Need help with the query and output

Similar Questions

• need help with the query, thx

  Hello
  I need a little help with the query I have to write;
  the table has 4 columns:

  col1               col2         col3       col4
  emp_name     empl_id    salary      year
  
  content of data:
  
  col1               col2         col3       col4
  smith             12           1200      1999
  smith             12           1340      2000
  smith             12           1500      2001
  jones             13           1550      1999 
  jones             13           1600      2000
  aron              14           1200      2002

  what I am asking is the following result: salary according to the latest available year
  i.e.

  smith         12         1500        2001
  jones         13         1600        2000
  aron          14         1200        2002

  ID appreciate some guidance on how to achieve
  Thank you
  Rgds

  select *from
  (select col1, col2,col3, col4,row_number() over(partition by col1 order by col4 desc)  rn  from 
  ) where rn=1
  

• NEED HELP WITH THE QUERY, NEED MORE RECENT FILE ONLY

  Hi all
  
  That is,
  
  I have an assignment I need to find agents that allow players to break the rules.
  
  So far, I have 41 results, in which there are 4 principles and 24 footballers and football player even beat more than one rule or the rule more than once.
  
  What I need now is to make arrangements so that every footballer appears once n matter how many times they have broken the rules.
  
  
  I have
  
  SELECT
  t.transfer_time | ' ' || a.first_name | ' ' || a.last_name | ' ' || f.first_name | ' ' || f.last_name | ' ' || f.footballer_id | ' ' || t.transfer_id
  Of
  agents a, t transfers, footballers f, footballers_fees fo
  WHERE
  a.agent_id = t.broker_id
  AND
  t.footballer_id = f.footballer_id
  AND
  f.footballer_id = fo.footballer_id
  AND
  (RULE 1 BROKEN AND RULE 2 BROKEN
  OR
  RULE 1 BROKEN AND ARTICLE 2 DOES NOT DECOMPOSE
  OR
  RULE 1 DOES NOT DECOMPOSE AND RULE 2 BROKEN)
  
  
  GROUP BY
  t.transfer_time | ' ' || a.first_name | ' ' || a.last_name | ' ' || f.first_name | ' ' || f.last_name | ' ' || f.footballer_id | ' ' || t.transfer_id
  ORDER BY
  t.transfer_time | ' ' || a.first_name | ' ' || a.last_name | ' ' || f.first_name | ' ' || f.last_name | ' ' || f.footballer_id | ' ' || t.transfer_id
  ;
  
  
  
  (I did not type the SQL code to rules 1 and 2 but I know it works)
  
  Now, I need not to show that every footballer once they broke rule and more than once or not.
  
  I was looking at the screen nearly enough hours 10 and any help or ideas would be greatly appreciated
  
  Thank you all :)

  Hello

  Welcome to the forum!

  Whenever you have a problem, please post a small example of data (CREATE TABLE and INSERT statements) so that people who want to help you can recreate the problem and test their ideas. You don't have to display a large amount of data. In this case, it seems that 2 to 10 lines for each table could give a good picture of the problem.
  After the results that you want samples fropm, and explain how you get those resulting from these data.
  Always tell what version of Oracle you are using.

  The ideal outcome would be just what you '; Re I get now, but with some deleted rows and only 1 line by left footballer? If so, do a subquery on the original query, and then add somehting like

  , ROW_NUMBER () OVER (PARTITION BY f.footballer_id ORDER BY NULL)  AS r_num
  

  in the SELECT clause.
  then, in the main query, display only lines

  WHERE   r_num  = 1
  

  ROW_NUMBER requires an ORDER byclause of analytics. If you ORDER BY a constant (e.g. NULL) then what line gets number 1 will be arbitrary. If you care who lines for a given player is numbered 1 (and therefore included in the final output), then adjust the analytical ORDER BY clause. (You the title mentions "most recent record only", so if the dt column indicates whether a line is "newer" than another, you can "ORDER BY dt DESC".)

  I know this response is vague in places. Without a concrete example (CREATE TABLE and instructions INSERT for examples of data and outcomes from these data), that's the best I can do.

