Number of login page
Hi all
We run 12.1.3 (with US + AR Lang) with 11.2.0.3 DB on EL 6.
We must go no to rac RAC...
only a node not rac ebs.
befor moving to the rac, functioned well as login page of English and Arabic is coming and the user can access and launch form etc.
After a migration successful cars online, English behaves as expected but problem with Arabic, login page is coming and visible
List of responsibilities, but when click on any of the form, he come and go immediately.
I tried running autoconfig on all DB and knots APPL... it is successful.
has run compiled adadmin forms and jsp, JAR generated...
Nothing very interested DB file alert nor invalid objects.
ora_nls10 is located on the path.
Hello
When no CARS migration of CARS you run perl cr9idata.pl? and it has worked successfully on both the DB node?
Check below if working in you case.
How do I solve the APP-FND-02950 starting forms by NLS language ( Doc ID 1061865.1 )
regds,
D<>A
Tags: Oracle Applications
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Number of Login ADF pages with ADF security
Hi all
I created a login using Jdeveloper 12 c page. I created this based on a demo of youtube video connection. (https://www.youtube.com/watch?v=mAWBezngA1s)
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I created the user-> business-> Application role role. Also given A newly created page protected.jsf to the application role.
I tried to replace 'protected.jsf' 'xyz.jsf' (scheduled to get an error because there is no page called xyz.jsf), but refreshes him just screen, do not throw any mistake also.
Could you please let me know what could be the problem.
I would like to know if I need to provide more details.
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Live view is registered in jdev 11 GR 2.
One of the big differences between 11 billion and 12 c is the default behavior for the button component.
11 g af:commandButton a partialSubmit = false, while in 12 c af:button a partialSubmit = true by default.
For example, the value partialSubmit = "false" on your login button.
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ENVIRONMENT:
JDeveloper 12.1.3.1.41
MAF 2.1.1.0.41
Xcode 6.2
10.9.5 OSX
Early 2011 Macbook Pro
Post edited by: rsmith248 Miskeyed JDeveloper version number.
Hello
Have you considered showing your registration page server side in an iframe?
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Steven Davelaar,
Oracle Mobile & Cloud A-team.
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Hello!
I would like to implement the feature (as is on the login page of LinkedIn) where according to saved cookie (username) there are certain notifications (messages, etc.).
How to make a such hing Apex 4.2? At least some advice what should be the right direction.
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Damir
See the Notification icon with the number of pending notifications
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Hello!
I have the page of connection (desktop, theme 25) which has been slightly modified by me. I use custom_auth on table mine of users.
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By comparing your login to app demo and mine the login page, I saw that in my login page is missing the bunch of js:
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that is the same. Part missing is obviously part for gas meter.Apex.jQuery( document ).ready( function() {
I tried all the browser and they are all the same as a result.
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I'm quite confused because before that this one was't of thing happened because before the introduction of "gas" I had no such a mistake... or I wasn't awre of them.
:-)
Any help or suggestion?
Damir Vadas
http://Damir-vadas.blogspot.com
Apex 4.2.1.00.08
Oracle 11.2.0.3 x 64
Apex listener 2.0.0.354.17.05So, you changed the page of connection somehow, perhaps recreate - and now things go wrong?
Firstly - if you want to authenticate on your own table, it is much easier to leave the single login page and use a custom authentication scheme.
Second - if you want the user to land on their own page, I find personally much easier to define a branch that manages that decision-making - perhaps something ruled separately during after authentication.
Scott
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from the login page in the apex 4.1.1
Hello
My requirement is to bypass the connection when run us the application and connect at the click of a tab.
I have legs like
Home, tab1, tab2, tab 3/Admin
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but, when I click on the Admin tab it should ask to connection and this must be validated from a database table. He should not claim again through the session.
some can help on this please.
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Vikas KodariHi Vikas,
Use the default login page that comes at the time of the creation of application
or try the below function
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Kind regards
Jitendra -
Display Messages customized login Page
I use a custom with APEX 4.1.1 authentication and I want to display error messages that are customized on the login page if authentication fails. In my authentication function, I use apex_util.set_authenication_result to set a result code (code below). I tried to use the apex_util.get_authenication_result on the login page to hide and display custom messages, but it does not work. I don't think that the apex_util.get_authenication_result is in fact to get the result? I'm doing something wrong? Is there a better way?
