Number of comparison in the sem_match filter clause failed to Jena

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  guys I have a table like this

   create table fgbtrnh ( fgbtrnh_doc_code varchar2(9),
                                           fgbtrnh_trans_date date,
                                           fgbtrnh_trans_amt number(17,2),
                                           fgbtrnh_acct varchar2(6) ,
                                           fgbtrnh_fund_code varchar2(6),
                                           fgbtrnh_rucl_code varchar2(6) );
   

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     insert into fgbtrnh( fgbtrnh_doc_code,fgbtrnh_trans_date,fgbtrnh_trans_amt,fgbtrnh_acct,fgbtrnh_rucl_code,fgbtrnh_fund_code) values('J0005445','31-MAY-10','38491','6001','BD01','360098');
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   insert into fgbtrnh( fgbtrnh_doc_code,fgbtrnh_trans_date,fgbtrnh_trans_amt,fgbtrnh_acct,fgbtrnh_rucl_code,fgbtrnh_fund_code) values('M0000002','30-JUN-08','90','7200','BD01','360098');

  I would like to get a total run of these elements, so I tried something like that.
  

  select  f.fgbtrnh_doc_code,f.fgbtrnh_trans_date,f.fgbtrnh_trans_amt, sum(f.fgbtrnh_trans_amt)
  over
  (--partition by  f.fgbtrnh_doc_code
  order by fgbtrnh_trans_date desc  ROWS UNBOUNDED PRECEDING 
  --group by  f.fgbtrnh_doc_code
  )total
  From fgbtrnh f 
  where f.fgbtrnh_fund_code in ('360098', '360125')
  and f.fgbtrnh_rucl_code = 'BD01'
  and f.fgbtrnh_acct = '6001'
  order by  f.fgbtrnh_trans_date desc,  f.fgbtrnh_doc_code

  but I find myself with a result set as
  
  
  'FGBTRNH_DOC_CODE', 'FGBTRNH_TRANS_DATE', 'FGBTRNH_TRANS_AMT', 'TOTAL '.
  "J0005445", MAY 31, 10, 38491, 38491
  "L0000005", 1 JULY 08, 38260, 76751
  "L0000002", 30 JUNE 08, 24425.29, 101176.29
  "L0000002", 30 JUNE 08, 48057.71, 149234
  
  
  
  
  I want to thave the cumulative total to start at the bottom in the other Word is my total column I would like to finish with the top 149234
  so it should look something like this.
  
  
  
  
  
  'FGBTRNH_DOC_CODE', 'FGBTRNH_TRANS_DATE', 'FGBTRNH_TRANS_AMT', 'TOTAL '.
  "J0005445", MAY 31, 10, 38491, 149234
  "L0000005", 1 JULY 08, 38260, 110743
  "L0000002", 30 JUNE 08, 24425.29, 72483
  "L0000002", 30 JUNE 08, 48057.71, 48057.71
  
  
  I've tried everything and can't seem to make this work can someone please point me in the right direction.
  I would really appreciate the help.
  Thank you
  Miguel

  Hi, Miguel.

  mlov83 wrote:
  ... Also, if you order only the lines, you won't need the windowing clause ("UNBOUNDED PRECEDING LINES"); the default value ("RANGE UNBOUNDED PRECEDING") will have exactly what you want, so you n;' no need to say it.

  I don't really understand what you mean by that? But if I take a quick glance you say that all my lines will have to be unique, and then I won't have to use ("UNBOUNDED PRECEDING LINES")

  I think you have guessed it right.
  The ORDER BY clause Analytics don't have to result in a single ranking. There are good reasons for having a single oprdering, and there are good reasons for not having a single collation.
  I mean that If the analytical ORDER BY is unique, then you need not to give a widnowing clause, such as the "LINES OF UNBOUNDED'.

  Frank sorry if im asking some really stupid questions, but I have tried and tried to read and understand "partion by" and "over" works, but I'm not quite sure I understand yet.

  It's not stupid at all! Analytical functions can be very subtle and confusing.

