Member access

Similar Questions

• Member access path Dynamics-shipping VI

  
  

  So, now that I rejected the CAR, you probably want an answer to your original question about how to get all the dynamic transmission screws, which has can be invoked by a particular VI.
  Sorry, I don't have an answer for you. Properties/methods to expose this was requested, but nothing has been put in place for this information directly. You can - if you did somehow access to scripts - cross diagram you are looking for all terminal nodes entry of dynamic distribution and then the name of these nodes, cross all hiearchies class in memory asking for any class that has a VI of the same name. It is not trivial to do at all.

• How to restrict the security report page member access

  c

  This is a current request for filters of planning as metaread - which will mimic what planning is. Cameron Lackpour has a hack for the same thing.

  Blog of Cameron for hackers Essbase: setting the filters of planning

  Concerning

  Celvin

• Outline in Planning access permissions

  Is it possible to have a report of the permissions that are given to the members of the planning outline 9.2.0.3 (via Administration-> size-> Assing access).
  
  We want something like:
  Product
  User1 100: read, user2: write
  100-10 user2: no
  100-20 user2: read
  100 30
  the 200 util_3: no
  ...
  
  
  Or something like:
  Product
  User1 100: read (idescendats), user2: write (idescesdants)
  User2 100-10: none (member)
  100-20 user2: read (member)
  the 200 util_3: none (idescendats)
  ...

  Hello

  Here is an example of SQL query that retrieves the authorization information, just run it against you planning database.
  It was written for SQL server, but can be easily changed for Oracle.

  SELECT usr.object_name as Username, mem.object_name as a member,
  "Access rights" = acc.access_mode CASE
  WHEN-1 THEN 'none '.
  WHEN 1 THEN 'read '.
  WHEN 2 THEN 'write '.
  WHEN 3 THEN 'write '.
  End OTHER 'unknown ',.
  'Relationship' = CASE acc.flags
  WHEN 0 THEN 'Member '.
  WHEN 5 THEN 'children '.
  WHEN 6 THEN '(inclusive) children '.
  WHEN 8 THEN "Descendants".
  WHEN 9 THEN 'Descendants (inclusive).
  End OTHER 'unknown '.
  Of
  hsp_access_control VAC, hsp_object mem, hsp_object usr
  WHERE acc.object_id = mem.object_id
  AND acc.user_id = usr.object_id
  - AND mem.object_name = 'option by member name '.

  See you soon

  John
  http://John-Goodwin.blogspot.com/

• delegate method calls to the members of a class

  Hello

  I'm new to LabView and using the 2013 version.

  I am familiar with the concepts of object-oriented programming.

  situation/goal

  I have a controller that controls axes. The controller said communication happens via plain text messages.

  I want to control the two axes with orders abstract (moving, stop, speed change, etc.) of LabView.

  That's why I created a class of axis with several parameters. (although)

  The controller communication is established via an ActiveX reference.

  I created a controller class that holds said reference in addition to the two axes.

  My goal here is to create a controller object, which past its ActiveX reference for the two axis.

  To add lines to the controller I dragged the class axis from the window of the class controller twice overall project.

  I created some accessors to all members of the class of the axis, including its ActiveX reference.

  problem

  In the Set accessor method for the controller class ActiveX reference, I would like to call the setters for the return of the two axes objects that contains the ActiveX controller.

  I can separate the controller to see the two axes, but I can neither unbundle either of the axes nor can I add a method node to them.

  It is logical that the separation is not possible to ensure encapsulation, but why can't I just call a method?

  Am I still add references to objects when you drag the axis class?

  Or is what adds the class itself?

  If this adds the class, how can I add a reference to an object of a certain class as a member of another class?

  I've attached a screenshot of the controller class.

  Thank you for your help.

  Hello

  The object Oriented Design is rater hard. Encapsulation banned, as you said, the data from your classes are defined outside their class.

  In your case it means that you have to create a data member access VI inside of the class of the Axes. These access screws (methods) allows you to set the values for these axes of type two objects inside of the controller of the class. Make sure that these two classes are in the less community.

  You can refer to a class using reference data value, Yes, BUT in this data type to the reference class is included. At the time, it seemed more convenient: LabVIEW programming job: The decisions behind the Design http://www.ni.com/white-paper/3574/en/

  Self an example here:

  Examples for the new reference value of data with the Forums of Discussion LVOOP https://forums.ni.com/t5/LabVIEW/Examples-for-New-Data-Value-Reference-with-LVOOP/td-p/1317493

  If you want to use data heavily references, I would recommend the GOOP package, which has different design questions build in singleton as etc. (which are not possible by default in LabVIEW)

• Call in reference to replacement VI

  I'm doing a VI dynamically a reshipment that accesses a property in a class with name. (see attachment) The idea was to use 'call of reference' for the property required to call the correct data VI member access. The CBR does not preserve the dynamic wire of the input to the output, causing the VI must be broken. (see second attachment)

  Two questions: first, why it does not work? I understand that Labview must ensure this type of performance is preserved by a dynamic send substitute VI, but why couldn't you just take and raise an error if the type is not maintained? Secondly, any ideas how to get around this limitation?

