Length of the column of type 'text '.

Similar Questions

• Increase the length of the column - restriction key foreign vs MS SQL

  Hello

  I need to increase the length of the column (nvarchar) in some tables. Between these tables are foreign keys.

  When I try to do it on MS SQL databases using the command as "ALTER TABLE TABLE_NAME ALTER COLUMN column NAME NVARCHAR (50) NULL" then I get the error like below:

  Column ' dbo. TABLEA. NAME ' is not the same length or scale as the referencing column or the 'FKNAME' object depends on the column 'name'.

  Therefore resume, on MS SQL I drop all constraints, alter table and re-create constraints.

  When I do this same thing on the oracle database (oracle database a same pattern as MS SQL database, same fk, same tables, columns, etc.) using the command as "ALTER TABLE table_name MODIFY COLUMN NVARCHAR2 (40);  " then length is change without any erros and I wounder t - it a correct situation on oracle? -all the constraints are enabled. Oracle checks the length of data to foreign key columns?

  As I understand the error (ORA-02267: column type incompatible with the type of the referenced column) is the show that if the data type name is not equal between data tables not type length (?)

  To reproduce:

  1 create tables

  CREATE TABLE "TABLEA".

  (ACTIVATE THE 'NAME' NVARCHAR2 (20) NOT NULL,)

  NUMBER OF "TEXTID",.

  'PK_TABLEA' CONSTRAINT PRIMARY KEY ("NAME")

  );

  CREATE TABLE 'TABLEB.

  (SELECT 'ID' NUMBER NOT NULL,)

  NVARCHAR2 (10) "NAME."

  NUMBER OF "WWW."

  "TABLEB' ('ID') PRIMARY KEY CONSTRAINT

  );

  2. create the fk

  ALTER TABLE TABLEB ADD CONSTRAINT FK_TABLEB FOREIGN KEY ('NAME') REFERENCES 'TABLEA' ('NAME');

  On MS SQL, you get an error message on the same length of column ;) no

  Thank you

  Best regards

  Mateusz

  Whatever it is, the answer seems to be here: https://docs.oracle.com/cd/E17952_01/refman-5.5-en/create-table-foreign-keys.html

  "Corresponding columns in the foreign key and the referenced key must have similar data types. The size and the sign of the integer types must be the same. The length of the string types are not necessarily the same. For the non-binary (character) string, the character set and collation columns must be the same. "

• The length of the BLOB data type.

  Hello world. I have a question about the Oracle Blob data type.

  I need to store Image data in my table, there are 4 fields that store 4 different images for a record in a table.

  The size of the image would be no more max 500Ko,

  It is advisable to specify the data type of column as just the BLOB (which is default to 2 GB size)

  Or specify the datalength?

  Length is specified in number of bytes, it is the same as a byte? so I go for BLOB(500K)?

  Kind regards

  Glen.

  You cannot specify a maximum size on a column of type BLOB.  There is no such thing as a BLOB (500000).  It's just a BLOB.

  Unless you are on a rather old version of Oracle, the maximum size of a BLOB is much more than 2 GB - depending on the size of block in a recent version of Oracle, the maximum size is in the range of TB.  Oracle, of course, will not affect TB of disk (or same GB drive) to a value which is only 500 KB.  It will affect only what suits him (according to the size of the segment specified in the definition of the BLOB, and other settings of BLOB storage).

  Justin

• Need help to modify the length of the column

  Hi Experts,
  
  I need to change the length of a column of char (10) to CHAR (5), but it is to show the error of:

  ALTER TABLE appr_group_table MODIFY (APPR_TBLNO CHAR(5)) 

  It is to show the error below:

  ERROR at line 1:
  ORA-01441: cannot decrease column length because some value is too big

  I checked in the dbase, but there is not any value in this column with more than 5 characters:

  SQL> SELECT APPR_TBLNO FROM appr_group_table;
  
  APPR_TBLNO
  ----------
  ANTAB
  ANTAB
  ANTST
  SCCTR
  SOTAB
  SOTAB
  SOTAB
  SOTAB
  SOTAB
  SOTAB
  SOTAB
  
  11 rows selected.

