NULL values in service management LESS

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  Mr President

  My worm jdev is 12.2.1

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• management of NULL values in a statement PIVOT 11 g

  Hi all
  
  In the following code, how can I get the cell showing 80001_sum_sales for employee 234567 as a zero instead of a NULL value?
  

  with t1 as 
  (
   select 123456 as emp_id, 80000 as category, 10 as sales from dual union all 
   select 123456 as emp_id, 80001 as category, 20 as sales from dual union all
   select 234567 as emp_id, 80000 as category, 10 as sales from dual 
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  I tried NVL in various parts of the application, but the problem is that the line does not actually exist to apply the NVL to. I also tried to add another level of subquery factoring to wrap each column in an NVL, something like:
  

  with t1 as 
  (
   select 123456 as emp_id, 80000 as category, 10 as sales from dual union all 
   select 123456 as emp_id, 80001 as category, 20 as sales from dual union all
   select 234567 as emp_id, 80000 as category, 10 as sales from dual 
  ), 
   t2 as (select *
          from t1 pivot ( sum(sales) as sum_sales for category in (80000, 80001)) )
  select emp_id,
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         from t2;

  but Oracle has a problem with the fact that the column name starts with a number and get ORA-00911. Something like:
  

  with t1 as 
  (
   select 123456 as emp_id, 80000 as category, 10 as sales from dual union all 
   select 123456 as emp_id, 80001 as category, 20 as sales from dual union all
   select 234567 as emp_id, 80000 as category, 10 as sales from dual 
  ), 
   t2 as (select *
          from t1 pivot ( sum(sales)  for category in (80000, 80001)) )
  select emp_id,
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         nvl(80001, 0) as "80001"
         from t2;

  shows just the values 80000 and 80001 rather than actual sales amounts. Unfortunately, my requirement is that these column headers must be digital, as is an interface in another system. I try to avoid a full outer join a list of categories to all employees, as my employee table has 180 m files in there.
  
  Are there SQL gurus out there who can see a way around this problem, before I attempt an outer join complete?
  
  Thank you
  Matt

  Hello

  Try this

  with t1 as
  (
   select 123456 as emp_id, 80000 as category, 10 as sales from dual union all
   select 123456 as emp_id, 80001 as category, 20 as sales from dual union all
   select 234567 as emp_id, 80000 as category, 10 as sales from dual
  ),
   t2 as (select *
          from t1 pivot ( sum(sales)  for category in (80000, 80001)) )
  select emp_id,
         nvl("80000", 0) as "80000",
         nvl("80001", 0) as "80001"
         from t2;
  

  see you soon

  VT

• Null value? What the h is a Null value in my registry events?

  while I'm compensation of errors I have 1 last error, apparently harmless but annoying nonetheless, I want to get all these events "Null" out of my system.

  Log name: System
  Source: Service Control Manager
  Date: 23/02/2013-11:54:52
  Event ID: 7026
  Task category: no
  Level: error
  Keywords: Classic
  User: n/a
  Computer: INTL
  Description:
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  Null value
  The event XML:
  http://schemas.Microsoft.com/win/2004/08/events/event">
   
     
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      0
      2
      0
      0
      0 x 8080000000000000
     
      9113
     
     
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  Null value
   
  

  your help is appreciated, thanks

  Al Adams

  Hello

  Thanks for the reply.

  Your question does contain all the required information necessary for us to help you. Please provide us with more information to continue troubleshooting as a result.

  See the link on how to ask questions or help on the Forums.

  Suggestions for a question on help forums: http://support.microsoft.com/kb/555375

  Thank you.

• NULL values in partition Table of Partition key

  Hi all

  I'm using Oracle 11.2.0.3.

  I can add a null value on partition of Partition table key.

  If so, how?

  Kind regards.

  • You cannot specify NULL in the VALUES clause.

  Referring to clauses PARTITION you set - not the data that you insert.

  If you cannot define a range partition that uses the VALUES LESS THAN and use null to this division. But you CAN use NULL values in the VALUES of integration clause.

  DROP TABLE mytable;

  CREATE TABLE MyTable

  (

  CREATION_DATE DATE,

  Identification number

  )

  PARTITION BY RANGE (CREATION_DATE)

  (

  PARTITION prior_to_2016 VALUES LESS THAN (TO_DATE ('2016-01-01', 'YYYY-MM-DD'));

  LESS THAN PARTITION of VALUES undesirable (MAXVALUE)

  )

  Insert into myTable values (null, null)

  You can use a VALUES clause to insert NULL values - this line will go into the MAXVALUE partition.

