Name of table of future approver/s details

Similar Questions

• How can I get a name of table 1, column A, if column B is a negative number and insert the names of table 2?

  How can I get a name of table 1, column A, if column B is a negative number and insert the names of table 2?

  What is the formula?

  

  You can do this with a column of "index" in table 1, as this assistance:

  

  The formula in C2, filled to the bottom:

  IF (B =<>

  That increments a counter each time that it finds a negative number in column B.

  In the second table, you can retrieve a list of negative values in this way:

  

  The formula in A2, filled to the bottom:

  = INDEX (array 1::A, CORRESPONDENCE (LINE (−1, Table 1::C), 0))

  It takes the line number, the formula is activated, subtracts 1 to the header line and look up the result in the column of table 1 C.  If it finds a match, it feeds the line number to the INDEX page with retrieves the value of the column of table 1A.

  To hide the red triangles of signage wrap the IFERROR formula, like this:

  = SIERREUR (INDEX (table 1::A, CORRESPONDENCE (LINE (−1, Table 1::C), 0)),"")

  Of course, you can also simply filter on column B without the need to set up a column from another table or index.

  

  SG

• Pick up the names of tables based on the value of the column

  I have a scheme in which I have 10000 tables and I want to pick up the names of tables in the schema where org_id is not equal to 1,
  Note: Org_id here is the column name.
  
  Could you please provide sql code me or a procedure to achieve this.
  
  Thanks in advance.

  This lthread can help

  How to find the column name and the name of the table with a value

• How to get the required column, the names of tables for the preparation of the report.

  Based on the MD50 how to get the exact name, the table names he joined for report development. as I am new on this project and the purchase of failet for R12.
  How can I start my approach to prepare the data for the report model? How can I search the database based on the respective diagrams of means?
  all input appreciated

  Hello

  You can find information about schema objects in eTRM Web site, you can also consult the documentation for product/module and see if it helps. If you already have any report (standard or custom), you can enable the trace and run the program to see which object it access or open the report using Report Designer and see the code.

  ETRM Oracle
  http://ETRM.Oracle.com

  Oracle Applications documentation
  http://www.Oracle.com/technology/documentation/applications.html

  Kind regards
  Hussein

• What table stores the name of the region, the IDs and details?

  Hello
  Pls know me this table where are stored the names and related info.
  
  Kind regards
  IDEOGRAM

  Hello

  You can see all the workspace Apex views
  Home > utilities > Application Express views

  And you can search by entering filed 'region '.

  If you want to see how it is build go schema Apex and
  See for example APEX_APPLICATION_PAGE_REGIONS dll that contains the region info

  BR, Jari

  Published by: jarola 4 November 2009 14:18

• Retrieve the name of tables and its plsql procedure schema

  Hello

  Help me please pass my last training evaluation

  the task is:

  between the username and the password and then who will retrieve tables exist and the script for each table.

  the output should be like:

  user name: -.

  table_name1:

  table_name1 script

  table_name1 script

  table_name1 script

  table_name2:

  table_name2 script

  table_name2 script

  table_name2 script

  .

  .

  .

  and so on

  in the last of the production
  You should see the following:

  No tables for: username: table_numbers

  Please help me.

  If your boss wants to test your ability to write code and understand the dictionary of data, then you can try something like this:

  begin
      for t in (
          select table_name from user_tables order by table_name
      )
      loop
          dbms_output.put_line(t.table_name);
  
          for c in (
              select * from user_tab_columns c
              where  c.table_name = t.table_name
              order by c.column_id
          )
          loop
              dbms_output.put_line('    ' || rpad(c.column_name,31) || c.data_type);
          end loop;
          dbms_output.new_line();
      end loop;
  end;
  

  This just lists the tables and their columns. You must understand how to add more details and to make a set of create table statements.

  If it ask for user name and password there must probably be a SQL * more script (.sql file). He could use ACCEPT to invite (there are examples at the bottom of the page).

