Logout fails authorization scheme

I use the following url to logout on the authentication scheme:
wwv_flow_custom_auth_std.logout? p_this_flow = APP_ID. & p_next_flow_page_sess = 140:12

Page 12 the authorization scheme is - no. Page no authorization required - and authentication is "Page is Public.

Page 12 fails during authentication. I get access denied by Application security control and the error message for the authentication scheme.

I know that it is because the authentication scheme uses a query to verify that the user exists in a table:

There is a SQL query
Select 1
staff
where upper (USERid) =: APP_USER

: APP_USER is now empty, because they left the game.

My question is how can I get the application to ignore the authentication scheme? I thought when I didn't take, 'no permissions required page' and 'page is public' the application does more check authentication and authorization.

Thanks, Elizabeth

I thought I covered that in ' you want to remove or add logic to the plan so that it does not draw if: APP_USER is null or one of the public user ('APEX_PUBLIC_USER', 'ANONYMOUS', 'nobody'),... ". »

Scott

Tags: Database

radius_attributes.PNG

and

vendor_specific_attributes.PNG

Hello Jim,

Try to use the domain host instead of multi-auth mode multiplayer.

Kind regards

Poonam Garg

Page restrictions - authorization scheme

I have a 8736 application this application in the form of 3 tabs
Tab1: information TAB2: Department tab 3: Admin
3 as a form in which tab SHOULD only be displayed to users what rights of authorization. I tried to do it for sometimes now and it's not working. I have a table called users
TABLE: users
access_level username
john919 2
sarah765 0
For the page to tab 3 If you have an access level of 2. You should be able to view this page, and if not, they should you get an error message saying "sorry you can not view this page.
In this case 'john919' should be able to view the tab tab '3' page and 'sarah765' SHOULD NOT.
I have this query in the authorization scheme and the type of plan: pl/sql function returning a Boolean
DECLARE
v_access_level NUMBER (2);
BEGIN
IF (: APP_PAGE_ID = 61)
THEN
SELECT MAX (ADMIN_LEVEL)
IN v_access_level
USERS
WHERE USER_NAME =: APP_USER.
IF v_access_level = 2
THEN
RETURN TRUE;
ON THE OTHER
RETURN FALSE;
END IF;
ON THE OTHER
RETURN TRUE;
END IF;
END
I have never try this before and I was ask autour and many people tell me that this should check the admin_level in the USERS table using the current username of the person that is whether they have access to this page. So far, it's like I miss. Help, please

Hi Dave,.

The code seems perfect, so the data required. You can use the two v ('APP_USER'); and: APP_USER. has no importance.

It is difficult to say without seeing the data, are the capital letters of usernames in the table? Try to use UPPER (USER_NAME) = UPPER(:APP_USER)

Although I suppose that it would give a no data found. What value is in the variable APP_USER? You can open a session that the use of the APEX debugging?

APEX_DEBUG_MESSAGE

Kind regards

Joni

Cannot authenticate because the authorization scheme limits the login page (101)
Hello.

I have a problem with authentication. I have an application with authentication and authorization schemas created from scratch. There is an option in the security attributes of the application that lets you apply a pattern of authorization for the entire application. I also have a login page (101) that I use for authentication purposes that I don't get, since approval is the application level. Even if the login page is established a system of authorisation that always succeeds APEX makes no difference. How do I approach this issue so that authorization for the entire application is always possible with authentication?

Thank you.
I'm not sure that it would necessarily change in the future because so many things in one schema authorization should be defined by the developer that it's probably wise for Oracle make Apex still do not know the application of the law on the login page. Although I can't think of a realistic example for now, maybe there could be reasons were based on external criteria that even the login page should not be available to a small group of people? I wouldn't exclude it as a possibility.

That's why when you implement a system of authorisation, it is probably best that Oracle makes no assumptions about what you want to do and you just explicitly it you include in the plan.

By dig a little and in defensive coding and style, you might not even want to consult directly the "101" page. May be wise to do a ' select PAGE_FUNCTION in the APEX_APPLICATION_PAGES where PAGE_ID =: APP_PAGE_ID and APPLICATION_ID =: APP_ID. If PAGE_FUNCTION comes back as "Login", then this is your login page and return TRUE. Otherwise, continue with some other logical returns boolean you have to leave. This way you stay clear page to hardcode and even independent of both page alias value (because they are not mandatory).

