Help with MYSQLi query and WHILE statement

Similar Questions

• Need help with the query and output

  I have a table that contains a list of property and each an asset contains a category field, each an asset can have several categories assigned, then the category column is filled in a list (for example, 14, 16, 17, 19).
  
  The values are based on a table of categories using the primary key as a reference number (for example 14 = keyboards, 16 = Trackballs, etc..)
  
  I tried to understand how the power of categories so that when the category is displayed, the list will appear under the name of the category as opposed to the non referenced.
  
  example:
  < name cfquery = "qIndex" datasource = "#appDSN #" >
  SELECT Asset.Reference, Asset.AssetName, Asset.Category
  Assets
  WHERE category LIKE ' %#URL. Category #% '
  < / cfquery >
  
  < cfoutput query = "qIndex" >
  #Asset.Reference # < br / >
  #Asset.AssetName # < br / >
  #Asset.Category #.
  < / cfoutput >
  
  Exhibition:
  AD_987738
  Keyboard XYZ
  11, 14, 17, 18
  
  Table for categories are:
  CatID = primary key
  Category = category name
  CatImage = header Image
  
  Thanks for any help.

  Finally figured this out. Had to insert an intermediate query within the output to filter each record, otherwise he was out the results of the first record only and repeat.

  
  SELECT *.
  Assets
  WHERE category LIKE ' %#URL. Category #% '
  

  
  SELECT the CATEGORY, AssetID
  Assets
  WHERE assetID = #qIndex.AssetID #.
  

  
  Category category WHERE CatID IN (#catids #)
  
  
  Category: #qCat.Category #,
  
  #qIndex.Asset #.
  
  #qIndex.Reference #.
  
  

  Thanks again for the help.
  Paul

• Help with the query to select only one record from the result set in double

  Hello

  Please help with the query. Version of Oracle database we use is 10g R2.

  I have a vision that is duplicated IDS, but they are used across the different functions. See below examples of data. Please help me with a query to select only one record (based on ID regardless of the area) from the bottom of the result set of duplicate records. For what is the point of view is there unique records, given the combination of the fields ID, Org, DF, dry, Sub-Sec

  ID	Org	DF	Sec	Sub-Sec

  
  (163)CQCPDMCPDMHD(163)PCENGENGENG(163)CQASICASICIS8888TSTACTACTAC(163)TSHEHESW6789CQINFOINFOFOS6789PCSECSYSSECSYSINFO16789TSSECSYSSECSYSINFO29009PCBMSBMSBMS1

  My result set must eliminate the duplicate identifiers regardless of whoever we choose of the result set. (I mean without distinction Org, DF, s, Sub-s). My expected result set should be.

  ID	DSB

  
  DF
  SEC
  Sub-Sec
  (163)CQCPDMCPDMHD8888TSTACTACTAC6789CQINFOINFOFOS9009PCBMSBMSBMS1

  
  

  Thank you

  Orton
  

  Hello

  This sounds like a job for ROW_NUMBER:

  WITH got_r_num AS

  (

  SELECT id, DSB, df, s, sub_sec org

  ROW_NUMBER () OVER (PARTITION BY ID.

  ORDER BY org

  ) AS r_num

  OF view_x

  )

  SELECT id, DSB, df, sub_sec s,

  OF got_r_num

  WHERE r_num = 1

  ;

  He is a Top - N query example, where you choose the elements of N (N = 1 in this case) from the top of an ordered list.

  I hope that answers your question.
  If not, post a small example of data (CREATE TABLE and INSERT, only relevant columns instructions) to your sample data and the results desired from these data.  (I know that you said that you were a view selection.  Just for this thread, pretending it is a picture and post simple CREATE TABLE and INSERT statements to simulate your point of view).
  Point where the above query is to produce erroneous results, and explain, using specific examples, how you get the right results from data provided in these places.  (I didn't quite understand the explanation above.  I don't know why you want to

  ID ORG DF DRY SUB_SEC

  --      ---     --      ---     -------

  1234 CQ DPRK DPRK HD

  and is not

  1234 IS CQ ASIC, ASIC

  or

  TS 1234 IT IT SW

  or

  1234 CQ ASIC ASIC HD

  )
  If you change the query at all, post your modified version.
  Always say what version of Oracle you are using (for example, 11.2.0.2.0).

  See the FAQ forum: https://forums.oracle.com/message/9362002

• Need help with a query result

  Oracle Version: 11.2.0.2.0

  I need assistance with the output of the query. Here is the table.

