Notice: Undefined index:
I have that works well on another site and have replicated just it but on this site, it does not work, anyone can see what I'm doing wrong?
I'm having an error come on my page success.php when returning to a paypal payment...
Notice: Undefined index: in E:\Domains\b\website.com\user\htdocs\success.php on line 248 OrderID
Basically when the transaction is successful the return page is return.php, this page tells
<? PHP
session_start();
$colname_rsReturn = "-1";
If (isset($_SESSION['OrderID'])) {}
$colname_rsReturn = $_SESSION ["OrderID"];
}
@mysql_select_db ($database_beau, $beau);
$query_rsReturn = sprintf ("SELECT filled WITH beauSS13_orders WHERE the beauSS13_orders.") (OrderID = %s", GetSQLValueString ($colname_rsReturn,"int"));
$rsReturn = mysql_query ($query_rsReturn, $beau) or die (mysql_error ());
$row_rsReturn = mysql_fetch_assoc ($rsReturn);
$totalRows_rsReturn = mysql_num_rows ($rsReturn);
If ($row_rsReturn ['fill'] == 1) {}
Header ("' Location: success.php '");
} another header ("' rental: order.php failed '");
? >
so the value of the order is 1 then it send to success.php to update the stock as follows
<? PHP
Update the stock *.
$details_table = "beauSS13_orderdetails";
$ID_column = "OrderID";
$details_prodID = "ProductID";
$details_qty = "amount";
$XStock_TableName = "beauSS13_products";
$XStock_FieldName = "stock";
$XStock_unID = "ProductID";
If (! session_id()) session_start();
If (isset($_SESSION["OrderID"])) {}
@mysql_select_db ($database_beau, $beau);
$details_Source = "select * from". $details_table. 'where '. $ID_column. " = " . $_SESSION ["OrderID"];
$detailsRS = mysql_query ($details_Source, $beau) or die (mysql_error ());
$row_detailsRS = mysql_fetch_assoc ($detailsRS);
{}
$XStock_qtySource = "select". $XStock_FieldName. "from". $XStock_TableName. 'where '. $XStock_unID. " = " . $row_detailsRS [$details_prodID]. "";
$XStock_rsUpd = mysql_query ($XStock_qtySource, $beau) or die (mysql_error ());
$row_XStock_rsUpd = mysql_fetch_assoc ($XStock_rsUpd);
If ($row_XStock_rsUpd [$XStock_FieldName] > 0) {}
$XStock_new = $row_XStock_rsUpd [$XStock_FieldName] - $row_detailsRS [$details_qty];
If ($XStock_new < 0) $XStock_new = 0;
$XStock_UpdSource = "update". $XStock_TableName. 'together '. $XStock_FieldName. " = " . $XStock_new. 'where '. $XStock_unID. " = " . $row_detailsRS [$details_prodID]. "";
$XStock_rsUpd = mysql_query ($XStock_UpdSource, $beau) or die (mysql_error ());
}
} While ($row_detailsRS = mysql_fetch_assoc ($detailsRS));
$XStock_rsUpd = null;
$detailsRS = null;
session_unregister ("OrderID");
}
? >
but when I get to this page, I get the error
Notice: Undefined index: in E:\Domains\b\website.com\user\htdocs\success.php on line 248 OrderID
and the stock is not updated
line 248 is order < p > <? PHP echo $_SESSION ["OrderID"];? > success < br / >
then he tells me that the session is not respected on the whole?
It is not clear from your code where line 248, but the last line of code you posted here using this:
session_unregister ("OrderID");
This destroys $_SESSION ["OrderID"]. Thus, if line 248 comes after this code, that would explain why you get notice of undefined index.
Furthermore, session_unregister() is obsolete and has been removed from PHP 5.4. You must use unset() instead:
unset($_SESSION['OrderID']);
Tags: Dreamweaver
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I received the same error message on the next section of code;
<? PHP
include("includes/DB.php");
include("includes/functions.php");
If ($_REQUEST ['command'] == 'delete' & & $_REQUEST ['pid'] > 0) <-Undefined index:
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of other if($_REQUEST['command']=='clear') <-Undefined index:
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? >
I'm not getting syntax errors, can enyone help please?
Moved to applications developed in Dreamweaver forum server-side.
Undefined index means that there is no such thing as a table variable. In each case, the error occurs on a line where you test the value of $_REQUEST ['command']. What this means is that 'order' is not sent to the page via a query (GET method) string or through the POST.
It is strongly discouraged to use $_REQUEST. The PHP online documentation contains this warning: "variables $_REQUEST are provided to the script via the GET, POST, and COOKIE input mechanisms and therefore can be modified by the remote user and cannot be trusted." You must specify the input mechanism you expect ($_GET or $_POST).
I see that you also use $_SESSION. This will not work unless your script starts with session_start().
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}It would be useful that you stated what was on line 64, rather than waiting for others to looking for a needle in a haystack.
However, I suspect that the problem is on this line:
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You initialize $i as 1, but PHP arrays start at 0. There are probably 22 items in the array $_POST ["jobpriority"], but article 22 is not shifted 22, but offset 21.
Furthermore, the code in your original hidden field was meaningless. To insert the $_POST ["jobpriority"] in the value attribute, you must use the echo. It should be:
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