Error in running code of authorization scheme
I run my application on APEX. ORACLE. COm and I immediately get the following error:

ORA-06550: line 13, column 28: PL/SQL: ORA-00942: table or view does not ORA-06550: line 12, column 14: PL/SQL: SQL statement ignored ORA-06550: line 16, column 19: PLS-00364: variable index of loop "C1" use is invalid ORA-06550: line 16, column 5: PL/SQL: statement ignored ORA-06550: line 17, column 15: PLS-00364: variable index of loop "C1" use is invalid ORA-06550 : line 17, column 5: PL/SQL: statement ignored ORA-06550: line 25, column 28: PL/SQL: ORA-00942: table or view does not ORA-06550: line
ERR-1082 error in authorisation system code execution.

Here's credentials:
Workspace: RGWORK
Request: The Certification of-21405 Online Application Prototype
User: TESTER
Password: test123

The public s/b application. I'm not able to identify the invalid authorization scheme. I checked all the authorisation schemes in the shared components > Security > authorisation schemes and can not find the culprit.

Can someone help please?

Thank you
Robert
My Blog: http://apexjscss.blogspot.com
Your permission scheme "administrator access - control" at this line of code that uses a table which is not there (or RGTEST does not have access to):
SELECT id, application_mode
of apex_adm.apex_access_setup

This authorisation system is used in the Admin tab.

If you run the page in debug mode, you will see (among other things):

0.19: authorization check: '11204012643155257465' user: 'nobody' component: 'tab '.
0.20: see the error page...

Who reported me to the section tab and there it was!

Determine the current item of blocks, region,... for use in the authorization scheme
Hello

y at - it a possiblity to understand, what element, region, etc. is currently rendered?

What I want to do is: create an authorization scheme that is attached to each article. The authorization scheme itself must be generic and configured through a config table. I think that it is only possible if the authorization scheme knows the element for which it is currently running.

Y at - it a possiblity to do this?

If this isn't the case, I think it would be a great improvement for future versions. Built a new substition string that points to the name of the currently displayed item (something like "pointer" in java).

Thank you for your help.
Stephan
Stephan - it is not yet available. We have had in mind for some time and hopes to implement in the next release.

Scott

Custom authorization scheme management has no errors
Is it possible that I can get when someone goes to a page, they are not allowed to be on (schema of authority used to apply it) instead of cold shutdown redirect them to the page of the application and use the global opinion to inform the user that he or she is not allowed in the selected page instead of going to the page of the red stop sign X? I used global notifications before, but I'm not sure if there is a way to secure my application page of the system of authorisation at the page level and do what I'm talking about. Any ideas?
This only happens when the user alter the URL, but it happens.

You can code your authorization scheme to return true when it detects an unauthorized access to a page, but first did use owa_util.redirect_url to access the page of notification of your choice.

Scott

Looking for sample configuration (failed authorization of the order)

I have problems Ganymede + work properly with ACS5.1 and a switch simple catalyst 3750.

I can authenticate with AAA, but I can't get a single command to work once I am 'failed command authorization"even on"enable ".

Can someone point me to a resource that will guide me in the process?

Thank you

You probably have permission to order enabled on your switch and access the GBA policy is not allowed commands. A way around this is to disable permission to command on the device or allow all the commands in your command under your access policy sets.

Check these settings and do not forget that the 'customize' command will help activate the rules or the permissions if you have trouble finding them.

Here is the guide of the user to ACS 5.2 - http://www.cisco.com/en/US/docs/net_mgmt/cisco_secure_access_control_system/5.2/user/guide/acsuserguide.html

Thank you

Tarik

Problem with authorization scheme
In my aplication homepage should be public, so that everyone can see.
Now when logging in I created patterns of custom authentication which checks if the connection user name and password are stored in a table in the database. Managed to do. Now, in the same table I column containing user Type because I have 3 types of users.