• How to replace a. null value in obiee report

  Hi gurus,

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  Try it out below mentioned formula.

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  Hi gurus,

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  < C'estr > < Ref > {C8D1FE60-7743-465B-ACA1-509C59EC4A75} < / Ref > < AppName / > < user / > < DBUpdate > 1 < / DBUpdate > < CSEC > < Num >-2147467259 < / Num > < Type > 1 < / Type > < DTime > 2014/06/12 12:01:54 < / DTime > < Svr > RJ1 - 2 K 8-BI-P06 < / Svr > < file > HfmADOConnection.cpp < / file > < line > 591 < / line > < worm > 11.1.2.3.500.4435 < /. Worm > < DStr > ORA-12519: found appropriate TNS:no services manager < / DStr > < / CSEC > < / RTSs >.

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  Hello

  Might or might not help, no harm trying though.

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• NULL value in Radio buttons 11.1.1.6.2 OBIEE

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  Even if add a where condition clause to restrict the values Null his watch upward.
  
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  Thank your.
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  Hello

  Uncheck the option 'nullable' for this column in the physical layer and restart presentation services. It should disappear.

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• creating table of partition with null values

  Hello
  
  I have a table with 20 GB of data. I changed this table in the table to partition with partition of the range
  the column with which I took for range (date), holding the values null
  
  can I have a partition for null values?

  Hello

  CREATE TABLE ICBS. KNET_STMT_EXTRACT_NEW_P
  (
  SRVC_TYPE VARCHAR2 (200 BYTE),
  FILLER_1 VARCHAR2 (200 BYTE),
  RTE_STAT VARCHAR2 (200 BYTE),
  TRAN_DATE VARCHAR2 (200 BYTE),
  TRAN_TIME VARCHAR2 (200 BYTE),
  POST_DATE VARCHAR2 (200 BYTE),
  DATE OF REC_INSERT_DT,
  DATE OF PROCESSED_DATE,
  KNET_RECON_RESSON VARCHAR2 (100 BYTE),
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  REASON VARCHAR2 (200 BYTE)
  REASON_IND NUMBER (5),
  NODE_ID VARCHAR2 (8 BYTE),
  PROGRAM_ID VARCHAR2 (8 BYTE),
  USER_ID VARCHAR2 (8 BYTE),
  TIME_STAMP DATE
  )
  ICBS TABLESPACE
  PCTUSED 0
  PCTFREE 10
  INITRANS 1
  MAXTRANS 255
  STORAGE)
  64K INITIALS
  MINEXTENTS 1
  MAXEXTENTS UNLIMITED
  PCTINCREASE 0
  DEFAULT USER_TABLES
  )
  LOGGING
  PARTITION BY RANGE (REC_INSERT_DT)
  (

  KNET_STMT_EXTRACT_NEW_P_DEC11 PARTITION VALUES LESS THAN (TO_DATE (' 2012-01-01 00:00:00 ',' SYYYY-MM-DD HH24:MI:SS ',' NLS_CALENDAR = GREGORIAN '))
  LOGGING
  NOCOMPRESS
  ICBS TABLESPACE
  PCTFREE 10
  INITRANS 1
  MAXTRANS 255
  STORAGE)
  INITIAL 1 M
  MINEXTENTS 1
  MAXEXTENTS UNLIMITED
  DEFAULT USER_TABLES
  ),
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  LOGGING
  NOCOMPRESS
  ICBS TABLESPACE
  PCTFREE 10
  INITRANS 1
  MAXTRANS 255
  STORAGE)
  INITIAL 1 M
  MINEXTENTS 1
  MAXEXTENTS UNLIMITED
  DEFAULT USER_TABLES
  ),
  PARTITION KNET_STMT_EXTRACT_NEW_P_MVAL VALUES LESS THAN (MAXVALUE)
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  NOCOMPRESS
  TABLESPACE TBL_MAXVALUE
  PCTFREE 10
  INITRANS 1
  MAXTRANS 255
  STORAGE)
  INITIAL 1 M
  MINEXTENTS 1
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  DEFAULT USER_TABLES
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  Published by: hitgon on April 30, 2012 10:56

  Published by: hitgon on April 30, 2012 10:58

  Published by: hitgon on April 30, 2012 10:59

• FTS by select as NOT NULL values

  Hello
  
  My version of Oracle is 10.2.0.3.0.
  
  I'm shot under SQL in the database, this SQL is a FTS during the race.
  
  SELECT *.
  Table_name FROM
  WHERE id_number IS NULL;
  
  Pease see below for the nature of the existing data in the table.
  
