Legacy and Class.getConstructor

Hello Java community.

I use Class.getConstructor because I don't know what case I need until execution.

I have a class A with an A (Type1) constructor. Type2 extends Type1. Now, when I call A (Type2), the compiler I have actually been calling the constructor has (Type1) because there is no such thing as A (Type2). However, when I call A.class.getConstructor (Type2.class), I get a runtime error saying that manufacturer that there is no such thing as a (type2). I can understand why this is happening, but I still want to provide a parameter of a subtype, and so that the runtime required manufacturer intuit...

I don't really know what kind of Builder, I need running (the call simplified to getConstructor above is only to indicate what is happening in my code) and I do not know if, for example, I will be instantiated an object of a subclass of A, or by using a setting of a subclass of Type1 (Type2, say, in the example). How to do a similar thing to arrive on time as this happens at the time of the compilation of performance?

Thanks for the help,

Owen.

Why my answer, marked by the correct OP, was eliminated from this thread?

I'm not going to type it in again, but it seems also here: http://stackoverflow.com/a/24772118/207421

Tags: Java

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