• Need help with the query to get the County

  Hello

  Oracle 10 g 2 10.2.0.3 - 64 bit

  I want back the number of accounts with two different types of funds (say A and B). Some accounts hold only one of the two funds, and some support both. I want to get the counts like this:

  • account held funds - has only
  • accounts holding funds-B only
  • accounts holding the Fund-A and B funds

  Here is what I started with but need assistance to meet the requirement above:

  select 
  count(distinct acct.bkoff_acct_no ) accounts_holding_fund_A
  from xe_account acct,
          xec_tal_investment_mandate iman,
          xec_tal_asset_allocation alloc,
          xe_benchmark bmark,
          xe_benchmark_usage bu,
          xe_object_description xod,
          xec_asset_class cls
  where iman.mandate_status_cd='A'
  and cls.asset_class_cd = alloc.asset_class_cd
  and iman.mandate_id = alloc.mandate_id
  and acct.account_id = iman.object_id
  and iman.object_type_cd = 'ACCT'
  and iman.mandate_id = xod.object_id
  and xod.field_nm='XEC_TAL_INVESTMENT_MANDATE.COMMENT_TXT'
  and xod.language_cd = 'E'
  and acct.acct_status_cd = 'O'
  and bu.object_type_cd(+) = 'TMAA'
  and bu.object_id(+) = alloc.asset_allocation_id
  and bmark.benchmark_id(+) = bu.benchmark_id
  and alloc.resp_txt like '%fund-A%'
  
  
  

  And suppose that the Fund-B has resp_txt like ' % of Fund-B»

  Please suggest.

  Concerning

  Hello

  Here is another way, it is easier to adapt to different jobs and different numbers of jobs:

  WITH got_distinct_jobs AS

  (

  SELECT DISTINCT deptno, job

  FROM scott.emp

  WHERE job IN ("ANALYST", "CLERKS") - or what

  )

  got_job_list AS

  (

  SELECT LISTAGG (job, ",") THE Group (ORDER BY work) AS job_list

  OF got_distinct_jobs

  GROUP BY deptno

  )

  SELECT job_list

  COUNT (*) AS num_departments

  OF got_job_list

  GROUP BY job_list

  ;

  This shows all the combinations of the jobs listed in the WHERE clause of got_distinct_jobs.  You don't need to change anything else in the query.  There may be any number of jobs.

  Output:

  JOB_LIST NUM_DEPARTMENTS

  ------------------------------ ---------------

  CLERK                                        2

  ANALYST, CLERK 1

• Need help with the query (transpose)

  Hello experts, please help here - 11 g Oracle, attribute APA APB are fixed values and can be hard coded in query

  Need to transpose these data. Max(decode.. perd les données en sortie à cause de la condition de Max.)

  Entry:

  Name | Attribute | Value

  A1 APP 10

  A1 PDB 11

  A1 APA 20

  A1 PDB 21

  A2 BPA 13

  A2 BPB 14

  Expected results:

  Name AttVal1 AttVal2

  A1 10 11

  13 14 A2

  20 21 A1

  Hello

  Here's one way:

  WITH relevant_columns AS

  (

  SELECT name

  value

  CASE

  WHEN the attribute ("APA", "BPA") THEN 1

  WHEN the attribute ("PDB", "BPB") THEN 2

  END AS c_num

  ROW_NUMBER () (PARTITION BY NAME, attirbute

  Value of ORDER BY

  ) AS r_num

  FROM table_x

  )

  SELECT name, attval1, attval2

  OF relevant_columns

  PIVOT (MAX (value)

  FOR c_num IN (1 AS attval1

  2 UNDER attval2

  )

  )

  ORDER BY r_num, name

  ;

  If you would care to post CREATE TABLE and INSERT statements for your sample data, and then I could test this.

  Why do you want to

  NAME ATTVAL1 ATTVAL2

  ----  -------  -------

  A1 10 11

  20 21 A1

  in the results, rather than

  NAME ATTVAL1 ATTVAL2

  ----  -------  -------

  10 21 A1

  20 11-A1

  ?  You would be satisfied to one or the other?

  Depending on your answer, you may need to modify the analytical ORDER BY clause in the ROW_NUMBER function.

