as CUREPRESS, PRESSTYPE, NAMING2, DATA01 DATA02 after leaving the joints as shown above and curepress as primary key.

When I tried using a General left join she gave much more duplicate rows.
I have 100 lines in curepress, then I would have only 100 lines in the final result but I get my as 233 lines output, this may be due to CUREPRESSMASTER. CURINGGROUP = NAMINGMASTER. Certificate3 this condition.

Please suggest me some queries.
This may be due to CUREPRESSMASTER. CURINGGROUP = NAMINGMASTER. Certificate3 this condition.

Yes. Because the above join result in one-to-MANY relationship. Look at your data
```
CUREPRESS PRESSTYPE CURINGGROUP
--------- --------- -----------
M02       63.5 HAM  31
M03       63.5 HAM  31
M04       63.5 HAM  31
M05       63.5 HAM  31
M06       63.5      31
M07       63.5 HAM  31
S03       63.5      31
S04       63.5 HAM  31
S05       63.5 HAM  31          

 9 rows selected 

CLASSIFICATION1 CLASSIFICATION2 CLASSIFICATION3 NAMING2
--------------- --------------- --------------- ----------
0               52              31              281
0               69              31              110
2               30              31              TBR
3               30              31              TIRE PLANT
0               51              31              261
A               30              31              PSR
A               31              31              PSR
H                               31              MTRLBhind
J               01              31
L               01              31
G                               31
8                               31              CambioMedi 

 12 rows selected 
```
The value is 31 for all rows in the table two. And so 9 * 12 output will be 108 lines. Its one expected result how you expect to only 9 lines?

You can show us your results as well. I guess you are missing some basic business requirements. Show us your results.

Left join with three-table join query
I am trying to create a query that left me speechless. Most of the query is simple enough, but I have a problem I do not know how to solve.

Background:
We have stock stored in i_action.

We have the attributes available for each type of action. The attributes available for each action are described in shared_action_attribute. Each type of action can have three attributes or none at all.

We have the values stored for the attributes in i_attribute_value.

An example says:
We have a transfer action (action_code B4). The action of B4 entry into i_action records the fact that the transfer took place and the date at which he spoke. The attributes available for a transfer action are the function code receiver, the receiving unit number and the reason of transfer code. These types of attributes available and their order are stored in shared_action_attribute. The actual values of the attributes for a specific action of transfer are stored in i_attribute_value.

Now i_action and i_attribute_value can be connected directly in action_seq in i_action and ia_action_seq in i_attribute_value. A left join on these two tables provides results for all actions (including actions that have no attributes) and assign values (see Query 1 below).

There are two questions. First of all, I want only the first two attributes. To specify the attributes of the first two, I also i_attribute_value a link to shared_action_attribute (which is where the order is stored). I can build a simple query (without the left join) which connects the three tables, but then shares without attributes would be excluded from my result (see Query 2 below).

The second problem is that I'd actually a row returned for each action with first_attribute and second_attribute in the form of columns instead of two lines.

The final query will be used to create a materialized view.

Here are the tables and examples of what is stored in the:

TABLE i_action
Name Type
----
ACTION_SEQ NUMBER (10)
DATE OF ACTION_DATE
ACTION_CODE VARCHAR2 (3)
VARCHAR2 (1) DELETED

EXAMPLE OF LINES
ACTION_SEQ ACTION_DATE DELETED ACTION_CODE
----
45765668 9 OCTOBER 09 B2 HAS
45765670 9 OCTOBER 09 BA HAS
45765672 B6 9 OCTOBER 09A
45765673 9 OCTOBER 09 B4 HAS
45765674 9 OCTOBER 09 G1 HAS
45765675 9 OCTOBER 09 M3 HAS

TABLE i_attribute_value
Name Type
---
IA_ACTION_SEQ NUMBER (10)
SACTATT_SACT_CODE VARCHAR2 (3)
SACTATT_SAT_TYPE VARCHAR2 (3)
VARCHAR2 VALUE (50)

EXAMPLE OF LINES
IA_ACTION_SEQ SACTATT_SACT_CODE SACTATT_SAT_TYPE VALUE
----
45765668 B2 COA 37 B
45765670 BA ROA D
45765670 BA ROR P
45765672 B6 CAT C
B4 45765673 RFC E
45765673 B4 TRC P
B4 45765673 RUN 7
45765674 G1 SS 23567
G1 45765674 ASG W

TABLE shared_action_attribute
Name Type
---
SACT_CODE VARCHAR2 (3)
SAT_TYPE VARCHAR2 (3)
ORDER NUMBER (2)
TITLE VARCHAR2 (60)

EXAMPLE OF LINES
SACT_CODE SAT_TYPE UNDER THE ORDER
----
B2 ACO 1 Office code
BA ROR 1 reason to re-open
Authority of BA ROA 2 reopen
B6 CAT 1 category
B4 RFC 1 reception function code
B4 RUN 2 receives the unit code
B4 TRC 3 transfer of reason code
Sequence of G1 SS 1 personal
Reason for G1 ASG 2 assignment