  With Tbl_Nm as

  (

  Select 'ABC1' SYSTEM_ID, REGION 'US', 'CHI' SUB_REGION 4000 BALANCE, to_date('1-JUN-2012 10:45:00 am', 'dd-mon-yyyy hh:mi:ss am') LAST_UPD_TIME, 'A' FLAG of union double all the

  Select 'PQR2', 'UK', 'LN', 2000, To_Date('1-JUL-2012 10:46:00 am', 'dd-mon-yyyy hh:mi:ss am'), has ' starting from dual Union All

  Select 'ABC1', 'IND","MAMA", 3500, To_Date('1-AUG-2012 11:47:00 am', 'dd-mon-yyyy hh:mi:ss am'), 'A' from dual Union All

  Select "LMN3", "US", "NJ", 2500, To_Date('1-SEP-2012 09:49:00 am', 'dd-mon-yyyy hh:mi:ss am'), 'A' from dual Union All

  Select "PQR2", "UK", "MC", 2600, To_Date('1-OCT-2012 04:45:00 am', 'dd-mon-yyyy hh:mi:ss am'), 'A' from dual Union All

  Select 'ABC1', 'US', 'NY', 3200, To_Date('1-OCT-2012 06:45:00 am', 'dd-mon-yyyy hh:mi:ss am'), has ' starting from dual Union All

  Select "LMN3", "UK", "BT", 2400, To_Date('1-NOV-2012 07:45:00 am', 'dd-mon-yyyy hh:mi:ss am'), has ' From Dual

  )

  Select * from tbl_nm

  I need the output below.

  PQR2 UK MC 2600 1 OCTOBER 2012 04:45

  ABC1 US NY 3500 October 1, 2012 06:45

  LMN3 UK BT 2500 November 1, 2012 07:45

  The need the disc according to this system_id flagged as "A". But if the last disc of 'd' then it must show that the amount, but the file should be displayed in 'A '.

  I've tried a few and got stuck. Help, please. Not able to get a balance '.

  This question is a bit similar to needing help with a query result

  With Tbl_Nm as

  (

  Select 'ABC1' System_Id, region 'US', 'CHI' Sub_Region, 4000 balance, To_Date('1-JUN-2012 10:45:00 am', 'dd-mon-yyyy hh:mi:ss am') Last_Upd_Time, 'A' flag of double Union All

  Select 'PQR2', 'UK', 'LN', 2000, To_Date('1-JUL-2012 10:46:00 am', 'dd-mon-yyyy hh:mi:ss am'), has ' starting from dual Union All

  Select 'ABC1', 'IND","MAMA", 3500, To_Date('1-AUG-2012 11:47:00 am', 'dd-mon-yyyy hh:mi:ss am'), 'A' from dual Union All

  Select "LMN3", "US", "NJ", 2500, To_Date('1-SEP-2012 09:49:00 am', 'dd-mon-yyyy hh:mi:ss am'), 'A' from dual Union All

  Select "PQR2", "UK", "MC", 2600, To_Date('1-OCT-2012 04:45:00 am', 'dd-mon-yyyy hh:mi:ss am'), 'A' from dual Union All

  Select 'ABC1', 'US', 'NY', 3200, To_Date('1-OCT-2012 06:45:00 am', 'dd-mon-yyyy hh:mi:ss am'), has ' starting from dual Union All

  Select "LMN3", "UK", "BT", 2400, To_Date('1-NOV-2012 07:45:00 am', 'dd-mon-yyyy hh:mi:ss am'), has ' From Dual

  )

  Select System_Id, region, Sub_Region, Balance, Last_Upd_Time of Tbl_Nm T1

  where t1. Last_Upd_Time = (select max (Last_Upd_Time) in the Tbl_Nm T2 where T1.) SYSTEM_ID = T2. SYSTEM_ID)

  So maybe you'd then

  ORDER BY DECODE(flag,'D',9,1) ASC...

  to get the Ds at the end of the list.

  or

  ORDER BY CASE WHAT flag = has ' (your other filters) AND then 9 or 1 end CSA,...

  HTH

• Help with check boxes and actions

  Hello

  I just downloaded a trial version of LiveCycle Designer ES2 to see if this program works for the company that I work for. I need to create order forms for our products that our customers can fill out online and then send an e-mail to our sales department.

  I have imported our current order form to LiveCycle as a work of art and have inserted check boxes on the form. I want the form to automatically add the price of the option they checked off the retail price of total at the bottom of the form. Do you have any suggestions for me?

  Thank you!

  Stefan

  Hello Stefan,

  LC Designer is a very powerful application. While you can drag and drop objects on the form, for things really move you need to put a script in objects. This allows to control the way in which the form will be according to the users actions.

  To begin with there is help. If you have a look at the Action Builder in the Tools menu, you can select an object, then use the plain instructions accumulates the desired interaction. When you click OK, LC Designer will insert the necessary script.

  Therefore, there may be a steep learning curve, so it depends on how comfortable you are to roll up your sleeves and do some scripts.

  First, you must configure your workspace. This tends to be a personal preference, but here's a basic layout.

  

  It is a bit small, because of the scale, but you get the idea. At any time, you should be able to see the page, the hierarchy and the script editor. The object library and the range of the object and other palette must be close to hand as well.