  We will use a query based on the table scott.emp, which includes lines for each seveal deptno.

  -- Tell SQL*Plus to put a blank line between deptnos, just to make the output easier to read
  BREAK     ON deptno   SKIP 1     DUPLICATES
  
  SELECT       deptno
  ,       ename
  ,       sal
  ,       SUM (sal) OVER ( PARTITION BY  deptno
                              ORDER BY        sal
                    ROWS            UNBOUNDED PRECEDING
                  )     AS running_total
  FROM       scott.emp
  ORDER BY  deptno
  ,            sal          DESC
  ,       ename
  ;
  

  Output:

  `   DEPTNO ENAME             SAL RUNNING_TOTAL
  ---------- ---------- ---------- -------------
          10 KING             5000          8750
          10 CLARK            2450          3750
          10 MILLER           1300          1300
  
          20 FORD             3000         10875
          20 SCOTT            3000          7875
          20 JONES            2975          4875
          20 ADAMS            1100          1900
          20 SMITH             800           800
  
          30 BLAKE            2850          9400
          30 ALLEN            1600          6550
          30 TURNER           1500          4950
          30 MARTIN           1250          2200
          30 WARD             1250          3450
          30 JAMES             950           950
  

  PARTITION BY deptno"means to do a separate calculation for each distinct value of deptno. Lines with deptno = 10 effect the outcome on the lines where deptno = 20 or deptno = 30. Since there are 3 distinct values of deptno, there are 3 separate running totals.

  Note that the analytical ORDER BY clause translates into only a partial ranking. If there are two or more lines in the same deptno who have the same sal, look what can happen:
  {code}
  "DEPTNO ENAME SAL RUNNING_TOTAL.
  ---------- ---------- ---------- -------------
  ... 30 1500 4950 TURNER
  30 MARTIN 1250 2200
  1250 3450 DISTRICT 30
  30 JAMES 950 950
  {code}
  MARTIN and WARD are in the same partition (deptno = 30), and they both have the same sal (1250), so there is no reason why one of these lines would be considered 'before' it. When you use a windowing clause based on the LINES, as stated above, and there is equality for which line comes first (as there is equality between MARTIN and WARD), then one of the lines will arbitrarily be condidered before this one. In this example, it happened to chose MARTIN as the 2nd lowest sal, so running_total = 2200 (= 950 + 1250) on the line for MARTIN and running_total = 3450 (950 + 1250 + 1250) on the WARD line. There is no particular reason for this; It is completely arbitrary. I could do exactly the same question tomorrow or in 10 minutes and get running_total = 2200 to the rank of WARD and 3450 on MARTIN.
  However, it is no coincidence that MARTIN comes before WARD at the exit. the * request * ORDER BY clause (which has nothing to do with the analytical ORDER BY clause) ensures that, when two lines have the same deptno and sal, then the one with the earlier ename will come first.

  Now, what is the difference between a window based on the LINES and a window on the BEACH bnased?
  One difference is that, when a link appears in the ORDER BY clause, all rows with the same value of sal get the same value for SUM (sal):
  {code}
  SELECT DeptNo
  ename
  sal
  SUM (sal) over (PARTITION BY deptno
  ORDER BY sal
  ) AS running_total
  FROM scott.emp
  ORDER BY deptno
  sal DESC
  ename
  ;
  {code}
  Note that the only difference between the first query above, and this one is that it does not have an analytical windowing clause, then the default window, * RANGE * UNBOUNDED PRECEDING is used.
  Output:
  {code}
  "DEPTNO ENAME SAL RUNNING_TOTAL.
  ---------- ---------- ---------- -------------
  10 5000 8750 KING
  10 2450 3750 CLARK
  10 1300 1300 MILLER