QUERY 1:
It's my current query as well as its results. Most are select simple but only one column is filled using the function analytic last_value (thank you guys). The last column in the view sub stores the value of the attribute. What I want is to replace this single column with two columns named first_attribute and second_attribute and eliminate all other attributes.
SELECT ia.action_seq, ia.action_date, ia.action_code cod,
NVL
(LAST_VALUE (CASE
WHEN ia.action_code = "G1".
AND iav.sactatt_sat_type = 'SS '.
THEN THE VALUE
WHEN ia.action_code IN ('A0', 'A1')
THEN '67089'
END IGNORE NULLS
) OVER (PARTITION BY ia.ici_charge_inquiry_seq ORDER BY ia.action_date,
IA.serial_number, ia.action_seq),
'67089'
) staff_seq,.
value
From i_action LEFT JOIN i_attribute_value iav AI
ON iav.ia_action_seq = ia.action_seq
WHERE ia.deleted = 'A ';

ACTION_SEQ ACTION_DA COD STAFF_SEQ VALUE
----
45765668 9 OCTOBER 09 B2 67089 37 B
45765670 9 OCTOBER 09 BA D 67089
45765670 9 OCTOBER 09 BA 67089 P
45765672 9 OCTOBER 09 B6 67089 C
45765673 9 OCTOBER 09 B4 67089 E
45765673 9 OCTOBER 09 B4 67089 P
45765673 9 OCTOBER 09 67089 7 B4
45765674 9 OCTOBER 09 23567 23567 G1
45765674 9 OCTOBER 09 G1 23567 W
45765675 9 OCTOBER 09 M3 23567

QUERY 2:
This query is limited to the first two attributes but he also filed actions which have no attributes, and it creates still several lines for each action instead of a single line with two columns for attributes.
SELECT ia.action_seq, ia.action_date, ia.action_code cod,
NVL
(LAST_VALUE (CASE
WHEN ia.action_code = "G1".
AND iav.sactatt_sat_type = 'SS '.
THEN THE VALUE
WHEN ia.action_code IN ('A0', 'A1')
THEN '67089'
END IGNORE NULLS
) OVER (PARTITION BY ia.ici_charge_inquiry_seq ORDER BY ia.action_date,
IA.serial_number, ia.action_seq),
'67089'
) staff_seq,.
value
OF shared_action_attribute saa, ims_action AI, ims_attribute_value iav
WHERE iav.ia_action_seq = ia.action_seq
AND iav.sactatt_sact_code = saa.sact_code
AND iav.sactatt_sat_type = saa.sat_type
AND saa.display_order IN ('1 ', ' 2')
AND ia.deleted = 'A ';

ACTION_SEQ ACTION_DA VALUE OF COD
----
45765668 9 OCTOBER 09 B2 67089 37 B
45765670 9 OCTOBER 09 BA D 67089
45765670 9 OCTOBER 09 BA 67089 P
45765672 9 OCTOBER 09 B6 67089 C
45765673 9 OCTOBER 09 B4 67089 E
45765673 9 OCTOBER 09 67089 7 B4
45765674 9 OCTOBER 09 23567 23567 G1
45765674 9 OCTOBER 09 G1 23567 W

I found it quite complex to try to write - I hope that I was clear.

Thank you very much!
Hello

You can use an alias for column (such as staff_seq) in the ORDER BY. Unfortunately, it's the only place where you can use it in the same query, where it was defined.
You can use it anywhere in the super-requetes, however, so you can still work around this problem in assigning the aliases in a subquery and GROUP BY (or other) in a Super query, like this:
```
WITH   ungrouped_data      AS
(
    SELECT ia.action_seq, ia.action_date, ia.action_code,
          NVL
              (LAST_VALUE (CASE
                              WHEN ia.action_code = 'G1'
                               AND sactatt_sat_type = 'SS'
                                 THEN VALUE
                              WHEN ia.action_code IN ('A0', 'A1')
                                 THEN '67089'
                           END IGNORE NULLS
                          ) OVER (PARTITION BY ia.ici_charge_inquiry_seq ORDER BY ia.action_date, ia.action_seq),
               '67089'
              )staff_seq,
           (CASE
              WHEN display_order = '1'
              THEN VALUE
           END) first_attribute,
           (CASE
              WHEN display_order = '2'
              THEN VALUE
           END) second_attribute
      FROM i_action ia
      LEFT JOIN i_attribute_value iav
           ON iav.ia_action_seq = ia.action_seq
      LEFT JOIN shared_action_attribute
           ON sactatt_sact_code = sact_code
         AND sactatt_sat_type = sat_type
     WHERE ia.deleted = 'A'
)
SELECT       action_seq
,       action_date
,       action_code
,       staff_seq
,       MIN (first_attribute)          AS first_attribute
,       MIN (second_attribute)     AS second_attribute
FROM       ungrouped_data
GROUP BY  action_seq
,       action_date
,       action_code
,       staff_seq
;
```
There are other alternatives for special cases, but none of them work in this particular case.

Left join for three tables
Hello

I wrote the following example query,

SELECT a.acc_rk
A,.
b,
c
WHERE a.acc_rk = b.acc_rk
AND b.acc_rk = c.acc_rk;

Now I need to change equi join left join
I have the left join table 'a' with table "b".
and again, I have to make tables of left join 'b' and 'c '.

