NEED HELP WITH THE QUERY, NEED MORE RECENT FILE ONLY

Hi all

That is,

I have an assignment I need to find agents that allow players to break the rules.

So far, I have 41 results, in which there are 4 principles and 24 footballers and football player even beat more than one rule or the rule more than once.

What I need now is to make arrangements so that every footballer appears once n matter how many times they have broken the rules.


I have

SELECT
t.transfer_time | ' ' || a.first_name | ' ' || a.last_name | ' ' || f.first_name | ' ' || f.last_name | ' ' || f.footballer_id | ' ' || t.transfer_id
Of
agents a, t transfers, footballers f, footballers_fees fo
WHERE
a.agent_id = t.broker_id
AND
t.footballer_id = f.footballer_id
AND
f.footballer_id = fo.footballer_id
AND
(RULE 1 BROKEN AND RULE 2 BROKEN
OR
RULE 1 BROKEN AND ARTICLE 2 DOES NOT DECOMPOSE
OR
RULE 1 DOES NOT DECOMPOSE AND RULE 2 BROKEN)


GROUP BY
t.transfer_time | ' ' || a.first_name | ' ' || a.last_name | ' ' || f.first_name | ' ' || f.last_name | ' ' || f.footballer_id | ' ' || t.transfer_id
ORDER BY
t.transfer_time | ' ' || a.first_name | ' ' || a.last_name | ' ' || f.first_name | ' ' || f.last_name | ' ' || f.footballer_id | ' ' || t.transfer_id
;



(I did not type the SQL code to rules 1 and 2 but I know it works)

Now, I need not to show that every footballer once they broke rule and more than once or not.

I was looking at the screen nearly enough hours 10 and any help or ideas would be greatly appreciated

Thank you all :)

Hello

Welcome to the forum!

Whenever you have a problem, please post a small example of data (CREATE TABLE and INSERT statements) so that people who want to help you can recreate the problem and test their ideas. You don't have to display a large amount of data. In this case, it seems that 2 to 10 lines for each table could give a good picture of the problem.
After the results that you want samples fropm, and explain how you get those resulting from these data.
Always tell what version of Oracle you are using.

The ideal outcome would be just what you '; Re I get now, but with some deleted rows and only 1 line by left footballer? If so, do a subquery on the original query, and then add somehting like

, ROW_NUMBER () OVER (PARTITION BY f.footballer_id ORDER BY NULL)  AS r_num

in the SELECT clause.
then, in the main query, display only lines

WHERE   r_num  = 1

ROW_NUMBER requires an ORDER byclause of analytics. If you ORDER BY a constant (e.g. NULL) then what line gets number 1 will be arbitrary. If you care who lines for a given player is numbered 1 (and therefore included in the final output), then adjust the analytical ORDER BY clause. (You the title mentions "most recent record only", so if the dt column indicates whether a line is "newer" than another, you can "ORDER BY dt DESC".)

I know this response is vague in places. Without a concrete example (CREATE TABLE and instructions INSERT for examples of data and outcomes from these data), that's the best I can do.

Tags: Database

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    PRIMARY KEY: PID

    PID     Pname    Color
    p1...........          Red
    P2.................    green
    p3...............       blue
    p4 ..................   red
    

    CAT TABLE (SID, PID, COST)
    KEY: SID MAIN + PID
    KEY REFERENCE: SID REFERENCE S.SID
    PID P.PID REFERENCES

    Sid        Pid       COst....
    S1        P1
    S2        P2
    S3        P3
    S1      P4
    S2       p1
    S3        p1
    

    now my question is:
    I want to find the SIDS of suppliers that provide a red and a green part

    for this I used the following query, but it gives the result worng...

    can help me please in this way to get this...

    select sid from cat
    where pid in (select pid from p where color= 'red'
              union
              select pid from p where color = 'gren')
    group by sid having count(pid) >= 2
    

    You don't like what is the number of lines with a pid; If you had 20 rows all said 'p1', that would be good enough. The number of distinct colors of the whole ('red', 'green') is what is important.
    Avoid the UNION when there is a simple alternative. The UNION tends to be slow.

    You can use a join instead, like this:

    SELECT       c.sid
    FROM       cat     c
    ,            p
    WHERE       p.pid          = c.pid
    AND       p.color       IN ('red', 'green')
    GROUP BY  c.sid
    HAVING       COUNT (DISTINCT p.color)     = 2
    ;
    

    If you would care to post CREATE TABLE and INSERT statements for the sample data and the results that you want from this data, then I could test this.

    Published by: Frank Kulash, January 10, 2011 15:25

  • Help with the query to create hourly statistics

    Hello!

    I have an array of jobs. Each task has a start_date and a column end_date. end_date can be null if the job is still running.

    I need to create a query to display the number of jobs running for all hours during the last two weeks.

    A job can run for more than an hour.