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MarkHello
Thank you.
In your example, it's that you have used the page element.
In this solution, you must use the application to store the custom login message.
I have fix your example. Please checkKind regards
Jari
-----
My Blog: http://dbswh.webhop.net/htmldb/f?p=BLOG:HOME:0
Twitter: http://www.twitter.com/jariolai -
APEX 4.1 Login page kills the existing session cookie
So far the session cookie enabled us to figure out if the user has already had a session and redirect them to the page they wanted using this session (thanks to a method on the page of connection). Just try APEX 4.1 and it seems that this quick hack will not work, because:
a. the session cookie has been replaced by the time that the login page is loading
b. the login page gives no clue as to the destination of the user actually wanted (used to be able to verify OWA_UTIL. GET_CGI_ENV('QUERY_STRING') to see what looked like the URL, but now the URL is simply the login page)
The problem that I am trying to solve is a job of logging system where users get a lot of e-mail notifications. With the standard behavior of the APEX, they will have to identify each time they click on a link in an e-mail. Because it is a rather unusual behavior for another web application, I used, anyone has any ideas about how to get the APEX to stop killing sessions by substituting the cookie whenever it sees a URL he dislikes? Have tried to use the session 0, but still it beats my cookie.Hey Capt egg,
Nice to see that you studied and found a solution. However, I think that things can be a bit improved. It seems that you already used a custom authentication scheme, it is good, because it allowed to use application session hooks join. However, I think that this does not exactly what you expect.
During the installation of the session, at the beginning of the Summit "request for treatment, he runs about this code:"
1 write the session id of the query (parameter to URL or POST) in a global variable
2 load of metadata application authentication (cookie name, Sentry function, function of invalid session, etc.)3. If a global session exists, run "Builtin Cookie Sentry":
3.1 query the table of the session by the value of the cookie.
3.2 If the session of the query id matches the overall session id, session information matching.
3.3. in the case, the session information is incomplete, reset the session variable.4. If this is not the login page, run application-specific Sentinel:
4.1 run the result of the Sentinel session function if a function is defined
4.2 If the Sentinel returned true function, run the validation function if it is set5. "create / reuse Session."
5.1. If the session variable points to a valid session record, the user to read and other variables of the session save
5.2 in the case, create a new session not authenticated6. write a new cookie in HTTP session if a new session was created
7. If the sentinels (4) returned false, run 'Invalid Session Manipulation':
7.1 save deep link in the current page
7.2 run invalid session function if a function is defined
7.3 redirect to url "Invalid Session" of authenticationThis is only an overview and implementation details may change. However, I think that it can show major problems with the help of the function of invalid session for Assembly of the session:
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function session_joining_sentry return boolean is l_cookie_session_id number; l_user APEX_WORKSPACE_SESSIONS.USER_NAME%TYPE; l_result boolean; procedure dbg(p_str in varchar2) is begin apex_application.debug('session_joining_sentry: '||p_str); end dbg; begin if APEX_CUSTOM_AUTH.GET_SESSION_ID is not null then dbg('apex could already determine session by URL session id and cookie value'); l_result := true; else dbg('apex could not determine session by URL session id and cookie value'); l_cookie_session_id := APEX_CUSTOM_AUTH.GET_SESSION_ID_FROM_COOKIE; if l_cookie_session_id is not null then dbg('apex found session via cookie. we try to re-use this as our current session id'); begin select user_name into l_user from APEX_WORKSPACE_SESSIONS where apex_session_id = l_cookie_session_id; l_result := true; exception when NO_DATA_FOUND then dbg('session could not be found in session table - sentry fails'); l_result := false; end; if l_result then dbg('re-using session for user '||l_user); APEX_CUSTOM_AUTH.DEFINE_USER_SESSION ( p_user => l_user, p_session_id => l_cookie_session_id); end if; else dbg('apex could not find the session cookie. sentry fails'); l_result := false; end if; end if; return l_result; end session_joining_sentry;
Also, it should be noted that the session join is precarious. If you plan to implement this, please make sure that you understand the dangers of the cross-site request forgery:
http://en.Wikipedia.org/wiki/cross-site_request_forgery
Kind regards
ChristianPublished by: Christian Neumueller on March 2, 2012 04:24
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BUG? Conditional processing on the incompatible LOGIN page
My login page 101 has no branching, so I guess that single processing step moving my users on 1/Home page, via:
Sequence processing 20, after calculations and validations
(wwv_flow_custom_auth_std). Login
P_UNAME = >: P101_USERNAME,.