  I agree that people can be so rude.  So ungrateful too.  What is the youth of today come at all.  I have really no idea.  The future is surely doomed.  Cursed I say!

  Now back on topic...

  Why don't simply implement you a class method rather than load a VI member by reference?  Simply, I do not understand the role of the party "by reference" here.

  If you MUST go this way (which I doubt at the moment) so please plan why call a DD VI dynamically is a requirement.  In the meantime, insert a primitive 'Preserve the class Run-Time' on the output of your dynamic call.

  That COULD help.

• Why the parent class does not report data for child in LVOOP class?

  Attached is a practical program that I wrote to learn about the legacy with LVOOP.

  I have the impression of OOP is a Parent class describes the type of object.  Then the children inherent description of the parent.  The child may also have additional qualities, but it still contains the description of the parent.  If a child does not have a VI bearing the same name as the parent and the parent VI will be loaded and executed.

  My questions:

  (1) why does the Parent.lvclass:Read.vi not report 'Child' in the channel indicator when the child write VI has been sent?

  2) matches the data of the child, do not at all seen by the parent company even when it has the same definition (that's the String)?  I understand that the Parent do not know anything about the unique child elements, but I think we should know about the common themes which inherited the child.

  Here is my sample code:

  

  These are two different sets of data. The parent class has a data set containing the string, the class of the child also has a data set containing the string, but both of these channels are separated.

  This can be made apparent, by changing the names of the channels based on their respective categories:

  

  What you want is for your children, class VI write to access the data of the parent class. You can do this with a simple data VI member access in VI of the child:

  

• Netflix password

  Original title: forgotten password

  I forgot my password for netflix

  Hi tristate (2),

  If you refer to the website (member access) Netflix password, please visit this link to Netflix.

  If this isn't what you are looking for, then respond with more information on the issue.

• LACP configurations 6509

  Hello everyone, I looked around the community to solve a problem on creating connections between my 6509 Ehter channel and a server using Broadcom Advanced Control Suite 4 to create the collection of NETWORK adapters.

  I found different configuration settings that revolve around similar settings, but in some cases items are excluded or included I may need.

  Our facility is 2 servers to connect to 6509 s 2.

  Each 6509 a g9/17, g9/19, g9/21 and g9/23 ports allocated for use.

  The idea is to have spend A connect on the first 2 and B connect to the second 2 on both 6509 s.

  9/17 and 9/19 ports must be configured for LACP create channels of ether.

  Someone at - it a good document referred me so I can create configurations?

  So far, I have:

  int g9/17

  no ip address

  channel-protocol lacp

  active in mode channel-group 1

  LACP port-priority 1

  I've seen other configurations which create the channel protocol int first, then trunking, which we don't think that we need.

  The addition of VLAN native plus the server VLAN which is located in the server.

  I really need to know when to use which type of configuration.

  EJ

  Normally configure you ports members first and make sure they have a compatible configuration. If you want to run it in L2 and with a single mode VLAN then set the Member access and in the correct VIRTUAL LAN ports. Something like:

  conf t

  int rank gi9/17, gi9/19

  switchport

  switchport mode access

  switchport access vlan x

  active in mode channel-group 1

  channel-protocol lacp

  Daniel Dib
  CCIE #37149

• Files shared/upgrade Win7

  I have a local network, ORGANIZATIONAL unit called "GroupA".

  All members of the GroupA can access the resources of the GroupA

  GroupA has a shared folder hosted on Win7 Pro PC.  On all the following folders are defined:

  MemberA, MemberB, MemberC and member access R/W access

  Member and MemberF can visit r

  MemberD is a user on the host computer.  MemberD has all rights of access as MemberA and MemberB MemberC

  MemberD can open and edit the files in the folder; However, when MemberD makes a change to a file, it will NOT refresh in the folder.  MemberD added a file in the folder, but no one can see it.  MemberD can only see it.

  MemberD can access a database in the shared folder and a record.  Nobody can see that added record.

  One thing I noticed on the shared folder is a check mark on the top left of the folder icon.  That this has something to do with the question?  (Not sure if she did or not)  All rights and permissions are the same as other users.

  Any ideas or suggestions?  Management of versions or libraries have something to do with its ability to change?

  Hello

   
  1. do you get an error message/code?
  2. don't you make changes to the computer before the show?
  3 are the computers via homegroup?
  3 are connected to a domain network computers?
   