  Thnx in advance for help out me...

  tank means fixed length variable. When you say char(10) oracle reserves 10 spaces for your data. to your output, it means that you are, because spaces are also considered to be data. This is the reason why, it does not reduce the size.

  best solution is to create a new column with the data type varchar2 or char (5) and transfer the data in this column in the new column, and then delete the original column.

• FRM-30187: size of the column of type CHAR in the record group must be between 1 and 2000.

  Hi, forms 6i, db 10g

  I created a lov based on this query

  select * from items_qty_vu -- database view
  

  and the view code is

  CREATE OR REPLACE FORCE VIEW items_qty_vu (serial, item_id, expiry_date, qty)
  AS
     WITH item_units_plus AS
          (SELECT item_id, unit_id, factor,
                  LEAD (factor, 1, 1e99) OVER (PARTITION BY item_id ORDER BY factor)
                                                                 AS next_factor,
                  ROW_NUMBER () OVER (PARTITION BY item_id ORDER BY factor DESC)
                                                                         AS rnk
             FROM item_units)
     SELECT     ID.serial, ID.item_id, ID.expiry_date,
                SUBSTR
                   (SYS_CONNECT_BY_PATH (   TRUNC (  MOD ((  ID.qty
                                                           - ID.qty_allocated
                                                          ),
                                                          iup.next_factor
                                                         )
                                                   / iup.factor
                                                  )
                                         || ' '
                                         || u.unit_name,
                                         ', '
                                        ),
                    3
                   ) AS qty
           FROM item_detail ID JOIN items i ON i.item_id = ID.item_id
                JOIN item_units_plus iup ON iup.item_id = ID.item_id
                JOIN units u ON u.unit_code = iup.unit_id
          WHERE CONNECT_BY_ISLEAF = 1
     START WITH iup.rnk = 1
     CONNECT BY iup.rnk = PRIOR iup.rnk + 1 AND ID.serial = PRIOR ID.serial
       ORDER BY ID.serial;
  
  

  When I compile the form, I face the error FRM-30187,

  If I replace my query "select * from items_qty_view" with "select item_id, serial, expiry_date of items_qty_vu", it compiles successfully.

  As salamualikum, Salem,.

  You must follow my instructions carefully.

  1. Select the record group.

  2. go in the record group property

  3. Select and open the column specifications

  4. highlight the column and check the decrease of the length, the bellows of the size that you cross more than 2000 then 2000.

  Compilation of now and you're done.

  Wow. you did.

  Hamid

• XMLTable: definition of the columns data type of table

  Hello world
  
  I am using ORACLE 11 g and you want to shred XML into a table called test used. I was hoping I'd be able to get the types of data to the employees table existing instead of specify them in the clause of columns. Is this possible?
  
  Here is an example of what I'm trying to do. But I get an error: PL/SQL: ORA-00907: lack the right parenthesis on the line starting with columns.
  

      insert into EMPLOYEES
       select *
         from xmltable(
         '/employees/employee'
          passing EMP_XML
  
          columns FIRST_NAME EMPLOYEES.FIRST_NAME%TYPE path 'first_name',
                  LAST_NAME  EMPLOYEES.LAST_NAME%TYPE  path 'last_name',
                  GENDER     EMPLOYEES.GENDER%TYPE     path 'gender',
                  AGE        EMPLOYEES.AGE%TYPE        path 'age'
          );

  Error details

          columns FIRST_NAME EMPLOYEES.FIRST_NAME%TYPE path 'first_name',
                              *          
  
  ERROR at line 16:
  ORA-06550: line 16, column 42:
  PL/SQL: ORA-00907: missing right parenthesis
  ORA-06550: line 11, column 5:
  PL/SQL: SQL Statement ignored

  Thank you.