• Need help with the query. Help, please

  Hey everyone, need your help.  Thank you in advance.  In my view, there is function Pivot.  Just do not know how to use this function.  I have the query that works.  The result is:

  11-111-1111 Vlad 16505 01/04/2013 5 August 13 dental plan pre-tax amount 29,65

  11-111-1111 Vlad 16505 01/04/2013 dental pre-tax 5 August 13 Plan level EE + SP

  11-111-1111 16505 Vlad 01/04/2013 5 August 13 pre-tax Option TOP dental plan

  11-111-1111 Vlad 16505 01/04/2013 5 August 13 pre-tax dental care plan pay the value

  11-111-1111 16505 Vlad 01/04/2013 dental pre-tax 5 August 13 Plan period Type

  11-111-1111 Vlad 16505 01/04/2013 amount pre-tax medical Plan of 5 August 13 149

  11-111-1111 Vlad 16505 01/04/2013 5 August 13 pre-tax Medical Plan level EE + SP

  11-111-1111 Vlad 16505 01/04/2013 5 August 13 pre-tax Plan medical Option MED

  11-111-1111 Vlad 16505 01/04/2013 5 August 13 plan pre-tax pay value

  11-111-1111 16505 Vlad 01/04/2013 5 August 13 pre-tax Medical Plan period Type

  11-111-1111 Vlad 16505 01/04/2013 5 August 13 pre-tax Plan PPO medical Plan

  11-111-1111 Vlad 16505 01/04/2013 5 August 13 Vision Plan amount 5.94 pre-tax

  But I need the result to be

  Amount of SSN ID name item level Option PayValue period Type

  11-111-1111 Vlad 16505 01/04/2013 null null high of 5 August 13 pre-tax Dental Plan 29,65 EE + SP

  11-111-1111 Vlad 16505 01/04/2013 null null MED 5 August 13 149 medical plan pre-tax EE + SP

  11-111-1111 Vlad 16505 01/04/2013 Vision Plan before taxes of 5 August 13

  Select distinct
  ' 11-111-1111 "as ssn,
  WOMEN'S WEAR. Employee_number,
  "Vlad" as EMPLOYEE_FULL_NAME,
  TO_CHAR (papf.start_date, "MM/DD/YYYY") as Date_Of_Hire
  a.effective_start_date,
  PETF.element_name,
  pivf. Name,
  peevf.screen_entry_value

  Of
  PER_all_PEOPLE_F women's wear
  per_assignments_f A
  pay_element_types_f petf
  pay_element_links_f pelf
  PAY_ELEMENT_ENTRIES_F penf
  PAY_ELEMENT_ENTRY_VALUES_F peevf
  pay_input_values_f pivf
  WHERE
  PETF.element_name ('Dental Plan before taxes', 'Medical Plan before taxes', "Vision Plan before taxes")
  and petf. ELEMENT_TYPE_ID = pelf. ELEMENT_TYPE_ID
  and (trunc (sysdate) BETWEEN pelf. EFFECTIVE_START_DATE AND pelf. EFFECTIVE_END_DATE)
  and (pelf. ELEMENT_LINK_ID = penf. ELEMENT_LINK_ID and a.assignment_id = penf. ASSIGNMENT_ID)
  and (trunc (sysdate) BETWEEN penf. EFFECTIVE_START_DATE AND penf. EFFECTIVE_END_DATE)
  and penf. ELEMENT_ENTRY_ID = peevf. ELEMENT_ENTRY_ID
  and peevf. INPUT_VALUE_ID = pivf. INPUT_VALUE_ID
  AND papf.employee_number IS NOT NULL
  AND A.assignment_type = 'E '.
  AND A.person_id = papf.person_id
  and papf.effective_end_date > sysdate
  and a.effective_end_date > sysdate
  and (trunc (sysdate) BETWEEN women's wear. EFFECTIVE_START_DATE AND women's wear. EFFECTIVE_END_DATE)
  and a.effective_start_date = (select MAX (effective_start_date) from PER_ASSIGNMENTS_f where assignment_id = a.assignment_id)
  and a.assignment_id = 42643
  and a.assignment_status_type_id = '1'
  order of petf.element_name;

  Change with your query

  SELECT * FROM (select distinct)

