Not a group by expression error

Similar Questions

• Listagg function gives ORA-00979: not a GROUP BY expression error

  Hello

  I have an environment that supports the Listagg function. Suite works perfectly:

  Select task_code, LISTAGG(ename||) e ('| role |') (',',') WITHIN GROUP (ORDER BY ename) as employees

  team

  where task_code = '01.07.05'

  Task_code group

  However, this is just a test request, the real is a little wider and I can't get the function works, I get ORA-00979: not a GROUP BY expression error.

  Here's my query (the column names are in Dutch, but that shouldn't really be a problem):

  SELECT distinct op_sod.sod_code, op_sod.sod_omschr_lang, op_ood.ood_code, op_ood.ood_omschr_lang, op_activiteit.act_code, op_activiteit.act_omschr_lang, op_taak.taak_code, op_taak.taak_omschr_lang, op_afdeling___master.afd_code, op_taak.belmo, op_taak_j.planning_la,

  LISTAGG (op_ploeg.wn_naam |) ' ('| op_ploeg.rol |') (',',') WITHIN GROUP (ORDER BY op_ploeg.wn_naam) as employees.

  "Write subtaak/mijlpaal toe."

  op_teamplanning.subtaak_mijlpaal as subtaak_of_mijlpaal,

  op_teamplanning.subtaak_omschr | -case when op_teamplanning.subtaak_mijlpaal = 'BELMO Mijlpaal' then ' (BRUNO mijlpaalnr: ' | nvl (op_teamplanning.nummer, 0) |) ')' other ' ' end

  as subtaak_mijlpaal_omschrijving, op_teamplanning.deadline as date limit, op_teamplanning.status as status,

  trim (both

  case when op_teamplanning.vlag1 = 'Geen' and op_teamplanning.vlag2 = 'Geen' and op_teamplanning.vlag3 = 'Geen' and op_teamplanning.vlag4 = 'Geen'

  and op_teamplanning.vlag5 = 'Geen' or op_teamplanning.vlag1 is null and op_teamplanning.vlag2 is null and op_teamplanning.vlag3 is null

  op_teamplanning.vlag5 is null and op_teamplanning.vlag4 is null then 'Geen '.

  Another pad (both case when op_teamplanning.vlag1 = 'Geen' then "else trim (both from op_teamplanning.vlag1) end) |

  trim (both case when op_teamplanning.vlag2 = 'Geen' then "another ',' | trim (both from op_teamplanning.vlag2) end) |

  trim (both case when op_teamplanning.vlag3 = 'Geen' then "another ',' | trim (both from op_teamplanning.vlag3) end) |

  trim (both case when op_teamplanning.vlag4 = 'Geen' then "another ',' | trim (both from op_teamplanning.vlag4) end) |

  trim (both case when op_teamplanning.vlag5 = 'Geen' then "another ',' | trim (both from op_teamplanning.vlag5) end) end) as Beleidsvlaggen,

  op_teamplanning.naam_verantw as quotation, op_teamplanning.subtaak_id as subtaak_id, nvl (op_teamplanning.nummer, 0) as Nummer, nvl (op_teamplanning.regelgevingsagenda, 'Nee') as

  Regelgeving, op_teamplan_subsubtaak.subsubtaak_submijlpaal as subsubtaak_submijlpaal, op_teamplan_subsubtaak.subsubtaak_id as subsubtaak_id, op_teamplan_subsubtaak.subsubtaak_omschr

  like subsubtaak_omschr, op_teamplan_subsubtaak.deadline, sub_deadline, op_teamplan_subsubtaak.status as sub_status, op_teamplan_subsubtaak.naam_verantw as naam_verantw

  Of...

  WHERE THE...

  Group of op_sod.sod_code, op_sod.sod_omschr_lang, op_ood.ood_code, op_ood.ood_omschr_lang, op_activiteit.act_code, op_activiteit.act_omschr_lang, op_taak.taak_code, op_taak.taak_omschr_lang, op_afdeling___master.afd_code, op_taak.belmo, op_taak_j.planning_la

  
  

  Can someone tell me the reason for this error?

  Thanks in advance!

  Kind regards

  NDG

  NDG123 wrote:

  I don't really understand your other question:

  Is below for example, a group of expression?

  op_teamplanning.subtaak_mijlpaal

  After some additional research:

  The group by mistake is not appear anymore when I delete all fields after the listagg field, that might be a clue to the solution.