P_PASSWORD = >: P101_PASSWORD,.
P_SESSION_ID = >: FLOW_SESSION,.
P_FLOW_PAGE = >: APP_ID | » : 1'
);
To this, I added a condition: there ARE
Select the id of tabA where col1 = 'TRUE' and upper (poc) = upper(:P101_USERNAME)
And sequences of treatment added 30, after calculations and validations
(wwv_flow_custom_auth_std). Login
P_UNAME = >: P101_USERNAME,.
P_PASSWORD = >: P101_PASSWORD,.
P_SESSION_ID = >: FLOW_SESSION,.
P_FLOW_PAGE = >: APP_ID | » : 2'
);
With the opposite condition: THERE is NO
Select the id of tabA where col1 = 'TRUE' and upper (poc) = upper(:P101_USERNAME)
-===============-
If the sql query returns no rows, normal go to page 1, but if the sql query return lines, go to page 2. No users are redirected to page 2 to login even if I query the database via SQLplus and I get lines.
I need help finding this.
Published by: Lee McCann 18 March 2011 09:01Hello
Instead of having two separate processes, why don't you have a process as follows:
DECLARE v_redirect_page NUMBER := 2;--assume this is next page v_count NUMBER; BEGIN select count(*) into v_count from tabA where col1 = 'TRUE' and upper(poc) = upper(:P101_USERNAME); if v_count >= 1 THEN v_redirect_page := 1; END IF; wwv_flow_custom_auth_std.login( P_UNAME => :P101_USERNAME, P_PASSWORD => :P101_PASSWORD, P_SESSION_ID => :FLOW_SESSION, P_FLOW_PAGE => :APP_ID || ':' || v_redirect_page ); END;
Van
Trent -
Hello
How can I set the table
I changed the method of authentication to my request: I put it in the database.
I created a table MYUSERS, table I copied from the demo application.
I have my 2 users: ADMIN and DEMOCREATE TABLE "REGUSERS" ( "USER_ID" NUMBER NOT NULL ENABLE, "USER_NAME" VARCHAR2(100 CHAR), "PASSWORD" VARCHAR2(4000 CHAR), "CREATED_ON" DATE, "EXPIRES_ON" DATE, "ADMIN_USER" CHAR(1 CHAR), CONSTRAINT "REGUSERS_PK" PRIMARY KEY ("USER_ID") ENABLE )
How can I fix that on Login, my application must go on MYUSERS username and password?
Also, I tried to create a new login page, but I still don't see where to assign the table MYUSERS
Thank you
Roseline
Published by: Roseline Nov. 26. 2009 06:39
Published by: Roseline on Dec 14. 2009 09:24Roseline,
You must create the custom authentication scheme, not database. See this post
Authentication "Database" means - users can use their credentails in the database you want to connect your application to APEX. For example if you have the account of SCOTT is not locked to your underlying database, you can use this account to connect to the APEX. When you set the database authentication scheme, then APEX will go and check the name of user and password in the underlying database users table.
It may be useful
See you soon,.
Hari -
I tried more than 5 tutorials.
I read the book of Ben Forta's CFWACK.
I read the follow-up Ben Forta Book.
After all this. My login page will not work. Period.
Can someone show me a code that actually WORKS PLEASE?
Point me in a direction? SOMETHING?
All I need is:
1. a login page where students enter a user ID number and pin code.
2. click on "log in" and this code magical I still find working properly checking against DB
3. it actually WORKS and takes you to another page! * exclamations to the miracle *.
4. the index page will be a list of courses in which they are registered.
5. the student can click on a course.
6. an evaluation of the class will be specific for courses and instructors.
7. the student questionnaire
8. press submit
9. the results of the survey get bounce the DB in a measurement results where the answers are recorded for reporting.
10. the results must be registered by number of class "index".
is - it even exist anymore?
:(OK, well, now I see what's happening with your data model.
You store the studentid and pin code to each entry in the database. If you want to follow the principles of good data modelling, you would break in a table of students. Suppose that StudentID is immutable (that is to say, cannot be changed).