  ' 11-111-1111 "as ssn,

  WOMEN'S WEAR. Employee_number,

  "Vlad" as employee_full_name,

  TO_CHAR (papf.start_date, "MM/DD/YYYY") as date_of_hire

  a.effective_start_date,

  PETF.element_name,

  pivf. Name,

  peevf.screen_entry_value

  Of

  PER_all_PEOPLE_F women's wear

  per_assignments_f A

  pay_element_types_f petf

  pay_element_links_f pelf

  PAY_ELEMENT_ENTRIES_F penf

  PAY_ELEMENT_ENTRY_VALUES_F peevf

  pay_input_values_f pivf

  WHERE

  PETF.element_name ('Dental Plan before taxes', 'Medical Plan before taxes', "Vision Plan before taxes")

  and petf. ELEMENT_TYPE_ID = pelf. ELEMENT_TYPE_ID

  and (trunc (sysdate) BETWEEN pelf. EFFECTIVE_START_DATE AND pelf. EFFECTIVE_END_DATE)

  and (pelf. ELEMENT_LINK_ID = penf. ELEMENT_LINK_ID and a.assignment_id = penf. ASSIGNMENT_ID)

  and (trunc (sysdate) BETWEEN penf. EFFECTIVE_START_DATE AND penf. EFFECTIVE_END_DATE)

  and penf. ELEMENT_ENTRY_ID = peevf. ELEMENT_ENTRY_ID

  and peevf. INPUT_VALUE_ID = pivf. INPUT_VALUE_ID

  AND papf.employee_number IS NOT NULL

  AND A.assignment_type = 'E '.

  AND A.person_id = papf.person_id

  and papf.effective_end_date > sysdate

  and a.effective_end_date > sysdate

  and (trunc (sysdate) BETWEEN women's wear. EFFECTIVE_START_DATE AND women's wear. EFFECTIVE_END_DATE)

  and a.effective_start_date = (select MAX (effective_start_date) from PER_ASSIGNMENTS_f where assignment_id = a.assignment_id)

  and a.assignment_id = 42643

  and a.assignment_status_type_id = '1')

  PIVOT (MAX (screen_entry_value) FOR (name) TO ("Amount" AS 'Amount', 'level' AS 'level', 'Option High' AS 'High Option', 'Pay the value' AS 'Value to pay', 'Period of Type' AS 'Type period'))

  order by element_name;

  (GOLD)

  SELECT ssn,

  Employee_number,

  employee_full_name,

  date_of_hire,

  effective_start_date,

  element_name,

  Max (decode (Name, 'Amount', screen_entry_value)) 'amount. "

  Max (decode (Name, 'Level', screen_entry_value)) 'level ',.

  MAX (DECODE (name, "High Option", screen_entry_value)) "High Option",

  MAX (DECODE (name, 'Value of pay', screen_entry_value)) 'value of pay. "

  MAX (DECODE (name, 'Period Type', screen_entry_value)) 'period of Type '.

  FROM (select distinct)

  ' 11-111-1111 "as ssn,

  WOMEN'S WEAR. Employee_number,

  "Vlad" as employee_full_name,

  TO_CHAR (papf.start_date, "MM/DD/YYYY") as date_of_hire

  a.effective_start_date,

  PETF.element_name,

  pivf. Name,

  peevf.screen_entry_value

  Of

  PER_all_PEOPLE_F women's wear

  per_assignments_f A

  pay_element_types_f petf

  pay_element_links_f pelf

  PAY_ELEMENT_ENTRIES_F penf

  PAY_ELEMENT_ENTRY_VALUES_F peevf

  pay_input_values_f pivf

  WHERE

  PETF.element_name ('Dental Plan before taxes', 'Medical Plan before taxes', "Vision Plan before taxes")

  and petf. ELEMENT_TYPE_ID = pelf. ELEMENT_TYPE_ID

  and (trunc (sysdate) BETWEEN pelf. EFFECTIVE_START_DATE AND pelf. EFFECTIVE_END_DATE)

  and (pelf. ELEMENT_LINK_ID = penf. ELEMENT_LINK_ID and a.assignment_id = penf. ASSIGNMENT_ID)

  and (trunc (sysdate) BETWEEN penf. EFFECTIVE_START_DATE AND penf. EFFECTIVE_END_DATE)

  and penf. ELEMENT_ENTRY_ID = peevf. ELEMENT_ENTRY_ID

  and peevf. INPUT_VALUE_ID = pivf. INPUT_VALUE_ID

  AND papf.employee_number IS NOT NULL

  AND A.assignment_type = 'E '.