In the authorization for the first program called BUYER scheme I have this as a PL/SQL function returning a Boolean:

declare
type_of_user number: = 0;
Start
Select type_of_user from users where username = user_type: APP_USER.
If type_of_user = "BUYER" then
Returns true;
otherwise return false;
end if;
end;

Now when I go to the development of another page this page 1 and run it, it connect and works perfectly, but when I run the Application it does not display the login page, go to page 1 and hangs by saying:

ORA-01403: no data found

ERR-1082 error in authorisation system code execution.

Back by demand.

I don't know how to fix this, so any help would be appreciated.

Kind regards
Raphaël
Raphael:

You can make the error go away if you manage the "non-donnees-not found" exception However, it would be useful to know why the code is executed at all! Maybe you could run page 1 in "debug mode" and who might reveal what is happening.
```
declare
type_of_user number :=0;
begin
select user_type into type_of_user from users where username= :APP_USER;
if type_of_user = 'BUYER' then
return true;
else return false;
end if;
exception when others then
return false;
end;
```
CITY

Failed authorization

Nice day.

Have a problem with authorization Ganymede +.

config:

AAA server Ganymede group + Ganymede-GDP

10.0.255.18 private server key single-connection 123

IP vrf forwarding mgmt

Ganymede IP source interface FastEthernet0/2/0

!

AAA authentication login default local group Ganymede-GDP

enable AAA, enable authentication by default group Ganymede-GDP

authorization AAA console

AAA authorization config-commands

AAA authorization exec default local group Ganymede-GDP

AAA authorization commands 15 default local group Ganymede-GDP

AAA authorization network default local group Ganymede-GDP

AAA accounting exec default group power Ganymede-GDP

AAA accounting command 15 by default start-stop Ganymede-GDP group

Debug:

HIGHER (000002FC) / 0/READING: read all header 12-byte (wait 16 bytes)

HIGHER (000002FC) / 0/READING: read all the reply 28 bytes

HIGHER (000002FC) / 0/15D4A80C: treat the response packet

MORE: Received the authentic GET_PASSWORD response status (8)

HIGHER (000002FC) / 0/no: started 120 sec timeout

MORE: Queuing request 764 AAA authentication processing

MORE: treatment authentication continue id request 764

MORE: Authentication continue package generated for 764

HIGHER (000002FC) / 0/no: timer collapsed

HIGHER (000002FC) / 0/WRITING/15D4A80C: started 5 sec timeout

HIGHER (000002FC) / 0/WRITING: wrote together 24 bytes of the request

HIGHER (000002FC) / 0/READING: read all 12 byte header (allow 6 bytes)

HIGHER (000002FC) / 0/READING: read all the reply 18 bytes

HIGHER (000002FC) / 0/15D4A80C: treat the response packet

MORE: Received the status of response authentic PASS (2)

MORE: Queuing request for AAA 764 transformation

MORE: treatment authorization request id 764

MORE: Protocol is set to None. Jump

MORE: Sending service AV = shell

MORE: Sending AV cmd *.

MORE: Application created to 764 (ingener)

MORE: previously set server group Ganymede-GDP 10.0.255.18

HIGHER (000002FC) / 0/IDLE/15D4A80C: got immediately connect on the new 0

HIGHER (000002FC) / 0/WRITING/15D4A80C: started 5 sec timeout

HIGHER (000002FC) / 0/WRITING: wrote requests to 64 bytes

MORE: Error in package header reading, stop the single sign-on

HIGHER (000002FC) / 0/15D4A80C: treat the response packet

MORE: Received invalid customer information in entry

And another question-

Why all the usernames on top of case?

username ADMIN privilege 15 secret *.

You can try without single-connection:

AAA server Ganymede group + Ganymede-GDP

10.0.255.18 private server

~ BR
Jatin kone

* Does the rate of useful messages *.

vCenter 5.1 to 6.0 external SQL 2008 upgrade fails during schema validation

We have:
-vCenter 5.1 on Windows 2008 server
-external SQL2008R2 SP2
We strive to upgrade to vCenter 6.0 on Windows server, but during the validation, we get this error: "Source vCenter Server Schema validation found a problem. Resolution: read the vcdb_err.log file and resolve the problems. »
This is the beginning of the vcdb_err.log:
_____________________________________________________
WARNING: Cannot run statement (rc = 100).
REMOVE FROM VPX_TABLE
^^^^^^^^^^
WARNING: Cannot run statement (rc = 100).
REMOVE FROM VPX_INDEX_COLUMN
^^^^^^^^^^
WARNING: Cannot run statement (rc = 100).
REMOVE FROM VPX_SCHEMA_HASH
^^^^^^^^^^
Error during l'execution.\upgrade-vmn-next-to-v2013\mssql\validate_mssql.sql:176, reason: cannot run statement (rc = - 1).
_____________________________________________________
All the world run into this problem?
Kind regards
F.

