Loop problem - please help :-)

Hi I'm relatively new to PLSQL and I'm having a problem with a loop does not execute properly. I'll show you the code below (it's a bit long sorry) and then I'll explain it in detail, and then explain the problem.

I'm looping 1.student_count

/*

HTP.print (' student # ');
HTP.print (i);
HTP.print (')
');
HTP.print ('PIDM: ');
HTP.print (pidm_store (i));
HTP.print (')
');
HTP.print (' participated in the answer: "");
HTP.print (atten_store (i));
HTP.print (')
');
HTP.print ('CRN #: ');
HTP.print (crn_store (i));
HTP.print (')
');
HTP.print ('~ ~ ~');
HTP.print (')
');
HTP.print (')
');

JK * /.

OPEN AttenCheck (pidm_store (i), crn_store (i));
Look FOR AttenCheck IN temp_atten;

IF temp_atten IS NOT NULL THEN

HTP. Print ('test');

ON THE OTHER

IF i < = 9 THEN

j in 1.100
loop
If atten_store.exists (j) then

IF substr (atten_store (j), 1, 1) = i AND substr (atten_store (j), 2, 1) = "a".
THEN

temp_codes: = 'a ';
temp_responses: = temp_responses | temp_codes;
temp_codes: = null;

ELSIF substr (atten_store (j), 1, 1) = i AND substr (atten_store (j), 2, 1) = "b".
THEN

temp_codes: = 'b ';.
temp_responses: = temp_responses | temp_codes;
temp_codes: = null;

ELSIF substr (atten_store (j), 1, 1) = i AND substr (atten_store (j), 2, 1) = "c".
THEN

temp_codes: = 'c ';
temp_responses: = temp_responses | temp_codes;
temp_codes: = null;

ELSIF substr (atten_store (j), 1, 1) = i AND substr (atten_store (j), 2, 1) = has '
THEN

temp_codes: = ';
temp_responses: = temp_responses | temp_codes;
temp_codes: = null;

ELSIF substr (atten_store (j), 1, 1) = i AND substr (atten_store, (j), 2, 1) = 'e '.
THEN

temp_codes: = 'e ';
temp_responses: = temp_responses | temp_codes;
temp_codes: = null;

ELSIF substr (atten_store (j), 1, 1) = i AND substr (atten_store (j), 2, 1) = "f".
THEN

temp_codes: = 'f';
temp_responses: = temp_responses | temp_codes;
temp_codes: = null;

ELSIF substr (atten_store (j), 1, 1) = i AND substr (atten_store (j), 2, 1) = "g".
THEN

temp_codes: = "g";
temp_responses: = temp_responses | temp_codes;
temp_codes: = null;

ELSIF substr (atten_store (j), 1, 1) = i AND substr (atten_store (j), 2, 1) = "h".
THEN

temp_codes: = 'h ';
temp_responses: = temp_responses | temp_codes;
temp_codes: = null;

ELSIF substr (atten_store (j), 1, 1) = i AND substr (atten_store (j), 2, 1) = "i".
THEN

temp_codes: = 'i ';
temp_responses: = temp_responses | temp_codes;
temp_codes: = null;

ELSIF substr (atten_store (j), 1, 1) = i AND substr (atten_store (j), 2, 1) = 'j '.
THEN

temp_codes: = 'j '.
temp_responses: = temp_responses | temp_codes;
temp_codes: = null;
END If;

END IF;

end loop;

j: = NULL;
temp_codes: = NULL;

ON THE OTHER
j: = 1;

j in 1.100
loop
If atten_store.exists (j) then

IF substr (atten_store, (j), 1, 2) = i AND substr (atten_store (j), 3, 1) = "a".
THEN

temp_codes: = 'a ';
temp_responses: = temp_responses | temp_codes;
temp_codes: = null;

ELSIF substr (atten_store (j), 1, 2) = i AND substr (atten_store (j), 3, 1) = "b".
THEN

temp_codes: = 'b ';.
temp_responses: = temp_responses | temp_codes;
temp_codes: = null;

ELSIF substr (atten_store (j), 1, 2) = i AND substr (atten_store (j), 3, 1) = "c".
THEN

temp_codes: = 'c ';
temp_responses: = temp_responses | temp_codes;
temp_codes: = null;

ELSIF substr (atten_store, (j), 1, 2) = i AND substr (atten_store (j), 3, 1) = has '
THEN

temp_codes: = ';
temp_responses: = temp_responses | temp_codes;
temp_codes: = null;