• the names of tables attached to irecruitment valuation

  Hello
  
  When the applicant take irecruitment evaluation, the evaluation of data is stored in tables that made? and how do I link it to the per_all_people_f table to get the applicants name and contact information of evaluation?
  
  Thank you
  Kumar

  If I'm not mistaken all evaluation data are stored to OTA (tables Learming). OTA_ATTEMPTS and OTA_PERFORMANCES for the overall result and progress.

  to get the name, you must bind person_id with user_id in ota_attempts or ota_performances.

  There is a LIVE view that allows you to get the detailed responses (OTA_UTEST_QUESTIONS_V) assessment result

• name of table 2D element names questions

  Hello

  I'm working on this little code where I want to choose a sensor which will be released 3 axes. but I put the list from the selection of the sensor box 1 or multiple selection mode. Also, when I take more than one sensor I get 6 axes (3 for each sensor) in my scoreboard. My problem is that I want the list of these axes in a list box. but the list for the axis box is table 1 d and the node property item names table 1 d as well. My problem is the reference for the axis of the sensor are table 2D. How to remember?

  Help, please... A picture of the short code is provided

  Note to admin - attachment deleted by user request

  Remodel allows to edit your 2D in a 1 d table table.

• Sort by label name references table

  I develop a DSC application with the alarming and shared variables and events with a quantity of hugh of variables. Each variable is displayed on the front panel in the tab controls. To reduce the time and effort during the expansion of variables, I want to organize my references from the front panel of the brand. I have attached some of the initialization of the façade. Here, I must manually unpack each variable in the variable shared library where the variable name must be in the same order as the definition of the cluster.

  My approach was to build a digital type references and sort the references by name of the label. Because the shared variables have the same name that controls, they would be in the same order and I could also dislaim the cluster of references.

  Maybe someone can give my a 'pipe '.

  Kind regards

  --

  Joachim

  Hello Joachim,.

  use the standard approach "sort a table of cluster!

  Put the label control and the reference (in that order!) in a cluster, make an array of these groupings and sort the table. It will sort by the label and you can ungroup the reference in the order...

• A record in the table is not approved

  We have a PS4100x Equallogic in production. A few days ago one of the drives has failed and we ordered an original Dell HDD for this device. When we replaced the damaged for a new, the console says that the disc is not approved.

  We checked the documentation and cannot find that this happens when there are questions of firmware when the drives are not original (who from not Dell) and not alike.

  The other thing is that when I try to add to the table, the "Add table" option is gray out.

  Any help would be grateful, thank you!

  Hello stamac,.

  I'm sorry, but only Dell Equallogic brand work readers in a table EQL.  It is custom firmware on the drive on which the search table.   There is no work around for this.

  Kind regards

  Don

• How to create the column of the table for long-form Master detail relationship

  Apex 4.1

  Oracle 11g

  I created a form master detail and see the main table hotel_list and table hotel_mapping as detailed below.

  Hotel_list

  ID HOTEL_NAME

  1 Holiday Inn

  Hotel Hilton 2

  Hotel_mapping

  ID HOTEL_NAME MAPPING_NAME

  1 Inn Holiday Inn Select hotel

  2 holiday hotel Holiday Inn Select

  3 hotel Holiday Inn Holiday Inn Hotel

  4 Hilton Hotel Hilton Hotel chain

  Hotel Hilton 5 HiltonHotel

  Table Hotel_name Hotel_list is a linked table Hotel_mapping

  When I add a line to the Hotel_mapping table for the selected row in the hotel_list table, mapping_name of column is null, therefore impossible to create the relationship between the main table and the secondary table.

  I would like to know, how to create the relationship?

  Thank you very much

  Best regards

  Yong Huang,

  simple step see creating a form detailed master with APEX - Assistant Master retail

  and check how to maintain the relationship between two tables,

  simple return the packaged application «Sample of Masters details»

  and try to understand this concept...