  20 FORD 3000 10875
  20 3000 10875 SCOTT
  20 JONES 2975 4875
  20 1100 1900 ADAMS
  20 SMITH 800 800

  30 2850 9400 BLAKE
  30 1600 6550 ALLEN
  30 1500 4950 TURNER
  30 MARTIN 1250 3450
  1250 3450 DISTRICT 30
  30 JAMES 950 950
  {code}
  Again, look MARTIN and WARD near the end. They have both the sal of the soul, so they both have the same running_total = 3450 (= 950 + 1250 + 1250). This is often a desirable outcome, but in your case, it seems not to be. If you want running_totals MARTIN and WARD, then recesses you must use a window LINE, as we have done previously, or add a breakage in the ORDER BY clause, like this:
  {code}
  SELECT DeptNo
  ename
  sal
  SUM (sal) over (PARTITION BY deptno
  ORDER BY sal
  , ename DESC - changed (this is the only change)
  ) AS running_total
  FROM scott.emp
  ORDER BY deptno
  sal DESC
  ename
  ;
  {code}
  Output:
  {code}
  "DEPTNO ENAME SAL RUNNING_TOTAL.
  ---------- ---------- ---------- -------------
  10 5000 8750 KING
  10 2450 3750 CLARK
  10 1300 1300 MILLER

  20 FORD 3000 10875
  20 3000 7875 SCOTT
  20 JONES 2975 4875
  20 1100 1900 ADAMS
  20 SMITH 800 800

  30 2850 9400 BLAKE
  30 1600 6550 ALLEN
  30 1500 4950 TURNER
  30 MARTIN 1250 3450
  1250 2200 DISTRICT 30
  30 JAMES 950 950
  {code}

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  Hi again!
  
  Following my previous thread...
  Re: Need help with RANK() on data ZERO
  
  I tried to apply the GROUP BY clause instead of preforming my query with RANK() to manage records NULL... I have a scenario where I also need to concatenate data from several lines.
  
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  INSERT INTO T_EMP VALUES (1002, 'DAVID');
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  COMMIT;
  
  I have a T_EMP master table that stores the name and number of the emp. Each emp is required to visit some departments. This mapping is stored in the T_EMP_DEPT table. An employee can visit one or more departments. T_EMP_VISITS table stores the dates where the employee visited the services required. I need to view the report which should show when an employee all completed visits, which is the maximum date when it finished to visit all departments. If he did not visit any of the report should display date max, otherwise NULL. I was able to do using GROUP BY such proposed by Salim, but how do I show a list separated by commas of the services required for an employee in the same query.
  
  SELECT
  EMP_NO,
  NAME,
  MAX (DEPT_NO) KEEP (DENSE_RANK LAST ORDER BY VISITED) MAX_DEPT_NO,.
  MAX (VISITED) KEEP (DENSE_RANK LAST ORDER PER VISIT) VISITS_COMP
  DE)
  SELECT
  T_EMP. EMP_NO,
  NAME,
  T_EMP_DEPT. DEPT_NO,
  VISITED
  OF T_EMP
  LEFT OUTER JOIN T_EMP_DEPT
  ON T_EMP. EMP_NO = T_EMP_DEPT. EMP_NO
  LEFT OUTER JOIN T_EMP_VISITS
  ON T_EMP_DEPT. EMP_NO = T_EMP_VISITS. EMP_NO
  AND T_EMP_DEPT. DEPT_NO = T_EMP_VISITS. DEPT_NO)
  GROUP EMP_NO, NAME;
  
  Output
  EMP_NO NAME MAX_DEPT_NO VISITS_COMP
  1001 MARK 20
  1002 DAVID 20
  1003 SHAUN 20 3 MAY 09
  JILL 1004
  
  Power required
  EMP_NO NAME REQ_DEPTS MAX_DEPT_NO VISITS_COMP
  1001 MARC 20 10.20
  1002 DAVID 10,20,30 20
  1003 SHAUN 20,30 20 3 MAY 09
  JILL 10 1004
  
  Can we do this in a single query?

  Hello

  user512647 wrote:
  ... Sanjay
  The query you provided that stragg() use seems to work but my requirement is not in the result set. I don't know how to use stragg with
  MAX (DEPT_NO) KEEP (DENSE_RANK LAST ORDER BY VISITED) MAX_DEPT_NO,.
  MAX (VISITED) KEEP (DENSE_RANK LAST ORDER PER VISIT) VISITS_COMP
  I need more, these two columns these gives me the date when they have completed all visits. If they missed any Department then the result must be NULL in the VISITS_COMP field.

