Number of conditional group

Similar Questions

• Conditional group

  Hello
  I need to make a conditional group based on the values of column grouped without the help of the trade unions. Is it possible to do in a single query...
  I need e exit suite
  with the trial as
  (
  Select 1 as col1, 10 as double amt
  Union
  Select 2 as col1, 11 as double amt
  Union
  Select 1 as col1, 12 as double amt
  Union
  Select 2 as col1, 13 as double amt
  Union
  Select 1 as col1, 14 as double amt
  )
  Select col1, sum (amt) test col2
  where col1 = 1
  Group of col1
  Union of all the
  Select col1, col2 amt test
  where col1 <>1
  
  Thanks in advance

  Hello

  Try something like:

  SQL> with test as
    2  (
    3  select 1 as col1 , 10 as amt from dual
    4  union
    5  select 2 as col1 , 11 as amt from dual
    6  union
    7  select 1 as col1 , 12 as amt from dual
    8  union
    9  select 2 as col1 , 13 as amt from dual
   10  union
   11  select 1 as col1 , 14 as amt from dual
   12  )
   13  select distinct
   14         col1
   15  ,      case when col1 = 1 then sum(amt) over (partition by col1) else amt  end col2
   16  from   test;
  
        COL1  COL2
  ---------- -----
           1    36
           2    11
           2    13
  
  3 rows selected.
  

• How to count the number of conditionally highlight cells in a column or row

  I'm working on a table to identify problems with my credit rating. So, I have a column that indicates the due date on the invoice and G that contains the date to which I made the payment.

  I'm trying to follow how many times I'm late with payments. I want to improve.

  So if the G column is later than column D, both with the Date formatting. So, now I've highlighted cells and I want to summarize for the year, how many times I was late payments.

  I thought a column G to count the number of days before or after that back I was with payments. But if the sum, it only gives me no useful information. I guess I could count the number of cells with values less than 0.

  I prefer to be able to put in the summary column for G something that said 0-12 years ago has highlighted cells in the column.

  Thank you

  You can not count based on sharing or formatting.  You can, however, be based on the same conditions.

  There are functions:

  COUNTIF() counties based on a condition is true

  and

  COUNTIFS() based on several conditions being true

  = NB. If

  Here is a way.  IT will take an additional column that calculates the "delay" in the days of a payment

  

  the first two lines are the lines of header

  H3 = IF (COUNTA (D3, G3) > 1, MAX ((G3−D3) DUR2DAYS, 0), "")

  It's shorthand dethrone select cell H3, and type (or copy and paste it here) the formula:

  = IF (COUNTA (D3, G3) > 1, MAX ((G3−D3) DUR2DAYS, 0), "")

  Now select cell H3, copy

  Select the H3 cells at the end of column H, dough

  H1 = "payments late =" & COUNTIF(H,">0")

• Consecutive date grouping and find the largest number of consecutive group

  Hi all

  I have given dates and I want to find the largest number of consecutive dates

  WIN_DATE_DATA

  2015-09-22

  2015-09-23

  2015-09-27

  2015-09-28

  2015-09-29

  2015-09-30

  2015-10-1

  
  

  In this example, there are 2 group of consecutive dates

  Group 1
  

  2015-09-22

  2015-09-23

  Group 2

  2015-09-27

  2015-09-28

  2015-09-29

  2015-09-30

  2015-10-1

  
  

  The OUTPUT should 5 which is the largest grouping of consecutive number.

  
  

  Thanks in advance for the help!
  

  
  

  
  

  
  

  Please take a look at the Community document: 101 PL/SQL: grouping sequence ranges (method Tabibitosan)

  will allow you to do.

• power-sum with condition group

  Hello
  I'm fighting with these totals.
  I can't understand the syntax <? sum (current - group (/AMOUNT))? > condition AMOUNT > 100.
  What I want him to have Total of any amounts that are greater than 100 for example. This 100 is supposed to be variable.
  
  I tried some things that have been proposed in the forum, but all raise error.

  You can try some thing like that

  [100])? >

  can you send me your model you use.

  E-mail: [email protected]

• number of conditional, exclusion of the counted and other.

  Hi guys,.

