mySQL Query Help

Is there an easy way to find all records where he is an ID in a list? For example if I have the following:

TABLE:
resources

FIELDS:
resourceID. listOfIDs | title

RECORDS:
1. 1,7,9 | Point 1
2. 2,3,7,8 | Point 2
5: 8.17. Point 3
4. 2.7 | Point 4

I want to query the table for all records where listOfIDs contains 7. That would be 1, 2, and 3. OR I can want to find where listOfIDs contains 2 AND 8. That would be 2, 3, and 4.

Normally I use another table and have each of the elements of the list as a record that links to the resource ID, but I have 6 columns of type different 'listOfIDs', so I just wanted to know if there is a better way.

Thanks for any help.

dbldutch wrote:

> Normally I use another table and have each of the elements of the list as a
> record that links to the resource ID, but I'll have 6 different
> 'listOfIDs' type columns so I just wanted to know if there is a better way.
>

The second related table * IS * the best way. That is why all
Ph.d. thesis of database are written on the standardization of data. Trust
them, six related tables will be much easier then six columns each
containing a list of numbers.

Why, because a list of numbers is not a list of numbers in a database
It is a string. And the only way to search is inefficient string
functions. Your where clause will have to consider something like this:

' WHERE listOfIDs LIKE ' 7, % ' OR listOfIDs LIKE '%, 7% ' OR listOfIDs like '%, 7' '.

And that is just to search for a possible value in the list, that
progresses of exponential complexity with each additional number
that research.

Tags: ColdFusion

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    ----------------

    VALUE OF PERSON COMPUTERNAME

    COMP1                    ABC                     3

    COMP2                    ABC                     5

    COMP1                    CAD                     3

    COMP3                    CAD                     5

    COMP2                    TES                      1

    COMP1                    TES                      5

    COMP3                    ABC                      2

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    Hello

    Subhash C-Oracle wrote:

    need help on creating pivot query

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    ----------------

    VALUE OF PERSON COMPUTERNAME

    COMP1                    ABC                    3

    COMP2                    ABC                    5

    COMP1                    CAD                    3

    COMP3                    CAD                    5

    COMP2                    TES                      1

    COMP1                    TES                      5

    COMP3                    ABC                      2

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    ----------------------------

    Select the link null, label, value1 COUNT (VALUE)

    from 'test1 '.

    CONTROL group PER PERSON

    Results

    ---------

    Link label value1

    -                    ABC                    3

    -                    CAD                    2

    -                    TES                      2

    My requirement

    ---------------

    can we have something like that out using the concept of pivot? If so can you share an example query pls.

    Link label value1

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    -CAD COMP1, COMP2

    -YOUR ORDI1, COMP3

    This sounds like a job for LISTAGG:

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    THE Group (ORDER BY ComputerName) AS value1

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    GROUP BY label

    ;

    If you would care to post CREATE TABLE and INSERT statements for your sample data, then I could test it.

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    COMP1, COMP2

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    user12183668 wrote:
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    By encapsulating the query as an interior view, something in this way:

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select
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from emp
where
sal between 2000 and 3000
and
hiredate >= add_months (trunc(sysdate, 'MM'), -5 )
group by empno
) a
where a.cnt = 6;

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    I need help in writing a query. The data that I now contains three columns. The values in the first column have duplicate, and the 2nd column entries. The third is unique. Here is an example of the data that I have today:

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    Tier1 Group1 2
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    Tier1 Group2 4
    Group level 1 3 5
    Level 1 Group 3 6


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    Tier1 Group1 1
    2
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    4
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    Hello

    Your front end that can probably not for you.
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SELECT    column1, column2, column3
FROM      table_x
ORDER BY  column3
;

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         WHEN ROW_NUMBER () OVER ( PARTITION BY  column1
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                        ) = 1
         THEN  column1

       END     AS col1
,       CASE
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                          ORDER BY         column3
                        ) = 1
         THEN  column1
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,       column3
FROM       table_x
ORDER BY  column3
;