  Just add them to the SELECT clause:

  SELECT    t_emp.emp_no,
         name,
         STRAGG (t_emp_dept.dept_no)     AS deptno,
         MAX (t_emp_dept.dept_no) KEEP (DENSE_RANK LAST ORDER BY visited)
                                    AS max_dept_no,
         MAX (visited)                      AS visits_comp
  FROM             t_emp
  LEFT OUTER JOIN      t_emp_dept     ON   t_emp.emp_no     = t_emp_dept.emp_no
  LEFT OUTER JOIN      t_emp_visits     ON   t_emp_dept.emp_no     = t_emp_visits.emp_no
                               AND  t_emp_dept.dept_no = t_emp_visits.dept_no
  GROUP BY  t_emp.emp_no
  ,            name
  ;
  

  The column called visit_comp is simply the last visited, regardless of how the employee visited departments.
  If you want to have the NULL value if the employee has not yet visited all 3 departments:

  ...       CASE
            WHEN  COUNT (DISTINCT t_emp_dept.dept_no) = 3
            THEN  MAX (visited)
         END                    AS visits_comp
  

  The 'magic number' 3 is the total number of departments.
  If you want to understand the correct value of that at the time of the execution of the query, replace the code literal 3 hard with a scalar subquery.

  Note that 'KEEP MAX (x) (DENSE_RANK OVER LAST SERVICE BY x)' (where the exact same column is used as an argument and that the ORDER BY column) is just "MAX (x)".

• What's the point of having several columns in the ORDER BY clause?

  DB version: 10 gr 2
  
  When you use the ORDER BY clause, the lines are always sorted by the first column in the ORDER BY clause. So, what's the point of having several columns in the ORDER BY clause (I always see this in production codes)?
  
  For the below SQLs' schema SCOTT, result sets are always classified according to the first column ename. When I added use asc and desc of employment, does not change the result set.
  

  SQL> select * from emp order by ename;
  
       EMPNO ENAME      JOB              MGR HIREDATE         SAL       COMM     DEPTNO
  ---------- ---------- --------- ---------- --------- ---------- ---------- ----------
        7876 ADAMS      CLERK           7788 23-MAY-87       1100                    20
        7499 ALLEN      SALESMAN        7698 20-FEB-81       1600        300         30
        7698 BLAKE      MANAGER         7839 01-MAY-81       2850                    30
        7782 CLARK      MANAGER         7839 09-JUN-81       2450                    20
        7902 FORD       ANALYST         7566 03-DEC-81       3000                    20
        7900 JAMES      CLERK           7698 03-DEC-81        950                    30
        7566 JONES      MANAGER         7839 02-APR-81       2975                    20
        7839 KING       PRESIDENT            17-NOV-81       5000                    20
        7654 MARTIN     SALESMAN        7698 28-SEP-81       1250       1400         30
        7934 MILLER     CLERK           7782 23-JAN-82       1300                    20
        7788 SCOTT      ANALYST         7566 19-APR-87       3000                    20
        7369 SMITH      CLERK           7902 17-DEC-80        800                    20
        7844 TURNER     SALESMAN        7698 08-SEP-81       1500          0         30
        7521 WARD       SALESMAN        7698 22-FEB-81       1250        500         30
  
  14 rows selected.
  
