Determine the current item of blocks, region,... for use in the authorization scheme

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• Cannot authenticate because the authorization scheme limits the login page (101)

  Hello.
  
  I have a problem with authentication. I have an application with authentication and authorization schemas created from scratch. There is an option in the security attributes of the application that lets you apply a pattern of authorization for the entire application. I also have a login page (101) that I use for authentication purposes that I don't get, since approval is the application level. Even if the login page is established a system of authorisation that always succeeds APEX makes no difference. How do I approach this issue so that authorization for the entire application is always possible with authentication?
  
  Thank you.

  I'm not sure that it would necessarily change in the future because so many things in one schema authorization should be defined by the developer that it's probably wise for Oracle make Apex still do not know the application of the law on the login page. Although I can't think of a realistic example for now, maybe there could be reasons were based on external criteria that even the login page should not be available to a small group of people? I wouldn't exclude it as a possibility.

  That's why when you implement a system of authorisation, it is probably best that Oracle makes no assumptions about what you want to do and you just explicitly it you include in the plan.

  By dig a little and in defensive coding and style, you might not even want to consult directly the "101" page. May be wise to do a ' select PAGE_FUNCTION in the APEX_APPLICATION_PAGES where PAGE_ID =: APP_PAGE_ID and APPLICATION_ID =: APP_ID. If PAGE_FUNCTION comes back as "Login", then this is your login page and return TRUE. Otherwise, continue with some other logical returns boolean you have to leave. This way you stay clear page to hardcode and even independent of both page alias value (because they are not mandatory).

• How to redirect to the error page custom when the authorization page schema fails

  Hello
  
  I've done a permission scheme using PL/SQL function return Boolean option.
  
  I made a custom error page.
  
  I put this program in one of my pages for authorization. If the authorization scheme fails, I would like the user to be redirected to the custom error page. Currently, it displays a blank page with the mentioned in the section "identify error message displayed when plan violated" page text of the authorization.
  
  Is there a way I can make this redirect to the custom on the failed authorization error page.
  
  I am currently using Apex 3.2.0
  
  Thank you
  Pradeep

  You can create an application process when loading and subordinate to run only when you load your pages, where you want to check if the authorization is successful or not. Your authorization process should run only once per session.

  DECLARE
     v_page_id   NUMBER := 1000;                      -- your custom error page
  BEGIN
     IF     NOT apex_util.public_check_authorization ('MY_AUTH')
        -- your authorization scheme
        AND :app_page_id NOT IN (101, 1000)
     THEN
        HTP.init;
        OWA_UTIL.redirect_url ('f?p=&APP_ID.:' || v_page_id || ':&SESSION.');
        HTMLDB_APPLICATION.g_unrecoverable_error := TRUE;
     END IF;
  END;
  

  Denes Kubicek
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• The current block size for a store of data in VMFS3 is 4 MB. Must upgrade thedatastore to VMFS5 and wants to change the block size of 1 MB

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• How to determine the index of an item in a cluster?

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• How to determine the threshold for an LED voltage

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• IPCC Express - determine the age of current contact

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  Check:

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• Equivalent of PowerShell for script following VBScript determine the active node of the cluster?

  Hello world

  I wonder if there is another similar Powershell script that can determine the currently active node of an MSCS?

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  Any kind of help is appreciated.

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  Best regards, Robert

• Determine the index of the selected items in a ListBox?

  Hello

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  I feel I'm missing something, but I can't seem to figure out who (if any) returns an index number if you use it with the recall of .onChange for a ListBox control.

  The following code implements that I need, but is not particularly efficient or elegant and can get confused if you introduce multiple lists to check.

  Any suggestions to reproduce this behavior, even with the best code would be appreciated.

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  var RES = ' palette {text: 'Example-list' properties: {resizable: true}-} ".

  NLP: Panel {orientation: 'row', preferredSize: [400 600]------}

  list1: ListBox {preferredSize: [400 550], properties: {multiselect: true, numberOfColumns:2, showHeaders:true, columnTitles: ["list 1", "item 0"]}}, \

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  Win.Show)

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  for (i = 0; i < win.pnl.list1.items.length; i ++) {}

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  }

  .. .in the same time, that should be enough

  win.pnl.list1.onChange = function() {
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  }
  

  I guess you already tried and the result is 'undefined', the reason is that you have this property

  multiselect:true
  

  in this case, the selection returns an array

  this.selection[0].index;
  

  I'd give you the first selected item, even if you only have a single element selected, for all selected items to loop through all the elements in the selection table.

  not sure if the wonderful guide Peter explains this (explained in the Guide to the tools), but you should read it too, he has tons of info.

• Is there a way to get the number of the current item?

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  Thank you
  
  Published by: WayneFMcKinstry on April 9, 2010 10:50

  If I get you correctly in tabular element that you want to know the current record or current, you can try this...

  For the current record

  :SYSTEM.CURSOR_RECORD;
  or
  :SYSTEM.CURRENT_RECORD;
  

  for the current element

  :SYSTEM.CURSOR_ITEM;
  

  -Clément

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  It seems that this topic has been posted on another thread, which can be found here. Other issues/updates should be posted on that thread. Thank you!