    I tried to define what it means for a job during an interval:


    Job.Start_date < = Interval.end AND Job.Finish_date > = Interval.start


    Can help you with this query?


    Thank you!

    Mihai


    Hi, Mihai,

    User810719-Oracle wrote:

    Hello!

    I have an array of jobs. Each task has a start_date and a column end_date. end_date can be null if the job is still running.

    I need to create a query to display the number of jobs running for all hours during the last two weeks.

    A job can run for more than an hour.

    I tried to define what it means for a job during an interval:

    Job.Start_date <= interval.end="" and="" job.finish_date="">= Interval.start...

    You gave essentially the solution yourself.  You just need to outside join your jobs table to a table (or, in the example below, a result set that acts like a table) containing 1 row for each interval.  You can use NVL to equate finish_dates with an effective DATE NULL, so they will be counted:

    WITH intervals AS

    (

    SELECT TRUNC (SYSDATE, 'HH') - ((LEVEL-1)/24) AS interval_start

    , TRUNC (SYSDATE, 'HH') - ((LEVEL-2)/24) AS interval_end

    OF the double

    CONNECT BY LEVEL<= 14="" *="">

    )

    SELECT i.interval_start

    EARL of (j.start_date) AS jobs_running

    Intervals I have

    LEFT OUTER JOIN jobs j WE j.start_date<=>

    AND NVL (j.finish_date

    i.interval_end

    ) > = i.interval_start

    ;

    If you would care to post a small example of data (CREATE TABLE and INSERT statements) and the results desired from this data, I was able to test this.

    Simplify the problem for display.  Do what you are interested only for the past 6 hours, not the last 2 weeks.  We will find a solution that can easily adapt to any number or intervals.

  • Help with the query to return the last possible value

    Can someone please help me to create a query for the situation below?

    Table: TABLEA
    Columns:
    FACID VARCHAR2 (10),
    DEPTID VARCHAR2 (10),
    CHARGENUMBER NUMBER (10)

    I have the following data:

    A, B, 1
    A, B, 2
    C, D, 3
    C, D, 4

    I will return the following:

    A, B, 2
    C, D, 4

    In other words, I would return the last possible CHARGENUMBER for FACID and DEPTID.
    The table has no index, and it is responsible for a worksheet in that order.

    Thank you very much!

    Hello

    If you have a TIMESTAMP column, called entry_dt, you can use a Top - N query like this to find the last x entries.

    WITH  got_rnum  AS
    (
         SELECT  my_table.*
         ,     RANK () OVER (ORDER BY entry_dt DESC)     AS rnum
         FROM     my_table
    )
    SELECT     *     -- or list all columns except rnum
    FROM     got_rnum
    WHERE     rnum     <= x
    ;
    

    It is very common to have a trigger to ensure that columns like entry_dt are met.

    If you have only one statement that inserts with hundreds of lines, they can all have the same entry_dt. (The value of SYSTIMESTAMP is constant throughout a statement, even if it takes a few seconds).
    The above query uses RANK, so if you tell him you want the last 10 entries, it can return more than 10, because it includes all lines with exactly the same entry_dt as the 10th. If you want to exactly 10 rows returned, even if there is a tie for 10th place, then use ROW_NUMBER instead of RANK; the rest of the query is the same.

  • Help with the query GROUP BY?

    Why the habit of this work? When I run the code with the first where clause it works fine.
    select diffrating, count (diffrating) 
    from IT220_HOLIDAYDETAILS
    where diffrating = 'A'
    GROUP BY diffrating
    It returns the result that there is a diffirating marked "A".

    However, when I try to add other clauses he says "no data found"?
    select diffrating, count (diffrating) 
    from IT220_HOLIDAYDETAILS
    where diffrating = 'A'
    and diffrating = 'B'
    and diffrating = 'C'
    and diffrating = 'D'
    and diffrating = 'E'
    GROUP BY diffrating
    How can this be when he came 'A' data in the first place? Surely, it should return 'A' as a negative because it worked before?

    What I want is to count all results for each diffrating and return them. Any reason, why it does not work?

    Thanks in advance!

    It returns nothing because you try to select a diffrating whose value has, b, c, d and e at the same time.

    select diffrating, count (diffrating)
    from IT220_HOLIDAYDETAILS
    GROUP BY diffrating
    

    is not already display what you want?

  • Need help with the query (transpose)

    Hello experts, please help here - 11 g Oracle, attribute APA APB are fixed values and can be hard coded in query

    Need to transpose these data. Max(decode.. perd les données en sortie à cause de la condition de Max.)