  In your example, use Hotel_list.ID as a foreign key in the table Hotel_mapping

  and maintain the relationship with the column ID...

  and choose the display type of the column Hotel_list.ID in table Hotel_mapping as List(Query Based LOV) select.

  otherwise the best way is to create sample on oracle.apex.com

  I hope this helps...

  Leave.

• Notice that based on the names of table in another table

  I have a table that contains the names of the other tables. I would like to create a view that contains a list of these tables as well as the number of records and the value of a specific column (shared) min/max.

  
  

  I found something that looked promising in a previous post that only seems to work in 11g, I am limited to 10g 2.
  

  
  

  I would like to get a notice that gives the result:

  
  

  Tbl_name Record_Count Min_Emp_ID

  3 7698 T1

  t2          4               10
  

  
  

  Thank you

  
  

  
  

  
  

  -Code below
  

  
  

  create table (dept

  DEPTNO number (2.0).

  DNAME varchar2 (14).

  Loc varchar2 (13)

  );

  create table emp)

  EmpNo number (4,0).

  Ename varchar2 (10),

  use varchar2 (9).

  Mgr number (4,0),

  HireDate date,

  SAL number (7.2).

  number (7.2), comm.

  DEPTNO number (2.0)

  );

  create table (bonus)

  Ename varchar2 (10),

  use varchar2 (9).

  number of SAL,

  number of comm

  );

  create table salgrade)

  number of grade,

  number of it,

  number of designate

  );

  Insert in the dept

  values (10, 'ACCOUNTING', 'NEW YORK');

  Insert in the dept

  values (20, "SEARCH", "DALLAS");

  Insert in the dept

  values (30, 'SALES', 'CHICAGO');

  Insert in the dept

  values (40, 'OPERATIONS', 'BOSTON');

  insert into the emp

  values)

  7839, 'KING', 'PRESIDENT', null,.

  TO_DATE ('17-11-1981', ' dd-mm-yyyy'),

  5000, null, 10

  );

  insert into the emp

  values)

  7698, 'BLAKE', 'MANAGER', 7839,.

  to_date('1-5-1981','dd-mm-yyyy'),

  2850, null, 30

  );

  insert into the emp

  values)

  7782, 'CLARK', 'MANAGER', 7839,.

  TO_DATE ('9-6-1981', ' dd-mm-yyyy'),

  2450, null, 10

  );

  insert into the emp

  values)

  7566, 'JONES', 'MANAGER', 7839,.

  to_date('2-4-1981','dd-mm-yyyy'),

  2975, null, 20

  );

  insert into the emp

  values)

  7788, 'SCOTT', 'ANALYST', 7566,.

  to_date('13-Jul-87','dd-mm-rr') - 85.

  3000, null, 20

  );

  insert into the emp

  values)

  7902, "FORD", "ANALYST", 7566,.

  to_date('3-12-1981','dd-mm-yyyy'),

  3000, null, 20

  );

  insert into the emp

  values)

  7369, 'SMITH', 'CLERKS', 7902.

  TO_DATE ('17-12-1980', ' dd-mm-yyyy'),

  800, null, 20

  );

  insert into the emp

  values)

  7499, "ALLEN", "SELLER", 7698.

  TO_DATE ('20-2-1981', ' dd-mm-yyyy'),

  1600, 300, 30

  );

  insert into the emp

  values)

  7521, 'WARD', 'SELLER', 7698.

  TO_DATE ('22-2-1981', ' dd-mm-yyyy'),

  1250, 500, 30

  );

  insert into the emp

  values)

  7654, 'MARTIN', 'SELLER', 7698.