Can someone tell me how to do this.

Thank you
Radha K
AJ99 wrote:
```
SELECT a.acc_rk
FROM (a LEFT JOIN b ON a.acc_rk = b.acc_rk)
LEFT JOIN c ON b.acc_rk = c.acc_rk;
```
There is no need for media. ;)
```
SELECT a.acc_rk
  FROM a LEFT JOIN b ON a.acc_rk = b.acc_rk
       LEFT JOIN c ON b.acc_rk = c.acc_rk;
```

Left join to another database
Hello
I had a scenario where I need to write a query that gets SQL Server database records, but have a left join on Oracle table, I know we can achiev this link between Oracle and SQL DB, but my team of DB are unwilling to create links from DB, is there a way probably from data models We can write a query that can call Oracle table too?
Here is an article from blog of tim on the subject:

http://blogs.Oracle.com/XmlPublisher/2008/07/multiple_datasources_i.html

Why left outer join with a table gives me more lines?

Hi gurus,
I can see "view_a" and a table 'table_a '.
view_a a county of 100 lines. Now, when I left outer join that discovers with a 'table_a', I expect all 100 lines.
However, I'm more than 100 lines. Is it still possible?
Also even to analyze these situations, how can I move forward?
Because it is very high volumn of sight and takes longer to run.
Select count (*) view_a, view_b
where view_a.col1 = view_b.col1 (+)
and view_a.col2 = view_b.col2 (+);
Thank you

I can see "view_a" and a table 'table_a '.

view_a a county of 100 lines. Now, when I left outer join that discovers with a 'table_a', I expect all 100 lines.

However, I'm more than 100 lines. Is it still possible?

Also even to analyze these situations, how can I move forward?

Because it is very high volumn of sight and takes longer to run.

Select count (*) view_a, view_b

where view_a.col1 = view_b.col1 (+)

and view_a.col2 = view_b.col2 (+);

Which is not necessarily related to the use of an outer join.

Just join of two tables in general will give you more rows of one table has.

Scott DEPT table contains ONE row for deptno = 10

The EMP table has THREE rows of deptno = 10

The number of rows you plan if you join two tables using an equi-join?

Three - what is MORE lines the DEPT table has for deptno = 10

Select * from Department where deptno = 10

DEPTNO, DNAME, LOC
10, ACCOUNTING, NEW YORK

Select * from emp where deptno = 10

MGR, EMPLOYMENT ENAME, EMPNO, HIREDATE, SAL, COMM, DEPTNO
7782, CLARK, MANAGER, 7839, 6/9/1981,2450, 10
7839, KING, PRESIDENT, 17 NOVEMBER 00, 10
7934, MILLER, CLERK, 7782, 23 JANUARY 00: 10

Select dept.*, emp.*
Department, emp
where dept.deptno = 10
and dept.deptno = emp.deptno

DEPTNO, DNAME, LOC, EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO_1
10, ACCOUNTING, NEW YORK, 7782, CLARK, MANAGER, 7839, 6/9/1981,2450, 10
10, ACCOUNTING, NEW YORK, 7839, KING, PRESIDENT, 17 NOVEMBER 00, 10
10, ACCOUNTING, NEW YORK, 7934, MILLER, CLERK, 7782, 23 JANUARY 00: 10

So if these are the lines ONLY in the table EMP and DEPT the query would give you THREE lines despite the DEPT table only ONE line.

No do you expect? You get ALL the child rows that belong to the parent company. Otherwise, how could it possibly work?

The OUTER join includes lines where the parent row exists but there is NO child line as others have shown.

Outer joins

Outer join extends the result of a simple join. Outer join returns all rows that satisfy the join condition and also returns some or all rows in a table for which no line of the other meet the join condition.

Get more lines to exist in one of the paintings is a basic necessity. It usually has NOTHING to with the question of whether you have an outside to join or not.

See the section on the JOINTS in the Oracle documentation

http://docs.Oracle.com/CD/B28359_01/server.111/b28286/queries006.htm

Left join of the two tables and multiple values into a single value separated by commas