    Entry:

    Name | Attribute | Value

    A1 APP 10

    A1 PDB 11

    A1 APA 20

    A1 PDB 21

    A2 BPA 13

    A2 BPB 14

    Expected results:

    Name AttVal1 AttVal2

    A1 10 11

    13 14 A2

    20 21 A1

    Hello

    Here's one way:

    WITH relevant_columns AS

    (

    SELECT name

    value

    CASE

    WHEN the attribute ("APA", "BPA") THEN 1

    WHEN the attribute ("PDB", "BPB") THEN 2

    END AS c_num

    ROW_NUMBER () (PARTITION BY NAME, attirbute

    Value of ORDER BY

    ) AS r_num

    FROM table_x

    )

    SELECT name, attval1, attval2

    OF relevant_columns

    PIVOT (MAX (value)

    FOR c_num IN (1 AS attval1

    2 UNDER attval2

    )

    )

    ORDER BY r_num, name

    ;

    If you would care to post CREATE TABLE and INSERT statements for your sample data, and then I could test this.

    Why do you want to

    NAME ATTVAL1 ATTVAL2

    ----  -------  -------

    A1 10 11

    20 21 A1

    in the results, rather than

    NAME ATTVAL1 ATTVAL2

    ----  -------  -------

    10 21 A1

    20 11-A1

    ?  You would be satisfied to one or the other?

    Depending on your answer, you may need to modify the analytical ORDER BY clause in the ROW_NUMBER function.

  • Need help with the query using the AVG function

    First post here.
    I am a student taking a SQL class and I can't find a query.
    I think I'm close to get it, but I can not quite all the way there.

    Three tables are involved in this problem. Here is a list of the tables and the areas concerned:
    orders table:
      order#
      shipstate
    
    orderitems table:
      order#
      isbn
      quantity         (How many copies of book purchased on that order)
    
    books table:
      isbn
      retail    (retail price of book)
    Problem:
    I want to get an average of "total amount" by shipstate.

    For example, in these tables, there are 8 records of the State of Florida.
    However, there are only 5 unique order # for this State.
    The amount of detail * quantity for these 8 disks (or 5 orders) is $345,10
    Now to get my average $345,10 should be divided by 5. (number of unique commands)
    In the following query it divides this $345,10 8. (number of records)

    How to make this request to divide by the number of unique order # rather than the number of records?
    SELECT shipstate, AVG(quantity * retail)
    FROM orders JOIN orderitems USING (order#)
    JOIN books USING (isbn)
    GROUP BY shipstate
    HAVING SUM(quantity * retail) =ANY
                                  (SELECT SUM(quantity * retail)
                                    FROM books JOIN orderitems USING (isbn)
                                    JOIN orders USING (order#)
                                    GROUP BY shipstate) 
    According to me, once I get this part down, I can understand the rest of the problem.
    The end result, I need, is to find all the individual commands that have a "total amount due" that is greater than the 'average amount due' for this state of clients.

    Any help, suggestions or comments welcome.
    Matt

    Your average take into account the shipstate (8 disks), you can do that for the expected results.
    With some examples of input data it would be easier, but here a try:

    SELECT shipstate, sum(quantity * retail)/count(distinct order#)
    FROM orders JOIN orderitems USING (order#)
    JOIN books USING (isbn)
    GROUP BY shipstate;
    

    Nicolas.

    delete the alias
    Edited by: N. Gasparotto on October 3, 2008 19:28

  • Need help with the query logic

    I have 2 tables.

    Table Tb1:
    THE PLAN_ID PARENT_PLAN_ID ARGUMENT
    Value null P1
    P1 P2
    P3 P2
    P4 P1

    Table tb2:
    THE PLAN_ID ACTIVITY_ID PICKING ARGUMENT
    P2 A1 5000
    P2 A2 5000
    P2 A3 5000
    P3 A1 10000
    P3 A2 10000
    P4 A1 4000


    I need to find the sum of the value of reduction of the workforce for each PLAN_ID which is parent root. In the case above, this is the argument PLAN_ID P1 (WHERE PARENT_PLAN_ID IS NULL). Please note that the value of the downsizing is repeated in the tb2 table. For example, the PLAN_ID P2 argument, the value of the downsizing is 5000 and not 5000 + 5000 + 5000.

    The result of the output for the above data must be
    THE ARGUMENT PLAN_ID DRAWDOWN
    P1 19000

    Published by: user10566312 on October 30, 2012 12:30
    with t as
    (   select t1.plan_id,t1.parent_plan_id,max(t2.DRAWDOWN) DRAWDOWN
        from tb1 t1,tb2 t2
        where t1.plan_id = t2.plan_id(+)
        group by  t1.plan_id,t1.parent_plan_id
    )
    select plan_id,sum(drawdown) drawdown
    from(
          select  connect_by_root plan_id as plan_id,
                  nvl(DRAWDOWN,0) DRAWDOWN
          from t
          start with parent_plan_id is null
          connect by parent_plan_id  = prior plan_id
        )
    group by plan_id  ; 
    
    PLAN_ID DRAWDOWN
    ------- --------
    P1         19000 
    

    Published by: JAC on October 30, 2012 13:23

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