  I have the following table:

  MATRIX - ID - Reason_1___Reason_2

  001004 7 B - 2014/04471 2

  001004 R/2014/000046 8 1

  001004 R/2014/000963 7 1

  001001 R/2014/000963 7 1

  001004 102311427365 7 1

  001004 102311428653 8 1

  001004 102311429331 7 1

  001004 102311429818 7 1

  001001 102311429818 7 5

  001004 14 - 0027835 7 1

  001001 14 - 0124520 7 1

  001004 14 - 0124520 2 1

  001004 7 1 2014MEL008627

  001004 7 1 2014MEL013736

  001004 7 1 2014MEL013737

  I need a meter that shows me the following:

  3 separate ID are displayed for both, matrix 001004 and 001001 (those who are R/2014/000963 102311429818 14-0124520)

  9 separate ID appear only for 001004 (3 above must have been excluded).

  0 distinct ID appear only for 001001 (the first 3 should have been excluded).

  No idea how to solve this problem?

  SQL> with t
    2  as
    3  (
    4  select '001004' matrix, 'B-2014/04471' id, 7 reason_1, 2 reason_2 from dual union all
    5  select '001004' matrix, 'R/2014/000046' id, 8 reason_1, 1 reason_2 from dual union all
    6  select '001004' matrix, 'R/2014/000963' id, 7 reason_1, 1 reason_2 from dual union all
    7  select '001001' matrix, 'R/2014/000963' id, 7 reason_1, 1 reason_2 from dual union all
    8  select '001004' matrix, '102311427365' id, 7 reason_1, 1 reason_2 from dual union all
    9  select '001004' matrix, '102311428653' id, 8 reason_1, 1 reason_2 from dual union all
   10  select '001004' matrix, '102311429331' id, 7 reason_1, 1 reason_2 from dual union all
   11  select '001004' matrix, '102311429818' id, 7 reason_1, 1 reason_2 from dual union all
   12  select '001001' matrix, '102311429818' id, 7 reason_1, 5 reason_2 from dual union all
   13  select '001004' matrix, '14-0027835' id, 7 reason_1, 1 reason_2 from dual union all
   14  select '001001' matrix, '14-0124520' id, 7 reason_1, 1 reason_2 from dual union all
   15  select '001004' matrix, '14-0124520' id, 2 reason_1, 1 reason_2 from dual union all
   16  select '001004' matrix, '2014MEL008627' id, 7 reason_1, 1 reason_2 from dual union all
   17  select '001004' matrix, '2014MEL013736' id, 7 reason_1, 1 reason_2 from dual union all
   18  select '001004' matrix, '2014MEL013737' id, 7 reason_1, 1 reason_2 from dual
   19  )
   20  select matrix
   21       , count(case when cnt > 1 then 1 end) common_id_count
   22       , count(case when cnt = 1 then 1 end) unique_id_count
   23    from (
   24            select matrix
   25                 , id
   26                 , count(distinct matrix) over(partition by id) cnt
   27              from t
   28         )
   29   group
   30      by matrix;
  
  MATRIX COMMON_ID_COUNT UNIQUE_ID_COUNT
  ------ --------------- ---------------
  001001               3               0
  001004               3               9
  
  SQL>
  

• get the maximum number for each group

  Hi, I am a newbie and work on a project for school. I worked this problem for a few days and made a bit of progress.
  I have two tables, student and register for a database of the College. I need to show students that have the most entries into each large. So far, I have:
  
  WITH COUNT_Q AS
  (
  SELECT B.SSN, B.MAJOR, COUNT (A.CLASS_NO) AS COUNTCLASS
  TO REGISTER A, STUDENT B
  WHERE A.SSN = B.SSN
  B.SSN GROUP, B.MAJOR
  )
  
  SELECT MAX (COUNTCLASS), MAJOR
  OF COUNT_Q
  GROUP BY MAJOR
  ;
  
  I get the correct results, but need to introduce the SSN and the Major of the studens. When I add in the SSN and major, as below, I get too many files.
  WITH COUNT_Q AS
  (
  SELECT B.NAME, B.SSN, B.MAJOR, COUNT (A.SSN) AS COUNTCLASS
  TO REGISTER A, STUDENT B
  WHERE A.SSN = B.SSN
  B.NAME, B.SSN, B.MAJOR GROUP
  )
  
  SELECT *.
  OF COUNT_Q
  WHERE (COUNTCLASS) IN (SELECT MAX (COUNTCLASS)
  OF COUNT_Q
  GROUP BY MAJOR
  )
  ;
  
  Can someone point me in the right direction?