  AND A.person_id = papf.person_id

  and papf.effective_end_date > sysdate

  and a.effective_end_date > sysdate

  and (trunc (sysdate) BETWEEN women's wear. EFFECTIVE_START_DATE AND women's wear. EFFECTIVE_END_DATE)

  and a.effective_start_date = (select MAX (effective_start_date) from PER_ASSIGNMENTS_f where assignment_id = a.assignment_id)

  and a.assignment_id = 42643

  and a.assignment_status_type_id = '1')

  GROUP BY ssn, employee_number, employee_full_name, date_of_hire, effective_start_date, NOM_ELEMENT

  order by element_name;

• Need help with the query using the AVG function

  First post here.
  I am a student taking a SQL class and I can't find a query.
  I think I'm close to get it, but I can not quite all the way there.
  
  Three tables are involved in this problem. Here is a list of the tables and the areas concerned:

  orders table:
    order#
    shipstate
  
  orderitems table:
    order#
    isbn
    quantity         (How many copies of book purchased on that order)
  
  books table:
    isbn
    retail    (retail price of book)

  Problem:
  I want to get an average of "total amount" by shipstate.
  
  For example, in these tables, there are 8 records of the State of Florida.
  However, there are only 5 unique order # for this State.
  The amount of detail * quantity for these 8 disks (or 5 orders) is $345,10
  Now to get my average $345,10 should be divided by 5. (number of unique commands)
  In the following query it divides this $345,10 8. (number of records)
  
  How to make this request to divide by the number of unique order # rather than the number of records?

  SELECT shipstate, AVG(quantity * retail)
  FROM orders JOIN orderitems USING (order#)
  JOIN books USING (isbn)
  GROUP BY shipstate
  HAVING SUM(quantity * retail) =ANY
                                (SELECT SUM(quantity * retail)
                                  FROM books JOIN orderitems USING (isbn)
                                  JOIN orders USING (order#)
                                  GROUP BY shipstate) 

  According to me, once I get this part down, I can understand the rest of the problem.
  The end result, I need, is to find all the individual commands that have a "total amount due" that is greater than the 'average amount due' for this state of clients.
  
  Any help, suggestions or comments welcome.
  Matt

  Your average take into account the shipstate (8 disks), you can do that for the expected results.
  With some examples of input data it would be easier, but here a try:

  SELECT shipstate, sum(quantity * retail)/count(distinct order#)
  FROM orders JOIN orderitems USING (order#)
  JOIN books USING (isbn)
  GROUP BY shipstate;
  

  Nicolas.

  delete the alias
  Edited by: N. Gasparotto on October 3, 2008 19:28

• HP Pavilion Notebook - 15-p199: need help with the installation and activation of 10 Windows after completely uninstalling Windows

  Hello HP assistants.

  I need help for a specific problem. My laptop came with an installation of Windows 8.1. Then I upgraded to 10 Windows when it became available. After a while, I decided to uninstall Windows completely (to wipe the hard drive) and install a Linux operating system.

  Now, I decided that I want to use some software that is not available on Linux and if I want to reinstall Windows 10. My problem is that Windows has completely disappeared in a form any. So now, I need to download Windows 10 from an official source (which I think can be done fairly easily from the official source of Microsoft, although if there is a better, HP official medium to do this then please recommend it) and then I need to activate Windows some how.

  As has been made clear, I have the right to use Windows 8.1 and 10 but I would need to download Windows 10 and turn it on. Is there a way to do this? I'm literally stuck without solution.

  Thanks in advance.

  Hello

  As long as the previous installation of Windows 10 had activated Ok after upgrade from 8.1, you can simply perform a new installation as described in the guide on the following link.  Note: On the activation screen, select "I don't have a product key" - Windows will activate automatically once installation is complete.

  http://www.howtogeek.com/224342/how-to-clean-install-Windows-10/

  Kind regards

  DP - K

• Need help with the query logic

  I have 2 tables.
  
