Need help with filterFunction with special character function

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• Newbie need help with string concatenation function.

  I'm totally new to LabView and am trying to work on a project that someone worked in the past.  I came to a string function concatenated on one of the existing provisions and only seen on some entries of the string function has an order of 'rel' and 'g '.  I don't know if it's a common command or what it is.  This is VI is that it requires a user to enter a base dimension (x-axis starting point and end point) and executes the steps in the sample desired within the "point of departure" and "end point".  "a3" is the name of the x-axis.  but I'm not sure of the meaning 'rel' and 'g '.  I posted part of the diagram.  Any help would be appreciated.  Thank you!

  This isn't a question of LabVIEW, but very specific to the device connected to the other end of the serial port. Do you have any documentation for it?

  Basically, the program needs form a consiting of command of a delimiter character, value and end of key word, etc. for example.

  Who wrote this program. It seems too complex and convoluted. Under certain conditions, it seems to send two commands at the same time, and there is no way to determine the order in which they run. Maybe it doesn't matter, but maybe it does. Most likely, what you need is a single structure dealing with a case for each condition and a unique series in the end writing. You can reach the actual program? There are also a lot of duplicate code. What is the purpose of the operations 1 x? Is this a Subvi?

• Need help with the analytical function select maximum and minimum of the results of the column

  Hey there OTN.

  I have an interesting application that I was hoping you would be able to help me with. I have a requirement to conditionally select the max and min of a column in bi-editor and since my editor works from an OBIEE analysis, I need store MAX and MIN of the column values in separate columns to match with. See the example below. You will notice that there are 4 stores including today's sales. I must have OBIEE through all the results of the column for sales, then choose the max of the dataset object. I can't use MAX here because he will choose the MAX of the line which will return only sales of this line. Instead, one must analyze all sales results and choose the appropriate column. Any idea on how to do this in OBIEE/publisher? Or is this not possible.

  Day	Store	Sales	Sales of MAX	Sales MIN
  05/11/15	Store 1	5000	8000	1000
  05/11/15	Store 2	7500	8000	1000
  05/11/15	Store 3	1000	8000	1000
  05/11/15	Store 4	8000	8000	1000

  I'm waiting for your answers. Thanks in advance!

  PS: I will always mark messages that are useful and eventually mark it as correct answer if we come to a resolution!

  See you soon.

  You can't do the same thing with RANK ("dirty")?

  Rank ("dirty") = 1: the max value in the result of sales

  RANK (-1 * "Sales") = 1: the min in the result of sales value

  I guess you can and then format the cells based on these values, where a value of 1 is the max or min according to the RANKING formula you used...

• Need help with the analytic function

  I want to get the highest employee details and the 2nd highest employee for a particular service. But also the Department should have more than 1 employee.
  I tried the query and it gave me the correct results. But I wonder if there is another solution than to use the subquery.
  
  Here is the table and the query result:
  

  with t as
  (
  select 1 emp_id,3 mgr_id,'Rajesh' emp_name,3999 salary,677 bonus,'HR' dpt_nme from dual union
  select 2 ,3 ,'Gangz',4500,800,'Finance' from dual  union
  select 3 ,4 ,'Sid',8000,12000,'IT' from dual  union
  select 4 ,null,'Ram',5000,677,'HR' from dual  union
  select 5 ,4,'Shyam',6000,677,'IT' from dual union
  select 6 ,4 ,'Ravi',9000,12000,'IT' from dual   
  )
  select * from 
  (select emp_id, mgr_id, emp_name, dpt_nme, salary, row_number() over (partition by dpt_nme order by salary desc) rn from t where dpt_nme in 
  (select dpt_nme from t group by dpt_nme having count(*) > 1)) where rn < 3

  Hello

  You need a subquery, but you don't need more than that.
  Here's a way to eliminate the additional subquery:

  WITH     got_analytics     AS
  (
       SELECT  emp_id,     mgr_id,     emp_name, dpt_nme, salary
       ,     ROW_NUMBER () OVER ( PARTITION BY  dpt_nme
                                 ORDER BY          salary     DESC
                         )         AS rn
       ,     COUNT (*)     OVER ( PARTITION BY  dpt_nme
                                     )         AS dpt_cnt
       FROM     t
  )
  SELECT  emp_id,     mgr_id,     emp_name, dpt_nme, salary
  ,     rn
  FROM     got_analytics
  WHERE     rn     < 3
  AND     dpt_cnt     > 1
  ;
  

  Analytical functions are calculated after the clause WHERE is applied. Since we need to use the results of the analytical ROW_NUMBER function in a WHERE clause, which means that we have to calculate ROW_NUMBER in a subquery and use the results in the WHERE clause of the main query. We can call the COUNT function analytical in the same auxiliary request and use the results in the same WHERE clause of the main query.

