Need help with TS to read the list of variables and/or LV

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  Hi people of Oracle
  
  I use Oracle
  
  Oracle Database 11 g Enterprise Edition Release 11.1.0.7.0 - 64 bit Production
  With partitioning, OLAP, Data Mining and Real Application Testing options
  
  I have a few responses from students and the valid values are + / / (alphabet) o/p and spaces at the end of the scam only not in the middle.
  
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  with x as)
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  SELECT '+-+-9OPPPPPP' STUDENT_RESPONSE, 4 numero_enregistrement FROM DUAL)
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  OR (INSTR (UPPER (TRIM (STUDENT_RESPONSE)), 'P') = 0)
  OR (INSTR (UPPER (TRIM (STUDENT_RESPONSE)),' ')! = 0)
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  Hi, Renon,

  Rb2000rb65 wrote:
  Hi people of Oracle

  I use Oracle

  Oracle Database 11 g Enterprise Edition Release 11.1.0.7.0 - 64 bit Production
  With partitioning, OLAP, Data Mining and Real Application Testing options

  Thanks for posting this (and the WITH clause for sample data). It is very useful.

  I have a few responses from students and the valid values are + / / (alphabet) o/p and spaces at the end of the scam only not in the middle.

  You combine several qeustions responses in a single VARCHAR2 column? It would be better to have a separate line for each question.

  According to my condition, the registration number 2 3.4 must be in the request but I'm alone (chart 3).

  What exactly are your needs? You try to find the rows where the student_response contains one of the forbidden characters, or if it contains a space anywhere, but at the end of the string?

  Can we use REG_EXP

  Yes, but it's pretty easy and probably more effective, do not use regular expressions in this case:
  Here's one way:

  SELECT     record_number
  ,     student_response
  FROM     x
  WHERE     TRANSLATE ( UPPER ( RTRIM (student_response, ' '))
              , 'X+-OP'
              , 'X'
              )     IS NOT NULL
  ;
  

  In other words, once you remove the spaces and all occurrences of '+', '-', 'o' or 'P', then the forbidden characters are left, and you want to select the line, if there is one of these.

  If you really, really want to use a regular expression:

  SELECT     record_number
  ,     student_response
  FROM     x
  WHERE     REGEXP_LIKE ( RTRIM (student_response)
                , '[^-+OP]'          -- or '[^+OP-]', but not '[^+-OP]'.  Discuss amongst yourselves
                , 'i'
                )
  ;
  

  but, again, it will be probably slower than the first solution, using TRANSLATE.

  Published by: Frank Kulash, October 17, 2011 13:05

  Published by: Frank Kulash, October 17, 2011 13:41
  What follows is a bit simpler that TRANSLATE:

  SELECT     record_number
  ,     student_response
  FROM     x
  WHERE     RTRIM ( UPPER ( RTRIM (student_response, ' '))
             , '+-OP'
             )          IS NOT NULL
  ;
  

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  , flag_a varchar2 (1)

  , flag_b varchar2 (1)

  , eff_date varchar2 (8)

  , term_date varchar2 (8)

  );

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  commit;

  Post edited by: user13040446

  It is the closest, I went to the solution
  

  
  

  I create two rows;

  Rnk1: partition by group name, order of eff_date / / desc: this grade will sort the records of the most recent and handed to zero for each group\

  Rnk2: (dense) partition by group name, flag_A, flagb: this grade for each combination of group\flag gives a number so that they are classified as "families".

  Then I use the function analytic min

  Min (eff_date) more (partition of GroupName, rnk2): the idea is that, for each Member of the same family, the new date is the min of the family (and the max for the date of the term), at the end I just need separate so that the duplicates are gone

  Now the problem. As you can see from the query below, records of 1 and 6 (as identified by rownum) are identified in the same family, because they have the same combination of flag, but they are not successive, so everyone must keep its own date of entry into force.

  If only I can make the distinction between these two that would solve my problem

  
  

  Query:

  
  

  Select rowNum,GroupName, flag_a, flag_b, eff_date, term_date, rnk1, rnk2

  , min (eff_date) more than (partition by GroupName rnk2( ) min_eff

  Of

  (

  Select rowNum,

  GroupName , flag_a , flag_b , eff_date , term_date

  rank() more than (partition by GroupName stopped by eff_date desc) rnk1

  DENSE_RANK() more than (partition by GroupName order by flag_A flag_B ( ) rnk2

  de dsreports . tmp_group_test

  ) order by rowNum

  Hello

  user13040446 wrote:

  Hi KSI.

  Thanks for your comments, you were able to distinguish between these lines highlight, but lost lines 2,3,4 which are supposed to have the same date min = 20060101.

  Please see the table wanted to see the final result I want to reach

  Thanks again

  This first answer is basically correct, but in the main query, you want to use the function MIN, not the analytical function aggregation and GROUP BY columns with common values, like this:

  WITH got_output_group AS

  (

  SELECT GroupName, flag_a, flag_b, eff_date, term_date

  ROW_NUMBER () OVER (PARTITION BY GroupName

  ORDER BY eff_date

  )

  -ROW_NUMBER () OVER (PARTITION BY GroupName, flag_a, flag_b)

  ORDER BY eff_date

  ) AS output_group

  OF tmp_group_test

  )

  SELECT GroupName, flag_a, flag_b

  MIN (eff_date) AS eff_date

  MAX (term_date) AS term_date

  OF got_output_group

  GROUP BY GroupName, flag_a, flag_b

  output_group

  ORDER BY GroupName

  eff_date DESC

  ;

  The result I get is

  GROUP_NA F F EFF_DATE TERM_DAT

  -------- - - -------- --------

  Group_A Y 20110101 99991231 Y

  N Group_A 20101231 20060101 N

  Group_A N 20051231 20040101 Y

  Group_A Y Y 20031231-20030101

  Group_B N Y 99991231 20030101

  which is what you asked for.

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