  It is not difficult to understand. You can have other columns not aggregated in your projection on the side of those listed in the group by expression.

  The reason for ORA-01489 is that the resulting string will become long and exceeds 4000 bytes.

  You will find several solution in this forum.

  For example

  Re: Listagg function excdding 4000 characters

• Subquery in the select clause and not "a group by expression" error.

  Hi all
  I hope someone out there can help me out with this one. I have a sql query that performs a subquery in the select case combined with an aggregate function and gives me a "not a group by expression.
  
  I created a simplified example

   SELECT COUNT(*)                     ,
    ai.invoice_num invoice_number      ,
    ai.description invoice_description ,
    (SELECT poh.po_header_id
         FROM po_headers poh ,
        po_distributions pod
        WHERE pod.po_distribution_id = aid.po_distribution_id
      AND pod.po_header_id           = poh.po_header_id
      ) po_number
       FROM ap_invoice_distributions aid ,
      ap_invoices ai
      WHERE ai.invoice_id = 1476932
    AND aid.project_id    = 8608   
    AND aid.task_id       = 462202  
    AND ai.invoice_id     = aid.invoice_id
   GROUP BY ai.invoice_num,
                  ai.description;

  I'm sure he expected me to add the po_number to the group by clause, but this does not work and gives the error "invalid identifier".
  
  Can someone suggest a way for a new concert the query so that I can add po_number to my education by clause.
  
  Kris

  You should try either:

  SELECT COUNT (*),
  AI.invoice_num invoice_number,
  have. Description invoice_description,
  (SELECT poh.po_header_id
  OF po_headers poh,.
  pod po_distributions
  WHERE pod.po_distribution_id = aid.po_distribution_id
  AND pod.po_header_id = poh.po_header_id
  ) po_number
  HELP ap_invoice_distributions.
  ap_invoices AI
  WHERE ai.invoice_id = 1476932
  AND aid.project_id = 8608
  AND aid.task_id = 462202
  AND ai.invoice_id = aid.invoice_id
  Ai.invoice_num GROUP,
  have. Description, aid.po_distribution_id;

  or

  SELECT COUNT (*),
  AI.invoice_num invoice_number,
  have. Description invoice_description,
  MAX ((SELECT poh.po_header_id
  OF po_headers poh,.
  pod po_distributions
  WHERE pod.po_distribution_id = aid.po_distribution_id
  AND pod.po_header_id = poh.po_header_id
  po_number))
  HELP ap_invoice_distributions.
  ap_invoices AI
  WHERE ai.invoice_id = 1476932
  AND aid.project_id = 8608
  AND aid.task_id = 462202
  AND ai.invoice_id = aid.invoice_id
  Ai.invoice_num GROUP,
  have. Description;

• ORA-00979: not a GROUP BY expression error

  Hi all
  
  I added a GROUP BY clause that includes all expressions of individual column listed.
  I don't know why this error occurs. ?
  How could I solve this problem?
  
  
  

  SELECT site_to_data_source_lane_v.site_id,  
          site_to_data_source_lane_v.site_lane_id,
          traffic_record.record_id,
          traffic_record.datetime,
          NVL(traffic_class.v_class, 0),
          NVL(SUM(traffic_status.status_code), 0) vehicle_status_count,  
          NVL(COUNT(traffic_error.error_code), 0)  vehicle_error_count ,
          NVL(site_to_data_source_lane_v.site_lane_id, 0) ,
          NVL(traffic_status.status_code, 0),
          NVL(traffic_error.error_code, 0)
      FROM traffic_record
      LEFT OUTER JOIN traffic_class
        ON traffic_record.record_id = traffic_class.record_id    
      LEFT OUTER JOIN traffic_error
        ON traffic_record.record_id =traffic_error.record_id              
      LEFT OUTER JOIN traffic_status
        ON traffic_record.record_id =traffic_status.record_id         
      JOIN site_to_data_source_lane_v
        ON traffic_record.data_source_id = site_to_data_source_lane_v.data_source_id
       AND traffic_record.lane = site_to_data_source_lane_v.data_source_lane_id
      JOIN edr_rpt_tmp_report_lanes
        ON site_to_data_source_lane_v.site_lane_id = edr_rpt_tmp_report_lanes.site_lane_id
      JOIN edr_rpt_tmp_report_classes
        ON NVL(traffic_class.v_class, 0) = edr_rpt_tmp_report_classes.class_id
      JOIN edr_rpt_tmp_inclusion_table
        ON TRUNC(traffic_record.datetime) = TRUNC(edr_rpt_tmp_inclusion_table.date_time)
     WHERE site_to_data_source_lane_v.site_id = 32
       AND traffic_record.datetime >= to_timestamp('07/01/2008 00:00:00', 'mm/dd/yyyy hh24:mi:ss')
       AND traffic_record.datetime <  to_timestamp('07/31/2008 00:00:00', 'mm/dd/yyyy hh24:mi:ss') 
       GROUP BY site_id,                        
                            site_lane_id,
                            record_id,
                            date_time,
                            v_class,                
                            status_code,
                error_code;
                