  Specification of column names is required, but you can omit the declaration of data types.

  See: the function XMLTABLE SQL/XML in Oracle XML DB

  XMLTable is used with storage XML based on a schema of XMLType data type is optional. If absent, the data type is inferred from the XML schema. If Oracle > XML DB is unable to determine the right type of a node, a default type VARCHAR2 (4000) is used.

  It is an Oracle extension; in the SQL/XML standard, the data type is always required.

  Note:
  The alleged data type might change as a result of the application of a patch or upgrade of Oracle XML DB. In particular, a new set of release or patch might be able to > determine the data type when the previous version was unable to do so (and therefore not reimbursed to VARCHAR2 (4000)). To protect against such an eventuality, specify an explicit data type with the data type.

• length of the column

  Hi all
  
  How to reduce the gap between the columns...
  
  Please notify
  
  Kai
  
  Edited by: user9338712 may 3, 2012 22:49
  
  Edited by: user9338712 may 3, 2012 23:02

  You use the char data type? in any case try this...

  SELECT Request_id,
  RPAD(user_concurrent_program_name||) NVL2 (fcrsv.description, ' (' | fcrsv.description |)) ((', NULL), 100) conc_prog,.
  fcrsv. Requestor
  Case
  When fcrsv.requested_start_date > fcrsv.request_date then 'no YES' Else ' ' end is_it_scheduled
  OF fnd_conc_req_summary_v fcrsv, fnd_responsibility_tl frt
  WHERE fcrsv.responsibility_application_id = frt.application_id AND fcrsv.responsibility_id = frt.responsibility_id AND status_code = 'E '.
  AND actual_start_date > SYSDATE - 1
  ORDER OF NVL (actual_start_date, actual_completion_date) / / DESC;

• Control the length of the column 1 - column 2 grows

  Hello

  I have a page of web HTML5 CSS3 with two columns. The left column has a background color and this extends as much as I add text in the left column. How can I force the background color in the left column to expand towards the bottom of the page, as more text is added in the right hand column of.

  Here is the CSS for the left column:-

  #sidebar {}
  Width: 230px;
  float: left;
  background-color: #A4C2C2;
  font: 12px Georgia;
  color: #336666;
  line-height: 18px;
  height: 100%;
  padding: 10px 10px 10px 10px;
  margin: 5px 5px 5px 0;
  border-radius: 7px;
  -moz-border-radius: 7px;
  -webkit-border-radius: 7px;
  }

  I guess another way to put it, it's that I want to replace the height: 100% above with:-If "right column grows beyond the height of the left column" then "increase the height of the left column.

  Any ideas would be very appreciated.

  Rgds

  Equal height CSS columns ~.

  http://ALT-Web.com/articles/equal-height-CSS-columns.shtml

  Nancy O.
  ALT-Web Design & Publishing
  Web | Graphics | Print | Media specialists
  http://ALT-Web.com/
  http://Twitter.com/ALTWEB

• Problem in the code for the adjustment of the length of the column

  I have a column of the item on the stores of the order of the day that this column must be 9 digits
  I'm labour code and examine the field if found 8 figures put zero on the left
  But this code does not work as I want it, although the implementation was done without errors
  
  DECLARE
  V_ITEM INVENTORIES. TYPE % INV_ITEM;
  START FOR ITEM_CUR IN (SELECT * FROM INVENTORIES) LOOP
  IF length (V_ITEM) = 8 then
  UPDATE OF INVENTORIES SET INV_ITEM = 0 | V_ITEM;
  END IF;
  END LOOP;
  END;

  Dear OracleLover2,

  All columns have the same data because there is no where clause in the update statement and that's why it would update all records.

  I don't know what should be the condition for the update, because this is business logic, which you need to know.

  There was the fundamental problem in the code that I pointed out above in my last comment.

  You write once appropriate where clause in your query of update, it will give you the desired results.