  SELECT  B.NAME,
          B.SSN,
          B.MAJOR
    FROM  (
           SELECT  B.NAME,
                   B.SSN,
                   B.MAJOR,
                   COUNT(A.CLASS_NO) SSN_MAJOR_COUNTCLASS
                   DENSE_RANK() OVER(PARTITION BY MAJOR ORDER BY COUNT(A.CLASS_NO) DESC) RNK
             FROM  ENROLL A,
                   STUDENT B
             WHERE A.SSN = B.SSN
             GROUP BY B.NAME,
                      B.SSN,
                      B.MAJOR
          )
    WHERE RNK = 1
  /
  

  SY.

  Published by: Solomon Yakobson, March 27, 2011 18:53

• Conditional formatting - stumped!

  I need to integrate a large number of conditions in my .rtf model in order to get the correct data to print a single column and am received my results when I get one or 2 conditions, but when I add the rest results are all screwed up! I tried to use the instr function, but I must not be doing right b/c if I check it is! = 0 or 0 results are the same.
  
  <? xdofx:If instr (TITLE, 'Secretary', 1, 1)! = 0 ? > <? TITLE? > <? end if? >
  <? xdofx:If instr (TITLE, 'Secretary', 1, 1) = 0? > <? ORGANIZATION? > <? end if? >-if the TITLE field contains the word 'Secretary' I want to print the TITLE, if the word is not in the title I want to print a different field, but I get the two fields on my report (I tried to use <? another? >, but which no longer works)
  
  Currently, I have the following code in my article where I want the printed results:
  
  <? for-each - group:current-group(); / TITLE? >
  <? If: contains(TITLE,'Secretary') or (TITLE, 'Chief') contains or contains (TITLE, 'Director') and (BRANCH! = ")? > <? TITLE? > <? end if? >-it works
  <? If@row:contains (TITLE, 'Secretary')? > <? attribute@InContext:background-color;' #ff99cc '? > <? end if? >-it works
  
  <? If: not (contains (TITLE, 'Secretary')) or not (contains (TITLE, 'Chief')) or not (contains (TITLE, 'Director')) and (BRANCH! = ")? > <? ORGANIZATION? > <? end if? >- If I add to this, I get the title and the Organization printed
  <? end foreach? >
  
  I have other conditions that I need to add more, based on the title not containing is not the above values, and if the Division field is / is not null to print other values in the field.
  
  As you can probably I'm trying to learn to code everything, and I'm not sure what the difference between the use of <? xdofx:If? > or <? If? >. My xml file is the result of a report generated using APEX. I use the desktop version of BI Publisher. Does make a difference as to what the model that I use?
  
  Any help would be appreciated... I've looked through the guide, but found no examples as involved as what I need, in the style code that I use (<? if...? >).
  Thanks in advance!
  T

  try to replace

  TO

• County group

  Hello

  Does anyone know if there is a function to calculate the amount of groups? I know there is a to calculate the number of channels: ChnNoMax but I can't find one to calculate the amount of groups

  Basically, what I want to do is to clear all the groups in the data portal to start with a data portal empty. To do this, the only function that I know is: "Data.Root.ChannelGroups.Remove (groupnumber)" and I want to use it in a loop For, but for this I need to know the last value of the loop For that is the number of groups...

  Thank you

  Hi Leillo,

  To count the number of channel groups use

  Data.Root.ChannelGroups.Count

  Please play around with the data API we implemented in DIAdem. It contains all the data that you see in the Dataportal. You can also have a look at the example script of DIAdem. Most of them use it.

  Greetings

  Walter

• How to find the number of data items in a file written with the ArryToFile function?

  I wrote a table of number in 2 groups of columns in a file using LabWindows/CVI ArrayToFile... Now, if I want to read the file with the FileToArray function so how do I know the number of items in the file. during the time of writing, I know how many elements array to write. But assume that I want the file to be read at a later time, then how to find the number of items in the file, so that I can read the exact number and present it. Thank you all

  Hello

  I start with the second question:

  bytes_read = ReadLine (file_handle, line_buffer, maximum_bytes);

  the second argument is the buffer to store the characters read, so it's an array of characters; It must be large enough to hold maximum_bytes the value NULL, if char [maximum_butes + 1]

  So, obviously the number of lines in your text tiles can be determined in a loop:

  Open the file

  lines = 0;

  While (ReadLine () > 0)

  {

  lines ++;

  }

  Close the file

• In the Contacts file, cannot create new contact groups

  The menu instructions help to declare the following: in the toolbar, click New Contact Group, type a name in the group name box and then fill in the tabs of the Contact Group and contact information group. You do not have to fill in all the boxes; Just type as much information as you want about the new contact group you create.