I did just this passage of 5.0 to 6.0.

Look to the right at the end of the error log: you see something like ERROR! Additional constraints: VPX_EXT_PRIVS. PK_VPX_EXT_PRIVS; ?

If so, back UP THE database (just in case...), then connect to the database and run the SQL command:

ALTER table VPX_EXT_PRIVS drop constraint PK_VPX_EXT_PRIVS

.. then retry the upgrade.

APEX_LDAP vs DBMS_LDAP and authorization schemas in the APEX.
I also posted this in the Oracle support community, so please forgive me if you've seen it twice now.

Grrr... This is the second time I'm trying this post. New communities here seem to have a strange way of not displayed properly.

My hair is going gray and I may soon be bald. I can't seem to work around a problem with APEX_LDAP and I can't seem to understand DBMS_LDAP. It seems that APEX_LDAP is written to be easier to use, but DBMS_LDAP is older and less refined.

Here's some code that I'm trying to use to a system of authorisation. This works, but only partially. It works for our entrepreneurs but not employees. Even if all of our users use the same format for their login name, they not stored with the same information for their DN in our OID. Now, because DBMS_LDAP has this property called filter, which can be used to target with the property to use when searching LDAP, can I use it to target the field UID instead of the NC and so all our users can use our OID for authentication. However, given that the APEX_LDAP package is that same property filter, my code breaks and I can't see a way around it.

What I need is an example of code that would remove a property by the Protocol LDAP using DBMS_LDAP and store in a variable I could call a little later on the name of the user to the APEX_LDAP.IS_MEMBER function. What I want in the end, it's for Oracle to add the filter for the various functions of the APEX_LDAP property.

-Start the block of Code-

DECLARE

L_TEST wwv_flow_global.vc_arr2;

L_TEST_VALUES wwv_flow_global.vc_arr2;

L_ATTRIBUTES wwv_flow_global.vc_arr2;

L_ATTRIBUTE_VALUES wwv_flow_global.vc_arr2;

L_CON_ATTRIBUTES wwv_flow_global.vc_arr2;

L_CON_ATTRIBUTE_VALUES wwv_flow_global.vc_arr2;

L_AUTH boolean;

L_VAL boolean;

L_WORKFORCEID NUMBER (8);

L_WORKFORCEID2 VARCHAR2 (21);

BEGIN

L_TEST (1): = "employeetype"

APEX_LDAP. () GET_USER_ATTRIBUTES

p_username = > V ('APP_USER').

p_pass = > NULL,

p_auth_base = > ' cn = users, dc = company, dc = com ",

p_host = > "servername."

p_port = > '389',.

p_attributes = > L_TEST,

p_attribute_values = > L_TEST_VALUES);

IF L_TEST_VALUES (1) = 'E' THEN

L_ATTRIBUTES (1): = "workforceid";

APEX_LDAP. () GET_USER_ATTRIBUTES

p_username = > V ('APP_USER').

p_pass = > NULL,

p_auth_base = > ' cn = users, dc = company, dc = com ",

p_host = > "servername."

p_port = > '389',.

p_attributes = > L_ATTRIBUTES,

p_attribute_values = > L_ATTRIBUTE_VALUES);

L_WORKFORCEID: = (L_ATTRIBUTE_VALUES (1));

L_WORKFORCEID2: = TO_CHAR (L_WORKFORCEID, ' 00000000');

L_AUTH: = APEX_LDAP.IS_MEMBER)

p_username = > (L_WORKFORCEID2).

p_pass = > NULL,

p_auth_base = > ' cn = users, dc = company, dc = com ",

p_host = > "servername."