  I am NOT inclined to import the form existing as work. This can limit the built-in options in LC Designer later. You can save your form existing in JPEG format and then in a new form to use the image object (value size full page) to display the image of the existing form.

  [ALTERNATIVE: you can also add fields to a PDF in Acrobat].

  Regarding scripting, the following JavaScript code should work in the click event of the checkbox (on the ground that the other field is named totalPrice).

  If (this.rawValue == 1)

  {

  totalPrice.rawValue = totalPrice.rawValue + 10;

  }

  on the other

  {

  totalPrice.rawValue = totalPrice.rawValue - 10;

  }

  This should take into account if the user changes of opinion and unticks the box.

  One thing to keep in mind about forms developed in the LC Designer, it is only the functions that will be available in the form (such as submit by e-mail in PDF format) will depend on whether the user has Acrobat or Reader, and also on whether the form has been active player (and how it has been activated). There is more information here: http://assure.ly/gYyYc2.

  I highly recommend JP Terry on LC Designer which is excellent - book "create dynamic with Adobe LiveCycle Designer Forms. It starts at the beginning and clearly sets out the key learning points. In the end, there are a few good examples that you can copy anywhere in your forms.

  We have solutions and blog posts on our website http://www.assuredynamics.com.

  There are also a range of online resources. You can find these resources useful:

  http://www.Adobe.com/go/learn_lc_scriptingBasics

  http://www.Adobe.com/go/learn_lc_scriptingReference

  http://www.Adobe.com/go/learn_lc_formCalc

  http://www.Adobe.com/devnet/LiveCycle/articles/Adobe_XML_Form_Object_M odel_Refer ence.pdf

  http://www.Adobe.com/devnet/Acrobat/PDFs/lc_migrating_acrobat_xmlform. PDF

  And a very convenient resource (and even if it's for version 6, it is still very good because of the way it is presented):http://partners.adobe.com/public/developer/en/tips/CalcScripts.pdf

  The HelpFile in the LC designer can also help with the syntax and LC designer itself comes with some great models and examples.

  Finally, discover the network of the developer on http://www.adobe.com/devnet/livecycle/

  A book that does not deal with the scripts at all, but is very good on the formatting is also ""does this work " by Caroline Jarrett and Gerry Gaffney."

  The Adobe "PDF forms Bible" is OK, but focuses mainly on AcroForms.

  WindJack Solutions have a service on subscription for the scripts and solutions tohttp://www.pdfscripting.com. There a lot of AcroForm script which can be modified according to LC designer and a growing library of LC Designer solutions.

  I hope this helps,

  Niall

• Dialog box that says ' Creative Cloud Installer wants to make changes. Type your password for this purpose"- I type my password for Adobe ID (creative cloud), but it will not accept it. who should I go for help with this query?

  Dialog box that says ' Creative Cloud Installer wants to make changes. Type your password for this purpose"- I type my password for Adobe ID (creative cloud), but it will not accept it. who should I go for help with this query?

  It does not ask the cloud your computer admin password password!

• need help with the query, thx

  Hello
  I need a little help with the query I have to write;
  the table has 4 columns:

  col1               col2         col3       col4
  emp_name     empl_id    salary      year
  
  content of data:
  
  col1               col2         col3       col4
  smith             12           1200      1999
  smith             12           1340      2000
  smith             12           1500      2001
  jones             13           1550      1999 
  jones             13           1600      2000
  aron              14           1200      2002

  what I am asking is the following result: salary according to the latest available year
  i.e.

  smith         12         1500        2001
  jones         13         1600        2000
  aron          14         1200        2002

  ID appreciate some guidance on how to achieve
  Thank you
  Rgds

  select *from
  (select col1, col2,col3, col4,row_number() over(partition by col1 order by col4 desc)  rn  from 
  ) where rn=1
  

• help with a query mysql in advance

  I use 7 CF to query a MySQL 5 DB.
  
  I was wondering if it is possible to add an OR operator in a subquery or at the end of a conditional statement. Let's say in my statement, WHERE after a few conditions inclusive, I wanted to add a logic "AND & or.
  perhaps by including the part of my code, I can be a little clearer:
  
  < cfquery name = "domysearch"... >
  SELECT
  a.ID as id,
  .....
  b.Company company
  .....
  c.add_line1 as add_line1,
  .....
  OF registratn_contacts a, registratn b, registratn_addresses c
  WHERE a.owner = #arguments.owner #.
  AND b.id = a.master_record
  AND a.address_id = c.id
  AND c.state = 'NY '.
  OR c.state = 'CA '.
  
  I would like to know if I can or should accomplish this in my application or if I should have this logic outside the query?
  
  Thanks for any help!
  
  Carlos

  WHERE THE...
  AND (c.state = 'NY' GOLD c.state = 'CA')

  You can use a RC, it is probably preferable to use an IN clause but it is essentially a RC and would be more effective.