  You choose: -.

  site_to_data_source_lane_v.Site_ID,
  site_to_data_source_lane_v.site_lane_id,
  traffic_record.record_id,
  traffic_record. DateTime,
  NVL (traffic_class.v_class, 0),
  NVL (Sum (traffic_status.status_code), 0) vehicle_status_count,
  NVL (Count (traffic_error. (Error_code), 0) vehicle_error_count,
  NVL (site_to_data_source_lane_v.site_lane_id, 0),
  NVL (traffic_status.status_code, 0),
  NVL (traffic_error.error_code, 0)

  But you are a grouping by

  Site_ID,
  site_lane_id,
  record_id,
  Date_Time,
  v_class,
  status_code,
  Error_code

  Quite a few differences...

• error: not a GROUP BY expression

  Hello world
  
  Looks like I need some help here... :) don't know what that means, but im getting this message
  00979 00000 - "not a GROUP BY expression"
  * Cause:
  * Action:
  Error on line: column 137: 36
  
  It's the function:
  
  function get_path (materialID in number, materialTypeID number, inTopFolderID number default null, inMaterialFolderID in the number default null, webMode in default number 1 in)
  return varchar2;
  
  
  and im using it on my query
  
  , (select material_util.get_path (m.material_id, 8, 1021695, min (mf.)) (IP_MATERIALFOLDERID), 1).
  material m, materialfolder mf
  where mf.nfx_link = m.MATERIAL_ID
  and t.template_id = m.template_id) as path
  
  It seems that min (mf. IP_MATERIALFOLDERID) is having some problems here... don't know why...
  
  Let me know guys...
  
  Thank you...
  
  J

  Read below for informative post from Frank Kulash on ABC in the group by clause
  {message: id = 9969583}

• SQL - ORA-00979: not a GROUP BY expression

  Hi Expert,
  
  I received the error message: ORA-00979: not a GROUP BY expression at the bottom of the sql statement
  
  Please advise - display total number of point of sale and the total amount of all items. Only display results when the total quantity is greater than 2.
  
  SELECT o.Qty, sum(o.Qty*o.salesprice) AS TOTALDOLLARS, description and i.Itemcode
  OF ORDERLINE o
  INNER JOIN POINT I
  ON o.itemcode = i.itemcode
  GROUP BY i.Itemcode
  After having o.qty > 2
  
  > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > >
  
  Create table ORDERLINE
  (
  Qty number 4,
  Salesprice Number (6.2),
  OrderNo Number (3).
  ItemCode Varchar2 (6).
  Primary key (OrderNo, Itemcode)
  Foreign Key (Itemcode) refers to POINT.
  Foreign Key (OrderNo) made reference SALESORDER
  
  
  Create table POINT
  (
  ItemCode Varchar2 (6).
  Description Varchar2 (50).
  Retailprice Number (6.2),
  Number of weight (4.1),
  Purchaseprice Number (6.2),
  Category Varchar2 (20).
  Primary Key (Itemcode)
  );

  Hi 845720,

  Based on the sql code, the sum must be grouped itemcodewise, descriptionwise, qtywise.
  This means that you have all these in a group by clause too with sum().

  eg : group by  i.Itemcode, i.Description, o.Qty
  

  Is this wise sum qty is logical? I do not know...