  SQL> select * from emp order by ename, job;
  
       EMPNO ENAME      JOB              MGR HIREDATE         SAL       COMM     DEPTNO
  ---------- ---------- --------- ---------- --------- ---------- ---------- ----------
        7876 ADAMS      CLERK           7788 23-MAY-87       1100                    20
        7499 ALLEN      SALESMAN        7698 20-FEB-81       1600        300         30
        7698 BLAKE      MANAGER         7839 01-MAY-81       2850                    30
        7782 CLARK      MANAGER         7839 09-JUN-81       2450                    20
        7902 FORD       ANALYST         7566 03-DEC-81       3000                    20
        7900 JAMES      CLERK           7698 03-DEC-81        950                    30
        7566 JONES      MANAGER         7839 02-APR-81       2975                    20
        7839 KING       PRESIDENT            17-NOV-81       5000                    20
        7654 MARTIN     SALESMAN        7698 28-SEP-81       1250       1400         30
        7934 MILLER     CLERK           7782 23-JAN-82       1300                    20
        7788 SCOTT      ANALYST         7566 19-APR-87       3000                    20
        7369 SMITH      CLERK           7902 17-DEC-80        800                    20
        7844 TURNER     SALESMAN        7698 08-SEP-81       1500          0         30
        7521 WARD       SALESMAN        7698 22-FEB-81       1250        500         30
  
  14 rows selected.
  
  SQL>  select * from emp order by ename, job desc;
  
       EMPNO ENAME      JOB              MGR HIREDATE         SAL       COMM     DEPTNO
  ---------- ---------- --------- ---------- --------- ---------- ---------- ----------
        7876 ADAMS      CLERK           7788 23-MAY-87       1100                    20
        7499 ALLEN      SALESMAN        7698 20-FEB-81       1600        300         30
        7698 BLAKE      MANAGER         7839 01-MAY-81       2850                    30
        7782 CLARK      MANAGER         7839 09-JUN-81       2450                    20
        7902 FORD       ANALYST         7566 03-DEC-81       3000                    20
        7900 JAMES      CLERK           7698 03-DEC-81        950                    30
        7566 JONES      MANAGER         7839 02-APR-81       2975                    20
        7839 KING       PRESIDENT            17-NOV-81       5000                    20
        7654 MARTIN     SALESMAN        7698 28-SEP-81       1250       1400         30
        7934 MILLER     CLERK           7782 23-JAN-82       1300                    20
        7788 SCOTT      ANALYST         7566 19-APR-87       3000                    20
        7369 SMITH      CLERK           7902 17-DEC-80        800                    20
        7844 TURNER     SALESMAN        7698 08-SEP-81       1500          0         30
        7521 WARD       SALESMAN        7698 22-FEB-81       1250        500         30
  
  14 rows selected.

  Search in this example, you will see the difference

  SQL> create table test_order (name varchar2(10), surname varchar2(10), age number);
  
  Table created.
  
  SQL> insert into test_order values('Kamran','Agayev',26);
  
  1 row created.
  
  SQL> insert into test_order values('Kamran','Taghiyev',26);
  
  1 row created.
  
  SQL> insert into test_order values('John','Kevin',23);
  
  1 row created.
  
  SQL> select * from test_order;
  
  NAME       SURNAME           AGE
  ---------- ---------- ----------
  Kamran     Agayev             26
  Kamran     Taghiyev           26
  John       Kevin              23
  
  SQL> select * from test_order
    2  order by age;
  
  NAME       SURNAME           AGE
  ---------- ---------- ----------
  John       Kevin              23
  Kamran     Agayev             26
  Kamran     Taghiyev           26
  
  SQL> select * from test_order
    2  order by age asc, surname desc;
  
  NAME       SURNAME           AGE
  ---------- ---------- ----------
  John       Kevin              23
  Kamran     Taghiyev           26
  Kamran     Agayev             26
  
  SQL>
  

  When in the second query, I sorted out only for age, you saw it there two 26 years old Keita, there was first Agayev, then Taghiyev. But if I want to get the family names in descending order when there are two very old person, then I will add the second column in the order by clause

  - - - - - - - - - - - - - - - - - - - - -
  Kamran Agayev a. (10g OCP)
  http://kamranagayev.WordPress.com

• A question about the analytical function used with the GROUP BY clause in SHORT

  Hi all
  
  I created the following table named myenterprise
  

  CITY       STOREID    MONTH_NAME TOTAL_SALES            
  ---------- ---------- ---------- ---------------------- 
  paris      id1        January    1000                   
  paris      id1        March      7000                   
  paris      id1        April      2000                   
  paris      id2        November   2000                   
  paris      id3        January    5000                   
  london     id4        Janaury    3000                   
  london     id4        August     6000                   
  london     id5        September  500                    
  london     id5        November   1000

  If I want to find which is the total sales by city? I'll run the following query

  SELECT city, SUM(total_sales) AS TOTAL_SALES_PER_CITY
  FROM myenterprise
  GROUP BY city
  ORDER BY city, TOTAL_SALES_PER_CITY;

  that works very well and produces the expected result, i.e.