  AND c.state ('NY', 'CA')

  Phil

• Help with the query to create hourly statistics

  Hello!

  I have an array of jobs. Each task has a start_date and a column end_date. end_date can be null if the job is still running.

  I need to create a query to display the number of jobs running for all hours during the last two weeks.

  A job can run for more than an hour.

  
  

  I tried to define what it means for a job during an interval:

  
  

  Job.Start_date < = Interval.end AND Job.Finish_date > = Interval.start

  
  

  Can help you with this query?

  
  

  Thank you!

  Mihai
  

  
  

  Hi, Mihai,

  User810719-Oracle wrote:

  Hello!

  I have an array of jobs. Each task has a start_date and a column end_date. end_date can be null if the job is still running.

  I need to create a query to display the number of jobs running for all hours during the last two weeks.

  A job can run for more than an hour.

  I tried to define what it means for a job during an interval:

  Job.Start_date <= interval.end="" and="" job.finish_date="">= Interval.start...

  You gave essentially the solution yourself.  You just need to outside join your jobs table to a table (or, in the example below, a result set that acts like a table) containing 1 row for each interval.  You can use NVL to equate finish_dates with an effective DATE NULL, so they will be counted:

  WITH intervals AS

  (

  SELECT TRUNC (SYSDATE, 'HH') - ((LEVEL-1)/24) AS interval_start

  , TRUNC (SYSDATE, 'HH') - ((LEVEL-2)/24) AS interval_end

  OF the double

  CONNECT BY LEVEL<= 14="" *="">

  )

  SELECT i.interval_start

  EARL of (j.start_date) AS jobs_running

  Intervals I have

  LEFT OUTER JOIN jobs j WE j.start_date<=>

  AND NVL (j.finish_date

  i.interval_end

  ) > = i.interval_start

  ;

  If you would care to post a small example of data (CREATE TABLE and INSERT statements) and the results desired from this data, I was able to test this.

  Simplify the problem for display.  Do what you are interested only for the past 6 hours, not the last 2 weeks.  We will find a solution that can easily adapt to any number or intervals.

• Need help with the query (transpose)

  Hello experts, please help here - 11 g Oracle, attribute APA APB are fixed values and can be hard coded in query

  Need to transpose these data. Max(decode.. perd les données en sortie à cause de la condition de Max.)

  Entry:

  Name | Attribute | Value

  A1 APP 10

  A1 PDB 11

  A1 APA 20

  A1 PDB 21

  A2 BPA 13

  A2 BPB 14

  Expected results:

  Name AttVal1 AttVal2

  A1 10 11

  13 14 A2

  20 21 A1

  Hello

  Here's one way:

  WITH relevant_columns AS

  (

  SELECT name

  value

  CASE

  WHEN the attribute ("APA", "BPA") THEN 1

  WHEN the attribute ("PDB", "BPB") THEN 2

  END AS c_num

  ROW_NUMBER () (PARTITION BY NAME, attirbute

  Value of ORDER BY

  ) AS r_num

  FROM table_x

  )

  SELECT name, attval1, attval2

  OF relevant_columns

  PIVOT (MAX (value)

  FOR c_num IN (1 AS attval1

  2 UNDER attval2

  )

  )

  ORDER BY r_num, name

  ;

  If you would care to post CREATE TABLE and INSERT statements for your sample data, and then I could test this.

  Why do you want to

  NAME ATTVAL1 ATTVAL2

  ----  -------  -------

  A1 10 11

  20 21 A1

  in the results, rather than

  NAME ATTVAL1 ATTVAL2

  ----  -------  -------

  10 21 A1

  20 11-A1

  ?  You would be satisfied to one or the other?

  Depending on your answer, you may need to modify the analytical ORDER BY clause in the ROW_NUMBER function.

• Help with the query

  Hi, can someone help me with the query. I try to display comm based on calculation below

  SAL < 5000 then 10%

  5000 - 10000 then 15%

  > 10000 then 20%

  This is the query

  DECLARE

  v_comm number (7.2);

  v_Name emp.ename%type;

  v_empno emp.empno%type;

  v_sal emp.sal%type;

  BEGIN

  SELECT ename, empno, sal IN

  v_Name, v_empno, v_sal

  EMP;

  v_comm: = (IF v_sal < v_sal*.10 then 5000;)

  ELSIF v_sal between 5001 AND 10000 THEN v_sal*.15;

  Of ANOTHER v_sal > 10001 THEN v_sal*.20;

  END IF ;);

  dbms_output.put_line(v_Name||) e with empno' | v_empno | "win a comm' | v_comm);

  END; /

  also tried

  DECLARE

  v_comm number (7.2);

  v_Name emp.ename%type;

  v_empno emp.empno%type;

  v_sal emp.sal%type;

  BEGIN

  SELECT ename, empno, sal IN

  v_Name, v_empno, v_sal

  EMP;

  IF v_sal < v_comm then 5000: = v_sal*.10;

  ELSIF v_sal between 5001 AND 10000 THEN v_comm: = v_sal*.15;

  Of ANOTHER v_sal > 10001 THEN v_comm: = v_sal*.20;

  END IF ;);

  dbms_output.put_line(v_Name||) e with empno' | v_empno | "win a comm' | v_comm);

  END;

  /

  Hello

  Look at the syntax of the IF in the PL/SQL manual.  Comapre to the instruction BOX and also the expression BOX.