Hello
I have following tables with their structures and their data as below.
CREATE TABLE 'BETODI '. "" BETINFO ".
(
VARCHAR2 (8 BYTE) "CURRENTPRESS."
ENABLE 'TYPEIDCONTAINER' VARCHAR2 (30 BYTE) NOT NULL
)
INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A24G', 'PMC');
INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A24D', 'Pensky-MARTENS');
INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ("A25D", "CMP");
INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A25G', 'PMC');
INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A26D', 'PMC');
INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A26G', 'PMC');
INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ("A32G", "V-BFC3");
INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A32D', "V-BFC2");
CREATE TABLE 'BETODI '. "" BETMASTER ".
(
ACTIVATE THE "CUREPRESS" TANK (5 BYTES) NOT NULL,
ACTIVATE THE "TYPE" VARCHAR2 (5 BYTE) NOT NULL,
NUMBER (5.0) "LASTPCIRIM".
)
INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A24', '45 M 8', 15);
INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A25', 42 16', 15);
INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ("A26", 16' 45, 15);
INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ("A27", '45 M 34', 16);
INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A28', '45 M 34', 16);
INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A29', '45 M 34', 16);
INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A30', '45MCH', 15);
INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ("A31", "45MCH", 16);
INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A32', '45MCH', 16);
INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A33', '45MCH', 16);
INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ("A34", "45MCH", 16);
These two tables have left join as
BETMASTER. CUREPRESS = substr (BETINFO. CURRENTPRESS, 1, 3)
now I want to have the data in the two tables with fields Curepress, Lastpcirim, typeidcontainer.
Also something like
Make a group of typeidcontainer if this value is greater than 1 by press separated the values of semicolon (;)
So, for example above, we should be given as
A24 PMC 15; PENSKY-MARTENS
A25 15 PMC
A26 15 PMC
A27 16 (NULL)
A28 16 (NULL)
A30 15 (NULL)
A31 16 (NULL)
A32 16 BFC2-V; V BFC3
A33 16 (NULL)
A34 16 (NULL)
How could do?
My current request is as
Select distinct Curepress, lastpcirim, typeidcontainer
BETMASTER STD left join INF BETINFO
on the trim (STD. CUREPRESS) = substr (trim (INF. CURRENTPRESS), 1, 3)
but I am unable to get the values separated by commas.
Any help would be appreciated.
Thank you
Mahesh.

Hi, Mahesh,

If you want to only 1 row of output for each distinct combination of currentpress and lastpcirim? This sounds like a job for GROUP BY.

And you want the row to contain a list of all different typidcontainers-delimited? This sounds like a job for the aggregate LISTAGG function.

WITH joined_data AS

(

SELECT DISTINCT

MST.curepress, mst.lastpcirim, inf.typeidcontainer

OF betmaster STD

LEFT JOIN betinfo ON TRIM (mst.curepress) inf = SUBSTR (TRIM (inf.currentpress)

1

3

)

)

SELECT curepress, lastpcirim

LISTAGG (typeidcontainer, ',')

THE Group (ORDER BY typeidcontainer) AS container_list

OF joined_data

Curepress GROUP, lastpcirim

;

Unfortunately, you can't say LISTAGG (DISTINCT ...), so you should always get the separate containers how you already are. (Note that the subquery is just what you posted).

Thanks for posting the CREATE TABLE and INSERT statements; It is very useful. Don't forget to tell what version of Oracle you are using. LISTAGG was new in Oracle 11.2.

Why not add CHECK constraints (and perhaps triggers) to your tables, so that curepress and currentpress are not stored with the head or trailing spaces? Then you wouldn't need to use the PAD in queries like this, and your code would be simpler and more effective.

The left join - no data in the table don't want to display the data from the table one

Hello

I'm writing a query. Here is my scenario, I have two tables EMP and EMP_TYPE. I want to join both the table and even if there is no matching record in the table for EMP EMP_TYPE, I want to return the record to the EMP table and empty values of EMP_TYPE.

create table EMP

(

  EMPID   NUMBER(10,2),

  EMPNAME VARCHAR2(100)

);

 

INSERT INTO emp (empid,empname) values (1, 'abc');

INSERT INTO emp (empid,empname) values (2, 'xyz');

INSERT INTO emp (empid,empname) values (3, 'UNJ');

 

create table EMP_Type

(

  ID          NUMBER(10,2),

  EMPID       NUMBER(10,2),

  TYPE_ID     NUMBER(10,2),

  END_DATE    DATE

);

 

INSERT INTO EMP_Type(id, empid, TYPE_ID, END_DATE) values (100, 2, 1, SYSDATE);

 

select *

  from emp e

  left outer join emp_Type t

    on e.empid = t.empid

 and t.type_id = 1



returns.



        EMPID     EMPNAME     ID             EMPID     TYPE_ID     END_DATE

     2.00             xyz            100.00     2.00             1.00             10/9/2012 5:18:59 PM

     3.00             UNJ                    

     1.00             abc                    





select *

  from emp e

  left outer join emp_Type t

    on e.empid = t.empid

 and t.type_id = 1

 and t.empid = 3



returns



        EMPID     EMPNAME     ID             EMPID     TYPE_ID     END_DATE

     2.00             xyz                 

     3.00             UNJ                    

     1.00             abc          



but instead I want



        EMPID     EMPNAME     ID             EMPID     TYPE_ID     END_DATE

     3.00             UNJ

Your conditions of conflict
>
and t.type_id = 1
and t.empid = 3
>
There is a record with t.empid 3

select *
  from empx e, empx_Type t
where e.empid = 3
  and e.empid = t.empid (+)

EMPID,EMPNAME,ID,EMPID_1,TYPE_ID,END_DATE
3,UNJ,,,,

LEFT JOIN increases the number of lines

Hi guys,.
I had a problem, my left join retrieves multiple values. I know he has only 252 in there that correspond to the place where
condition. If I use the table in a left join with the same condition where my row count increases.
-1176 lines
Select count (erg_ID) of
MySchema. T_STA_ERG sta_erg
INNER JOIN T_MEN hoechst
ON sta_erg. PARAMETER = hoechst. PARAMETER
AND sta_erg. JAHR = 2014
where sta_erg. MESSERG_KNG = 'A' AND sta_erg. MESSERG_ALPHA IN ('03 ") and sta_erg. NORM_MESS is null
-252 lines
Select distinct erg_ID myschema. T_STA_ERG sta_erg where sta_erg. MESSERG_KNG = 'A' AND sta_erg. MESSERG_ALPHA IN ('03 ") and sta_erg. NORM_MESS is null
any clue´s how I can build in conditions in my join which would not increase the results of the line?