Students
==========
StudentID
PIN
FIRSTNAME
MIDDLENAME
LASTNAMEFaculty
==========
FacultyID
FirstName
LastNameCourse
=========
CourseID
SectionNumber
FacultyIDStudentToCourse
==============
StudentID
CourseIDThat's if you'd like to do things. If you just want to get what you work, then you must change the following line in LoginCheck.cfm:
TO:
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Problem creating conditional branching to different login Pages
Hi all
My requirement is very similar to what is said in this post. But I use LDAP for authentication
I've implemented it exactly in the way that andy mentioned 3 steps. Here is my PL/SQL
declare
l_page varchar2 (30);
v_role varchar2 (20);
Start
Select CTS_GROUP in the cts_Administrator_contacts v_role where CN_ID = LOWER(:APP_USER);
If v_role = l_page then 'Network': = '79';
Another l_page: = '71';
end if;
(wwv_flow_custom_auth_std). Login
P_UNAME = >: P101_USERNAME,.
P_PASSWORD = >: P101_PASSWORD,.
P_SESSION_ID = > v ('APP_SESSION').
P_FLOW_PAGE = >: APP_ID |': ' | l_page
);
end;
When I try to connect after you change the login process, get ORA-01403: no found error...
Can you get it someone please let me know what the problem is... Because the CN_ID with which I tried is the database... Is the problem, m because it uses the LDAP authentication... Must it be done differently...
I also tried the following in the SQL workshop
declare
l_page varchar2 (30);
v_role varchar2 (20);
Start
Select CTS_GROUP in the cts_Administrator_contacts v_role where CN_ID = LOWER(:APP_USER);
If v_role = l_page then 'Network': = '79';
Another l_page: = '71'; -default home page
end if;
Dbms_output.put_line (l_page);
end;
and it print the correct page number... I don't know that I need to change the process of connection in a different way, since I use LDAP authentication and groups are in my database... Can someone point me in the right direction...
Thank you
Yvettewhere CN_ID = LOWER(:APP_USER);
You get an exception because no data found: APP_USER is null on the login page. Reference: P101_USERNAME instead.
Scott
-
RW-50016: Login Page error all in R12
Hi all
I was able to start the installation of Oracle Apps R12 and I am at stage 4/5 of the installation during the audit of the system of fast installation
RW-50016: Login Page error all in R12
All other controls are passed with the exception of this one.
Could someone, please let me know to go further.
I use the latest p7308107_R12_GENERIC.zip startcd quick installation
Thank you
Rizwan.Rizwan,
I think you started the application services last time, so all changes since then?
Please, stop all the services application, check the OS that no active process still exist and remove the locking file according to the following document.
Note: 555214.1 - Oacore process does not start after having increased their number in Oracle Applications version 12 in Context.xml
https://metalink2.Oracle.com/MetaLink/PLSQL/ml2_documents.showDocument?p_database_id=not&P_ID=555214.1Once you have finished, start the application services and then check.
Kind regards
Hussein -
Problem with adding a new value to the default login Page
I hope he's a simple guy, I added an element of the selection list to the standard login page (P101) to allow the user to select a FIELD as well as their username and password.
When the next page appears and I am trying to retrieve the value which is held in the new domain, it has been deleted, but the values entered in the elements
P101_USERNAME and P101_PASSWORD are always present.
I can't understand why the values that held in points P101_USERNAME and P101_PASSWORD are always present, but P101_DOMAIN has been deleted.
I tried to create value to the zero page and writing in the field of value using pl/sql and javascript, but as soon as the page is requested, the value is cleared.
Any ideas how to get around this problem?
Thanks in advanceI guess that your login page contains a process like this:
BEGIN wwv_flow_custom_auth_std.login (p_uname => v ('P101_USERNAME'), p_password => :p101_password, p_session_id => v ('APP_SESSION'), p_flow_page => :app_id || ':1' ); :t_random_number := :p101_random_number; /* this is something I added to my code */ END;
Now, if you go to this page:
http://Apex.Oracle.com/pls/OTN/f?p=31517:1
Please note the random number assigned to you. Once you login, the same number will appear on page 1 (near the top).
So, this is how you can solve your problem.
:t_random_number
is a part of the application.
Denes Kubicek
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