Moving columns in the tabular presentation

Similar Questions

• Dynamically set read-only columns in the tabular presentation at record levels

  Hello

  Is it possible to activate and deactivate fields at the level of the line in a tabular presentation... I use OFA to create a page that should give the possibility to activate and deactivate certain fields in the table on the fly...

  Here's the requirement:

  examples of data

  Item_code |   Review | Point Attrib1 | Article attrib2 | Article attrib3 | Columna | ColumnB

  1.234               100           A                         B                    _                  A               _

  1.235               100          B                              _                 B                 _                   A

  fields point attrib3 and Columnb should be read-only if the value of attrib1 point is A

  Even if point value attrib1 is B columna and attrib2 of the element must be read-only...

  I have PPR on item_attrb1 to manage the change of value in the attrib1 element, but I'm not able to make fields read only at the level of the line... Please help me if someone has work around this

  Is this possible?

  Thank you

  Dilip

  Hello..

  It is possible. Made myself.

  You must use SPEL for this.

  Steps to follow:

  1. the Caisse one type of transitional say as Boolean column ReadOnly

  2 set the Readonly property for that column as ReadOnly

  (Syntax FRO SPEL-> {oa. VO. ReadOnly})

  3 al ' PPR after checking the status, the ReadOnly Anaïs value accordingly.

  .

  You can get the idea here.

  https://blogs.Oracle.com/manojmadhusoodanan/entry/hiding_an_item_conditionally_through

• I need to rename a column for a tabular presentation

  How to rename a column, I created for a tabular presentation?

  I added a new column to a tabular presentation (using 'add a new link in the column') and he gave me a name of column, called "link column. I tried to change, but it does not - note: I can't change a sql column does not exist outside Apex - I created it for the display of a calculation.

  I don't know that it can be done as I did before.

  change the column name

  Does not change the name of so cannot reference in my calculation

  Well, I found a way to do it anyway. This should be changed in the definition of region > source.

• How to use a Select list on a second primary key column in a tabular presentation?

  Hello
  
  I created a tabular presentation located on the details page of the user (form), that allows to manage roles for this user.
  
  The shape of table contains 3 elements:
  -> a checkbox
  -> user (PK) column is hidden, and its default value is generated by a function pl/sql (to submit the time), which refers to the element to username.
  -> the role of the column is displayed as a named select list LOV: add you a line, choose a role, submit, etc..
  
  But my ROLES table (not created by me...) contains 2 columns: USER and GRANTED_ROLE.
  The USER is the primary key, but a user can have multiple roles (= one line per role).
  GRANTED_ROLE is the second primary key, so that we can differentiate between one line of another.
  
  At the moment my tabular form has only one primary key (USER), so the GRANTED_ROLE can display as a list select.
  But, for this reason, in my opinion, remove the button do not work: all the lines of the user have the same key, so when I select a few lines to remove these, all lines in the form of tables are deleted.
  
  I don't know how my button Delete could recognize the subkey to remove only selected rows...
  Or maybe I should use a different type of region?
  
  Thanks for your help!
  Fanny

  In the process of ApplyMRD, try to specify the 'secondary key' column in the section "Source: Multi line Update and Delete"to the second column key in tabular form.»

  I have not tested this with your situation, but worth it.

• How to add the new column in the tabular layout editor in Oracle Forms

  Hello
  
  I need to add the new column to a datablock and display the newly added column in the form. What are the steps I need to follow.
  
  1. I chose the new column from the view to the datablock.
  2. Add the text element in the layout editor. But this position is not correct. It overlaps with another column. How to add the new column to the layout editor?
  
  Thank you
  HC

  In the layout editor, you can simply drag the fields so that they do not overlap.
  See http://www.youtube.com/watch?v=7emNa7THMLg

  Sandeep Gandhi

• How the Group of columns in the tabular section?

  I have a table have many columns, how to hardcode in a few columns combined text group name1 and remains of columns in Group 2?

  Summit theme universal - 42

  development environment: apex.oracle.com

  

  Ramani_apex wrote:

  I have a table have many columns, how to hardcode in a few columns combined text group name1 and remains of columns in Group 2?

  Summit theme universal - 42

  development environment: apex.oracle.com

  

  Why "Group 1" appear twice? If there are only two groups involved then all columns of 'Group 1' must be contiguous, followed by all the columns "group 2"(otherwise there are actually three groups...)