Why not just an inner join then?

Clarification on NULL or behavior LEFT JOIN behavior

Good day ladies------Gentlemen\ gurus-Experts-and Al:
Just when I thought I got my mind wrapped around the notion of NULL value, as defined by Oracle, I met what follows below. Basically, what you are watching is how our employees of the human resources tables are set up (for the most part). We have the employees, employee contracts table and the tables of positions. When I want to make a list of active staff, I always use the filter end date, you will see below in the Super request, essentially looking for staff who do not have a contract AND a position end date entered in the DB. It works like a charm. However, today, I noticed an official on the list, who has never had a position is entered in the comic book, and he had an 'open' contract In my example below, why would "Hal Jordan" appear on the active staff list? Yes, he spends the first part of my predicate (contract_end is null), but it does not work (at least by my understanding) past the second part of the predicate which is position_end has the value NULL because there not even a record is entered in the comics! Why would he appear? Is it because of the LEFT JOIN or a NULL rule type, I'm not aware of? Thanks for your help!
Aqua

EMPLOYEES AS

(

SELECT '10' AS emp_id, 'Banner' last_name, 'Robert' NAME FROM dual

UNION ALL

SELECT '20', 'Wayne', 'Bruce' OF THE double

UNION ALL

SELECT '30', 'Kent', 'Clark' FROM dual

UNION ALL

SELECT "40", "Parker", "Peter" OF THE double

UNION ALL

SELECT '50', 'Last', 'Tony' FROM dual

UNION ALL

SELECT '60', 'Jordan', 'Hal' OF THE double

),

emp_contracts AS

(

SELECT '10' AS emp_id, to_date (January 1, 2011 ',' MON-DD-YYYY "") LIKE contract_start, to_date (1 January 2012 ',' MON-DD-YYYY') AS contract_end FROM dual

UNION ALL

To_date '10', SELECT (January 1, 2010 ',' MON-DD-YYYY ""), to_date (December 31, 2011 ',' MON-DD-YYYY') OF double

UNION ALL

To_date '10', SELECT (January 2, 2012 ',' MON-DD-YYYY ""), double NULL

UNION ALL

To_date '20', SELECT (January 1, 2011 ',' MON-DD-YYYY ""), to_date (1 January 2012 ',' MON-DD-YYYY') OF double

UNION ALL

To_date '20', SELECT (January 1, 2010 ',' MON-DD-YYYY ""), to_date (December 31, 2011 ',' MON-DD-YYYY') OF double

UNION ALL

To_date '20', SELECT (January 2, 2012 ',' MON-DD-YYYY ""), double NULL

UNION ALL

To_date '30', SELECT (January 1, 2011 ',' MON-DD-YYYY ""), to_date (1 January 2012 ',' MON-DD-YYYY') OF double

UNION ALL

To_date '30', SELECT (January 1, 2010 ',' MON-DD-YYYY ""), to_date (December 31, 2011 ',' MON-DD-YYYY') OF double

UNION ALL

To_date '30', SELECT (January 2, 2012 ',' MON-DD-YYYY ""), double NULL

UNION ALL

To_date '40', SELECT (January 1, 2011 ',' MON-DD-YYYY'), to_date (1 January 2012 ',' MON-DD-YYYY') FROM dual

UNION ALL

To_date '40', SELECT (January 1, 2010 ',' MON-DD-YYYY'), to_date (December 31, 2011 ',' MON-DD-YYYY') FROM dual

UNION ALL

To_date '40', SELECT (January 2, 2012 ',' MON-DD-YYYY ""), double NULL

UNION ALL

To_date '50', SELECT (January 1, 2011 ',' MON-DD-YYYY ""), to_date (1 January 2012 ',' MON-DD-YYYY') OF double

UNION ALL

To_date '50', SELECT (January 1, 2010 ',' MON-DD-YYYY ""), to_date (December 31, 2011 ',' MON-DD-YYYY') OF double

UNION ALL

To_date '50', SELECT (January 2, 2012 ',' MON-DD-YYYY ""), double NULL

UNION ALL

To_date '60', SELECT (January 1, 2011 ',' MON-DD-YYYY ""), to_date (1 January 2012 ',' MON-DD-YYYY') OF double

UNION ALL

To_date '60', SELECT (January 1, 2010 ',' MON-DD-YYYY ""), to_date (December 31, 2011 ',' MON-DD-YYYY') OF double