  It will be useful,
  CKLP

  Published by: CKLP April 14, 2011 22:10

• Not a group by Expression

  I have the following table AR_Complex

  Country_code	Country	Complex_Amt	Child_Amt
  CC_1	CC	5000	1000
  CC_1	CC		1000
  CC_1	CC		2000
  CC_1	CC		1000
  US_2	WE	3000	1000
  US_2	WE		500
  US_2	WE		200
  US_2	WE		100

  I wrote the following query

  Select * from (select Country_code, sum (Complex_Amt), sum (Child_Amt), (sum (Complex_Amt) - sum (Child_Amt)) as a Diff of AR_Complex

  Country_code group)

  where Diff > 1

  which works very well.

  How can I get the Country column in the query because when I adds the Country column it does not appear a group by EXPRESSION.

  I think you want:

  Select * from (select Country_code, country, sum (Complex_Amt), sum (Child_Amt), (sum (Complex_Amt) - sum (Child_Amt)) as a Diff of AR_Complex

  Country_code group, country)

  where Diff > 1

• Not a GROUP BY clause error

  Hi all
  
  Can someone tell me what is wrong with the query below? I get an exception is NOT a GROUP OF CLAUSE:
  

  SELECT
          LAST_DAY((xxx.timevalue)) as  SUMMARYDATE
        , xxx.acct AS ACCTNUM
        , xxx.referenceid AS SEARCHTYPE
         , CASE WHEN NVL(xxx.PRIMARYSRCH_IND,'N') = 'Y' THEN COUNT(xxx.searchid) ELSE 0 END  Cnt_PrimarySearches
                 , CASE WHEN NVL(xxx.primarysrch_ind,'N') = 'N' THEN COUNT(xxx.Searchid) ELSE 0 END  Cnt_SecondarySearches
       
        FROM XXX_Tablename xxx
        WHERE
         xxx.referenceid NOT IN ('Alert','Search','Collection')
        GROUP BY
    LAST_DAY((xxx.timevalue))  
    , xxx.acctnum
    , xxx.referenceid 

  Hello

  Try this

  SELECT
          LAST_DAY((xxx.timevalue)) as  SUMMARYDATE
        , xxx.acct AS ACCTNUM
        , xxx.referenceid AS SEARCHTYPE
         ,COUNT( CASE WHEN NVL(xxx.PRIMARYSRCH_IND,'N') = 'Y' THEN (xxx.searchid) ELSE 0 END  Cnt_PrimarySearches)
                 , COUNT(CASE WHEN NVL(xxx.primarysrch_ind,'N') = 'N' THEN (xxx.Searchid) ELSE 0 END) Cnt_SecondarySearches
  
        FROM XXX_Tablename xxx
        WHERE
         xxx.referenceid NOT IN ('Alert','Search','Collection')
        GROUP BY
    LAST_DAY((xxx.timevalue))
    , xxx.acctnum
    , xxx.referenceid
  

  Not tested

• ORA-00979: not a GROUP BY expression

  Hello

  And if you want to include aggregate functions, you must make sure of all the other columns are included in the group by clause...