  Perhaps, instead of an IF statement

  v_comm: = (IF v_sal<5000 then="">

  ELSIF v_sal between 5001 AND 10000 THEN v_sal*.15;

  ELSE v_sal > 10001 THEN v_sal*.20;

  END IF ;);

  you wanted to write an expression BOX, like this:

  v_comm: = BOX

  WHEN v_sal< 5000                ="" then="" v_sal="" *="">

  WHEN v_sal BETWEEN 5001 AND 10000 THEN v_sal *.15

  WHEN v_sal > 10001 THEN v_sal *.20

  END;

  Or perhaps cela:

  v_comm: = v_sal * CASE

  WHEN v_sal<=  5000="" then="">

  WHEN v_sal<= 10000="" then="">

  OF AUTRE.20

  END;

  You can also use a CASE expression in the SELECT statement.

• NEED HELP WITH THE QUERY, NEED MORE RECENT FILE ONLY

  Hi all
  
  That is,
  
  I have an assignment I need to find agents that allow players to break the rules.
  
  So far, I have 41 results, in which there are 4 principles and 24 footballers and football player even beat more than one rule or the rule more than once.
  
  What I need now is to make arrangements so that every footballer appears once n matter how many times they have broken the rules.
  
  
  I have
  
  SELECT
  t.transfer_time | ' ' || a.first_name | ' ' || a.last_name | ' ' || f.first_name | ' ' || f.last_name | ' ' || f.footballer_id | ' ' || t.transfer_id
  Of
  agents a, t transfers, footballers f, footballers_fees fo
  WHERE
  a.agent_id = t.broker_id
  AND
  t.footballer_id = f.footballer_id
  AND
  f.footballer_id = fo.footballer_id
  AND
  (RULE 1 BROKEN AND RULE 2 BROKEN
  OR
  RULE 1 BROKEN AND ARTICLE 2 DOES NOT DECOMPOSE
  OR
  RULE 1 DOES NOT DECOMPOSE AND RULE 2 BROKEN)
  
  
  GROUP BY
  t.transfer_time | ' ' || a.first_name | ' ' || a.last_name | ' ' || f.first_name | ' ' || f.last_name | ' ' || f.footballer_id | ' ' || t.transfer_id
  ORDER BY
  t.transfer_time | ' ' || a.first_name | ' ' || a.last_name | ' ' || f.first_name | ' ' || f.last_name | ' ' || f.footballer_id | ' ' || t.transfer_id
  ;
  
  
  
  (I did not type the SQL code to rules 1 and 2 but I know it works)
  
  Now, I need not to show that every footballer once they broke rule and more than once or not.
  
  I was looking at the screen nearly enough hours 10 and any help or ideas would be greatly appreciated
  
  Thank you all :)

  Hello

  Welcome to the forum!

  Whenever you have a problem, please post a small example of data (CREATE TABLE and INSERT statements) so that people who want to help you can recreate the problem and test their ideas. You don't have to display a large amount of data. In this case, it seems that 2 to 10 lines for each table could give a good picture of the problem.
  After the results that you want samples fropm, and explain how you get those resulting from these data.
  Always tell what version of Oracle you are using.

  The ideal outcome would be just what you '; Re I get now, but with some deleted rows and only 1 line by left footballer? If so, do a subquery on the original query, and then add somehting like

  , ROW_NUMBER () OVER (PARTITION BY f.footballer_id ORDER BY NULL)  AS r_num
  

  in the SELECT clause.
  then, in the main query, display only lines

  WHERE   r_num  = 1
  

  ROW_NUMBER requires an ORDER byclause of analytics. If you ORDER BY a constant (e.g. NULL) then what line gets number 1 will be arbitrary. If you care who lines for a given player is numbered 1 (and therefore included in the final output), then adjust the analytical ORDER BY clause. (You the title mentions "most recent record only", so if the dt column indicates whether a line is "newer" than another, you can "ORDER BY dt DESC".)

  I know this response is vague in places. Without a concrete example (CREATE TABLE and instructions INSERT for examples of data and outcomes from these data), that's the best I can do.

• need help with the query: (Frank)

  Hi Frank,.
  