UNION ALL

To_date '60', SELECT (January 2, 2012 ',' MON-DD-YYYY ""), double NULL

),

emp_positions AS

(

SELECT '10' AS emp_id, '43XY' AS title_id, to_date (January 1, 2011 ',' MON-DD-YYYY "") LIKE position_start, to_date (1 January 2012 ',' MON-DD-YYYY') AS position_end FROM dual

UNION ALL

SELECT ' 10', '47NT', to_date (January 1, 2010 ',' MON-DD-YYYY ""), to_date (December 31, 2011 ',' MON-DD-YYYY') OF double

UNION ALL

SELECT ' 10', '41JE', to_date (January 2, 2012 ',' MON-DD-YYYY ""), double NULL

UNION ALL

SELECT ' 20', '48AW', to_date (January 1, 2011 ',' MON-DD-YYYY ""), to_date (1 January 2012 ',' MON-DD-YYYY') OF double

UNION ALL

SELECT ' 20', '42KD', to_date (January 1, 2010 ',' MON-DD-YYYY ""), to_date (December 31, 2011 ',' MON-DD-YYYY') OF double

UNION ALL

SELECT ' 20', '46LD', to_date (January 2, 2012 ',' MON-DD-YYYY ""), double NULL

UNION ALL

SELECT ' 30 ', 45 MI', to_date (January 1, 2011 ',' MON-DD-YYYY'), to_date (1 January 2012 ',' MON-DD-YYYY') FROM dual

UNION ALL

SELECT ' 30', '44KH', to_date (January 1, 2010 ',' MON-DD-YYYY ""), to_date (December 31, 2011 ',' MON-DD-YYYY') OF double

UNION ALL

SELECT ' 30', '43LL', to_date (January 2, 2012 ',' MON-DD-YYYY ""), double NULL

UNION ALL

SELECT ' 40', '41', to_date (January 1, 2011 ',' MON-DD-YYYY ""), to_date (1 January 2012 ',' MON-DD-YYYY') OF double

UNION ALL

SELECT ' 40', '40', to_date (January 1, 2010 ',' MON-DD-YYYY ""), to_date (December 31, 2011 ',' MON-DD-YYYY') OF double

UNION ALL

SELECT ' 40', '42DX', to_date (January 2, 2012 ',' MON-DD-YYYY ""), double NULL

UNION ALL

SELECT ' 50', '48IB', to_date (January 1, 2011 ',' MON-DD-YYYY ""), to_date (1 January 2012 ',' MON-DD-YYYY') OF double

UNION ALL

SELECT '50 ', 47 DL', to_date (January 1, 2010 ',' MON-DD-YYYY'), to_date (December 31, 2011 ',' MON-DD-YYYY') FROM dual

UNION ALL

SELECT ' 50', '42A', to_date (January 2, 2012 ',' MON-DD-YYYY ""), double NULL

)

SELECT
1. ES.emp_id,
2. ES.last_name,
3. ES.first_name,
4. EP.title_id,
5. EP.position_start,
6. EP.position_end
Employees are

LEFT JOIN emp_contracts ec

ON ec.emp_id = es.first_name

LEFT JOIN emp_positions ep

ON ep.emp_id = es.emp_id

WHERE ec.contract_end IS NULL AND ep.position_end IS NULL

Hello

AquaNX4 wrote:

Good day ladies------Gentlemen\ gurus-Experts-and Al:

Just when I thought I got my mind wrapped around the notion of NULL value, as defined by Oracle, I met what follows below. Basically, what you are watching is how our employees of the human resources tables are set up (for the most part). We have the employees, employee contracts table and the tables of positions. When I want to make a list of active staff, I always use the filter end date, you will see below in the Super request, essentially looking for staff who do not have a contract AND a position end date entered in the DB. It works like a charm. However, today, I noticed an official on the list, who has never had a position is entered in the comic book, and he had an 'open' contract In my example below, why would "Hal Jordan" appear on the active staff list? Yes, he spends the first part of my predicate (contract_end is null), but it does not work (at least by my understanding) past the second part of the predicate which is position_end has the value NULL because there not even a record is entered in the comics! Why would he appear? Is it because of the LEFT JOIN or a NULL rule type, I'm not aware of? ...

It's the outer join.

When you say

Employees are

LEFT JOIN emp_positions ON ep.emp_id = es.emp_id ep

then, at the time when the WHERE clause is evaluated, the result set contains at least 1 row for each line of employees. If there is no line in emp_postitions that meet the join condition, then all the columns that should be provided by the emp_positions table will be NULL. This is precisely what concerns the outer join.

Think about it for a minute. NULL means the absence of any value. Is there is no corresponding row in the emp_positions table, then there is no value for emp_position.position_end. If so doesn't; "have a value, then, by definition, it is NULL.

It if were not NULL, then this would mean that it had a value. Would what value? Why the request would give him one value rather than another?

Thanks for the display of the data of the sample; It's always useful!

Double left join creates a unwanted loop...

I have therefore two paintings, I need to extract the counts of "tickets".

I want to have the date given match then I use a 'connect by level' so that the same dates without data will have records in the result set.

There are two tables I want to join on this "timeline" when I join each of them that individually, it works but when I join together that there is an order of operations issue I'm not sure how to move.