  SELECT THE CAG. SystemId,
  CAG. BankId,
  CR. ClearingNumber,
  CAG. AgreementId,
  CAs.timestampchanged AS ApprovedLGDDate,
  LGD. ApprovedLGDValue,
  CASE. ModelId,
  CASE. ModelVersion,
  CAG. CaseId,
  CASE. Creator,
  BOX WHEN CAG. SystemId = 'ASK' THEN CAG. SystemidProduct
  ANOTHER NULL
  END as SystemidProd,
  BOX WHEN CAG. SystemId = 'REQUEST' AND CAG.agreementid LIKE ' %: % ' THEN
  To_char (TO_NUMBER (SUBSTR (CAG.agreementid, INSTR (CAG.agreementid, ' :') + 1), "xxxxxxxxxxxxxxx")))
  WHEN CAG. SystemId = 'REQUEST' AND CAG.agreementid NOT LIKE ' %: % ' THEN
  CAG.agreementid
  ANOTHER NULL
  END as AgreementidUNP,
  case. DecisionDate
  OF CAG CustomerAgreement
  JOIN CreditLGD LGD ON (CAG. SystemId = LGD. SystemId
  AND CAG. BankId = LGD. BankId
  AND CAG. AgreementId = LGD. AgreementId
  AND CAG. AgreementSubId = LGD. AgreementSubId
  AND CAG. CaseId = LGD. CaseId
  )
  Credit to JOIN CR ON (CAG. SystemId = CR. SystemId
  AND CAG. BankId = CR. BankId
  AND CAG. AgreementId = CR. AgreementId
  AND CAG. AgreementSubId = CR. AgreementSubId
  AND CAG. CaseId = CR. CaseId
  )
  NO. CASE CASE OF JOIN ON (CAG. BankId = CASE. BankId
  AND CAG. CaseId = CASE. CaseId
  AND THE AC. State = 'approved '.
  )
  JOIN CU customer ON (CU.bankid = CAS.bankid
  AND CU.latestapprovedcaseid = CAS.caseid
  AND CU.customerid = CR.customerid
  )
  WHERE CAG. SYSTEMID IN ("ACC", "APL", "GOF", "GRK", "HPD", "KRF", "LIM", "PRO", "SPI", "SPS", "ASK")
  CAG group. SystemId
  CAG. BankId
  CR. ClearingNumber
  CAG. AgreementId
  cas.timestampchanged
  LGD. ApprovedLGDValue
  CASE. ModelId
  CASE. ModelVersion
  CAG. CaseId
  CASE. Creator
  CASE WHEN CAG. SystemId = 'ASK' THEN CAG. SystemidProduct
  ANOTHER NULL
  END
  CASE WHEN CAG. SystemId = 'REQUEST' AND CAG.agreementid LIKE ' %: % ' THEN
  To_char (TO_NUMBER (SUBSTR (CAG.agreementid, INSTR (CAG.agreementid, ' :') + 1), "xxxxxxxxxxxxxxx")))
  WHEN CAG. SystemId = 'REQUEST' AND CAG.agreementid NOT LIKE ' %: % ' THEN
  CAG.agreementid
  ANOTHER NULL
  END
  cas.decisiondate

• SQL error: ORA-00979: not a GROUP BY

  Hi team,

  I am trying to execute the query

  SELECT DISTINCT comp.company_name |' -' || COMP.contract_number AS 'company_name '.

  , UPPER (bh.first_name) AS 'budget_holder '.

  , INITCAP (sup.first_name) |' -' || SUP. Surname AS 'supervisor '.

  , INITCAP (emp.status) AS "Department".

  , INITCAP (emp.first_name |) » '|| EMP. Surname) AS "employee."

  r.employee_id

  , emp.paaf_number AS 'paaf_num '.

  , emp.employee_payroll_number AS 'payroll_num '.

  , emp.discipline AS 'discipline '.

  , NVL (SUM (tg.week_day1), 0) AS "day 1".

  , NVL (SUM (tg.week_day2), 0) AS "day 2".

  , NVL (SUM (tg.week_day3), 0) AS day '3 '.

  , NVL (SUM (tg.week_day4), 0) AS "day4.

  , NVL (SUM (tg.week_day5), 0) AS "day5".

  , NVL (SUM (tg.week_day6), 0) AS "day6.

  , NVL (SUM (tg.week_day7), 0) AS "day 7".

  r.valid_from

  r.valid_to

  Tw_roster_data r

  JOIN tw_employee emp

  ON emp.employee_id = r.employee_id

  JOIN tg tw_timesheet_stage

  ON tg.employee_id = r.employee_id

  AND tg.week_commencing = r.valid_from

  JOIN the tw_contracting_company comp

  ON comp.contracting_company_id = r.contracting_company_id

  JOIN tw_supervisor sup

  ON sup.supervisor_id = tg.supervisor_id

  JOIN tw_budget_holder bh

  ON bh.budget_holder_id = sup.budget_holder_id

  WHERE r.contracting_company_id = 101

  AND r.VALID_FROM = January 31, 2015.

  AND r.VALID_TO = February 6, 2015"

  Group of r.employee_id, comp.company_name, bh.first_name,

  EMP.paaf_number, emp.employee_payroll_number, emp.discipline,

  r.valid_from, r.valid_to;

  But still the error below

  Error in the command line: 1 column: 17

  Error report-

  SQL error: ORA-00979: not a GROUP BY expression

  00979 00000 - "not a GROUP BY expression"

  Can help.