  I have the oracle 8 database.
  I have the following table with the data structure:
  
  TABLE P (PID, PNAME, COLOR)
  PRIMARY KEY: PID
  

  PID     Pname    Color
  p1...........          Red
  P2.................    green
  p3...............       blue
  p4 ..................   red

  CAT TABLE (SID, PID, COST)
  KEY: SID MAIN + PID
  KEY REFERENCE: SID REFERENCE S.SID
  PID P.PID REFERENCES
  

  Sid        Pid       COst....
  S1        P1
  S2        P2
  S3        P3
  S1      P4
  S2       p1
  S3        p1

  now my question is:
  I want to find the SIDS of suppliers that provide a red and a green part
  
  for this I used the following query, but it gives the result worng...
  
  can help me please in this way to get this...
  

  select sid from cat
  where pid in (select pid from p where color= 'red'
            union
            select pid from p where color = 'gren') 
  group by sid having count(pid) >= 2

  Hello

  Jojo wrote:
  Hi Frank,.

  It would be nice if someone with a different name helped you? Do not restrict yourself by addressing someone in particular in your subject line or the first message.

  I have the oracle 8 database.
  I have the following table with the data structure:

  TABLE P (PID, PNAME, COLOR)
  PRIMARY KEY: PID

  PID     Pname    Color
  p1...........          Red
  P2.................    green
  p3...............       blue
  p4 ..................   red
  

  CAT TABLE (SID, PID, COST)
  KEY: SID MAIN + PID
  KEY REFERENCE: SID REFERENCE S.SID
  PID P.PID REFERENCES

  Sid        Pid       COst....
  S1        P1
  S2        P2
  S3        P3
  S1      P4
  S2       p1
  S3        p1
  

  now my question is:
  I want to find the SIDS of suppliers that provide a red and a green part

  for this I used the following query, but it gives the result worng...

  can help me please in this way to get this...

  select sid from cat
  where pid in (select pid from p where color= 'red'
            union
            select pid from p where color = 'gren')
  group by sid having count(pid) >= 2
  

  You don't like what is the number of lines with a pid; If you had 20 rows all said 'p1', that would be good enough. The number of distinct colors of the whole ('red', 'green') is what is important.
  Avoid the UNION when there is a simple alternative. The UNION tends to be slow.

  You can use a join instead, like this:

  SELECT       c.sid
  FROM       cat     c
  ,            p
  WHERE       p.pid          = c.pid
  AND       p.color       IN ('red', 'green')
  GROUP BY  c.sid
  HAVING       COUNT (DISTINCT p.color)     = 2
  ;
  

  If you would care to post CREATE TABLE and INSERT statements for the sample data and the results that you want from this data, then I could test this.

  Published by: Frank Kulash, January 10, 2011 15:25

• Help with Hard Drive and registry

  Hey, it kinda turns out to be a long and difficult history, but I recently had a small problem that spread to a problem much bigger (and catastrophic).

  I had a problem with freezxing on my laptop (HP Pavilion Dv5 with the 64-bit version of Vista I think). I've tried a few things m ais it froze just in case. Finally I found someone who said they ran a registry cleaning program and that did the trick. I tried and I had no more freezing. Unfortunately, I connected an external hard drive and all hell broke loose. It froze and I turned off the laptop. I have it turned on and was greeted with this message:

  STOP: c000021a {Fatal System Error}
  The Session Manager failed to create protected prefixes system process terminate
  d unexpectedly with a status of 0x000003a (0x00000000 0x00000000).
  The system has been shut down.
  

  I tried to boot in safe mode and found:

  STOP: c0000218 {Registry File Failure}
  The registry cannot load the hive (file):\SystemRoot\system32\config\SOFTWARE or its log alternative.
  It is corrupt, absent, or not writable.
  

  Then, she went and made the collection of data, and that was all. After that, I tried the boot recovery option and that never worked. I searched internet and found a few people with similar, but never the same questions. Someone, somewhere, says something about execution of system restore after having access to the menu by pressing F8 at startup. I tried. It did not work. I pressed F8 at startup upward and chose the first option. It has established a list of things to try. System Restore (and other options such as checking memory and bring up the command prompt) did not work because the C drive has been used. Large. I tried to use the disks that came with my laptop and I never once found while they were actually useful because I could never the laptop to run.

  Now, I wanted to try to use the command prompt. Never really had a chance. Now, when I start the computer I'm greeted by the inspiring message of hard drive are not.

  Sweet. Now, I'm a little stuck on what to try. I tried to reset the BIOS defaults and nada. I have no idea what it must try now and would love to help anyone.

  I would be very happy and I thank you for your time.

  It depends on how much you have to pay to get the new hard drive installed and running. Get a quote for a computer shop trust you.  So I think that if the computer has been done what you wanted to do before he went wrong.  If it was enough for you and the price of the repair is not too high (maybe less), I would. If the price is more than $ 200, I would start thinking about applying your money towards a new laptop computer, but that cheaper isn't always the best deal.  Do some research and try some mobile friends to see if it is fast enough for you and you enjoy the feeling. Stop in some stores that display laptops and taste. Laptops with dedicated video card memory will do better with the games.  If the games are starting to become important to you, consider a desktop computer instead of a laptop where you can buy a killer video card. I like the new Ivy bridge to intel for laptops so look for it.  This is the new family of Intel processors. I7 Ivy bridge is the finest, then the i5, then the i3.  You really need to sit with someone who knows computers and discuss your needs for the future and how you want to use your computer.