  Table Tb1:
  THE PLAN_ID PARENT_PLAN_ID ARGUMENT
  Value null P1
  P1 P2
  P3 P2
  P4 P1
  
  Table tb2:
  THE PLAN_ID ACTIVITY_ID PICKING ARGUMENT
  P2 A1 5000
  P2 A2 5000
  P2 A3 5000
  P3 A1 10000
  P3 A2 10000
  P4 A1 4000
  
  
  I need to find the sum of the value of reduction of the workforce for each PLAN_ID which is parent root. In the case above, this is the argument PLAN_ID P1 (WHERE PARENT_PLAN_ID IS NULL). Please note that the value of the downsizing is repeated in the tb2 table. For example, the PLAN_ID P2 argument, the value of the downsizing is 5000 and not 5000 + 5000 + 5000.
  
  The result of the output for the above data must be
  THE ARGUMENT PLAN_ID DRAWDOWN
  P1 19000
  
  Published by: user10566312 on October 30, 2012 12:30

  with t as
  (   select t1.plan_id,t1.parent_plan_id,max(t2.DRAWDOWN) DRAWDOWN
      from tb1 t1,tb2 t2
      where t1.plan_id = t2.plan_id(+)
      group by  t1.plan_id,t1.parent_plan_id
  )
  select plan_id,sum(drawdown) drawdown
  from(
        select  connect_by_root plan_id as plan_id,
                nvl(DRAWDOWN,0) DRAWDOWN
        from t
        start with parent_plan_id is null
        connect by parent_plan_id  = prior plan_id
      )
  group by plan_id  ; 
  
  PLAN_ID DRAWDOWN
  ------- --------
  P1         19000 
  

  Published by: JAC on October 30, 2012 13:23

• Need help with the query using the aggregation

  If I have a table, defined as follows:
  
  CREATE TABLE range_test
  (
  range_id NUMBER (20) NOT NULL,
  rank of char (1) NOT NULL,
  lower_bound_of_range NUMBER (5.2) NOT NULL,
  upper_bound_of_range NUMBER (5.2) NOT NULL,
  received_date_time_stamp SYSTIMESTAMP NOT NULL DEFAULT TIMESTAMP
  );
  
  And I wanted to query the table to find the range associated with the last line inserted for each 'class' (for example 'A', 'B', 'C', etc.), how would I go about this?
  
  I want something like the following, but I know that it will not work right:
  
  SELECT
  grade,
  lower_bounding_of_range,
  upper_bounding_of_range,
  Max (received_date_time_stamp)
  Of
  range_test GROUP BY received_date_time_stamp;
  
  Thanks for your help... I am frustrated with this one and I think that it should be possible without having to use the PL/SQL (i.e. the functions of SQL aggregation or subqueries should work).

  Perhaps something along the lines of...

  SQL> ed
  Wrote file afiedt.buf
  
    1  select deptno, empno, ename, hiredate
    2  from emp
    3* order by deptno, empno
  SQL> /
  
      DEPTNO      EMPNO ENAME      HIREDATE
  ---------- ---------- ---------- --------------------
          10       7782 CLARK      09-JUN-1981 00:00:00
          10       7839 KING       17-NOV-1981 00:00:00
          10       7934 MILLER     23-JAN-1982 00:00:00
          20       7369 SMITH      17-DEC-1980 00:00:00
          20       7566 JONES      02-APR-1981 00:00:00
          20       7788 SCOTT      19-APR-1987 00:00:00
          20       7876 ADAMS      23-MAY-1987 00:00:00
          20       7902 FORD       03-DEC-1981 00:00:00
          30       7499 ALLEN      20-FEB-1981 00:00:00
          30       7521 WARD       22-FEB-1981 00:00:00
          30       7654 MARTIN     28-SEP-1981 00:00:00
          30       7698 BLAKE      01-MAY-1981 00:00:00
          30       7844 TURNER     08-SEP-1981 00:00:00
          30       7900 JAMES      03-DEC-1981 00:00:00
  
  14 rows selected.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  select deptno, empno, ename, hiredate
    2  from (
    3        select deptno, empno, ename, hiredate
    4              ,row_number() over (partition by deptno order by hiredate desc) as rn
    5        from emp
    6       )
    7  where rn = 1
    8* order by deptno, empno
  SQL> /
  
      DEPTNO      EMPNO ENAME      HIREDATE
  ---------- ---------- ---------- --------------------
          10       7934 MILLER     23-JAN-1982 00:00:00
          20       7876 ADAMS      23-MAY-1987 00:00:00
          30       7900 JAMES      03-DEC-1981 00:00:00
  
  SQL>
  

• need help with the query: (Frank)

  Hi Frank,.
  