  Everything would be easier if "New group contact" appeared on the toolbar.  He isn't here.  I was in the past, because I have a number of contact groups in the file.  What happened to him?

  Please repost your question in the Forum program: http://social.answers.microsoft.com/Forums/en-US/vistaprograms/threads where people who specialize in programs other than Vista and IE (like Windows Contacts) will be more than happy to help you with your question.

  Good luck! Lorien - a - MCSE/MCSA/network + / A +.

• members of reading address book group

  Hello

  I'm fighting to read the address book of members in a group.

  By doing below:

  BlackBerryContactList = contact list

  (BlackBerryContactList) BlackBerryPIM.getInstance () .openPIMList (PIM. CONTACT_LIST, PIM. READ_ONLY);

  Elements of the enumeration = contactList.items (BlackBerryContactList.SEARCH_GROUPS);

  I was able to get the name of the group. But I don't know how to read his name and phone number of the group.

  Help me please read the address book of the Member.

  I spent several days now.

  Thank you

  DK

  The enumeration returned by contactList.items (BlackBerryContactList.SEARCH_GROUPS) contains BlackBerryContactGroup objects. Using this object you can get each Member as a Contact by calling BlackBerryContactGroup.getContact (int index).

• The combination of several AD ACS 4.2 security groups

  Hello

  Our ACS is used for AAA for the wireless, the IOS CLI access and access to the unix server. For net admins and administrators unix, there are two levels, so indeed, we have 5 groups of individual devices that a user can be granted access.

  User groups are defined in Active Directory.

  I am looking for a way to combine information from several AD security groups to determine what a user can access. For example, a net administrator may or may not be a unix admin as well.

  Is it possible to do other than to have to have a large number of ad groups with one for each combination of authorization privileges?

  Thank you

  Luke

  HI Luke,.

  Definition of mapping of the hybrid is the best way to achieve this.

  Kind regards

  ~ JG

  Note the useful messages

• Access control and security group

  Hi all

  I need to know about the access control and what data are suitable for the security group and roles if I have the script like this:

  i. There are 2 different app namely ARA (96 branches with different types of reports) and TRACS400 (6 branches with different types of reports)

  II al ' ARA, users of Branch01 can NOT check Branch02.

  III. different report type is measured by Branch01 and Branch02 are different.

  IV. in Branch01, there are some reports are Read (Cannot download) only and some reports are read and write (downloadable).

  My questions are:

  1. from the above scenario, do I need create all the 96 security group and assign it to different leadership roles?

  2. How can I control read and write access, as I have tested the READ access the user is still able to download the report.

  3. How can I control to branch 01, report Type A is a read and report Type B read and write access?

  4. I noticed that if I use the account, the security group can be used be limited to 50 only security groups. Is this good? I may be an application later in the future. These 2 request for test only. But if I do not use the account, there are any number of security groups that can be used?

  Appreciate for your help.

  Hi aziela

  As mentioned by the friends of the forum, it is advisable to have the minimum security group given that its impact on the scalability of the application (rule). Accounts provide the best security solution of dimension view group.

  Security group corresponds to the role, role is mapped to the users. The permissions are obtained at the level of role-SG.

  Accounts are mapped directly to users. So you can have a precise control at the level of the user (eliminating the abstraction of the role).

  All these aspects are impacting performance where rule of thumb is mentioned in the documentation. In general, if a user belongs to many groups and accounts then it will take more time to process the request of content for this user.

  w.r.t. prohibiting the read-only users so that they will not be able to download content, there is a setting, please try option mentioned in this link http://docs.oracle.com/cd/E14571_01/doc.1111/e10792/e01_interface001.htm#CACCFHHA

  WRT performance calculation, see http://docs.oracle.com/cd/E14571_01/doc.1111/e10792/c03_security003.htm#CSMSP143

  Hope this helps

• SQL error: ORA-00979: not a GROUP BY

  Hi team,

  I am trying to execute the query

  SELECT DISTINCT comp.company_name |' -' || COMP.contract_number AS 'company_name '.

  , UPPER (bh.first_name) AS 'budget_holder '.

  , INITCAP (sup.first_name) |' -' || SUP. Surname AS 'supervisor '.