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    Published by: Frank Kulash, March 21, 2012 16:15

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    Following the script nicely:
    CREATE TABLE ACCOUNT_LOOCKUP
(
  SERIAL_ID     NUMBER,
  ACCOUNT_ID    NUMBER,
  ACCOUNT_RATE  NUMBER,
  ACCOUNT_MAX   NUMBER
)

ALTER TABLE ACCOUNT_LOOCKUP ADD (
  CONSTRAINT PK_ACCOUNT_LOOCKUP
 PRIMARY KEY
 (SERIAL_ID, ACCOUNT_ID));



Insert into ACCOUNT_LOOCKUP
   (SERIAL_ID, ACCOUNT_ID, ACCOUNT_RATE, ACCOUNT_MAX)
 Values
   (1, 1, 10, 200);
Insert into ACCOUNT_LOOCKUP
   (SERIAL_ID, ACCOUNT_ID, ACCOUNT_RATE, ACCOUNT_MAX)
 Values
   (2, 1, 12, 150);
Insert into ACCOUNT_LOOCKUP
   (SERIAL_ID, ACCOUNT_ID, ACCOUNT_RATE, ACCOUNT_MAX)
 Values
   (3, 1, 8, 400);
Insert into ACCOUNT_LOOCKUP
   (SERIAL_ID, ACCOUNT_ID, ACCOUNT_RATE, ACCOUNT_MAX)
 Values
   (1, 2, 7, 100);
Insert into ACCOUNT_LOOCKUP
   (SERIAL_ID, ACCOUNT_ID, ACCOUNT_RATE, ACCOUNT_MAX)
 Values
   (2, 2, 5, 200);
COMMIT;


SELECT * FROM ACCOUNT_LOOCKUP

 SERIAL_ID ACCOUNT_ID ACCOUNT_RATE ACCOUNT_MAX
---------- ---------- ------------ -----------
         1          1           10         200
         2          1           12         150
         3          1            8         400
         1          2            7         100
         2          2            5         200
         
         
CREATE TABLE ACCOUNT_AMOUNT(
ACCOUNT_ID NUMBER(10),
ACCOUNT_AMNT NUMBER(10))


Insert into ACCOUNT_AMOUNT
   (ACCOUNT_ID, ACCOUNT_AMNT)
 Values
   (1, 9);
Insert into ACCOUNT_AMOUNT
   (ACCOUNT_ID, ACCOUNT_AMNT)
 Values
   (1, 35);
COMMIT;
 
SELECT * FROM ACCOUNT_AMOUNT
 
ACCOUNT_ID ACCOUNT_AMNT
---------- ---------------
         1               9
         1              35
           
I want by select query calculte ACCOUNT_TOTAL every ACCOUNT_ID exists in table ACCOUNT_AMOUNT as below ,

1. every ACCOUNT_ID have SERIAL_ID and ACCOUNT_RATE and ACCOUNT_MAX in table ACCOUNT_LOOCKUP,
2. to calculte ACCOUNT_TOTAL every ACCOUNT_ID : 
   
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   - make sum ACCOUNT_AMNT every ACCOUNT_ID in table ACCOUNT_AMOUNT,
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   - product (sum ACCOUNT_AMNT) * ACCOUNT_RATE  result as ACCOUNT_TOTAL,(in ex: sum ACCOUNT_AMNT  = 44   ) ,
   - if ACCOUNT_TOTAL > ACCOUNT_MAX then 
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         * Goto the second record by ascending (in ex SERIAL_ID = 2 ) ,
           make ( ACCOUNT_TOTAL / ACCOUNT_RATE ) for first record ,
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            *Goto the second record by ascending (in ex SERIAL_ID = 2 ) ,   
               Remainder ACCOUNT_AMNT 24 * (12) ACCOUNT_RATE for second record = 288 as ACCOUNT_TOTAL 
               -if ACCOUNT_TOTAL > ACCOUNT_MAX then 
               * ACCOUNT_TOTAL = ACCOUNT_MAX for second record(in ex SERIAL_ID = 2 ) ,
                  * Goto the third record by ascending (in ex SERIAL_ID = 3 ) ,
                  make ( ACCOUNT_TOTAL / ACCOUNT_RATE ) for second record ,
                   ( 150 / 12 ) result 12.5
               