• Need help with the query. Help, please

  Hey everyone, need your help.  Thank you in advance.  In my view, there is function Pivot.  Just do not know how to use this function.  I have the query that works.  The result is:

  11-111-1111 Vlad 16505 01/04/2013 5 August 13 dental plan pre-tax amount 29,65

  11-111-1111 Vlad 16505 01/04/2013 dental pre-tax 5 August 13 Plan level EE + SP

  11-111-1111 16505 Vlad 01/04/2013 5 August 13 pre-tax Option TOP dental plan

  11-111-1111 Vlad 16505 01/04/2013 5 August 13 pre-tax dental care plan pay the value

  11-111-1111 16505 Vlad 01/04/2013 dental pre-tax 5 August 13 Plan period Type

  11-111-1111 Vlad 16505 01/04/2013 amount pre-tax medical Plan of 5 August 13 149

  11-111-1111 Vlad 16505 01/04/2013 5 August 13 pre-tax Medical Plan level EE + SP

  11-111-1111 Vlad 16505 01/04/2013 5 August 13 pre-tax Plan medical Option MED

  11-111-1111 Vlad 16505 01/04/2013 5 August 13 plan pre-tax pay value

  11-111-1111 16505 Vlad 01/04/2013 5 August 13 pre-tax Medical Plan period Type

  11-111-1111 Vlad 16505 01/04/2013 5 August 13 pre-tax Plan PPO medical Plan

  11-111-1111 Vlad 16505 01/04/2013 5 August 13 Vision Plan amount 5.94 pre-tax

  But I need the result to be

  Amount of SSN ID name item level Option PayValue period Type

  11-111-1111 Vlad 16505 01/04/2013 null null high of 5 August 13 pre-tax Dental Plan 29,65 EE + SP

  11-111-1111 Vlad 16505 01/04/2013 null null MED 5 August 13 149 medical plan pre-tax EE + SP

  11-111-1111 Vlad 16505 01/04/2013 Vision Plan before taxes of 5 August 13

  Select distinct
  ' 11-111-1111 "as ssn,
  WOMEN'S WEAR. Employee_number,
  "Vlad" as EMPLOYEE_FULL_NAME,
  TO_CHAR (papf.start_date, "MM/DD/YYYY") as Date_Of_Hire
  a.effective_start_date,
  PETF.element_name,
  pivf. Name,
  peevf.screen_entry_value

  Of
  PER_all_PEOPLE_F women's wear
  per_assignments_f A
  pay_element_types_f petf
  pay_element_links_f pelf
  PAY_ELEMENT_ENTRIES_F penf
  PAY_ELEMENT_ENTRY_VALUES_F peevf
  pay_input_values_f pivf
  WHERE
  PETF.element_name ('Dental Plan before taxes', 'Medical Plan before taxes', "Vision Plan before taxes")
  and petf. ELEMENT_TYPE_ID = pelf. ELEMENT_TYPE_ID
  and (trunc (sysdate) BETWEEN pelf. EFFECTIVE_START_DATE AND pelf. EFFECTIVE_END_DATE)
  and (pelf. ELEMENT_LINK_ID = penf. ELEMENT_LINK_ID and a.assignment_id = penf. ASSIGNMENT_ID)
  and (trunc (sysdate) BETWEEN penf. EFFECTIVE_START_DATE AND penf. EFFECTIVE_END_DATE)
  and penf. ELEMENT_ENTRY_ID = peevf. ELEMENT_ENTRY_ID
  and peevf. INPUT_VALUE_ID = pivf. INPUT_VALUE_ID
  AND papf.employee_number IS NOT NULL
  AND A.assignment_type = 'E '.
  AND A.person_id = papf.person_id
  and papf.effective_end_date > sysdate
  and a.effective_end_date > sysdate
  and (trunc (sysdate) BETWEEN women's wear. EFFECTIVE_START_DATE AND women's wear. EFFECTIVE_END_DATE)
  and a.effective_start_date = (select MAX (effective_start_date) from PER_ASSIGNMENTS_f where assignment_id = a.assignment_id)
  and a.assignment_id = 42643
  and a.assignment_status_type_id = '1'
  order of petf.element_name;

  Change with your query

  SELECT * FROM (select distinct)