  , INITCAP (emp.status) AS "Department".

  , INITCAP (emp.first_name |) » '|| EMP. Surname) AS "employee."

  r.employee_id

  , emp.paaf_number AS 'paaf_num '.

  , emp.employee_payroll_number AS 'payroll_num '.

  , emp.discipline AS 'discipline '.

  , NVL (SUM (tg.week_day1), 0) AS "day 1".

  , NVL (SUM (tg.week_day2), 0) AS "day 2".

  , NVL (SUM (tg.week_day3), 0) AS day '3 '.

  , NVL (SUM (tg.week_day4), 0) AS "day4.

  , NVL (SUM (tg.week_day5), 0) AS "day5".

  , NVL (SUM (tg.week_day6), 0) AS "day6.

  , NVL (SUM (tg.week_day7), 0) AS "day 7".

  r.valid_from

  r.valid_to

  Tw_roster_data r

  JOIN tw_employee emp

  ON emp.employee_id = r.employee_id

  JOIN tg tw_timesheet_stage

  ON tg.employee_id = r.employee_id

  AND tg.week_commencing = r.valid_from

  JOIN the tw_contracting_company comp

  ON comp.contracting_company_id = r.contracting_company_id

  JOIN tw_supervisor sup

  ON sup.supervisor_id = tg.supervisor_id

  JOIN tw_budget_holder bh

  ON bh.budget_holder_id = sup.budget_holder_id

  WHERE r.contracting_company_id = 101

  AND r.VALID_FROM = January 31, 2015.

  AND r.VALID_TO = February 6, 2015"

  Group of r.employee_id, comp.company_name, bh.first_name,

  EMP.paaf_number, emp.employee_payroll_number, emp.discipline,

  r.valid_from, r.valid_to;

  But still the error below

  Error in the command line: 1 column: 17

  Error report-

  SQL error: ORA-00979: not a GROUP BY expression

  00979 00000 - "not a GROUP BY expression"

  Can help.

  Hello

  When to use analytical function oracle other columns used based on the analysis, must be included in the GROUP BY Clause

  SELECT expression1, expression2, ... expression_n,
    aggregate_function (expression)
  FROM tables
  WHERE conditions
  GROUP BY expression1, expression2, ... expression_n;
  

  SQL 101: Seen are medium and other aggregate data

    SELECT DISTINCT
           comp.company_name || ' - ' || comp.contract_number AS "company_name",
           UPPER (bh.first_name) AS "budget_holder",
           INITCAP (sup.first_name) || ' - ' || sup.surname AS "supervisor",
           INITCAP (emp.status) AS "department",
           INITCAP (emp.first_name || ' ' || emp.surname) AS "employee",
           r.employee_id,
           emp.paaf_number AS "paaf_num",
           emp.employee_payroll_number AS "payroll_num",
           emp.discipline AS "discipline",
           NVL (SUM (tg.week_day1), 0) AS "day1",
           NVL (SUM (tg.week_day2), 0) AS "day2",
           NVL (SUM (tg.week_day3), 0) AS "day3",
           NVL (SUM (tg.week_day4), 0) AS "day4",
           NVL (SUM (tg.week_day5), 0) AS "day5",
           NVL (SUM (tg.week_day6), 0) AS "day6",
           NVL (SUM (tg.week_day7), 0) AS "day7",
           r.valid_from,
           r.valid_to
      FROM tw_roster_data r
           JOIN tw_employee emp
              ON emp.employee_id = r.employee_id
           JOIN tw_timesheet_stage tg
              ON tg.employee_id = r.employee_id
                 AND tg.week_commencing = r.valid_from
           JOIN tw_contracting_company comp
              ON comp.contracting_company_id = r.contracting_company_id
           JOIN tw_supervisor sup
              ON sup.supervisor_id = tg.supervisor_id
           JOIN tw_budget_holder bh
              ON bh.budget_holder_id = sup.budget_holder_id
     WHERE     r.contracting_company_id = 101
           AND r.VALID_FROM = '31-JAN-2015'
           AND r.VALID_TO = '06-FEB-2015'
  GROUP BY
  comp.contract_number
  ,comp.company_name
  ,bh.first_name
  ,sup.first_name
  ,sup.surname
  , emp.status
  ,emp.first_name
  ,emp.surname
  r.employee_id,
  emp.paaf_number,
  emp.employee_payroll_number,
  emp.discipline,
   r.valid_from,
   r.valid_to;