  1. create a copy of the Standard report template. Notice that the model contains a hard-coded column layout names of columns of that group it can be used only for tabular forms and reports containing this specific set columns in this provision and it must therefore be appointed accordingly.

  2. change the new report template, the definition column header before changing to:

  
    Group 1Group 2Group 3
  

  3. edit the report used in the region in a table in the new model model.

• Date of the tabular presentation should show only 1 date every year

  can someone please help.

  on the date in a table column, can we choose only on or before January 1 of each year.

  Apex. Oracle.com

  w/u/p: nani5048/test/test

  Thank you

  Nani

  fact

• setting the selection list values in the tabular presentation

  Hi all
  
  I have a form of a table with a column that contains lists of selection I need to set the values for all rows in the form of tables.
  I'm trying to set the values on the click of a button, but apparently not enough to work.
  
  Is there another way to do it, perhaps with javascript?
  
  Any help would be appreciated.
  
  Kind regards
  Cleo

  Cleo,

  He's working now, sorry I missed the fundamental thing that you try on a selection list and not entry, as says my above entry script...

  Just use this code

  $('select[name="f10"]').val('Y');
  
  //OR this if you need to loop through them
  
  function approveAll(){
     jQuery.each($('select[name="f10"]'), function(i) {
      this.value ='Y';
    });
  }
  

  It was me!

  Published by: VC on July 13, 2012 15:57

• Change the index file in the tabular presentation

  OK, this is probably the most stupid and at the same time more simple question ever, but I couldn't find an answer until now

  I use Dreamweaver CS3 and want to build a very simple page with three columns and two rows, where a file is links to each cell. I can set up very well, line up a file for each cell, everything seems correct, but...

  .. If I open the index by the file manager file, even though I see the index page, I can only work directly in the built-in secondary files (and their file names appear in the tab at the top). But I would also like to work in the index file, i.e. change the size of the columns, etc. file names. How can I directly edit the index file (with the exception of the use of an external text editor?).

  Thx for your help!

  Sorry for the confusion between you

  It is an html file and I want to modify it using Dreamweaver.

  The link you provided gave me a clue where to check...

  I activated--> view-->--> frame borders Visual AIDS

  Now, I can see the different frames and edit them and also to change the index file itself.

  So thx for your reply, it has been useful

• How to access a column value in a Select list in a tabular presentation for each line

  Hello

  Environment: Using Oracle APEX v4.2.1 on an Oracle 11 g 2 DB

  In a tabular presentation using the following example query, i.e.:

  select
  "EMPNO",
  "EMPNO" EMPNO_DISPLAY,
  "ENAME",
  "HIREDATE",
  "SAL",
  "DEPTNO",
  "MY_LOV"
  from"#OWNER#"."EMP"
  
  

  I need access to every line of my sub form of table, the EMPNO of this line value, within a list of selection (query based LOV) in the column "MY_LOV."

  So, basically, the MY_LOV column in my table presentation, would be a list of selection (query based LOV) where MY_EMPNO =: EMPNO (first column in the select statement above), for each line of the tabular presentation.

  With the help of a picture ( Tom's Blog ) and assuming 'Deptno' column here is actually my new column, i.e. "MY_LOV, I want to know how this list of selection based on lov query would be able to access each EMPNO down in the form of tables, i.e. 7839, 7698, 7782 etc.?

  

  Any help would be appreciated.

  Thank you.

  Tony.

  Hi Tony,.

  Take a look at the API APEX_ITEM for LOV

  http://docs.Oracle.com/CD/E37097_01/doc/doc.42/e35127/apex_item.htm#AEAPI208

  Kind regards

  Brad

• Tabular presentation - defining a line just to the first of the default value.

  Hi all
  
  How to set a default tabular form only in the first row?
  When I click on "add row" I want the new line have an empty value.
  
  Thanks in advance.

  Hello

  When you add a new line to the shape of the table, all existing lines must be recorded in the database. You can, therefore, to verify the existence of these files and set the value of a page hidden as a result element. The default value for an item of tabular presentation can then rest on this hidden item.