  Here are some links that may be useful:
   
  Share files with anyone
  http://Windows.Microsoft.com/en-in/Windows7/share-files-with-someone
   
  File sharing essentials
  http://Windows.Microsoft.com/en-in/Windows7/file-sharing-essentials
   
  File and printer sharing: frequently asked questions
  http://Windows.Microsoft.com/en-SG/Windows7/file-and-printer-sharing-frequently-asked-questions
   
  "Access denied" or other errors in the access to or work with files and folders in Windows
  http://support.Microsoft.com/kb/2623670
   
  I hope this helps. If you have any other queries/issues related to Windows, write us and we will be happy to help you further.

• Is there a way to create a site of members paying using Muse?

  A customer is willing to a Web site that has an area that is available for paid subscriptions. I already read about how to create secure areas, I was wondering if there was a way to create a part of the paid subscription to the form. I've seen several clues as to what is a possibility. Was wondering if anyone has experience in this particular area? Or even a sense of research.

  Thanks for the info.

  It would be as follows:

  -Create a page in British Colombia, who you want to be the launch page of the safe zone, where users are connecting and then they will be directed to this page.

  -Go to the Site Manager > Secure area > create secure area, check selling member access, set, currency, amount and frequency. Monetary would be the currency of country members, frequency and the amount you want to users to pay would be that time which membership expire.

  -Go to the Site Manager > Web forms > create web form > edit properties, select the area safe in the secure area list > add a user name and password field > specify the payment method

  -Open the page where you want to insert the secure area login form and web form allowing users to enroll in the secure area and make the payment.

  Now with Muse, you can insert the html part of the content that you have created in Colombia-British

  -Open the page in Muse where you want to insert the sign in form, copy the html code of the form that you created in British Colombia and then insert into the Muse Page.

  -In the same way do sign in form.

  Please note that the published site of Muse are hosting sites web which does not include the secure area, so you would need to upgrade the site plan which is a subscription to a different site.

  Although you can first try with a trial site (get in touch with support where they can modify the sitemap of your trial site) as well as how it works, and then after that you finalize your site you can switch to the paid site.

  This document includes instructions how to safe installation zone:

  http://helpx.Adobe.com/business-catalyst/partner/add-secure-area-your-site.html#id_31582

  I uploaded a short video for your reference showing the steps, please download here:

  https://www.dropbox.com/s/5vpg1qu3jpnx1bz/Tut_Eproduct.mov

  Thank you

  Sanjit

• Reapply rules for existing users

  Hello to all IDMers;
  
  We have a seasonal group called for the Member access is based on the rule that there are two fields an is true and also based on the employee type that is "seasonal."
  There are other users who are of type EMP different BUT with the other field set to true.
  Now what we have decided is to all who on the ground are true in this group, regardless of their type of employee.
  
  So go ahead for new users we can easily implement this because I'll delete the Emp Type = seasonal status of the creator of the rule.
  But can you please tell me if there is an easy way to juice using design or admin console to apply this condition to all existing users.
  
  I hope that I don't confuse you all.
  
  Best regards;
  
  VSN

  Have you tried that? It must return all groups...

  Thank you
  Suren

• Users that are not not in Shared Services

  I created a Hyperion Planning 11.1.1, application commissioning has been done perfectly, while providing access via "* access control report *" I couldn't pick any user, including native users as "admin", none of the users are in the field available users or groups. "
  
  Configured applications of Hyperion which: Essbase, Planning, Shared Services and space to work with SQL server 2000.
  
  Please suggest. Thanks in advance.

  Hello

  First of the security warning means that all dimensions standards need to access permissions applicable to them (account, entity, scenario, version)
  Also administrator doesn't have the same constraints on access permissions, which means that you do not need configure the security of the members to the admin user

  If you directly connect to shared services (http://: 28080/interop/index.jsp)
  Expand user directories > native Directory > users > New > annotates
  Right click on the new user and available, give the user one of the planning no administrator roles, I would say that the role of Planner.

  Now you connect in planning and try and assign permissions member access, you should be able to assign permissions to the new user.

  See you soon

  John
  http://John-Goodwin.blogspot.com/

• Cannot access the directory, even if I am a member of the Group

  Hello

  I created the folder on C:\Temp2 and give full persmisons as the Domain Admins group. I am logged on as a member of Domain admins.

  

  When I try to access the C:\Temp2 folder I get this error:

  

  Why system does not recognize me? I am a member of the domain admins group? Strange...

  Reparse point?

  OK, but this also happens if I set the permisions in Local Administrators (instead of the Domain Admins group)

  And Yes, I am administrator of domain in our society for real :)

  Why not ask Google:

  What is a reparse point?

  A lot of great responses. And I still recommend Technet for your post related to the areas.

• My user is a member of the Administrators group, but I got ACCESS DENIED with some files?

  My user is a member of the Administrators group, but I got ACCESS DENIED with some files?

  I know the meaning of the trace, I did not sense trace in this sentence! Once again, I don't undrestand why a user as an administrator cannot access anythings?

  Administrators can access anything, but they often need to take ownership of a file or folder to open it. By examining the details of the property, the owner can easily say that an administrator has reviewed his file or folder.