  TO_DATE ('28-9-1981', ' dd-mm-yyyy'),

  1250, 1400, 30

  );

  insert into the emp

  values)

  7844, 'TURNER', 'SELLER', 7698.

  to_date('8-9-1981','dd-mm-yyyy'),

  1500, 0, 30

  );

  insert into the emp

  values)

  7876, "ADAMS", "REGISTRAR", 7788

  TO_DATE (July 13, 87 ', 'dd-mm-rr')-51.

  1100, null, 20

  );

  insert into the emp

  values)

  7900, 'JAMES', 'THE REGISTRAR', 7698.

  to_date('3-12-1981','dd-mm-yyyy'),

  950, null, 30

  );

  insert into the emp

  values)

  7934, 'MILLER', 'THE REGISTRAR', 7782.

  TO_DATE ('23-1-1982', ' dd-mm-yyyy'),

  1300, null, 10

  );

  Insert into salgrade

  values (1, 700, 1200);

  Insert into salgrade

  values (2, 1201, 1400);

  Insert into salgrade

  values (3, 1401, 2000);

  Insert into salgrade

  values (4, 2001, 3000);

  Insert into salgrade

  values (5, 3001, 9999);

  commit;

  
  

  create table t1 as select empno, ename from emp where rownum < = 3;

  create table t2 as select deptno empno, ename dname of the Department;

  create table-master (select ID, 't1' union table_name 1 double all the)

  Select 2 id, 't2' double table_name);

  Select * from t1;

  Select * from t2;

  Select * from master.

  -NEXT LINE FAILS

  create or replace view v_t

  as

  Select table_name, x.*

  from (select table_name, ' ora: view("' ||)) table_name | "")(' onglets dele de maître), "

  XMLTable (tabs id int path 'EMPNO', ename varchar2 columns (20) path 'ENAME') x;

  Select * from v_t;

  SQL > select t.table_name, x.*

  2 master t

  3, xmltable ("'/ LINES/LINES")

  4 by the way (dbms_xmlgen.getXMLType)

  5 ' select count (*) NTC, minvalue, maxvalue (empno) max (empno) min of.

  6                      || dbms_assert. SQL_OBJECT_NAME (t.table_name)

  7                 )

  path number 8 columns cnt 'CNT '.

  9 road number minvalue "MINVALUE.

  10, path number maxvalue "MAXVALUE.

  (11) x

  12;

  TABLE_NAME CNT MINVALUE MAXVALUE

  ---------- ---------- ---------- ----------

  3-7369-7521 T1

  t2                  4         10         40

• Only reset the names of table of contents?

  Is there any method of resetting the table of contents without impact on the custom groups? I have a lot of groups I place directly in the table of contents, and now I need to insert a new slide that should appear in the table of contents. Hit the reset TOC button will add new slides and insert the name of the slide in the table of contents, but then I have to Setup custom all my groups of TOC. All I can do to avoid this? I suppose not, but thought I would check.

  I'm sorry, but the answer is no. I've learned since TOC appeared to create and modify only after completing the project. BTW the highest group level, you can group slides into the film, the name of the group will be included in the table of contents. If you want more than one level of grouping, the subgroups can be created in the table of contents, not in the film.

• Field name uncreated table but cannot change even in oracle 6i report

  I have an emp information report, I've increated ename field width of 10 to 15 characters in the table and insert the name of length 15 characters in the emp table, but when I ran it report its name of the character 10 showing in the report, I tried to update the width of the name field in the report, but I cannot do the same.
  
  Can someone please help and let me know how can I increase width of name field in the report.
  
  Published by: Mohan Kumar on May 13, 2013 08:34

  I know it's really stupid in the reports, but you must use a workaround:
  Open the query and modify just with something wrong (such as adding a space somewhere). This will cause the generator of reports for re - analyze the query.

• Drag the names of table of contents

  How to drag the names to display in captivate TOC?  Each blade has a name, but TOC display "Slide 1', slide 2' etc. Thank you

  I guess it is not updated. Click on the button refresh below the table of contents, and you should see the names.

  Anthony