ORIGINAL DATA:

TABLE SMINCREQ:

OPEN_DATE

NUMBER

JANUARY 12, 2015

IM392039

JANUARY 12, 2015

IM399495

JANUARY 12, 2015

RM394950

JANUARY 13, 2015

IM394958

JANUARY 13, 2015

RM394958

TABLE SMINTERACTIONS:

OPEN_DATE

INCIDENT_ID

JANUARY 12, 2015

SD394858

JANUARY 12, 2015

SD399495

JANUARY 12, 2015

SD394950

JANUARY 13, 2015

SD394958

JANUARY 13, 2015

SD394958

THE QUERY:

SELECT to_char(DAYS_,'DD-MON-YYYY'),
      
      sum(decode(INSTR(SMINCREQ."NUMBER",'IM'),'1','1',0)) "INCIDENT",
      sum(decode(INSTR(SMINCREQ."NUMBER",'RM'),'1','1',0)) "REQUEST"
     --sum(decode(INSTR(SMINTERACTIONS.INCIDENT_ID,'SD'),'1','1',0)) "INTERACTION"  
      FROM
  ( SELECT (TRUNC(to_date(SYSDATE-ROWNUM),'DD')) DAYS_ FROM DUAL
CONNECT BY LEVEL <= (SELECT 14 FROM DUAL)
  ) THE_TIMELINE
    LEFT OUTER JOIN SMINCREQ ON  (to_char(DAYS_,'DD-MON-YYYY')=to_char(SMINCREQ.OPEN_TIME,'DD-MON-YYYY')  and (OPEN_GROUP like '%HELP%'))
    --LEFT OUTER JOIN SMINTERACTIONS on (to_char(DAYS_,'DD-MON-YYYY')=to_char(SMINTERACTIONS.OPEN_TIME,'DD-MON-YYYY')  and PRIMARY_ASSIGNMENT_GROUP like '%HELP%')
    GROUP BY to_char(DAYS_,'DD-MON-YYYY') ORDER BY to_char(DAYS_,'DD-MON-YYYY')
  ;

When I run the present and just get the number of SMINCREQ is

DATE	INCIDENTS	REQUEST
JANUARY 12, 2015	103	4
JANUARY 13, 2015	59	10

When I run the query for SMINTERACTIONS I get

DATE	INTERACTION
JANUARY 12, 2015	55
JANUARY 13, 2015	50

When I try to run the two left joins them together I get:

DATE	INCIDENTS	APPLICATIONS	INTERACTIONS
JANUARY 12, 2015	5665	220	5885
JANUARY 13, 2015	2950	500	3450

I know that what is happening is a loop where the date is is developed in a relationship 1 to many through the joints and then the GROUP is not the case until the end.

What I want to achieve is:

DATE	INCIDENTS	REQIEST	INTERACTION
JANUARY 12, 2015	103	4	55
JANUARY 13, 2015	59	10	50

Thanks for the tips

I decided to go this route that will just join the new data (INTERACTIONS) of INCIDENTS already implemented and APPLICATIONS:

SELECT NULL LINK,DAYS,INCIDENT,"REQUEST",sum(decode(INSTR(SMINTERACTIONS.INCIDENT_ID,'SD'),'1','1',0)) "INTERACTION" from(

SELECT to_char(DAYS_,'DD-MON-YYYY') DAYS,sum(decode(INSTR(SMINCREQ."NUMBER",'IM'),'1','1',0)) "INCIDENT",
      sum(decode(INSTR(SMINCREQ."NUMBER",'RM'),'1','1',0)) "REQUEST"
      FROM
  ( SELECT (TRUNC(to_date(SYSDATE-ROWNUM),'DD')) DAYS_ FROM DUAL
 CONNECT BY LEVEL <= (SELECT 14 FROM DUAL)
  ) THE_TIMELINE
    LEFT OUTER JOIN SMINCREQ ON  (to_char(DAYS_,'DD-MON-YYYY')=to_char(SMINCREQ.OPEN_TIME,'DD-MON-YYYY')  and (OPEN_GROUP like '%HELP CENTER%')
)

    GROUP BY to_char(DAYS_,'DD-MON-YYYY') ORDER BY to_char(DAYS_,'DD-MON-YYYY')
) LEFT JOIN SMINTERACTIONS on (DAYS=to_char(OPEN_TIME,'DD-MON-YYYY') and (PRIMARY_ASSIGNMENT_GROUP like '%HELP CENTER%'))
GROUP BY DAYS,INCIDENT,"REQUEST" order by DAYS ASC;

Thanks for all the entries...