  Hello

  When to use analytical function oracle other columns used based on the analysis, must be included in the GROUP BY Clause

  SELECT expression1, expression2, ... expression_n,
    aggregate_function (expression)
  FROM tables
  WHERE conditions
  GROUP BY expression1, expression2, ... expression_n;
  

  SQL 101: Seen are medium and other aggregate data

    SELECT DISTINCT
           comp.company_name || ' - ' || comp.contract_number AS "company_name",
           UPPER (bh.first_name) AS "budget_holder",
           INITCAP (sup.first_name) || ' - ' || sup.surname AS "supervisor",
           INITCAP (emp.status) AS "department",
           INITCAP (emp.first_name || ' ' || emp.surname) AS "employee",
           r.employee_id,
           emp.paaf_number AS "paaf_num",
           emp.employee_payroll_number AS "payroll_num",
           emp.discipline AS "discipline",
           NVL (SUM (tg.week_day1), 0) AS "day1",
           NVL (SUM (tg.week_day2), 0) AS "day2",
           NVL (SUM (tg.week_day3), 0) AS "day3",
           NVL (SUM (tg.week_day4), 0) AS "day4",
           NVL (SUM (tg.week_day5), 0) AS "day5",
           NVL (SUM (tg.week_day6), 0) AS "day6",
           NVL (SUM (tg.week_day7), 0) AS "day7",
           r.valid_from,
           r.valid_to
      FROM tw_roster_data r
           JOIN tw_employee emp
              ON emp.employee_id = r.employee_id
           JOIN tw_timesheet_stage tg
              ON tg.employee_id = r.employee_id
                 AND tg.week_commencing = r.valid_from
           JOIN tw_contracting_company comp
              ON comp.contracting_company_id = r.contracting_company_id
           JOIN tw_supervisor sup
              ON sup.supervisor_id = tg.supervisor_id
           JOIN tw_budget_holder bh
              ON bh.budget_holder_id = sup.budget_holder_id
     WHERE     r.contracting_company_id = 101
           AND r.VALID_FROM = '31-JAN-2015'
           AND r.VALID_TO = '06-FEB-2015'
  GROUP BY
  comp.contract_number
  ,comp.company_name
  ,bh.first_name
  ,sup.first_name
  ,sup.surname
  , emp.status
  ,emp.first_name
  ,emp.surname
  r.employee_id,
  emp.paaf_number,
  emp.employee_payroll_number,
  emp.discipline,
   r.valid_from,
   r.valid_to;
  

• Not able to receive e-mail messages in Outlook Express, error number: 0x800CCC92

  original title: outlook express error

  Since yesterday I have been unable to receive emails via outlook express. He constantly asks me for a password that we have never had to put forward that she "remembers" the password. If you get rid of the box it then comes up with the following msg

  There was a problem connecting to your e-mail server. Your password was rejected. Account: 'pop3', server: 'pop3.ntlworld.com', Protocol: POP3, server response: '-ERR [AUTH] username and password not accepted.', Port: 110, secure (SSL): no, Server error: 0x800CCC90, error number: 0x800CCC92
  I can send but not receive emails, have tried a system restore which initially solved the problem, but almost immediately the problem has re-emerged... any help gratefully received... I've tried everything I know, but can not solve the problem. Thank you

  See if you can log in to read your mail on the site NTLWorld. If he accepts the password, you may need to reset your password.

• in Outlook Express, how can I send the same message to a group important (in the address book already), but have to each recipient can only see his name (not the Group)

  In Outlook Express, how can I send the same message to the large group (already in the address book), but have to each recipient can only see his name (not the Group)?

  To use the functionality of the BCC (Blind Carbon Copy), in a new message window, click View | All headers and type the addresses separated by a; Or: Click the button to. You will see your list of contacts and the choice to put them in the To, CC, or BCC field. Click on an address, and then click BCC to add it. Repeat for all of the contacts you want. (Note: most of the providers have limits as to how many messages you can send both a. 25 is common, but it varies).

  Put your own address in the box to. That's the only name/address that any recipient will see. If you leave the field empty, some people may not receive e-mail because of message rules they put in place, or restrictions imposed by their ISP.

  You can also make an entry in the address book using your e-mail address, but put something like the mailing list in the area of the display.

  *********************

  You can also create groups if you send e-mail to the same people often.

  To create a group of contacts:

  You can create a single group name (or alias) to use when sending a message to several contacts at the same time. Just create a group name and add individual contacts to the group. Then just type the name of the group in the box for when you send mail.