  It will be useful.

  Check the answer as useful / OK, if this can help you

  Carole

• update the column of type char to stem after insert or update the same column

  I have the table "people":
  
  DESC PEOPLE
  Name Null? Type
  ------------------------------- -------- ------------
  ID NOT NULL NUMBER
  NAME VARCHAR2 (25) NOT NULL
  
  and I need to make sure that the NAME column is always in uppercase letters, so I did as he illustrated in this link:
  http://asktom.Oracle.com/tkyte/mutate/
  
  I did this: -.
  ==================================
  CREATE OR REPLACE TRIGGER parent_bi
  BEFORE THE INSERT OR UPDATE
  ON people
  BEGIN
  state_pkg.newrows: = state_pkg.empty;
  END;
  /
  -----------------------------------------------------------------
  CREATE OR REPLACE TRIGGER parent_aifer
  AFTER INSERT OR UPDATE
  ON PEOPLE
  FOR EACH LINE
  BEGIN
  state_pkg.newrows (state_pkg.newrows.COUNT + 1): =: NEW. ROWID;
  END;
  /
  ------------------------------------------------------------------
  CREATE OR REPLACE TRIGGER HR. PARENT_AI
  AFTER INSERT OR UPDATE
  ON HUMAN RESOURCES. PEOPLE
  REFERRING AGAIN AS NINE OLD AND OLD
  FOR EACH LINE
  BEGIN
  BECAUSE me in 1... state_pkg.newrows.count
  LOOP
  UPDATE of the people
  NAME = UPPER (NAME)
  People WHERE. ROWID = state_pkg.newrows (i);
  END LOOP;
  END;
  /
  ======================================
  
  but nothing is coming, as the same that these triggers do not exist.
  
  So, what is wrong?
  and how I workaround to make this statement:-
  Setting a DAY people SET NAME = UPPER (NAME);
  whenever I update or insert in the name column.

  It is much simpler that that - you just need a BEFORE INSERT trigger

  CREATE OR REPLACE TRIGGER your_trigger_name
    BEFORE INSERT OR UPDATE ON persons
    FOR EACH ROW
  BEGIN
    :new.name := UPPER( :new.name);
  END;
  /
  

  As you can see from this example, which will force all uppercase

  SQL> create table persons (
    2    name varchar2(10)
    3  );
  
  Table created.
  
  SQL> CREATE OR REPLACE TRIGGER your_trigger_name
    2    BEFORE INSERT OR UPDATE ON persons
    3    FOR EACH ROW
    4  BEGIN
    5    :new.name := UPPER( :new.name);
    6  END;
    7  /
  
  Trigger created.
  
  SQL> insert into persons values( 'justin' );
  
  1 row created.
  
  SQL> insert into persons select lower(ename) from emp;
  
  14 rows created.
  
  SQL> select * from persons;
  
  NAME
  ----------
  JUSTIN
  SMITH
  ALLEN
  WARD
  JONES
  MARTIN
  BLAKE
  CLARK
  SCOTT
  KING
  TURNER
  ADAMS
  JAMES
  FORD
  MILLER
  
  15 rows selected.
  

  Also, you generally want to add a check constraint to ensure that NAME = UPPER (NAME).

  Justin

• How to get the current layer type (text, art, layer group, etc.).

  Hi, I'm traveling on all layers using layerIndex. I can get current name later following the path. char * NomCouche = new char [100]; Int32 len = 100; PIUGetInfoByIndex (layerIndex, classLayer, keyName, NomCouche and len); I tried to use the keyType and sound in the same way, but I'm not able to get the type of the layer directly. Why? Also, I found a similar discussion, check the layer is SectionStart, SectionEnd or SectionContent. Get plugin C++ layer groups if the layer is a 'SectionContent', how I have in addition to check its type (textlater, adjustmentlayer, artlayer, ect)?

  Ok

  Later, I noticed that the value of a layer type is int32.