p_port = > 389,

p_use_ssl = > 'n',.

p_group = > "BlahBlah_Test_Group"

p_group_base = > ' cn = Test, cn = groups, dc = company, dc = com ");"

ON THE OTHER

L_CON_ATTRIBUTES (1): = 'UID ';

APEX_LDAP. () GET_USER_ATTRIBUTES

p_username = > V ('APP_USER').

p_pass = > NULL,

p_auth_base = > ' cn = users, dc = company, dc = com ",

p_host = > "servername."

p_port = > '389',.

p_attributes = > L_CON_ATTRIBUTES,

p_attribute_values = > L_CON_ATTRIBUTE_VALUES);

L_AUTH: = APEX_LDAP.IS_MEMBER)

p_username = > (L_CON_ATTRIBUTE_VALUES (1)).

p_pass = > NULL,

p_auth_base = > ' cn = users, dc = company, dc = com ",

p_host = > "servername."

p_port = > 389,

p_use_ssl = > 'n',.

p_group = > "BlahBlah_Test_Group"

p_group_base = > ' cn = Test, cn = groups, dc = company, dc = com ");"

END IF;

IF L_AUTH = FALSE

THEN

L_VAL: = FALSE;

ON THE OTHER

L_VAL: = TRUE;

END IF;

IF L_VAL = TRUE THEN

HTP.p ('SUCCESS');

ON THE OTHER

HTP.p ("I go YOU BANKRUPT");

END IF;

END;

-End Code block-

Any help would be appreciated.

R. otto R. Wessels
Hi Otto.

Christian means something like the code I've used here: {message identifier: = 10197833}
You would need to adapt this code of course. Basically: bind, retrieve values, set values in an application (or elements). Then, create the authorisation schemes that test the values in these application elements.

Access an element on a page based on authorization scheme
Hello

I have two authorisation schemes: ADMIN and VIEW. I created a public page which will be available under both plans. But I want to display an item only to ADMIN not schema of the VIEW on this page in particular region.

Thank you
Manoi.
for properties in this area, go to conditional display and use the bult in function (after you choose plsql function to return a Boolean value): APEX_UTIL. PUBLIC_CHECK_AUTHORIZATION ('your_auth_scheme');
This function returns true if the current user is in this authorisation scheme:.

Let me know if this is useful,

Sam K.

How to redirect to the error page custom when the authorization page schema fails
Hello

I've done a permission scheme using PL/SQL function return Boolean option.

I made a custom error page.

I put this program in one of my pages for authorization. If the authorization scheme fails, I would like the user to be redirected to the custom error page. Currently, it displays a blank page with the mentioned in the section "identify error message displayed when plan violated" page text of the authorization.

Is there a way I can make this redirect to the custom on the failed authorization error page.

I am currently using Apex 3.2.0

Thank you
Pradeep
You can create an application process when loading and subordinate to run only when you load your pages, where you want to check if the authorization is successful or not. Your authorization process should run only once per session.
```
DECLARE
   v_page_id   NUMBER := 1000;                      -- your custom error page
BEGIN
   IF     NOT apex_util.public_check_authorization ('MY_AUTH')
      -- your authorization scheme
      AND :app_page_id NOT IN (101, 1000)
   THEN
      HTP.init;
      OWA_UTIL.redirect_url ('f?p=&APP_ID.:' || v_page_id || ':&SESSION.');
      HTMLDB_APPLICATION.g_unrecoverable_error := TRUE;
   END IF;
END;
```
Denes Kubicek
------------------------------------------------------------------------------
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------------------------------------------------------------------------------

command authorization failed

I turned on the aaa command authorization without applying the correct user privileges. I can now log on this user, but the ASA 5510 displays an error:

============================

EUKFW2 # show running-config

^

% ERROR: invalid input detected at ' ^' marker.

ERROR: Failed authorization control

============================

I'm unable to change the configuration of the firewall. Is there any default user through which I can connect and disable the authorization of aaa? If this is not the case, how can I solve this problem?

Please visit this link

http://www.ciscotaccc.com/Kaidara-Advisor/security/showcase?case=K10386224

Please evaluate the useful messages

Kind regards

~ JG

Logout fails authorization scheme

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