  Would what results you if there is a link for the 2nd highest salary in some Department? For example, if you add this line to your sample data:

  select 7 ,3 ,'Sunil',8000,12000,'IT' from dual  union
  

  ? You can use RANK rather than ROW_NUMBER.

• Need help with the listagg function

  Hi all

  I try to use Listagg in the query below, but not able to get the answer. It is throwing an error message saying ORA-00979: not a GROUP BY expression.

  If I try to remove the Group By function and run the query, I get the following error ORA-00937: not a function of simple-group.

  Help, please.

  Select Distinct V.User_X, V.Original_Request_Id, (V.Support_Group_Name, ',') listagg Group (order of V.Support_group_name) as Group1,

  T.Individualassignedto, T.Status, T.Groupassignedto, T.Ticketcategory, T.Tickettype, T.orgcompany, T.submitter,

  T.Orgassignedto, T.Urgency

  Display V

  INNER JOIN K_TICKET T ON T.TICKETNUMBER = V.ORIGINAL_REQUEST_ID

  V.Original_Request_ID group

  Because you use a GROUP BY, you don't need SEPARATE.

  All the columns you are not aggregate (list) should be in the GROUP BY.

• Need help with rewrite PLSQL function EVALUATE

  Hi all
  
  I'm trying to convert some PLSQL (from Discoverer) in a column of answers and I can't seem to get the correct formula.
  
  The original formula:
  MIN (Processed_Date) MORE (SCORE OF Business_Area, product, Serial_No)
  
  I guess that this must be done in an evaluation function, but I can't work on the correct syntax.
  
  This formula:
  Evaluate ('MIN (%1) OVER (PARTITION OF 2%, 3%, 4%)) ", Business_Area, Processed_Date, Serial_No, product)
  Has generated this error:
  [nQSError: 10058] A general error occurred. [nQSError: 22027] Union of incompatible types. (HY000)
  
  I do not know what causes the error, and tried casting explicitly throughout the column, but still getting errors.
  
  
  I am open to any suggestion.
  
  Thank you.
  
  Published by: jasonr on Dec 14, 2010 09:54

  Jasonr,

  highlighted in bold is the change
  Try this EVALUATE ('MIN (%1) OVER (PARTITION OF 2%, 3%, 4%)) AS the DATE, Processed_Date, Business_Area, product, Serial_No)
  update if it solved your problem.

  -bifacts
  http://www.obinotes.com
  J

  Published by: bifacts on December 14, 2010 21:52

• Need help with the INSTR function

  I try to use SUBSTR and INSTR function to parse a variable without breaking to the top of the variable. As you can see that the problem is space, negotiating
  

   
  DECLARE
       blank_space NUMBER(2);
       full_name VARCHAR2(30) := 'Robert P. Simmons');
       first_name VARCHAR2(30);
       last_name VARCHAR2(30);
       
  BEGIN 
       blank_space := INSTR(full_name, ' ');
       first_name := SUBSTR(full_name, 1, (blank_space -1));
       DBMS_OUTPUT.PUT_LINE( 'Your first name is ' || first_name);
       last_name := SUBSTR(full_name, (blank_space + 1),
       (LENGTH(full_name) - blank_space));                
       DBMS_OUTPUT.PUT_LINE( 'You have ' || 
       LENGTH(last_name) || ' characters in your last name!');
       
  END;     

  How can I enter the number of characters in name only? It lists just to the right of the 1st blank_space.
  
  Thank you

  SQL> declare
     blank_space   number (2);
     full_name     varchar2 (30) := 'Robert P. Simmons';
     first_name    varchar2 (30);
     last_name     varchar2 (30);
  begin
     blank_space := instr (full_name, ' ');
     first_name := substr (full_name, 1, (blank_space - 1));
     dbms_output.put_line ('Your first name is ' || first_name);
  
     dbms_output.put_line ('You have ' || length (substr (full_name, instr (full_name, ' ', -1) + 1)) || ' characters in your last name!');
  end;
  /
  Your first name is Robert
  You have 7 characters in your last name!
  PL/SQL procedure successfully completed.
  

• Need help with the DECODE function

  Hello
  
  I try to use by default within the decode service and whenever I get a missing expression. I searched everywhere and can not know what I am doing wrong. Thank you
  
  Select decode (request_id, 0, "no file found", by DEFAULT)

  select decode (request_id,0,'No files found', request_id)...
  

• Need help with the rtrim function

  Hi people,
  
  Honestly, I'm embarrassed to ask this, but I'm stumped
  
  Environment: 10 g Rel 2
  
  Entry:
  14:mm
  where mm can be no matter what integer between 0 and 9
  
  Desired output:
  I want to preserve the hours and to truncate the colons and minutes
  for example 14
  
  My attempt of the solution:
  
  Select rtrim('14:33',':')
  Double;
  
  Result: 14:33
  
  I would appreciate assistance from the Member
  
  rogers42

  Hello

  You can do this in several ways.

