No preference for the report answers option to display all of the results?

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  I have written 3 applications using regular expressions, but I'm not very clear on the outcome. Looking for help to understand the logic.

  Here are the queries:

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  2 > SELECT REGEXP_SUBSTR ('APT-101, BLDG 34, community xyz, XYZ ROAD, BANGALORE - 560066', ' [[: alpha:]] +') ADDR FROM DUAL;

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  Question: My understanding is:

  a > the regular expression [[: alpha:]] + represents one or more continuous occurrences of alphabets.

  b > parenthesis (i.e.) - represents the exact mactch

  c > carrot i.e. ^ represents the negation, that is to say. NOT (xyz)

  I can somehow convince myself that regular expressions - ' ([[: alpha:]] +)' and ' [[: alpha:]] +' in the given scenario may return the same string that is 'APT', but in the last query the regex ([[: alpha:]] + is preceded by ^, which according to my understanding should return something that isn't ONE or MORE CONTINUOUS OCCURRENCE OF ALPHABETS, but even this query is retune "APT".) Ask for help to understand this.

  Thank you

  Amrit Pandey

  
  

  Hi, Amrit,

  ba1fbc36-dd1f-46af-80EE-a9cedf91e344 wrote:

  I have written 3 applications using regular expressions, but I'm not very clear on the outcome. Looking for help to understand the logic.

  Here are the queries:

  1 > SELECT REGEXP_SUBSTR ('APT-101, BLDG 34, community xyz, XYZ ROAD, BANGALORE - 560066', '([[:alpha:]]+)') ADDR FROM DUAL;

  2 > SELECT REGEXP_SUBSTR ('APT-101, BLDG 34, community xyz, XYZ ROAD, BANGALORE - 560066', ' [[: alpha:]] +') ADDR FROM DUAL;

  3 > SELECT REGEXP_SUBSTR ('APT-101, BLDG 34, community xyz, XYZ ROAD, BANGALORE - 560066',(^'[[:alpha:]]+) ') ADDR FROM DUAL;

  All requests above returns the same result, i.e. 'APT '.

  Question: My understanding is:

  a > the regular expression [[: alpha:]] + represents one or more continuous occurrences of alphabets.

  b > parenthesis (i.e.) - represents the exact mactch

  c > carrot i.e. ^ represents the negation, that is to say. NOT (xyz)

  I can somehow convince myself that regular expressions - ' ([[: alpha:]] +)' and ' [[: alpha:]] +' in the given scenario may return the same string that is 'APT', but in the last query the regex ([[: alpha:]] + is preceded by ^, which according to my understanding should return something that isn't ONE or MORE CONTINUOUS OCCURRENCE OF ALPHABETS, but even this query is retune "APT".) Ask for help to understand this.

  Thank you

  Amrit Pandey

  Be careful.  Cut and paste the exact code you run.

  I do not get the same results for alI these queries.  I get an error message ' ORA-00936: missing expression. "for the 3rd.  Maybe you wanted to have the circumflex accent (^) inside the single quotes, like this:

  SELECT REGEXP_SUBSTR (' APT-101, 34 BLDG, community xyz, XYZ ROAD, BANGALORE - 560066' ")

  , ('^ [[: alpha:]] +')

  ) AS addr

  DOUBLE;

  a > you're right;

  [[: alpha:]] +.

  refers to a group of characters 1 or more adjacent, which are all letters of the alphabet.

  b > an expression can almost always be enclosed in parentheses free.  In other words, almost anywhere, you can use an expression

  x you can also use

  (x)               or

  ((x))                  or

  (((x))) and so on.  Each of them the same meaning.

  This has nothing to do with regular expressions.

  In expressions regular, curved brackets can be used for the Backreferences, for example \1 can be used to return to exactly what corresponded to the subexpression inside the 1st pair of parentheses.  You are not using anything like \1 here, so this backreferences do not apply to this question.

  c > sign means negation only when it comes immediately after [.]  For example

  SELECT REGEXP_SUBSTR (' APT-101, 34 BLDG, community xyz, XYZ ROAD, BANGALORE - 560066' ")

  ", ' [^ [: alpha:]] +"

  ) AS addr

  DOUBLE;

  product

  ADDR

  ------

  -101,

  in other words, the characters 1 or more consecutive which are NOT letters of the alphabet.

  Outside square brackets, the circumflex accent means the beginning of the string.

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