  		Int32 layertype = 0;
  		DescriptorTypeID runlayertypeKey = 0;
  		sPSActionControl-> StringIDToTypeID ("layerKind", & runlayertypeKey);
  		error = PIUGetInfoByIndex (layerIndex, classLayer, runlayertypeKey, & layertype, NULL);

• Store an Image in the column of type BLOB of a Table

  It is about saving an Image file, a temp_photo table.
  
  UNDER LINUX, I created the Directory object.
  Step # 1
  SQL > create directory MSGS3 as ' / home/HD/om4000/I_MESSAGES ";
  Created directory.
  
  Step 2: set up the temp_photo Table.
  
  SQL > create table temp_photo
  (
  ID NUMBER (3) NOT NULL,
  PHOTO_NAME VARCHAR2 (50).
  PHOTO BLOB
  );
  Table created.
  
  Step: 3 this is the procedure that I have created to load the file from the file system of the database.
  
  create or replace PROCEDURE load_file)
  number of P_ID,
  p_photo_name in varchar2) IS
  src_file BFILE.
  dst_file BLOB;
  lgh_file directory.
  BEGIN
  src_file: = bfilename ('MSGS3', p_photo_name);
  -Insert a NULL record to lock
  INSERT INTO temp_photo
  (id, photo_name, photo)
  VALUES
  (p_id, p_photo_name, EMPTY_BLOB())
  RETURN photo INTO dst_file;
  -lock the folder
  SELECT photo
  IN dst_file
  OF temp_photo
  ID WHERE p_id =
  AND photo_name = p_photo_name
  UPDATE;
  -Open the file
  DBMS_LOB. FileOpen (src_file, dbms_lob.file_readonly);
  -determine the length
  lgh_file: = dbms_lob.getlength (src_file);
  -Read the file
  DBMS_LOB. LoadFromFile (dst_file, src_file, lgh_file);
  -update the blob field
  UPDATE temp_photo
  Photo SET dst_file =
  ID WHERE p_id =
  AND photo_name = p_photo_name;
  -close file
  DBMS_LOB. FileClose (src_file);
  END load_file;
  /
  
  
  Step 4: when I test it by running the procedure in the following assistance:
  SQL > execute load_file (1, 'Omega5000.jpg');
  
  I get the following error:
  
  Error from line 5 in order:
  run load_file(1,'Omega5000.gif')
  Error report:
  ORA-22288: file or LOB FILEOPEN operation failed
  No such file or directory
  ORA-06512: at "SYS." DBMS_LOB", line 805
  ORA-06512: at "HD. Load_file", line 23
  ORA-06512: at line 1
  22288 00000 - "file or LOB operation %s failed\n%s".
  * Cause: Failure of the attempted operation on the file or the LOB.
  * Action: See the following error message in the more detailed error stack
  information. In addition, make sure that the file or LOB exists and that
  privileges are set for the specified operation. If
  the error continues, report the error to the user DBA.
  
  He said: no such file or directory, but I double checked that the file is located in the same directory and directory is it physically (for which I created the above directory object.)
  Can someone help me where I'm doing something wrong. This is the first time I use the BLOB in my table. Can anyone suggest what's not here.

  >
  He said: no such file or directory, but I double checked that the file is located in the same directory and directory is it physically (for which I created the above directory object.)
  >
  Oracle is disagreeing with you.

  Post your proof that the file exists in the path you provided.

  See this example Oracle-base
  http://www.Oracle-base.com/articles/Misc/HTML-with-embedded-images-from-plsql.php
  >
  CONN / AS SYSDBA
  CREATE or REPLACE DIRECTORY of images AS "/ host /";
  GRANT READ, WRITE on DIRECTORY images TO test;
  >
  Write down everything you missed? Tip: Look at the last character of the DIRECTORY string. Second Tip: See the grant?

  SQL>create directory MSGS3 as '/home/mh/om4000/I_MESSAGES' ;
  

• query on the column data type CLOB display part of instruction. Why?