  CITY       TOTAL_SALES_PER_CITY   
  ---------- ---------------------- 
  london     10500                  
  paris      17000            

  Now in one of my books SQL (Mastering Oracle SQL) I found another method by using the SUM, but this time as an analytic function. Here's what the method of the book suggests as an alternative to the problem:

  SELECT city, 
         SUM(SUM(total_sales)) OVER (PARTITION BY city) AS TOTAL_SALES_PER_CITY
  FROM myenterprise
  GROUP BY city
  ORDER BY city, TOTAL_SALES_PER_CITY;

  I know that the analytic functions are executed after the GROUP BY clause has been transformed completely and Unlike regular aggregate functions, they return their result for each line belonging to the partitions specified in the partition clause (if there is a defined partition clause).
  
  Now my problem is that I do not understand what we have to use two functions SUM? If we only use one only, i.e.

  SELECT city, 
         SUM(total_sales) OVER (PARTITION BY city) AS TOTAL_SALES_PER_CITY
  FROM myenterprise
  GROUP BY city
  ORDER BY city, TOTAL_SALES_PER_CITY;

  This generates the following error:

  Error starting at line 2 in command:
  SELECT city, 
         SUM(total_sales) OVER (PARTITION BY city) AS TOTAL_SALES_PER_CITY
  FROM myenterprise
  GROUP BY city
  ORDER BY city, TOTAL_SALES_PER_CITY
  Error at Command Line:2 Column:11
  Error report:
  SQL Error: ORA-00979: not a GROUP BY expression
  00979. 00000 -  "not a GROUP BY expression"
  *Cause:    
  *Action:

  The error is generated for the line 2 column 11 which is, for the expression SUM (total_sales), well it's true that total_sales does not appear in the GROUP BY clause, but this should not be a problem, it has been used in an analytical function, so it is evaluated after the GROUP BY clause.
  
  So here's my question:
  
  Why use SUM (SUM (total_sales)) instead of SUM (total_sales)?
  
  
  Thanks in advance!
  :)
  
  
  
  
  
  In case you are interested, that's my definition of the table:

  DROP TABLE myenterprise;
  CREATE TABLE myenterprise(
  city VARCHAR2(10), 
  storeid VARCHAR2(10),
  month_name VARCHAR2(10),
  total_sales NUMBER);
  
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('paris', 'id1', 'January', 1000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('paris', 'id1', 'March', 7000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('paris', 'id1', 'April', 2000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('paris', 'id2', 'November', 2000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('paris', 'id3', 'January', 5000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('london', 'id4', 'Janaury', 3000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('london', 'id4', 'August', 6000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('london', 'id5', 'September', 500);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('london', 'id5', 'November', 1000);

  Edited by: dariyoosh on April 9, 2009 04:51

  It is clear that thet Analytics is reduntant here...
  You can even use AVG or any analytic function...

  SQL> SELECT city,
    2         avg(SUM(total_sales)) OVER (PARTITION BY city) AS TOTAL_SALES_PER_CITY
    3  FROM myenterprise
    4  GROUP BY city
    5  ORDER BY city, TOTAL_SALES_PER_CITY;
  
  CITY       TOTAL_SALES_PER_CITY
  ---------- --------------------
  london                    10500
  paris                     17000
  

• How to change the number of minutes for the exercise of the activity of the application

  How to change the number of minutes for the exercise of the activity of the application

  Hello

  It is not currently possible to change the goal of daily exercise.

  If you want to suggest that Apple consider adding this option, you can submit a request here:

  https://www.Apple.com/feedback/watch.html