  I have the oracle 8 database.
  I have the following table with the data structure:
  
  TABLE P (PID, PNAME, COLOR)
  PRIMARY KEY: PID
  

  PID     Pname    Color
  p1...........          Red
  P2.................    green
  p3...............       blue
  p4 ..................   red

  CAT TABLE (SID, PID, COST)
  KEY: SID MAIN + PID
  KEY REFERENCE: SID REFERENCE S.SID
  PID P.PID REFERENCES
  

  Sid        Pid       COst....
  S1        P1
  S2        P2
  S3        P3
  S1      P4
  S2       p1
  S3        p1

  now my question is:
  I want to find the SIDS of suppliers that provide a red and a green part
  
  for this I used the following query, but it gives the result worng...
  
  can help me please in this way to get this...
  

  select sid from cat
  where pid in (select pid from p where color= 'red'
            union
            select pid from p where color = 'gren') 
  group by sid having count(pid) >= 2

  Hello

  Jojo wrote:
  Hi Frank,.

  It would be nice if someone with a different name helped you? Do not restrict yourself by addressing someone in particular in your subject line or the first message.

  I have the oracle 8 database.
  I have the following table with the data structure:

  TABLE P (PID, PNAME, COLOR)
  PRIMARY KEY: PID

  PID     Pname    Color
  p1...........          Red
  P2.................    green
  p3...............       blue
  p4 ..................   red
  

  CAT TABLE (SID, PID, COST)
  KEY: SID MAIN + PID
  KEY REFERENCE: SID REFERENCE S.SID
  PID P.PID REFERENCES

  Sid        Pid       COst....
  S1        P1
  S2        P2
  S3        P3
  S1      P4
  S2       p1
  S3        p1
  

  now my question is:
  I want to find the SIDS of suppliers that provide a red and a green part

  for this I used the following query, but it gives the result worng...

  can help me please in this way to get this...

  select sid from cat
  where pid in (select pid from p where color= 'red'
            union
            select pid from p where color = 'gren')
  group by sid having count(pid) >= 2
  

  You don't like what is the number of lines with a pid; If you had 20 rows all said 'p1', that would be good enough. The number of distinct colors of the whole ('red', 'green') is what is important.
  Avoid the UNION when there is a simple alternative. The UNION tends to be slow.

  You can use a join instead, like this:

  SELECT       c.sid
  FROM       cat     c
  ,            p
  WHERE       p.pid          = c.pid
  AND       p.color       IN ('red', 'green')
  GROUP BY  c.sid
  HAVING       COUNT (DISTINCT p.color)     = 2
  ;
  

  If you would care to post CREATE TABLE and INSERT statements for the sample data and the results that you want from this data, then I could test this.

  Published by: Frank Kulash, January 10, 2011 15:25

• Need help with the query string manipulation

  Hello
  
  With the help of 10.1.0.4.2
  
  Given a table called PREFIX_CODES that contains a column called PREFIX_CODE
  with the following data:
  
  PREFIX_CODE - VARCHAR2 (20)
  -------------------
  AAA
  BENAMER
  CARTER
  
  and another table called SUBSCRIBERS with a column called SUBSCRIBER_ID
  with the following data:
  
  SUBSCRIBER_ID - VARCHAR2 (30)
  ---------------------
  BBBB-123456
  AAA-444444
  DD-2222222
  EEEE-888888
  
  Is there a query that will pull all the SUBSCRIBER_ID that begin with
  each of the PREFIX_CODES? The following query is not valid, but it
  This will give you an idea of what I'm trying to do:
  
  SELECT SUBSCRIBER_ID
  SUBSCRIBERS
  WHERE AS SUBSCRIBER_ID (SELECT PREFIX_CODE |) » %'
  OF PREFIX_CODES)
  
  Using the data from above, I would like that the query to return:
  
  BBBB-123456
  AAA-444444
  
  Thanks for your help!

  Hello

  Welcome to the forum!