                    * calculate Remainder ACCOUNT_AMNT =  the sum ACCOUNT_AMNT 24 - 12.5 = 11.5 
                    Remainder ACCOUNT_AMNT 9.5 * (12) ACCOUNT_RATE for third record = 92 result as ACCOUNT_TOTAL 
                    if result <= ACCOUNT_MAX then 
                        ACCOUNT_TOTAL = 92 
    except result
------------

SERIAL_ID ACCOUNT_ID ACCOUNT_RATE ACCOUNT_MAX   ACCOUNT_TOTAL          ** explain ** 
---------- ---------- ------------ -----------  -------------  *****  sum ACCOUNT_AMNT  = 44 for ACCOUNT_ID = 1from table ACCOUNT_AMOUNT ******
         1          1           10         200          200  >> (44 * 10 ) = 440 >>  200 /10 rate = 20 >> 44 - 20 = 24 Remainder ACCOUNT_AMNT
         2          1           12         150          150  >> (22 * 12 ) = 288 >>  150 /12 rate = 12.5 >> 24 - 12.5 = 11.5 Remainder ACCOUNT_AMNT
         3          1            8         400           92  >> (11.5 * 8)  = 92  And so on ....
        
another insert 
Insert into ACCOUNT_AMOUNT
   (ACCOUNT_ID, ACCOUNT_AMNT)
 Values
   (2, 10);         
   
   
SELECT * FROM ACCOUNT_AMOUNT
 
ACCOUNT_ID ACCOUNT_AMNT
---------- ---------------
         1               9
         1              35
         2              10    
         

except result
------------
  

SERIAL_ID ACCOUNT_ID ACCOUNT_RATE ACCOUNT_MAX   ACCOUNT_TOTAL          ** explain ** 
---------- ---------- ------------ -----------  -------------  *****  sum ACCOUNT_AMNT  = 10 for ACCOUNT_ID = 2 from table ACCOUNT_AMOUNT ******
         1          1           10         200          200  
         2          1           12         150          150  
         3          1            8         400           92           
         1          2            7         100           70    10 * 7 = 70
    Help me please
    Thanks in advance

    Published by: 900510 on December 5, 2011 08:05

    900510 wrote:
    Hi all

    First I want to apologize for my English, this isn't flunet.

    Following the script nicely:

    CREATE OR REPLACE VIEW V_ACCOUNT (ACCOUNT_ID,ID,ACCOUNT_RATE,ACCOUNT_MAX,ACCOUNT_TOTAL)
AS
SELECT  1, 2, 10 ,200 , 0 FROM DUAL
UNION
SELECT  1, 5, 12 ,150 , 0 FROM DUAL
UNION
SELECT  1, 9, 8  ,400 , 0 FROM DUAL
UNION
SELECT  2 ,1, 7  ,100 , 0 FROM DUAL
UNION
SELECT  2 ,3 ,5  ,200 , 0 FROM DUAL
ORDER BY 1,2

ACCOUNT_ID         ID ACCOUNT_RATE ACCOUNT_MAX ACCOUNT_TOTAL
---------- ---------- ------------ ----------- -------------
1          2           10         200             0
1          5           12         150             0
1          9            8         400             0
2          1            7         100             0
2          3            5         200             0

    I must be missing something... in your opinion, by definition does only selected literals 5 double. How you expect what you do for any other table to change those returned by the view?

    Published by: EdStevens on December 5, 2011 08:51

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---------- ---- ---- ----- ----------
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         1 Vols krog lunch         34
         1 Vols krog munch          0
         2 Mols flog food           0
         2 Mols flog lunch          0
         2 Mols flog munch         24

6 rows selected.

SQL>

    SY.

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