  ' 11-111-1111 "as ssn,

  WOMEN'S WEAR. Employee_number,

  "Vlad" as employee_full_name,

  TO_CHAR (papf.start_date, "MM/DD/YYYY") as date_of_hire

  a.effective_start_date,

  PETF.element_name,

  pivf. Name,

  peevf.screen_entry_value

  Of

  PER_all_PEOPLE_F women's wear

  per_assignments_f A

  pay_element_types_f petf

  pay_element_links_f pelf

  PAY_ELEMENT_ENTRIES_F penf

  PAY_ELEMENT_ENTRY_VALUES_F peevf

  pay_input_values_f pivf

  WHERE

  PETF.element_name ('Dental Plan before taxes', 'Medical Plan before taxes', "Vision Plan before taxes")

  and petf. ELEMENT_TYPE_ID = pelf. ELEMENT_TYPE_ID

  and (trunc (sysdate) BETWEEN pelf. EFFECTIVE_START_DATE AND pelf. EFFECTIVE_END_DATE)

  and (pelf. ELEMENT_LINK_ID = penf. ELEMENT_LINK_ID and a.assignment_id = penf. ASSIGNMENT_ID)

  and (trunc (sysdate) BETWEEN penf. EFFECTIVE_START_DATE AND penf. EFFECTIVE_END_DATE)

  and penf. ELEMENT_ENTRY_ID = peevf. ELEMENT_ENTRY_ID

  and peevf. INPUT_VALUE_ID = pivf. INPUT_VALUE_ID

  AND papf.employee_number IS NOT NULL

  AND A.assignment_type = 'E '.

  AND A.person_id = papf.person_id

  and papf.effective_end_date > sysdate

  and a.effective_end_date > sysdate

  and (trunc (sysdate) BETWEEN women's wear. EFFECTIVE_START_DATE AND women's wear. EFFECTIVE_END_DATE)

  and a.effective_start_date = (select MAX (effective_start_date) from PER_ASSIGNMENTS_f where assignment_id = a.assignment_id)

  and a.assignment_id = 42643

  and a.assignment_status_type_id = '1')

  PIVOT (MAX (screen_entry_value) FOR (name) TO ("Amount" AS 'Amount', 'level' AS 'level', 'Option High' AS 'High Option', 'Pay the value' AS 'Value to pay', 'Period of Type' AS 'Type period'))

  order by element_name;

  (GOLD)

  SELECT ssn,

  Employee_number,

  employee_full_name,

  date_of_hire,

  effective_start_date,

  element_name,

  Max (decode (Name, 'Amount', screen_entry_value)) 'amount. "

  Max (decode (Name, 'Level', screen_entry_value)) 'level ',.

  MAX (DECODE (name, "High Option", screen_entry_value)) "High Option",

  MAX (DECODE (name, 'Value of pay', screen_entry_value)) 'value of pay. "

  MAX (DECODE (name, 'Period Type', screen_entry_value)) 'period of Type '.

  FROM (select distinct)

  ' 11-111-1111 "as ssn,

  WOMEN'S WEAR. Employee_number,

  "Vlad" as employee_full_name,

  TO_CHAR (papf.start_date, "MM/DD/YYYY") as date_of_hire

  a.effective_start_date,

  PETF.element_name,

  pivf. Name,

  peevf.screen_entry_value

  Of

  PER_all_PEOPLE_F women's wear

  per_assignments_f A

  pay_element_types_f petf

  pay_element_links_f pelf

  PAY_ELEMENT_ENTRIES_F penf

  PAY_ELEMENT_ENTRY_VALUES_F peevf

  pay_input_values_f pivf

  WHERE

  PETF.element_name ('Dental Plan before taxes', 'Medical Plan before taxes', "Vision Plan before taxes")

  and petf. ELEMENT_TYPE_ID = pelf. ELEMENT_TYPE_ID

  and (trunc (sysdate) BETWEEN pelf. EFFECTIVE_START_DATE AND pelf. EFFECTIVE_END_DATE)

  and (pelf. ELEMENT_LINK_ID = penf. ELEMENT_LINK_ID and a.assignment_id = penf. ASSIGNMENT_ID)

  and (trunc (sysdate) BETWEEN penf. EFFECTIVE_START_DATE AND penf. EFFECTIVE_END_DATE)

  and penf. ELEMENT_ENTRY_ID = peevf. ELEMENT_ENTRY_ID

  and peevf. INPUT_VALUE_ID = pivf. INPUT_VALUE_ID

  AND papf.employee_number IS NOT NULL

  AND A.assignment_type = 'E '.

  AND A.person_id = papf.person_id

  and papf.effective_end_date > sysdate

  and a.effective_end_date > sysdate

  and (trunc (sysdate) BETWEEN women's wear. EFFECTIVE_START_DATE AND women's wear. EFFECTIVE_END_DATE)

  and a.effective_start_date = (select MAX (effective_start_date) from PER_ASSIGNMENTS_f where assignment_id = a.assignment_id)

  and a.assignment_id = 42643

  and a.assignment_status_type_id = '1')

  GROUP BY ssn, employee_number, employee_full_name, date_of_hire, effective_start_date, NOM_ELEMENT

  order by element_name;