  You were on the right track. To find if a given subscriber corresponds to any prefix_code, you can do an EXISTS subquery:

  SELECT     subscriber_id
  FROM     subsribers     s
  WHERE     EXISTS ( SELECT  NULL
                    FROM      prefix_codes
             WHERE      s.subscriber_id     LIKE prefix_code || '%'
              )
  ;
  

  This will tell you if at least a prefix code. It won't tell you exactly how many, or what they were.
  Your message, I'm guessing that there may be more than one, and you can deduct the subscriber_id itself, then the above query should work for you.

• Need help with the formatting and reinstalling windows

  Hi, I have a Compaq Presario C700 p/n GR598EA #ABU I got to work about 3 years ago.

  Recently, it does not load windows, even in safe mode and I can't get back either.

  I used a disc to boot from linux to access and backup of all my important files and now I want to reformat the hard drive, resintall windows and start over (or try something else which will fix it)

  The laptop has been pre-installed with Windows Vista and HP stuff had already installed on it.  I don't have a Windows disc or discs of driver with the laptop.

  How can I format and reinstall windows and drivers, if I don't have records?

  Help, please.

  Thank you.

  Hello:

  You can order a Vista recovery disk set for your laptop if they are still available. See the instructions below:

  http://support.HP.com/US-en/document/c00810334=

  If you live not in the US or the Canada, you can contact HP Support worldwide for the country you live and ask recovery disks command to your laptop

  The link to the assistance of HP WW is below:

  http://welcome.HP.com/country/us/en/wwcontact_us.html

  Paul

• HP Pavilion a6000n - improvement of the system. Need help with the decision and suggestions

  Hi all

  I have a HP Pavilion a6000n, spec even with this link , except that I have 3 GB of memory and Window Vista Home Premium 32-bit.

  I think to update some of my computer hardwares that can run more smooth in some games and to improve my gaming experience.

  I'm looking to replace the processor and graphics card.  At the present time, I have an AMD Athlon (TM) 64 X 2 Dual Core Processor 4200 + 2.2 and a NVIDIA Geforce 6150SE nforce 430.

  My price range is around $100-$200 for processor and graphics together.

  I looked at cela processor and graphics card

  They will make a big difference and improvement than what I have at the moment?   If this isn't the case, then can you guys give me some suggestions on the choice of the better ones out there?

  Thank you!

  You have only a 300w ATX PSU (Power Supply Unit), then you will need to update if you plan to install a good graphics card.  Check the manufacturers minimum power required for the card you decide on getting.  As for the CPU, it does not require the upgrade - the graphics card is what causes your performance problems (in the games).  I would like to spend more money on a power supply and graphics card and leave the CPU alon (so far )

  Message edited by Kalt on 05/12/2008 23:18

• Need help with the links and the fill color

  Hi all, I just recently discovered liveCycle and I am very impressed with it! I tried to get a calendar of working from home for awhile now and I did for the most part, but there are a few things more that I would like to add that I do not know how to do.

  I have experience HTML and Java, but very few XML or JavaScript experience. I have a feeling that what I try to do is relatively simple, but I just can't understand it! I spent hours on Google and the help files, and I feel that I got the end again, but not joy.

  I have attached my calendar (truncated to fit the size of max 5 MB attachments) so far. I would like it to do more than two things:

  1. have the background color of the table cells change from white to green when the checkbox is enabled.

  (Alternatively, I would really like to get rid of boxes to tick all the thogether and just the table cells background become green with a hotkey, such as "ctrl + D" to 'make'.) "But if this is not possible, then the color change with the box is fine).

  2. I want the button called "WORD DOC" in the upper right of the form to open a document in word on my local computer. I just push this button and a doc of work opens right in Word in another window.

  I was able to get. PDFs to open in the other two buttons here ('Big Java' and 'Beginning Java II') by adding the script

  app.openDoc ("Big Java.pdf");

  and

  app.openDoc ("Java beginning II.pdf");

  for each buttons respectively, but these PDF files must be in the same folder as the calendar to make it work. I tried just to edit this script by replacing the name of the PDF file by the name of a file to Word doc like this:

  app.openDoc ("test.docx");

  but the button does not work, there is simply nothing.

  So what I'm trying to do. I spent hours messing around with everything I could think of to make it work, but unfortunately I do not know the language well enough so he can work.

  I'd appreciate really any advice on this at all. I thank very you much for your review.

  Click on the second box to check and see the result.

  Is that what you want?

  Nith