  1. in the address book, select the folder in which you want to create a group. Click New in the toolbar, and then click New Group.
  2. the Properties dialog box opens. In the group name box, type the name of the group.
  3. There are several ways to add people to the Group:
  a. to add a person from your address book list, click Select members, and then click a name in the address book list.
  (b) to add a person directly to the group without adding the name to your address book, type the person's name and e-mail address at the bottom of the Properties dialog box and then click Add.
  to add a person to both the Group and your address book, click New Contact and enter the appropriate information.
  (d) to use a directory service, click Select members, and then click search. Select a directory service in the drop-down list at the end of the text box. After finding and selecting an address, it is automatically added to your address book.
  4. Repeat for each addition until your group is defined.

  Note

  a. to view a list of your groups separately from the list of address book in the address book on the view menu, make sure that folders and groups is selected.
   
  b. you can create multiple groups, and contacts can belong to several groups.

  If you want to send to a group without addresses are displayed for each recipient, open the address book and make a new entry. Enter the name of the group in the area of the display, but use your address. (Some Internet service providers require a legitimate address in the line to and recipients will know it's from the Group).

  Click on the button to. Enter the name of the group using your address. Enter the group in the BCC field.

• Expression error: object named: javax.faces.convert.IntegerConverter not fo

  I get the below error when I try to run the xhtml file.
  Can I find out how to import the "IntegerConvertor"?
  >
  Expression error: object named: javax.faces.convert.IntegerConverter not found.
  >
  

  <?xml version='1.0' encoding='UTF-8' ?>
  <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
  <html xmlns="http://www.w3.org/1999/xhtml"     xmlns:h="http://java.sun.com/jsf/html"     xmlns:f="http://java.sun.com/jsf/core">
  <h:head>
       <title>Facelet Title</title>
  </h:head>
  
  <h:body>
  
  <h:inputText converter="javax.faces.convert.IntegerConverter" />
  
  
  </h:body>
  
  </html>

  Edited by: anIdiot December 12, 2011 23:52

• Tecra M9 - PCI Express Error at startup

  Hello everyone...

  I have a Toshiba Tecra M9 (PTM91E-04R03TEN)

  http://www.Toshiba.IE/innovation/JSP/supportMyProduct.do?service=IE#TAB0;

  Setting in motion,-wristwatch splach Toshiba and then "PCI Express error." screen on a black screen
  I can't get beyond this black screen
  and I can't get into the BIOS?

  Once that he managed to start completely, let him turn for a while I record information from the HARD drive. but then, the problem started again.

  In my view, that it is a problem with the nvidia GPU (in cycle Fatigue on the BGA) card
  I have the stripted computer laptop down... and bought ArctiClean thermal Pad, & Arctic Silver for "repair".

  Should I have someone analyze the material and find the troublemaker?... OR... should I just of reflow of the GPU.

  I'm technical interest... but not a PC / laptop technician: (..)
  any instructions on how to proceed would be received with gratitude...
  Can I just "bung it in the oven" and see how it goes? :) :) .

  Kind regards
  Peter

  Hello

  I found and read your other post regarding this problem and in my opinion the PCI Express error is related to a PCI device (i.e miniPCI module as WLan / Bluetooth, etc.) connected to the motherboard.

  Of course I can't say for certain that this question isn't related to a GPU malfunction.
  Usually, these details can be provided only by a technician who checked the laptop's hardware.

  Usually I put t recommend to disassemble the laptop. It s very difficult to perform this procedure and of course there is always a risk of damage part do such procedure without any instructions.

• Qosmio G40 - 10F won't boot up - PCI Express error

  I recently installed a windows update and the laptop came in restart mode.
  When the system boots it tries to start then I get a say black screen error PCI Express.

  I tried a system restore, but the disc does not start, also tried to access the bios and it does not work.

  Can I please ask for more help on this one because I don't have any problems at all, everything seems that a windows update has messed with my config in the bios.

  Help, please!

  Hello

  I can't believe that Windows update would affect the BIOS.

  In my opinion, this must be just bad luck.

  PCI Express error means generally that a PCI device on the motherboard has started to malfunction.

  This means that it could be a motherboard problem that could be solved by replacing the mobo

  Sorry man, but I think that you don't have a lot of options here... seems that Toshiba ASP technician should take a look at this question :(