  Hi all
  Why when I have queries on the CLOB column display only part of instruction.
  
  as follows
  
  
  drop table test_clob;
  
  create table test_clob (number (9) id, article clob);
  
  insert into test_clob values (1,' 1. Quality and perfection: the international quality
  standards, including port of commitment and discipline,
  and to discover the best of the features that cater to the
  charity society has been able to get the most important
  International certificates in achieving quality, administrative, industrial and food. ") ;
  
  
  SQL > select * from test_clob;
  
  ARTICLE ID
  ---------- ----------------------------------------
  1-1. Quality and perfection: the boarding school
  international quality
  standards, including what
  
  
  but in the request of me don't show that part of the statement
  
  
  concerning
  Wael

  set long 5000
  

• Problems in 10g in the column of type date

  Hello
  
  I have a test_abc of the table in which I have a column event_date who picks up the sysdate for any removable on this table. Now, if I have 2 rows in the table with the same value for the event_date column in the table, and then on actually doing a:
  Select * from test_abc by event_date;
  
  The results are retrieved correctly in 9i, i.e. in the order in which they were inserted. However, in 10g, the results are not retrieved from absolute randomly. Here's the scenario:
  
  create table test_abc (inv_id number event VARCHAR2 (3), date event_date, varchar2 (10)) remarks;
  
  insert into test_abc values (7552, 'ADD', TO_DATE (' October 1, 2009 10:45:48 ',' MON-DD-YYYY HH24:MI:SS'), 'test1');
  
  insert into test_abc values (7552, 'REL', TO_DATE (' October 1, 2009 10:45:48 ',' DD-MON-YYYY HH24:MI:SS'), "test2");
  
  insert into test_abc values (7552, 'RTE', TO_DATE (' October 1, 2009 10:45:48 ',' DD-MON-YYYY HH24:MI:SS'), "test3");
  
  insert into test_abc values (7552, 'SET', TO_DATE (' October 1, 2009 10:45:48 ',' MON-DD-YYYY HH24:MI:SS'), "test4");
  
  
  Now about the conduct of a select * from test_abc by event_date, I get the following in 9i result:
  
  INV_ID EVENT EVENT_DATE REMARKS
  -------- -------- ---------------------------------- --------------
  7552 ADD 01/10/2009 10:45:48 test1
  7552 REL 01/10/2009 10:45:48 test2
  7552 RTE 01/10/2009 10:45:48 test3
  7552 SET 01/10/2009 10:45:48 test4
  
  Whereas, in 10g, the output is:
  
  INV_ID EVENT EVENT_DATE REMARKS
  -------- -------- ---------------------------------- --------------
  7552 ADD 01/10/2009 10:45:48 test1
  7552 SET 01/10/2009 10:45:48 test4
  7552 RTE 01/10/2009 10:45:48 test3
  7552 REL 01/10/2009 10:45:48 test2
  
  Could someone help me understand what could be the problem.
  
  Thanks in advance.

  The point is that Oracle does not guarantee that lines emerge in one order other than that covered by the order by clause.

  In a statement, a game of results without an order by (or without enough order bys in your case) can change at any time.

  Mainly because that the plan of the SQL and the inner workings of the CBO for this plan will determine the order and there are many factors that can cause this plan change.

  If the INSERT command is important to you, you can use a sequence number, possibly peopled by a trigger, increase your order in event_date.

• How to download all the images in the folder to the column of type BLOB (problem of area to create BLOB)

  Hello

  I use JDeveloper 11.1.2.3 version, I need to download all the images in my local folder to the database at a time table. The problem I face is to create BLOBDomain for each of them?

  Best regards,

  Julien

  If you can access the files, that only works if they are on the server, you can read the file and create the domain of the BLOB in the file directly. The technique is the same as in the blob. Only difference is that you pass the file to the method and open the input stream of the file instead of the UploadedFile.

  Timo