  This is possible by setting the Source used for "Always,...» "on the hidden item called, say, P1_DEPTNO_DEFAULT, and the Source to something like:

  DECLARE
   X NUMBER;
  BEGIN
   SELECT COUNT(*) INTO X FROM EMP WHERE DEPTNO = :P1_DEPTNO;
   IF X > 0 THEN
    RETURN '';
   ELSE
    RETURN :P1_DEPTNO;
   END IF;
  END;
  

  It is a Type of Source of "body of the PL/SQL function.

  In this example, we will check if there are all the records with a DEPTNO value that matches the P1_DEPTNO EMP. If there is, then the tabular presentation must contain at least one line already, so we return an empty string. If there is no record, the tabular presentation should be empty, so return us the value of P1_DEPTNO.

  The default settings on the DEPTNO column in tabular form would then be:

  Default type: (name of the application or page element) Element
  Default: P1_DEPTNO_DEFAULT

  Andy

• Get the selected value of a select list item in a tabular presentation.

  Hi, I have a tabular form and I'm trying to get the selected value of a select list item and store the selected value in a page element hidden elsewhere on the form of tables, so I can use this value.
  
  I already have something similar to the input on the tabular presentation elements.
  
  Get the initial values
  var line = $x_UpTill (this.triggeringElement, 'TR');
  numberOfItems var = $(' input [nom = "f12"]', ligne) [0];
  
  numberOfItems = 123456.123
  
  What I want to do is soemthing similar as above but capture the value of a select element in tabular form. I thought I could do something like:
  
  Get the selected value
  var line = $x_UpTill (this.triggeringElement, 'TR');
  numberOfItems var = $('selected [name = "f08"] .val ()', line) [0];
  
  But this method leaves the as undefined var numberOfItems.
  
  Please help me to find a way to identify the item 'select' in the tabular form called "f08" and get this value.
  
  I am a newbie to jQuery selectors etc...
  
  Thank you.

  Strange that you do not get an error when you run your 2nd selector.
  In any case for this kind of thing, see the HTML code of your tabular form and tell us what triggers, the element can be useful. Or better create an example at apex.oracle.com.
  In any case, I see two errors:
  (1) is there any html element "not selected" instead, the LOV in the APEX element has the select tag
  (2) you can not write a. val() inside a selector that you must place it after your selection.

  So I'd like to rewrite your code to:
  var line = $x_UpTill (this.triggeringElement, 'TR');
  numberOfItems = $("select_[nom_="f08"]",_row).val () var [0];

• Make a column based on another value of the column in the same table

  JDev 11.1.1.6.0

  It may be a silly question but I'm stuck

  I need to conditionally return a column that said Condition is as if the value in the other column of the same table B is equal to F. I should make A column only when this condition is met. I tried the following code:

  	< af:column sortProperty = "PhoneNumber1."
  	sortable = "false".
  	headerText = "#{bindings." A.hints.PhoneNumber1.label}.
  	ID = "c146.
  	rendering = "#{rank." PhoneNumber1ResponseFlag eq 'F'} ">"
  	< af:outputText value = "#{rank." PhoneNumber1}.
  	ID = "ot130" / >
  	< / af:column >
  	< af:column sortProperty = "PhoneNumber1ResponseFlag."
  	sortable = "false".
  	headerText = "#{bindings." B.hints.PhoneNumber1ResponseFlag.label}.
  	ID = "c80" rendered = "true" >
  	< af:outputText value = "#{rank." PhoneNumber1ResponseFlag}.
  	ID = "ot129" / >
  	< / af:column >

  The data presented in the table for the PhoneNumber1ResponseFlag column are F. Still my condition does not work.

  Well, I've finally sorted it myself by managed bean.

  Here are the steps I followed:

  1. Wrote a new bean managed.
  2. Added a Boolean variable called flag and made to true when the "'PhoneNumber1ResponseFlag ' current line attribute is equal to F."
  3. Changing the property made column on this indicator.

• Tabular presentation displays lines not (although it should be)

  HI -.
  
  I have a page that contains a tabular presentation, which I call in an iframe. Frame recharge parent the tabular presentation when an item on a jquery tree is selected (settings for the new page).
  
  I open a page of the child who doesn't have any line in, choose 'Add new lines', then back to the parent page and select another node in the tree. Loading of the page of the child, but no data is displayed in my tabular form - even if there is data. I get a header and the line of paging only. If I click on the button "next" pagination, refreshes the page of the child and the data is displayed as I hope.
  