  1. If the 14:mm is a varchar2

  select substr('14:10',1,instr('14:10',':')-1) from dual
  

  2. If the 14:mm is a varchar2

  select to_char(to_date('14:10','HH24:MI'),'HH24') from dual
  

  Arun-

• I'm suddenly needing help with my browser Firefox (6.0.2)

  Hello
  I'm suddenly needing help with my browser Firefox (6.0.2)

  (OS: I use Windows XP).

  When I open the browser, I don't see is a totally white screen of white, with all the toolbars at the top.

  I know that my physical connections are very good: I have tested the modem, turned the pc market etc and I can also receive/send emails.

  This problem started today, September 8, 2011 and has never happened before.

  Is it a coincidence that Firefox itself to day before I disconnected yesterday evening? Could this be something to do with this particular new update?

  I also noticed that just before I "opened" Firefox, I now get a small box indicating:

  [JAVASCRIPT APPLICATION]
  Handl exc in Ev: TypeError: this oRoot.enable is not a function

  This never appeared before - I hope that it offers a clue has what is wrong.

  The browser not be stuck in Mode safe, said by the way.

  Of course, I can't find solutions to the problem on the internet, I don't physically see all Web sites!
  (A friend sends this request in my name from their pc)

  Any light you can throw on this problem of confusion would be much appreciated. I'd rather not have to uninstall and reinstall Firefox if possible.

  If the only option is to uninstall Firefox and reinstall from your site, I'm also in trouble (I can not see the internet or download).
  In this case, would you be able to send the .exe file as an attachment to my e-mail address? In the affirmative, please let me know and I'll give you more details.

  Thanks in advance.

  One possible cause is security software (firewall) that blocks or limits Firefox or plugin-container process without informing you, possibly after the detection of changes (update) for the Firefox program.

  Delete all rules for Firefox in the list of permissions in the firewall and leave your firewall again ask permission to get full unlimited access to the internet for Firefox and the plugin-container and the update process.

  See:

  • https://support.Mozilla.com/kb/server+not+found
  • https://support.Mozilla.com/kb/firewalls

  Start Firefox in Firefox to solve the issues in Safe Mode to check if one of the extensions of the origin of the problem (switch to the DEFAULT theme: Firefox (Tools) > Add-ons > appearance/themes).

  • Makes no changes on the start safe mode window.
  • https://support.Mozilla.com/kb/safe+mode

• Need help with network home using Airport extreme

  I need help with my home network.  I'm not very aware when it comes to all things network.  Here's how my network is currently set up.

  Cable modem to Airport Extreme for Gigabit Switch.  Cables come out of the switch to all areas of the House.  I have 2 other extreme airport connected in other rooms of the House directly on the wall that dates back to the switch.  I hope I am explaining that properly.

  My problem is that this seems to have caused some of my connections cable does not work.  When everything is configured, it has worked well.  All connections in the House worked.  Then we have disconnected one of the extreme airport and moved to another location in the House to have the best wifi coverage.  Since that time, a lot of the ethernet wall plugs are not working.  For example, when I plug in my Macbook Pro in making ethernet in my kitchen, it says connected but it has an assigned ip address and cannot connect to the internet.

  Any help you can provide would be great.

  I would like to get the return tech to help you to...

  But it is likely that something (or someone) has tampered with the settings.

  The layout is fine... but you can cause problems with the network by creating a loop.

  This can happen because the AE you moved is connected wrongly... somewhere in the network it is connected to the switch again.

  Or AE is set to expand wireless... It's FAKE... It will loop the network on the back main EI wireless.

  Unplug the two AE you have that function as extensions...

  Turning off everything else... then it works again...

  Do it in this order.

  Modem... Wait 2 min

  AE... Wait 2 min

  Switch.

  Now check that the network is working properly... power of customers in various locations and make sure everything is good.

  If so, then manually reset the two AE of factory and redo their installation.

• I have a mess of error. about microsoft Isatap adapter... plug and play id root\ * Isatap\0002 error tv-configmgrerr31 need help with drivers

  need help with this.is there a link for the drivers. The only changes to my system is a new modom.netgear wireless g54.thank you

  Hello

  (1) what is the complete error message you receive?

  (2) when exactly you get this error message?

  (3) how long have you been faced with this problem?

  You can ignore this error message. This error message does not indicate a problem with the adapter. The adapter will continue to function correctly.