ELSIF substr (atten_store (j), 1, 2) = i AND substr (atten_store, (j), 3, 1) = 'e '.
THEN
;

temp_codes: = 'e ';
temp_responses: = temp_responses | temp_codes;
temp_codes: = null;

ELSIF substr (atten_store (j), 1, 2) = i AND substr (atten_store (j), 3, 1) = "f".
THEN

temp_codes: = 'f';
temp_responses: = temp_responses | temp_codes;
temp_codes: = null;

ELSIF substr (atten_store (j), 1, 2) = i AND substr (atten_store (j), 3, 1) = "g".
THEN

temp_codes: = "g";
temp_responses: = temp_responses | temp_codes;
temp_codes: = null;

ELSIF substr (atten_store (j), 1, 2) = i AND substr (atten_store (j), 3, 1) = "h".
THEN

temp_codes: = 'h ';
temp_responses: = temp_responses | temp_codes;
temp_codes: = null;

ELSIF substr (atten_store (j), 1, 2) = i AND substr (atten_store (j), 3, 1) = "i".
THEN

temp_codes: = 'i ';
temp_responses: = temp_responses | temp_codes;
temp_codes: = null;

ELSIF substr (atten_store (j), 1, 2) = i AND substr (atten_store (j), 3, 1) = 'j '.
THEN

temp_codes: = 'j '.
temp_responses: = temp_responses | temp_codes;
temp_codes: = null;

END IF;

END IF;

end loop;

END IF;

So here's the problem with this code.

I collect responses from the box on an html form - each (if enabled) box adds value to atten_store which is in this format (student #) to j, if the student is no. 1 and the person checks 3 checkboxes (the top 3), then the values of atten_store (1)-(3) would be 1 a, 1 b 1 c respectively. - so I store these responses in atten_store (x). The following code loops through student records and controls for their individual responses.

There may be up to 50 students with up to 9 responses each. so up to 450 values in atten_store.

The above loop starts by counting the total number of students and a loop in each where i represents the student number. IF statements are of course intended to determine if the student is # 1-9 or 10 + the reason for this is the values box... all students will be from 1 to 9 have values like this: 1a, 5 g, 9j etc - where the nature, the research will build on these 2 characters to find the right letter for a given total student. Loops removes the previous letter and gives the values provided for each student. The value of end, sent to the DB for 1 student is so, as you can see if student 1 gave a 1a, 1 c, 1f 'acf '.

For students who are > student # 9 must be treated differently as its replies of 3 characters. ex: 10A, 10B, so if I < = 9 then do one thing, if I > = 10 then do something else. By something else I am just searching differently if characters.

Of course, I suppose that there is a way better way to do it, but if you make the suggestion please try to explain it better, you can so I can try to implement with the rest of the code. in any case this is the problem...

On the entry screen with check boxes when I press on submit on page 1 - Page 2, load - which the above code is responsible. Page 2 shows the responses so far, and will soon add to DB. When I put in no value for student 1-9, this code works and display page 2. It will show the answers given for each student (ONLY WHEN I GET the ANSWERS FOR STUDENTS 10 +) if I get any response for students does not load 1-9, page 2. I get no error at all - so I guess its a kind of problem of NULL value or something (why not IE or Firefox displays an error? just page not found), but when I come back and only enter values for students 10 + it works beautifully.

So of course, my need is this: I want to be able to enter values for any student 1-9 or 10 +! She's. I guess it is a mistake to loopback somewhere in there, and I would be grateful any entry :-)

Thanks in advance,
Jeff

Published by: 795018 on Sep 15, 2010 08:25

Hello

You can simplify your code (parts):

IF i <= 9 THEN
  for j in 1..100
  loop
    if atten_store.exists(j) then
      IF substr(atten_store(j), 1, 1) = i
      and substr(atten_store(j), 2, 1) in ( 'a','b','c','d','e','f','g','h','i','j')
      THEN
          temp_responses := temp_responses || substr(atten_store(j), 2, 1);
      END IF:
   end if;
 end loop;
else
  -- same kind of code only for i>= 10

There is no closing the cursor (OPEN AttenCheck (pidm_store (i), crn_store (i))); in your code shown. Where you don't close it?

In addition, you have only a loop from 1 to 100 for j, but you mentioned, it could be 450. Is it possible that the students of 1-9 are not in this range? The atten_store table begins with your students of 1-9, or perhaps with the number 22.

Hope that helps a bit

Herald tiomela
http://htendam.WordPress.com

Tags: Database

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