  I think that paging is being upset in some sort of page being refreshed by the parent to halfway between the creation of a new line and saving it.
  
  How can I say specifically the page re - load with regular pagination values? Or I'm doing something too hard?
  
  Thanks in advance - I would be recognizing all of the ideas, we're really stuck!

  Rochelle,

  Looks like you need to reset pagination when you click on the tree to recharge your tabular presentation, you can do this by putting "RP" in the URL that you call, here the section in the doc that explains the syntax of the URL:

  http://download.Oracle.com/docs/CD/E17556_01/doc/user.40/e15517/concept.htm#BEIJCIAG

  Then look at this description of URL:

  f? p = App:Page:Session:Request:Debug:ClearCache:itemNames:itemValues:PrinterFriendly

  ... you need to get PR in the position where it says ClearCache, for example (assuming that your tabular form is on page 10):

  f? p = & APP_ID: 10: & SESSION. : RP

  I just want to mention that when you use 4 APEX, you can actually refresh regions in a table through dynamic actions, without iFrames.

  Kind regards
  Marc

• Tabular presentation - column to turn it off (with picture) based on another value of the column

  Hi all

  I haven't worked much on tabular forms and JS. I'm looking for help in this regard.

  I'm working on a tabular presentation. with several editable fields... I need to disable a column (just for this single line), which contains an image, based on a field of LOV (static) list) (Y/N). The image column must be disabled if the value is N.

  My SQL for the report is something like this: (will keep things simple)

  Select

  emp_id,

  emp_name,

  static_list,

  (case when STATIC_LIST = "Y" THEN ' < a title = "Edit SAMPLE TBL" href = "f?) p = & APP_ID.:10: & APP_SESSION.:NO:P10_EMP_ID, P10_EMP_NAME :'|| EMP_ID | «, » || EMP_NAME | "" "> < img src =" "#IMAGE_PREFIX #SAMPLE.gif" border = '0' (> < /a > ' other ' ' end) as disable_col, "

  dept_name

  of sample_table

  I scoured the topics in this forum. Most of them were made using the table ID f_001, f_002.

  I tried to follow the same path by inspecting the item but the disable_col does not have any ID.  Let's say, f_003 is for the static list and f_004 is assigned to dept_name.

  I tried dynamic actions, but it did not work. Read in a topic that dynamic action does not work on tables. So I chose this approach. Is there a simpler way to solve this?

  need your help on how to proceed with this scenario. Thank you in advance.

  Versions: Apex: 4.2, DB: 11 g

  Thank you

  Daniel

  Hi Daniel_A,

  Daniel_A wrote:

  I did my job in Page 4.

  If the IS_VALID column is select as 'Yes' then the column hyper must be enabled, allowing the user to click on it. If she chose the 'no', then the column Hyper must be disabled for this line.

  The initial question about toggle the hyperlink is resolved. Check your App-> Page 4 35160.

  This is done with the help of two dynamic actions:

  • DA first loading of the Page / after updating of region "tabular":

  Event: After refresh

  Selection type: region

  Region: The other 'tabular '.

  Condition: No strings attached

  Action: Run the JavaScript Code

  Fire on loading the Page: Yes

  Code:

  $( 'select[name="f08"]' ).each(function() {
    if ( $(this).val() === "N" ) {
      $(this).closest("tr").find('td[headers="HYPER"]').find("a").addClass("apex_disabled").unbind("click");
    }
  });
  

  Items concerned: no item affected

  • Second DA on the evolution of the selection list:

  Event: change

  Selection type: jQuery Selector

  jQuery Selector: select [name = "f08"]

  Condition: No strings attached

  Action: Run the JavaScript Code

  Fire on loading the Page: No.

  Code:

  var el = this.triggeringElement;
  if ( el.value === "N" ) {
      $(el).closest("tr").find('td[headers="HYPER"]').find("a").addClass("apex_disabled").unbind("click");
  } else {
      $(el).closest("tr").find('td[headers="HYPER"]').find("a").removeClass("apex_disabled").bind("click");
  }
  

  Items concerned: no item affected

  NOTE: as the original question/topic related to toggle the image link in the column, for the problem with the Page 5, please create a new thread with the details.

  Kind regards

  Kiran