Left join

Hello world
Im trying to create the query that displays the values that are not available in the other table.
Scenario:
I have two tables, the material and materialfolder. I want to display documents that are not available in materialfolder.
Here's my query
```
SELECT m.material_id
    ,  m.MATERIAL_TYPE_ID
    ,  m.name
    ,  m.created
        FROM material m
        LEFT  JOIN materialfolder mf ON m.material_id = mf.material_id
        where to_char(m.CREATED, 'yyyy') >= ('2011')
        and to_char(m.CREATED, 'yyyy') <= ('2013');
```
The result does not show the correct values. Don't know what my error here...
Hoping that someone could help me.
Thank you.
Kind regards
Ed

Hello

If you just want to know the values that are not available in materialfolder, use a NOT EXISTS condition:

SELECT m.material_id

m.MATERIAL_TYPE_ID

$m.name

m.created

MATERIAL m

If NOT EXISTS (select null from materialfolder mf

where m.material_id = mf.material_id

)

AND m.CREATED > = TO_DATE('01/01/2011', 'dd/mm/yyyy') AND m.CREATED< to_date('01/01/2014',="">

LEFT JOIN DUPLICATION PROBLEM

Hello
I'm having a problem with the left join query, when I join table a two table based on column task1 I get duplicate in table1.task1, table1.price.
Table1. Task1 Table1. Price table2. Task1 table2. Resource table2. Price
001 100 001 A 50
001 100 001 B 250
How can I make a request to get a result as below.
Table1. Task1 Table1. Price table2.Task2 table2. Resource table2. Price
001 100 001 A 50
001 B 250
Thank you.

Note that your query uses an inner join. Your original question mentioned a join left, generally interpreted as meaning a left OUTER join.

Anyway, according to Frank, you can use the BREAK command in SQL * Plus for the goal sought through formatting. You can also use an analytical function as Roger suggests. I think ROW_NUMBER() might do the trick, but we must be clear about the criteria for partitioning and ordering the results, for example
```
WITH table1 AS (
  SELECT '001' AS task1
       , 100 AS price
  FROM   dual
), table2 AS (
  SELECT '001' AS task1
       , 'A' AS resources
       , 50 AS price
  FROM   dual
  UNION ALL
  SELECT '001' AS task1
       , 'B' AS resources
       , 250 AS price
  FROM   dual
)
SELECT DECODE(ROW_NUMBER() OVER (PARTITION BY t1.task1, t1.price ORDER BY t2.resources, t2.price),1,t1.task1) AS task1_alt
     , DECODE(ROW_NUMBER() OVER (PARTITION BY t1.task1, t1.price ORDER BY t2.resources, t2.price),1,t1.price) AS price_alt
     , t2.task1 AS task_with_resource
     , t2.resources
     , t2.price
FROM   table1 t1
INNER JOIN table2 t2
ON     t1.task1 = t2.task1
ORDER BY t1.task1, t1.price, t2.resources, t2.price;
```

How to avoid the union and use a left join

Hello

I have the following tables

{code}

create the table mainTable

(col1 varchar2 (2) varchar2 (2) col2, col3 varchar2 (2), col4 varchar2 (2));

create table secTable

(col1 varchar2 (2));

create the table secTable1

(col2 varchar2 (2));

create the table secTable2

(col3 varchar2 (2));

Insert in maintable

values ('a', 'b', 'this,' would be ');

Insert in maintable

values (', 'o', 'n', 'p');

insert into secTable

values ('a');

insert into secTable1

values ('b');

insert into secTable2

values ('c');

commit;

{code}

I made a request, drank, I would use join without clause union how can I change to receive the same result as the following query?

{code}

	Select t1.*, 'bad value' \| T1.Col1
	from maintable t1
	T1.Col1 left join t2 = t2.col1 sectable
	where t2.col1 is null
	Union of all the
	Select t1.*, 'bad value' \| T1.col2
	from maintable t1
	Join t2 left on t1.col1 = t2.col2 sectable1
	where t2.col2 is null
	Union of all the
	Select t1.*, 'bad value' \| T1. COL3
	from maintable t1
	Join t2 left on t1.col1 = t2.col3 sectable2
	where t2.col3 is null

{code}

Thank you

Coco

Like this?:

SQL > SELECT col1, col2, col3, col4, xvalue

2 from (SELECT m0.*

3, NVL (t0.col1, 'bad value t0' | m0.col1) t0_col1

4, NVL (t1.col2, 'bad value t1' | m0.col2) t0_col2

5, NVL (t2.col3, 'bad value t2' | m0.col3) t0_col3

Maintable m0 6

LEFT OUTER JOIN sectable t0 7

8. WE (m0.col1 = t0.col1

9 AND t0.col1 IS NULL)

10 LEFT OUTER JOIN sectable1 t1

11. WE (m0.col1 t1.col2 =

12 AND t1.col2 IS NULL)

13 LEFT OUTER JOIN t2 sectable2

14. WE (m0.col1 = t2.col3

15 t2.col3 AND IS NULL))

16 UNPIVOT INCLUDES NULL values (xvalue wrongly IN (t0_col1, t0_col2, t0_col3))

17 ORDER BY xvalue

18.

COL1 COL2 COL3 COL4 XVALUE

------ ------ ------ ------ ---------------------------------------------------

a b c d bad value t0 a

m o n p bad value m t0

a b c d bad value t1 b

m o n p o t1 value of evil

a b c d bad value t2 c

m o n p value t2 n bad

6 selected lines.

Table1. Task1	Table1. Price	table2. Task1	table2. Resource	table2. Price
001	100	001	A	50
001	100	001	B	250

Table1. Task1	Table1. Price	table2.Task2	table2. Resource	table2. Price
001	100	001	A	50
		001	B	250

left join on 1 table

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