  SQL > select count (*) from table_name where id_number is null;
  
  COUNT (*)
  ----------------
  1456
  
  SQL > select count (*) from table_name;
  
  COUNT (*)
  ----------------
  9392730
  
  However, there is an index on the column id_number and the SQL where clause (where id_number is null) picks up only 0.1% of the rows in the table. Although SQL is a FTS on the table table_name. Is there a way I can remove this execute SQL FTS.
  
  Thanks in advance.
  
  Best regards
  oratest

  oratest wrote:
  Means there is no another way/workaround to grant this SQL? :(

  Major responses in this thread.

  If you change the SQL statement or set up a bitmap index (not a good choice index if the table is subject to frequent changes), there is another solution. I think I've seen this approach on the blog of Richard Foote:
  http://richardfoote.WordPress.com/2008/01/23/indexing-nulls-empty-spaces/

  Here's a sample:

  CREATE TABLE T1(
    C1 NUMBER NOT NULL,
    C2 VARCHAR2(50) NOT NULL,
    C3 NUMBER,
    C4 VARCHAR2(300));
  
  INSERT INTO T1
  SELECT
    ROWNUM,
    TO_CHAR(ROWNUM,'0000000')||'A',
    DECODE(MOD(ROWNUM,1000),0,NULL,ROWNUM),
    LPAD('A',300,'A')
  FROM
    (SELECT
      ROWNUM RN
    FROM
      DUAL
    CONNECT BY
      LEVEL <= 1000) V1,
    (SELECT
      ROWNUM RN
    FROM
      DUAL
    CONNECT BY
      LEVEL <= 1000) V2;
  
  CREATE INDEX IND_T1_C3 ON T1(C3);
  
  EXEC DBMS_STATS.GATHER_TABLE_STATS(OWNNAME=>USER,TABNAME=>'T1',CASCADE=>TRUE)
  

  The foregoing has created a ranking table 1 000 000, where 1 of 1,000 rows contains a NULL value. An index has been created and then on the table, and the statistics have been updated.

  Now the first test:

  SET AUTOTRACE TRACEONLY EXPLAIN
  
  SELECT
    COUNT(*)
  FROM
    T1
  WHERE
    C3 IS NULL;
  
  Execution Plan
  ----------------------------------------------------------
  Plan hash value: 3724264953
  
  ---------------------------------------------------------------------------
  | Id  | Operation          | Name | Rows  | Bytes | Cost (%CPU)| Time     |
  ---------------------------------------------------------------------------
  |   0 | SELECT STATEMENT   |      |     1 |     5 | 10994   (2)| 00:00:45 |
  |   1 |  SORT AGGREGATE    |      |     1 |     5 |            |          |
  |*  2 |   TABLE ACCESS FULL| T1   |  2000 | 10000 | 10994   (2)| 00:00:45 |
  ---------------------------------------------------------------------------
  
  Predicate Information (identified by operation id):
  ---------------------------------------------------
     2 - filter("C3" IS NULL)
  

  Note that the index is not used. A second test with a slightly modified definition of the index:

  CREATE INDEX IND_T1_C3_NULL ON T1(C3,' ');
  
  EXEC DBMS_STATS.GATHER_INDEX_STATS(OWNNAME=>USER,INDNAME=>'IND_T1_C3_NULL')
  
  SELECT
    COUNT(*)
  FROM
    T1
  WHERE
    C3 IS NULL;
  
  Execution Plan
  ----------------------------------------------------------
  Plan hash value: 265035506
  
  ------------------------------------------------------------------------------------
  | Id  | Operation         | Name           | Rows  | Bytes | Cost (%CPU)| Time     |
  ------------------------------------------------------------------------------------
  |   0 | SELECT STATEMENT  |                |     1 |     5 |    25   (0)| 00:00:01 |
  |   1 |  SORT AGGREGATE   |                |     1 |     5 |            |          |
  |*  2 |   INDEX RANGE SCAN| IND_T1_C3_NULL |  2000 | 10000 |    25   (0)| 00:00:01 |
  ------------------------------------------------------------------------------------
  
  Predicate Information (identified by operation id):
  ---------------------------------------------------
     2 - access("C3" IS NULL)
  

  This time notice that the special index was used without having to change the SQL statement.

  Charles Hooper
  Co-author of "Expert Oracle practices: Oracle Database Administration of the Oak Table.
  http://hoopercharles.WordPress.com/
  IT Manager/Oracle DBA
  K & M-making Machine, Inc.

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  I don't know if it's a bug or do something wrong but here is my case:
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  In page view of all of VO, aaa I bind a variable named
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  Jack

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  Timo

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  Hey guys,.

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