  See the article below

  On a Windows Vista-based computer or on a Windows Server 2008-based computer, the Microsoft ISATAP map appears with a yellow exclamation mark next to it in Device Manager, and you also receive an error message
  http://support.Microsoft.com/kb/932520

• need help with windows update C8000F1A error code

  I need help with an error code that is given to my PC when I try to put up-to-date

  Hello

  1. don't you make recent changes?

  2. This does happen with any special updates or all updates?

  I suggest you to follow these steps and check if that helps:

  Method 1:

  If you have installed a security software on the computer, then I suggest you try to disable temporary and check to see if the same problem happens. Make sure that you enable security software back once the diagnosis is made to prevent the computer from virus attacks.
  http://Windows.Microsoft.com/en-us/Windows-Vista/disable-antivirus-software

  Method 2:
  I suggest you follow the steps in the link below and check if it helps:
  http://Windows.Microsoft.com/en-us/Windows-Vista/troubleshoot-problems-with-installing-updates

  It will be useful.

• Need help with setting up in checkbox in interactive reports

  I need help with setting up in checkbox in interactive reports, I use this statement a query

  SELECT apex_item.checkbox

  (

  1, ROLEID,

  'onchange = "spCheckChange (this);". ',

  : F_ROLEID_LIST,.

  ':'

  ), del.

  ROLEID, ROLEDESCRIPTION

  OF EBA_ROLES

  When I run it I get the following

  < input type = "checkbox" name = "f01" value = "1" onchange = "spCheckChange (this); ' / > instead of the checkbox

  Do I need to configure anything else

  Aditya Gupta wrote:

  I need help with setting up in checkbox in interactive reports, I use this statement a query

  SELECT apex_item.checkbox

  (

  1, ROLEID,

  'onchange = "spCheckChange (this);". ',

  : F_ROLEID_LIST,.

  ':'

  ), del.

  ROLEID, ROLEDESCRIPTION

  OF EBA_ROLES

  When I run it I get the following

  instead of the checkbox

  Do I need to configure anything else

  This is one of the most frequently asked questions in this forum. Set the column attribute the text to display as Standard report column and not display text (special escape characters).

  
  

  Always include the information referred to in these guidelines when you ask a question and if you use APEX 5.0, State, if you develop using the pages or the view of the component designer.

• Need help with a SQL query

  Hello

  I have a data in table (raj_table) with columns (char11) raj_id, raj_number (varchar2 (15)), raj_format (NUMBER), Primary_ID (identity with the values of the primary key column)

  Primary_ID raj_id Raj_number Raj_format

  1                            raj                 rajvend                      1

  2                            raj                 rajvend                      1

  3                            raj                 rajvendor1                 2

  4                            raj                 rajvendor1                 2

  5                            raj                 rajvendor1                 2

  6                            raj                 rajvendor2                 3

  I used under SQL to get query output as below, but has not achieved the required result:

  Select client_id vendor_number, vendor_format, primary_id, row_number() on sl_no (client_id partition, primary_id, vendor_format order of client_id primary_id, vendor_format, vendor_number, vendor_number)

  from raj_table by sl_no asc

  SL_NO raj_id raj_number raj_format primary_id

  1                   1                   raj              rajvendor                 1

  1                   2                  raj              rajvendor                 1

  2                   3                   raj              rajvendor1                2

  2                   4                   raj              rajvendor1                2

  2                   5                  raj               rajvendor1                2

  3                   6                    raj              rajvendor2                3

  I need help with a SQL query to get the result as above without using the group by clause. I want to bring together the combination of separate line of the three columns (raj_id, raj_number, raj_format) and add a unique serial number for each online game (SL_NO column below). So, above there are 3 unique set of (raj_id, raj_number, raj_format) I can get in a group by clause, but I can not add prmiary_id, SL_NO values if I group by clause. I used the analytical functions like row_number() but no luck. Need solution for this.

  with t as)

  Select 'raj' raj_id, 'rajvend' raj_number, 1 raj_format, 1 primary_id Union double all the

  Select option 2, 'raj', 'rajvend', 1 double Union all

  Select 3, 'raj', 'rajvendor1', 2 double Union all

  Select 4, 'raj', 'rajvendor1', 2 double Union all

  Select 5, 'raj', 'rajvendor1', 2 double Union all

  Select 6, 'raj', 'rajvendor2', 3 double

  )

  Select dense_rank() over (order of raj_id, raj_number, raj_format) sl_no,

  t.*

  t

  order by primary_id

  /

  PRIMARY_ID RAJ RAJ_NUMBER RAJ_FORMAT SL_NO
  ---------- ---------- --- ---------- ----------
  1 1 raj rajvend 1
  1 2 raj rajvend 1
  2 3 raj rajvendor1 2
  2 4 raj rajvendor1 2
  2 5 raj rajvendor1 2
  3 6 raj rajvendor2 3

  6 selected lines.

  SQL >

  SY.